A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position for a -6.0 nC charge.

Answers

Answer 1

Answer: [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.

Explanation:

Given

The magnitude of the first charge is  [tex]Q_1=3.5\ nC[/tex]

The magnitude of the second charge is [tex]Q_2=5\ nC[/tex]

[tex]-6\ nC[/tex] charge must be placed in between the two charges to establish equilibrium

The electrostatic force is given by

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Equilibrium will be established when force by both the charges balance out each other. Suppose [tex]-6\ nC[/tex] is placed at a distance of [tex]x[/tex] cm from [tex]3.5\ nC[/tex] . So, we can write

[tex]\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}[/tex]

Canceling similar terms

[tex]\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm[/tex]

Thus, the equilibrium position is [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.

Answer 2

Answer:

What school do you go to?

Explanation:


Related Questions

a Q. No. la sap
What is derived is one second time?

Answers

Answer:

The second (abbreviation, s or sec) is the Standard International ( SI ) unit of time. One second is the time that elapses during 9,192,631,770 (9.192631770 x 10 9 ) cycles of the radiation produced by the transition between two levels of the cesium 133 atom. ... One second is equal to 1/86,400 of a mean solar day.

Explanation:

1. What is the magnitude of the force on a charge of +40 μC that is 0.6 m from a charge of - 80 μC?

Answers

Answer:

The magnitude of the force is 79.893 N.

Explanation:

The magnitude of the electrostatic force between the two particles is determined by Coloumb's Law, whose formula is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)

Where:

[tex]\kappa[/tex] - Electrostatic constant, in newtons-square meters per square coulomb.

[tex]q_{A}, q_{B}[/tex] - Electric charges, in coulombs.

[tex]r[/tex] - Distance, in meters.

If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q_{A} = +40\times 10^{-6}\, C[/tex], [tex]q_{B} = - 80\times 10^{-6}\, C[/tex] and [tex]r = 0.6\,m[/tex], then the magnitude of the force is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]

[tex]F = 79.893\,N[/tex]

The magnitude of the force is 79.893 N.


7. An object can be accelerating even if its speed is
constant if it
(a) comes to a stop
(b) is not possible
(C) changes direction
(d) moves in a straight line​

Answers

Answer:

I think that the answer might be d

Answer:

D

Explanation:

If a car is moving very fast in a straight road or a highway in such a way that it has reached its limits as soon as it is going that fast it can break it limit

Waves that move through space are called

Answers

Answer:

Electromagnetic waves are waves that can travel through matter or through empty space

Can someone list me 6 disadvantages of renewable energy?

Answers

1. Can be very expensive
2. It can still generate pollution
3. Lack of knowledge on how to even harness these forms of energy
4. Can be hard to generate the quantities of electricity
5. Takes a lot of space to install
6. Fluctuation problems (solar)

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject

Answers

Answer:

Third option

Explanation:

To calculate meters per second you divide the distance by the time.

it's 8m/s


State the relationship between the mass of trolley and acceleration of the trolley?

Answers

Answer: The complementary relationship indicated by the Newton's second law...

For a given applied force the acceleration of the trolley is inversely proportional to it's mass.

A 25 kg block is sliding down 28o incline at a constant speed.

Answers

try photo math it helps

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject

Answers

Explanation:

speed : • how fast an object changes position

• miles per hour.

• distance/time.

velocity: • speed in a direction

• miles per hour North

• distance/ time in a direction

Decribe the general shape of the graph.​

Answers

Answer:

the results increase, positive

Which of the following statements is true about absolute zero?

It is the point at which electrons separate from the nucleus of atoms.
It is the point at which electrons separate from the nucleus of atoms.

It is theoretically the point at which all particle motion stops.
It is theoretically the point at which all particle motion stops.

It occurs at 273 degrees Kelvin.
It occurs at 273 degrees Kelvin.

It is the point at which protons separate from neutrons in the nucleus

Answers

Answer:

It is the point at which electrons separate from the nucleus of atoms. It is the point at which electrons separate from the nucleus of atoms. It is theoretically the point at which all particle motion stops. ... It occurs at 273 degrees Kelvin. ... It is the point at which protons separate from neutrons in the nucleus.

Explanation:

Why must the Moon travel more than a full orbit around the Earth for the full moon to be complete?

Answers

Answer:

The difference between the sidereal and synodic months occurs becuase as our moon moves around the earth, the earth also moves around our sun. Our moon must travel a little farther in its path to make up for the added distance and complete the phase cycle.

Explanation:

Hope this helps.

What are examples of changes in people, animals, or objects that would help you make a claim about their age? NO LINKS OR YOURE GETTING REPORTED. Thanks


It’s Earth Science

Answers

Answer:

An example of changes in people based on their age, are mood changes,playfulness and as of objects you can say old or broken, animals can use the same reference as humans, the more mature you are can suggest your older, such as the more worn down your are based on a object

How do you rationalize the tension being used in Tennis Racket strings using the concept of impulse and momentum?

Answers

Answer:

The momentum, ΔP, and therefore, kinetic energy given to the ball in a serve is the result of the product of the tension force, 'F', in the string and the time of contact, Δt, between the ball and the string

ΔP = F × Δt

Explanation:

The impulse, ΔP, is the produce of the force, 'F', applied to a body for a given period of time, Δt', that gives motion to the body, and it is equal to the change of momentum of the body

ΔP = F × Δt

The momentum, 'P', of a body is the product of the mass, 'm', of the body and its velocity, 'v'

P = m × v

Tension is the axial pulling force of a string

T = Axial Force, F[tex]_{axial}[/tex]

The tension used in Tennis Racket strings is between 40 to 65 lbs.

When high tension is used in the string, the string is taut, and the contact duration between the Racket string and the ball is minimal, and the player needs to use more force to obtain a high momentum, and therefore, energy in the ball, which reduces control, and increase stress, as force is more emphasized

When low tension is used in the string, the Tennis Racket strings are more elastic. During a serve, the ball pushes the strings further back into the racket, such that the ball spends more time in contact with the string, (Δt is larger), and therefore, the impulse, F·Δt = ΔP, given to the ball is larger, therefore, the ball has a larger change in momentum, and therefore more energy in the intended direction.

However, a very slackened string will increase the increase area and time (large Δt) of contact of the ball and the racket such that the force given to the ball, F = ΔP/(large Δt) is reduced and therefore reduce the likelihood of gaining points from a serve against an opponent with a much forceful return of a serve.

Three people push a piano on wheels with forces of 130 N to the right, 150 N to the left, and 165 N to the right. What is the strength and direction of the net force on the piano?

Answers

Answer:

45 N to the right possibly?

A 35 g block of ice is cooled to −83 ◦C. It is added to 565 g of water in an 87 g copper calorimeter at a temperature of 22◦C. Find the final temperature. The specific heat of copper is 387 J/kg · ◦C and of ice is 2090 J/kg · ◦C . The latent heat of fusion of water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg · ◦C . Answer in units of ◦C.

Answers

Answer:

Explanation:

Heat gained by ice in warming up to 0⁰C = .035 x 2090 x (83-0)= 6071.45 J

heat used up by ice to melt at 0⁰C = .035 x 3.33 x 10⁵ J = 11655 J

Heat used up in warming up water to t⁰C = .035 x 4186 x t = 146.51 t

heat released by warm water to cool from 22⁰C to t = .565 x 4186 x ( 22 - t )

=52032 -2365.1 t

heat released by copper calorimeter  to cool from 22⁰C to t =  .087 x 387 x ( 22 - t ) = 740.72 - 33.7 t

total heat released = 52032 -2365.1 t  + 740.72 - 33.7 t

= 52772.72 - 2398.8 t

Heat lost = heat gained

52772.72 J- 2398.8 t  = 6071.45 J + 11655 J + 146.51 t

2545.31 t = 35046.27

t = 13.8°C.

The semi-major axis of this ellipse is 8.8 cm, and the distance from one of the foci to the
center is 4.4 cm. What is the eccentricity of the ellipse?

Answers

The eccentricity is 0.5

How are the surface of Mercury and Mars similar to the surface of the Earth?

Answers

Answer:

The terrestrial planets all have rocky surfaces that feature mountains, plains, valleys and other formations. ... Mars has very low atmospheric pressure, and Mercury has almost none, so craters are more common on these planets.

Explanation:

Milk is a very weak acid. What might its pH value be ?

Answers

Answer:

pH value is between 6.5 and 6.8

Explanation:

Explanation:

Milk fresh from the cow typically has a pH between 6.5 and 6.7. The pH of milk changes over

Which type of map best shows the three dimensions of Earth’s surface?

Answers

Answer:

please give me brainlist and follow

Explanation:

topographic map

A topographic map shows a three-dimensional representation of a flat surface. It has contour lines joining points of equal elevation; the closer the lines are the steeper the elevation is.

it did work lollllllllllllllll

Answers

Answer:

Ok.............

hfjjjjjjlnggmm

Based on the graph, describe how momentum changes with time for an object in free fall. If you can help, I would be so grateful.

Answers

With time, momentum increases as it builds speed assuming their is nothing in the way to stop it. Based on the graph, you can see that example being displayed as the line on the graph gets higher

John, a fireman, slides down a pole when the fire alarm sounds. He reaches the ground at 5m^-1. Give that his mass is 60kg. Find the friction that acts against his motion as he slides down the pole.

Answers

Friction as it is acting upon an object over a surface

In the the table there is 20 kj of coal, how much energy in joules is 1g of coal?

Answers

Answer:

what do u meN by this i really don't know

______ charges repel each other.

Answers

Answer:

like I commented it yesterday can i have brainiest

Explanation: oh and HI

Answer:

Like

Explanation:

I put it before but my answer got deleted

A 20 g block of ice is cooled to −65 ◦C. It

is added to 570 g of water in an 76 g copper

calorimeter at a temperature of 26◦C.

Find the final temperature. The specific

heat of copper is 387 J/kg ·

◦C and of ice is

2090 J/kg ·

◦C . The latent heat of fusion of

water is 3.33 × 10^5

J/kg and its specific heat

is 4186 J/kg ·

◦C .

Answer in units of ◦C.

Answers

Answer:

The final temperature is approximately 23.55°C

Explanation:

The given parameters are;

The mass of the ice block, m₁ = 20 g

The initial temperature of the block, T₁ = -65°C

The mass of the water to which the block is added, m₂ = 570 g

The mass of the copper container containing the water, m₃ = 76 g

The initial temperature of the water and the copper, T₂ = 26°C

The specific heat capacity of copper, c₃ = 387 J/(kg·°C)

The specific heat capacity of ice, c₄ = 2,090 J/(kg·°C)

The latent heat of fusion of ice, l = 3.33 × 10⁵ J/kg

The specific heat capacity of water, c₁ = 4,186 J/(kg·°C)

We have;

ΔQ = m₁·c₁·ΔT + m₁·l = m₂·c₂·ΔT + m₃·c₃·ΔT

Therefore, we get;

20 × 2,090 × -65 +  20 × 3.33 × 10⁵ + 20 × T × 4,186  = 570 × 4,186 × (26 - T) + 76 × 387 × (26 - T)

Using a graphing calculator, we get;

83720·T + 3943000 = 62801232 - 2415432·T

The final temperature, T ≈ 23.55 °C

A tuba creates a 4th harmonic of frequency 116.5 Hz. What is the frequency of the third harmonic? (Speed of sound = 343 m/s) (Unit = Hz )​

Answers

Answer:

3rd Harmonic Frequency created by tuba is equal to [tex]87.375[/tex] hertz

Explanation:

Given -

4th Harmonic frequency created by tuba is equal to [tex]116.5[/tex] hertz

1st Harmonic Frequency created by tuba is equal to [tex]\frac{116.5}{4}[/tex] hertz

3rd Harmonic Frequency created by tuba is equal to [tex]3* \frac{116.5}{4}[/tex] hertz

3rd Harmonic Frequency created by tuba is equal to [tex]87.375[/tex] hertz

Answer:

87.375 Acellus

Explanation:

Please help me look at the image below

Answers

I can’t see anything

The half-life of technetium-99 is 6 hours.How much of a 100 milligram sample of
technetium-99 will remain after 30 hours? *
O 3.125 mg
O 12.5 mg
O 6.25 mg
O 1.56 mg

Answers

6.25 mg ...............

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration

Answers

[tex]\Large {{ \sf {Question :}}} [/tex]

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?

[tex]\Large {{ \sf {Given :}}} [/tex]

Initial Velocity (u) - 5 m/sFinal Velocity (v) - 15 m/sTime (t) - 10 sec

[tex]\Large {{ \sf {Formulae :}}} [/tex]

If the velocity of an object changes from an initial value u to the final value v in time t, the acceleration a is, [tex]a \: = \frac{v - u}{t} [/tex][tex]\Large {{ \sf {Step-by-step explanation :}}} [/tex]

[tex]a \: = \frac{v - u}{t} \\ or \: \: a = \frac{(15 - 5)}{10} m \: s^{ - 2} \\ or \: \: a \: = \frac{10}{10}m \: s^{ - 2} \\ or \: \: a = 1m \: s^{ - 2} [/tex]

[tex]\Large {{ \sf {Answer :}}} [/tex]

His acceleration is [tex]1m \: s^{ - 2} [/tex]
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