Which equation could not be used to determine straight line acceration?
Answer:
the answer for the question is the last option
Highlight two factors which shows that heat from the sun does reach the earth's surface by convection.
radiation
when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation
Absence of medium is the factor which shows that heat from the sun does reach the earth's surface by convection.
The heat of the sun reaches the earth only through radiation because radiation does not require any medium for the transfer of energy but convection and conduction required a medium to transfer heat energy.
We know that there is no medium present in vacuum so convection and conduction are impossible in a vacuum that's why the sun's heat does not reach the earth by conduction or convection.
Learn more about convection here: https://brainly.com/question/9382711
Learn more: https://brainly.com/question/22811911
state and explain the disadvantages of anomalous expansion of water
Answer:
я не знаю старайся изо всех сил
Explanation:
[tex]\huge{\mathbb{\tt { QUESTION↓}}}[/tex]
[tex]\color{green}{\tt State \: and \: explain \: the \: disadvantages}[/tex]
[tex]\color{green}{\tt { of \: anomalous \: expansion \: of \: water}}[/tex]
[tex]\huge{\mathbb{\tt {ANSWER↓}}}[/tex]
[tex]{\boxed{\boxed{\tt { DISADVANTAGES \: of \: anomolous \: expansion \: of \: water }}}}[/tex]
Since the maximum density can be found for a positive temperature, water's own weight will prevent it from freezing from the bottom up. However, the anomalous expansion of water has some negative consequences. ... As the water freezes it expands and can rip pipes open.[tex]{\boxed{\boxed{\tt { What \: is \: the \: state \: of \: anomalous \: expansion \: of \: water? }}}}[/tex]
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph#CarryOnLearning
#JustEnjoyTheSummer
→XxKim02xXCalculate the refractive index for a substance where the angle of incidence is 300 , the angle of refraction is 600 , and the refractive index of second substance is 1.5
Answer:
η₁ = 2.6
Explanation:
Here, we will use snell's law to calculate the refractive of the substance:
[tex]\frac{\eta_2}{\eta_1} = \frac{Sin\theta_1}{Sin\theta_2}[/tex]
where,
η₁ = refractive index of first substance = ?
η₂ = refractive index of second substance = 1.5
θ₁ = angle of incidence = 30°
θ₂ = angle of refraction = 60°
Therefore,
[tex]\frac{1.5}{\eta_1} = \frac{Sin\ 30^0}{Sin\ 60^0}[/tex]
η₁ = 2.6
A decibel measures the _____________ of sound.
A.pitch
B,frequency
C.loudness
D.amplitude
how is momentum of an object related to stopping distance
Answer:
To stop a car must lose its momentum and its kinetic energy. ... If the forces on two cars are equal then the greater the kinetic energy the greater the distance before stopping. But there will be a relationship to the momentum because momentum and mass are both related to the kinetic energy.
What is the momentum of a 200 kg truck travelling at 20 m/s?
Answer:
p = 4000 kg-m/s
Explanation:
Given that,
The mass of a truck, m = 200 kg
Speed of the truck, v = 20 m/s
We need to find the momentum of the truck. The formula for momentum is given by :
p = mv
so,
[tex]p=200\times 20\\\\p=4000\ kg-m/s[/tex]
So, the momentum of the truck is equal to 4000 kg-m/s.
Milk is a very weak acid. What might its pH value be ?
Answer:
pH value is between 6.5 and 6.8
Explanation:
Explanation:
Milk fresh from the cow typically has a pH between 6.5 and 6.7. The pH of milk changes over
Is telekinesis real??? I really wanna start learning it!
Answer:
if you only have to control your chakra and know how to get all your vibes to pass it to objects and it takes time to practice
PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject
Answer:
Third option
Explanation:
To calculate meters per second you divide the distance by the time.
it's 8m/s
An object is located 20.0 cm from a convex lens. The lens focuses light at a
distance of 10.0 cm. What is the image distance?
A. 6.67 cm
B. -6.67 cm
C. -20.0 cm
D. 20.0 cm
The Answer Is : D. 20.0 cm
My Reason : These types of problems can all be solved using the lens or mirror equation.
1/20 +1/q= 1/10
q=20 cm
The image is formed behind the lens at 2f or the center of curvature.
It is real, inverted, and the same size as the object
The Answer Is: D. 20.0 cm
Explanation: I did the test :)
A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connected to a movable object. The spring and object are compressed by 0.065 m, released from rest, and subsequently oscillate back and forth with an angular frequency of 11.3 rad/s. What is the speed of the object at the instant when the spring is stretched by 0.048 m relative to its unstrained length
Answer:
Explanation:
Given that:
angular frequency = 11.3 rad/s
Spring constant (k) = [tex]= \omega^2 \times m[/tex]
k = (11.3)² m
k = 127.7 m
where;
[tex]x_1[/tex] = 0.065 m
[tex]x_2[/tex] = 0.048 m
According to the conservation of energies;
[tex]E_1=E_2[/tex]
∴
[tex]\Big(\dfrac{1}{2} \Big) kx_1^2 =\Big(\dfrac{1}{2} \Big) mv_2^2 + \Big(\dfrac{1}{2} \Big) kx_2^2[/tex]
[tex]kx_1^2 = mv_2^2 + kx_2^2[/tex]
[tex](127.7 \ m) \times 0.065^2 = v_2^2 + (127.7 \ m) \times 0.048^2[/tex]
[tex]0.5395325 = v_2^2 +0.2942208 \\ \\ 0.5395325 - 0.2942208 = v_2^2 \\ \\ v_2^2 = 0.2453117 \\ \\ v_2 = \sqrt{0.2453117} \\ \\ \mathbf{ v_2 \simeq0.50 \ m/s}[/tex]
Light travels at the same speed at all times. True False
Answer:
true hope this help :}
Explanation: