N₂ + 3H₂ --> 2NH₃

If 207.0 g of H₂ reacts, what mass of NH₃ is produced?

Answer: 25

Explanation:

The new volume will be 18 L

The volume of a dry gas of a given mass was inversely proportional to its pressure at constant temperature, according to Boyle's law. At moderate pressures and temperatures, most gases behave like ideal gases.

Calculation of new volume is shown as below:

The new volume of can be calculated by using Boyle's law.

[tex]P_{1} V_{1} = P_{2} V_{2}[/tex]

It is given that, [tex]P_{1}[/tex] = 0.9 atm. [tex]V_{1}[/tex] = 4 L, [tex]P_{2}[/tex] = 0.20 atm

Now, put the values of given data in above equation.

[tex]V_{2}[/tex] = [tex]P_{1}V_{1}[/tex] / [tex]P_{2}[/tex].

[tex]V_{2}[/tex] = (0.9) ×4 / 0.20

= 3.6 / 0.20

= 18 L

therefore, the new volume will be 18 L.

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Answer:

(d) Why is the fuel cell in Question (c) described as an alkaline fuel cell? (e) Another type of fuel cell uses methanol instead of hydrogen.

Explanation:

Answer:

2.41x10²¹ atoms

Explanation:

First we calculate the mass of nickel in the coin, using the given mass and percent composition:

Then we convert 0.2355 grams of nickel to moles, using its molar mass:

Finally we convert moles into number of atoms, using Avogadro's number:

Answer:

I believe the answer is "b". "During the experiment, the scientist has only one element, or variable, that is changed to test the hypothesis."

Explanation:

I remember from last year but I'm not totally sure. Good luck!

The experimental setup has been the design that includes the experimental and the control group. during the experiment, only one variable is changed to test the hypothesis. Thus, option b is correct.

The experiment design includes the testing of the hypothesis to solve the problem and reach the solution through the analysis of the observations. It has been the setup that includes the test and the control group that involves the dependent, independent, and controlled variables.

Testing one variable in the experimental designs means changing one of the elements of the experience to prove the reliability of the hypothesis. This variable is the factor that alters and affects the other factors of the experiment and leads to a cause and effect.

The result of the effect of the hypothesis proves the testability of the experiment and provides solutions to the research question. This further leads to the formulation of the law and theory.

Therefore, option A. testing one variable involves proving the hypothesis.

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Answer:

Performance Tasks 188; Instructional Videos 75

Explanation:

Answer:

21883.75 Joules are required to melt the ice!

Answer:

c. 10–14[H3O+]

Explanation:

On a calculator, calculate 10-8.34, or "inverse" log ( - 8.34). Example: What is the pOH of a solution that has a hydroxide ion concentration of 4.82 x 10-5 M? The hydroxide ion concentration can be found from the pOH by the reverse mathematical operation employed to find the pOH.

Answer:

There are 0.379 moles of Ca in the given sample.

Explanation:

Hey there!

We're given that we have 15.2 grams of Ca (Calcium). We need to convert grams to moles.

There are many different conversion types for moles. A few examples are:

There are really endless possibilities for conversion factors. Since we want to find the number of moles in a certain sample, we first need to define what a mole is.

A mole is one unit of a certain item. For instance, one cup would be equivalent to one mole. Moles are simply a hypothetical unit in chemistry that act as a placeholder.

Now, how do we find the number of moles?

We know that a mole of something is one of that substance. In this case, we're referring to one atom of Calcium.

Therefore, we need to reference a periodic table to understand what the mass of one atom of calcium is equivalent to. I'll be using the official AP Chemistry periodic table as issued by the College Board.

When we reference the periodic table, we see the mass of one atom of calcium is equivalent to 40.08 amu (atomic mass units).

We learn in chemistry that we can use the terms amu and grams interchangeably, so we have learned that one mole of calcium is equivalent to 40.08 grams.

How do we work this out?

Now, we need to find out how many moles are in 15.2 grams of calcium. We can use dimensional analysis to work this out.

Our starting unit will be 15.2 grams of Ca.

We want to convert this into moles, so we need to cancel out our grams value. Additionally, since we know that we have 40.08 grams of Ca in one mole, we can set these up as two ratios:

These ratios can be used to express the relationship between the moles of calcium and the mass of one calcium atom. However, we need our value of grams to cancel out, so since we will be using cross multiplication in our dimensional analysis, we need to use the ratio with grams on the bottom.

Now that we have selected our ratio, we can set up a multiplication problem of our two ratios:

[tex]\displaystyle \text{15.2 grams Ca} \times \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]

We assume that we have a denominator of 1 below 15.2 grams Ca.

Now, we perform our multiplication.

[tex]\displaystyle \frac{\text{15.2 grams Ca} \ \times \ \text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]

We see that our remaining unit is going to be mole(s) Ca, so we can go ahead and drop our grams Ca unit.

[tex]\displaystyle \frac{\text{15.2} \ \times \ \text{1 mole Ca}}{\text{40.08}}[/tex]

Now, we need to simplify a little bit.

[tex]\displaystyle \frac{\text{15.2}}{\text{40.08}} = \text{? moles Ca}[/tex]

Finally, let's divide our fraction and evaluate our equation to find the value of moles Ca.

[tex]\displaystyle \frac{15.2}{40.08} = \text{0.379241517 moles Ca}[/tex]

Are we done yet?

Not just yet! To complete our work, we need to find the number of significant figures we can use. We are given two values in which we can use to judge how many significant figures we are limited to.

In chemistry, we always use the least number of significant figures for precision calculations, so we need to round our answer to three significant figures.

[tex]0.379241517 \approx 0.379[/tex]

Therefore, there are approximately 0.379 moles of Ca in the given sample.

Answer:

323 kJ/g

Explanation:

ck-12 said it was correct

Answer:

A chemical bond holds atoms together.

The name of the given alkene is 2-methyl-1-propene. The correct option is A.

Alkenes are inorganic compounds. They are the series of hydrocarbons, that are formed by carbon-carbon double bonds. To find out alkenes, you have to see that the number of hydrogen atoms is always double the number of carbons.

Propene is an unsaturated compound, which is the second-simplest compound, and it contains a single double bond, and it is a colorless gas and has a texture of petroleum jelly.

CH₃C = CH₂

I

CH₃

Here, the three CH₃ are shown in the diagram, so it will be the methyl because it contains 3 CH₂, and now see the propene means one double bond and four carbon atoms. So it will be the 2-methyl-1-propene.

Thus, the correct option is A. 2-methyl-1-propene.

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Answer:

C.Potential Energy

Explanation:

Answer:

C) Organic Weathering

Explanation:

Heat and Cold

And if some people start reporting and making fun of me in this answer don't listen to them.

They are hunting me down.

Answer:

1.175 M

Explanation:

The balanced reaction is:

First we calculate how many moles of KOH reacted, using the given concentration and volume:

Then we convert moles of KOH to moles of H₂SO₄, using the stoichiometric coefficients of the balanced reaction:

Finally we calculate the molarity of the acid:

Answer:

71.6 g of Ru(CO)₅ is the maximum mass that can be formed.

The limiting reactant is Ag

Explanation:

The reaction is:

RuI₃ (s) + 5CO (g) + 3Ag (s) → Ru(CO)₅ (s) + 3AgI (s)

Firstly we determine the moles of each reactant:

169 g . 1mol /481.77g = 0.351 moles of RuI₃

58g . 1mol /28g = 2.07 moles of CO

96.2g . 1mol/ 107.87g = 0.892 moles

Certainly, the excess reactant is CO, therefore, the limiting would be Ag or RuI₃.

3 moles of Ag react to 1 mol of RuI₃

Then 0.892 moles of Ag may react to (0.892 . 1) /3 = 0.297 moles

We have 0.351 moles of iodide and we need 0.297 moles, so this is an excess. In conclussion, Silver (Ag) is the limiting.

1 mol of RuI₃ react to 3 moles of Ag

Then, 0.351 moles of RuI₃ may react to (0.351 . 3) /1 = 1.053 moles

It's ok, because we do not have enough Ag. We only have 0.892 moles and we need 1.053.

5 moles of CO react to 3 moles of Ag

Then, 2.07 moles of CO may react to (2.07 . 3) /5 = 1.242 moles of Ag.

This calculate confirms the theory.

Now, we determine the maximum mass of Ru(CO)₅

3 moles of of Ag can produce 1 mol of Ru(CO)₅

Then 0.892 moles may produce (0.892 . 1) /3 = 0.297 moles

We convert moles to mass → 0.297 mol . 241.07g /mol = 71.6 g

Answer:

b

Explanation:

i know

Answer:

1. 2Al + Cl2 = Al2Cl2

2 TiCl4 + 2Na = Ti + 2NaCl2

3. H2O2 = H2O + O2

4. Na2S + 2HCl = H2S + 2NaCl

5. Mg(OH)2 + 2HCl = MgCl2 + 2H2O

1. 3O2 = 2O3

Answer:

After checking many websites as well

I haven't seen any answer for this reaction

While I found answers or other reactions

Therefore I think this reaction cannot occur

Answer:

n = 0.0102 mol.

Explanation:

Hello there!

In this case, according to the ideal gas law, which allows us to set up a relationship among volume, pressure, temperature and moles, we can define it as:

[tex]PV=nRT[/tex]

Thus, given the volume in liters (0.1000 L), temperature in kelvins (298.15 K) and pressure in atmospheres (2.50 atm), we can solve for moles as shown below:

[tex]n=\frac{PV}{RT}[/tex]

Thereafter, we plug in the aforementioned values to obtain:

[tex]n=\frac{2.50atm*0.1000L}{0.08206\frac{atm*L}{mol*K}*298.15K}\\\\n=0.0102mol[/tex]

Best regards!

Answer: Balanced molecular equation :

[tex]2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)[/tex]

Total ionic equation:

[tex]6Na^+(aq)+3PO_4^{2-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)[/tex]  

The net ionic equation:

[tex]2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)[/tex]

Explanation:

Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as  product.

The balanced molecular equation will be,

[tex]2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)[/tex]

The total ionic equation in separated aqueous solution will be,

[tex]6Na^+(aq)+2PO_4^{3-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)[/tex]

In this equation, and  are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

[tex]2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)[/tex]

Answer:

J 9. , indicates the most sudden change in temperature

Answer:

1. 23.3 g

2. 82 g

3. 0.402 mol

4. 0.506 mol

Explanation:

We can convert moles (n) to mass (m) using the following expressions that include the molar mass (M).

n = m/M

m = n × M

1. The molar mass of NH₄Cl is 53.49 g/mol.

m = 0.436 mol × 53.49 g/mol = 23.3 g

2. The molar mass of Ca(NO₃)₂ is 164.09 g/mol.

m = 0.50 mol × 164.09 g/mol = 82 g

3. The molar mass of NaCl is 58.44 g/mol.

n = 23.5 g/(58.44 g/mol) = 0.402 mol

4. The molar mass of KMnO₄ is 158.03 g/mol.

n = 79.9 g/(158.03 g/mol) = 0.506 mol

I haven't done these in some time, so I'm not sure if they are 100% right.

1) 6.3 moles of H2( 2 mol of NH3 / 3  mol of H2)= 4.2 mol of NH3

6.3 moles of H2( 2 mol of NH3/ 3 mol of H2)(17.04 g of NH3/1 mol NH3)= 71.57 g of NH3

2) 2.5 moles of N2(2 mol of NH3/1 mol of N2)= 5 moles of NH3

2.25 moles of N2(2 mol of NH3/ 1 mol of N2)(6.02x10^23 particles/ 1 mol of NH3)= 3.01x10^24 particles of NH3

3) 425 g of NH3(1 mol of NH3/17.04 g NH3)= 24.9 moles of NH3

425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)(28.02 g of N2/1 mol N2)= 349 g of N2

425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)= 12.5 mol of N2

4) 10 moles NH3(3 moles of H2/2 moles of NH3)= 15 moles H2

10 moles NH3(3 mol of H2/2 mol of NH3)(2.02 g of H2/1 mol of H2)= 30.3 g of H2

30.3 g = .0303 liters of H2

Answer:

it would be 2

Explanation:

Answer:

A. True

Explanation:

Answer:

Sally's average speed is 0.5 km/min

Explanation:

speed=distance/time

so, 5km/10min=0.5 km/min