An object is located 20.0 cm from a convex lens. The lens focuses light at a
distance of 10.0 cm. What is the image distance?

A. 6.67 cm
B. -6.67 cm
C. -20.0 cm
D. 20.0 cm

Answers

Answer 1

The Answer Is :  D. 20.0 cm

My Reason : These types of problems can all be solved using the lens or mirror equation.

1/20 +1/q= 1/10

q=20 cm

The image is formed behind the lens at 2f or the center of curvature.

It is real, inverted, and the same size as the object

Answer 2

The Answer Is: D. 20.0 cm

Explanation: I did the test :)


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я не знаю старайся изо всех сил

Explanation:

[tex]\huge{\mathbb{\tt { QUESTION↓}}}[/tex]

[tex]\color{green}{\tt State \: and \: explain \: the \: disadvantages}[/tex]

[tex]\color{green}{\tt { of \: anomalous \: expansion \: of \: water}}[/tex]

[tex]\huge{\mathbb{\tt {ANSWER↓}}}[/tex]

[tex]{\boxed{\boxed{\tt { DISADVANTAGES \: of \: anomolous \: expansion \: of \: water }}}}[/tex]

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[tex]{\boxed{\boxed{\tt { What \: is \: the \: state \: of \: anomalous \: expansion \: of \: water? }}}}[/tex]

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph

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