Answer: 2.2x10^4
Explanation: in a adiabatic process pV^y = constant.
So V2=3V1 and p2 = p1 / 3^1.67 = 2.2x10^4 Pa
7. An object can be accelerating even if its speed is
constant if it
(a) comes to a stop
(b) is not possible
(C) changes direction
(d) moves in a straight line
Answer:
I think that the answer might be d
Answer:
D
Explanation:
If a car is moving very fast in a straight road or a highway in such a way that it has reached its limits as soon as it is going that fast it can break it limit
Please help me look at the image below
State the relationship between the mass of trolley and acceleration of the trolley?
Answer: The complementary relationship indicated by the Newton's second law...
For a given applied force the acceleration of the trolley is inversely proportional to it's mass.
Based on the graph, describe how momentum changes with time for an object in free fall. If you can help, I would be so grateful.
Why must the Moon travel more than a full orbit around the Earth for the full moon to be complete?
Answer:
The difference between the sidereal and synodic months occurs becuase as our moon moves around the earth, the earth also moves around our sun. Our moon must travel a little farther in its path to make up for the added distance and complete the phase cycle.
Explanation:
Hope this helps.
What are examples of changes in people, animals, or objects that would help you make a claim about their age? NO LINKS OR YOURE GETTING REPORTED. Thanks
It’s Earth Science
Answer:
An example of changes in people based on their age, are mood changes,playfulness and as of objects you can say old or broken, animals can use the same reference as humans, the more mature you are can suggest your older, such as the more worn down your are based on a object
Which statement best summarizes the development of the atomic theory over time?
Answer:
electrons move around nucleus in specific regions
We have that the correct statement that summarizes atoms over time will be
The discovery of new evidence resulted in changes to the atomic theory.
Option B
Generally
The Image shows that in the early 1800 the knowledge of atom was limited and it increased over time and by 1920 it had gone through a 4 stages of modifications to the atomic model
Atoms are solid spheresElectrons are attached to atom surfaceElectrons move around in the nucleus in a specificRapid motion of electrons in the cloudTherefore the correct statement that summarizes atoms over time will be
The discovery of new evidence resulted in changes to the atomic theory
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A 20 g block of ice is cooled to −65 ◦C. It
is added to 570 g of water in an 76 g copper
calorimeter at a temperature of 26◦C.
Find the final temperature. The specific
heat of copper is 387 J/kg ·
◦C and of ice is
2090 J/kg ·
◦C . The latent heat of fusion of
water is 3.33 × 10^5
J/kg and its specific heat
is 4186 J/kg ·
◦C .
Answer in units of ◦C.
Answer:
The final temperature is approximately 23.55°C
Explanation:
The given parameters are;
The mass of the ice block, m₁ = 20 g
The initial temperature of the block, T₁ = -65°C
The mass of the water to which the block is added, m₂ = 570 g
The mass of the copper container containing the water, m₃ = 76 g
The initial temperature of the water and the copper, T₂ = 26°C
The specific heat capacity of copper, c₃ = 387 J/(kg·°C)
The specific heat capacity of ice, c₄ = 2,090 J/(kg·°C)
The latent heat of fusion of ice, l = 3.33 × 10⁵ J/kg
The specific heat capacity of water, c₁ = 4,186 J/(kg·°C)
We have;
ΔQ = m₁·c₁·ΔT + m₁·l = m₂·c₂·ΔT + m₃·c₃·ΔT
Therefore, we get;
20 × 2,090 × -65 + 20 × 3.33 × 10⁵ + 20 × T × 4,186 = 570 × 4,186 × (26 - T) + 76 × 387 × (26 - T)
Using a graphing calculator, we get;
83720·T + 3943000 = 62801232 - 2415432·T
The final temperature, T ≈ 23.55 °C
John, a fireman, slides down a pole when the fire alarm sounds. He reaches the ground at 5m^-1. Give that his mass is 60kg. Find the friction that acts against his motion as he slides down the pole.
Decribe the general shape of the graph.
Answer:
the results increase, positive
how is momentum of an object related to stopping distance
Answer:
To stop a car must lose its momentum and its kinetic energy. ... If the forces on two cars are equal then the greater the kinetic energy the greater the distance before stopping. But there will be a relationship to the momentum because momentum and mass are both related to the kinetic energy.
HELP pleaseee which nucleus completes the following equation?
Answer:
its D
Explanation:
i just got it correct on a. p. e. x. :)
Milk is a very weak acid. What might its pH value be ?
Answer:
pH value is between 6.5 and 6.8
Explanation:
Explanation:
Milk fresh from the cow typically has a pH between 6.5 and 6.7. The pH of milk changes over
1. What is the magnitude of the force on a charge of +40 μC that is 0.6 m from a charge of - 80 μC?
Answer:
The magnitude of the force is 79.893 N.
Explanation:
The magnitude of the electrostatic force between the two particles is determined by Coloumb's Law, whose formula is:
[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)
Where:
[tex]\kappa[/tex] - Electrostatic constant, in newtons-square meters per square coulomb.
[tex]q_{A}, q_{B}[/tex] - Electric charges, in coulombs.
[tex]r[/tex] - Distance, in meters.
If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q_{A} = +40\times 10^{-6}\, C[/tex], [tex]q_{B} = - 80\times 10^{-6}\, C[/tex] and [tex]r = 0.6\,m[/tex], then the magnitude of the force is:
[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]
[tex]F = 79.893\,N[/tex]
The magnitude of the force is 79.893 N.
Which of the following statements is true about absolute zero?
It is the point at which electrons separate from the nucleus of atoms.
It is the point at which electrons separate from the nucleus of atoms.
It is theoretically the point at which all particle motion stops.
It is theoretically the point at which all particle motion stops.
It occurs at 273 degrees Kelvin.
It occurs at 273 degrees Kelvin.
It is the point at which protons separate from neutrons in the nucleus
Answer:
It is the point at which electrons separate from the nucleus of atoms. It is the point at which electrons separate from the nucleus of atoms. It is theoretically the point at which all particle motion stops. ... It occurs at 273 degrees Kelvin. ... It is the point at which protons separate from neutrons in the nucleus.
Explanation:
How do you rationalize the tension being used in Tennis Racket strings using the concept of impulse and momentum?
Answer:
The momentum, ΔP, and therefore, kinetic energy given to the ball in a serve is the result of the product of the tension force, 'F', in the string and the time of contact, Δt, between the ball and the string
ΔP = F × Δt
Explanation:
The impulse, ΔP, is the produce of the force, 'F', applied to a body for a given period of time, Δt', that gives motion to the body, and it is equal to the change of momentum of the body
ΔP = F × Δt
The momentum, 'P', of a body is the product of the mass, 'm', of the body and its velocity, 'v'
P = m × v
Tension is the axial pulling force of a string
T = Axial Force, F[tex]_{axial}[/tex]
The tension used in Tennis Racket strings is between 40 to 65 lbs.
When high tension is used in the string, the string is taut, and the contact duration between the Racket string and the ball is minimal, and the player needs to use more force to obtain a high momentum, and therefore, energy in the ball, which reduces control, and increase stress, as force is more emphasized
When low tension is used in the string, the Tennis Racket strings are more elastic. During a serve, the ball pushes the strings further back into the racket, such that the ball spends more time in contact with the string, (Δt is larger), and therefore, the impulse, F·Δt = ΔP, given to the ball is larger, therefore, the ball has a larger change in momentum, and therefore more energy in the intended direction.
However, a very slackened string will increase the increase area and time (large Δt) of contact of the ball and the racket such that the force given to the ball, F = ΔP/(large Δt) is reduced and therefore reduce the likelihood of gaining points from a serve against an opponent with a much forceful return of a serve.
PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject
Answer:
Third option
Explanation:
To calculate meters per second you divide the distance by the time.
it's 8m/s
PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject
Explanation:
speed : • how fast an object changes position
• miles per hour.
• distance/time.
velocity: • speed in a direction
• miles per hour North
• distance/ time in a direction
Two waves, each with an amplitude of 0.5m are superimposed with constructive interference such that they are in phase. Describe the resultant amplitude
The resultant amplitude of the two waves is 1.0m
Interference occurs when two or more waves are superimposed over each other. These waves can either be destructive or constructive in nature. If the waves are superimposed with constructive interference such that they are in phase, the resultant amplitude will be the sum of the amplitude of both waves.Resultant amplitude = 0.5m + 0.5m
Resultant amplutude = 1.0m
Hence the resultant amplitude of the two waves is 1.0m
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The semi-major axis of this ellipse is 8.8 cm, and the distance from one of the foci to the
center is 4.4 cm. What is the eccentricity of the ellipse?
The eccentricity is 0.5
A tuba creates a 4th harmonic of frequency 116.5 Hz. What is the frequency of the third harmonic? (Speed of sound = 343 m/s) (Unit = Hz )
Answer:
3rd Harmonic Frequency created by tuba is equal to [tex]87.375[/tex] hertz
Explanation:
Given -
4th Harmonic frequency created by tuba is equal to [tex]116.5[/tex] hertz
1st Harmonic Frequency created by tuba is equal to [tex]\frac{116.5}{4}[/tex] hertz
3rd Harmonic Frequency created by tuba is equal to [tex]3* \frac{116.5}{4}[/tex] hertz
3rd Harmonic Frequency created by tuba is equal to [tex]87.375[/tex] hertz
Answer:
87.375 Acellus
Explanation:
A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration
[tex]\Large {{ \sf {Question :}}} [/tex]
A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?[tex]\Large {{ \sf {Given :}}} [/tex]
Initial Velocity (u) - 5 m/sFinal Velocity (v) - 15 m/sTime (t) - 10 sec[tex]\Large {{ \sf {Formulae :}}} [/tex]
If the velocity of an object changes from an initial value u to the final value v in time t, the acceleration a is, [tex]a \: = \frac{v - u}{t} [/tex][tex]\Large {{ \sf {Step-by-step explanation :}}} [/tex][tex]a \: = \frac{v - u}{t} \\ or \: \: a = \frac{(15 - 5)}{10} m \: s^{ - 2} \\ or \: \: a \: = \frac{10}{10}m \: s^{ - 2} \\ or \: \: a = 1m \: s^{ - 2} [/tex]
[tex]\Large {{ \sf {Answer :}}} [/tex]
His acceleration is [tex]1m \: s^{ - 2} [/tex]A 35 g block of ice is cooled to −83 ◦C. It is added to 565 g of water in an 87 g copper calorimeter at a temperature of 22◦C. Find the final temperature. The specific heat of copper is 387 J/kg · ◦C and of ice is 2090 J/kg · ◦C . The latent heat of fusion of water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg · ◦C . Answer in units of ◦C.
Answer:
Explanation:
Heat gained by ice in warming up to 0⁰C = .035 x 2090 x (83-0)= 6071.45 J
heat used up by ice to melt at 0⁰C = .035 x 3.33 x 10⁵ J = 11655 J
Heat used up in warming up water to t⁰C = .035 x 4186 x t = 146.51 t
heat released by warm water to cool from 22⁰C to t = .565 x 4186 x ( 22 - t )
=52032 -2365.1 t
heat released by copper calorimeter to cool from 22⁰C to t = .087 x 387 x ( 22 - t ) = 740.72 - 33.7 t
total heat released = 52032 -2365.1 t + 740.72 - 33.7 t
= 52772.72 - 2398.8 t
Heat lost = heat gained
52772.72 J- 2398.8 t = 6071.45 J + 11655 J + 146.51 t
2545.31 t = 35046.27
t = 13.8°C.
A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connected to a movable object. The spring and object are compressed by 0.065 m, released from rest, and subsequently oscillate back and forth with an angular frequency of 11.3 rad/s. What is the speed of the object at the instant when the spring is stretched by 0.048 m relative to its unstrained length
Answer:
Explanation:
Given that:
angular frequency = 11.3 rad/s
Spring constant (k) = [tex]= \omega^2 \times m[/tex]
k = (11.3)² m
k = 127.7 m
where;
[tex]x_1[/tex] = 0.065 m
[tex]x_2[/tex] = 0.048 m
According to the conservation of energies;
[tex]E_1=E_2[/tex]
∴
[tex]\Big(\dfrac{1}{2} \Big) kx_1^2 =\Big(\dfrac{1}{2} \Big) mv_2^2 + \Big(\dfrac{1}{2} \Big) kx_2^2[/tex]
[tex]kx_1^2 = mv_2^2 + kx_2^2[/tex]
[tex](127.7 \ m) \times 0.065^2 = v_2^2 + (127.7 \ m) \times 0.048^2[/tex]
[tex]0.5395325 = v_2^2 +0.2942208 \\ \\ 0.5395325 - 0.2942208 = v_2^2 \\ \\ v_2^2 = 0.2453117 \\ \\ v_2 = \sqrt{0.2453117} \\ \\ \mathbf{ v_2 \simeq0.50 \ m/s}[/tex]
Can someone list me 6 disadvantages of renewable energy?
Which one of these Target games uses the underhand throw?
A: Golf
B: KanJam
C: Corn-Hole
D: None Of The Above
HELP!!
Answer:
Cornhole
Explanation:
A rock at the edge of a cliff has 10 Joules of potential energy. A goat comes along and kicks the rock off the edge. At the moment right before the rock hits the ground about how much kinetic energy does it have? (remember, a Joule is the SI unit for measuring energy).
Answer:
27 J
Explanation:
A meter is larger than a
A.
hectometer
B.
kilometer
C.
decimeter
D.
dekameter
The half-life of technetium-99 is 6 hours.How much of a 100 milligram sample of
technetium-99 will remain after 30 hours? *
O 3.125 mg
O 12.5 mg
O 6.25 mg
O 1.56 mg
How can we teach our kitty to behave properly
Answer:
I have no idea.
Explanation:
I just wanted to tell you I absolutely read this wrong.