Answer:
Fractional distillation of crude oil in laboratory
Explanation:
In general, we can sort them according to their boiling point.
We should first place a ball of mineral wool soaked with petroleum into a boiling tube and heat it with a Bunsen flame. At the beginning of the experiment, heat the mineral with a gentle flame, and then more strongly later. The fraction with a lower boiling range will distil out first. Since petrol is quite volatile, it should be condensed by cooling with water or an ice-water bath.
Petrol will be collected first, as it has a lower boiling point than kerosene. It will turn into vapour and condense again in the receive tub in the beaker.
Does Borax pure substance?
Answer:
Borax is a natural mineral with a chemical formula Na2B4O7 • 10H2O. Borax also is known as sodium borate, sodium tetraborate, or disodium tetraborate. It is one of the most important boron compounds. The International Union of Pure and Applied Chemistry (IUPAC) name for borax is sodium tetraborate decahydrate.
Exit ticket: Name the 2 factors that Terrestrial Biomes are separated by ___________ & ________
Answer:
temperature and rainfall
Explanation:
Unit 4.2 quiz chemistry
Answer:
H₂SO₄ is the correct answer sorry im late
calculate the percentage mass of oxgen in water, H2O
Answer:
the mass of oxygen in water is 16.00.
A 20 mL sample of human urine was found to have 10 mg of
urea during analysis. The molar mass of urea is 60.1 g/mol.
Calculate the molarity of urea in the given sample.
What is the other product for this reaction? Hbr + NaOH —> ( select 2)
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Answer: HBr + NaOH = nabr + h2o
Explanation:
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Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
The balanced chemical equation using the smallest possible whole number stoichiometric coefficients is:
[tex]3Br_{2} + I_{2} \rightarrow 2IBr_{3}[/tex]
What is a balanced equation?A balanced chemical equation is an equation in which the the moles of atoms in of elements of reactants is equal to mole of atoms of elements of the product.
The balanced chemical equation of the reaction is given below:
[tex]3Br_{2} + I_{2} \rightarrow 2IBr_{3}[/tex]
Therefore, the balanced chemical equation using the smallest possible whole number stoichiometric coefficients is given above.
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Chromium is manufactured by heating a mixture of chromium(III) oxide with aluminium powder.
Cr2O3(s) + 2Al(s) → 2Cr(s) + Al2O3(s)
a=Calculate the mass of aluminium needed to react with 50 g of Cr2O3.
b=Calculate the mass of chromium produced from 50 g of Cr2O3.
c=Calculate the mass of chromium produced from 5 kg of Cr2O3.
d=Calculate the mass of chromium produced from5 tonnes of Cr2O3.
Note: 1 tonne = 1,000,000 g
Ar: Cr = 52, O = 16, Al = 27
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?
Answer:
The gas is decreasing at a rate of 50 cubic centimeters per minute.
Explanation:
The Boyle's Law is represented by the following expression:
[tex]P\cdot V = k[/tex] (1)
Where:
[tex]P[/tex] - Pressure, in kilopascals.
[tex]V[/tex] - Volume, in cubic centimeters.
[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.
By definitions of rate of change and implicit differentiation, we derive the following differential equation:
[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)
Where:
[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.
[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.
Then, we clear the rate of change of the volume within (2):
[tex]P\cdot \dot V = -\dot P\cdot V[/tex]
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]
The gas is decreasing at a rate of 50 cubic centimeters per minute.
A student placed 2 drops of an unknown sample in a test tube and added 2 mL of ethanol to the test tube while mixing gently. They added 2 drops of potassium permanganate reagent to the test tube and mixed the contents of the test tube gently. The initial color was a deep purple but then changed to a yellow color which precipitates as a brown solid. What compound is most likely the unknown
Answer:
2-propanol
Explanation:
From the given information
2 drops of an unknown sample were said to be placed in a test tube followed by the addition of 2 ml of ethanol then gentle mixing. They then initiate a further addition of 2 drops of potassium permanganate reagent (KMNO₄) to the test tube and mixed the contents of the test tube thoroughly. After adding 2 drops of potassium permanganate reagent, the reagent oxidizes the secondary alcohols(2-propanol) to ketone(i.e acetone) and no further reaction will take place since there are no reactive C-H bonds left. The diagram attached below shows how the reaction proceeds.
If a mechanical wave has a frequency of 0.147 Hz and a wavelength of 12.05 m, what is the velocity of the wave? (round to the hundredths place)
Answer:
0.147 Hz because I took the test
The velocity of a wave is the product of its frequency and wavelength. The velocity of wave with 0.147 Hz and 12.05 m is 1.77 m/s.
What is frequency ?The frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of time period of the wave. It is inversely proportional to the wavelength. Unit of frequency is Hz which is equivalent to s⁻¹.
The wavelength of a wave is the distance between two consecutive crests or troughs. The wavelength λ, and frequency ν of a wave is related to the velocity v of the wave as follows:
v = νλ
Given that,
frequency = 0.147 Hz
wavelength = 12.05 m
then, velocity = 0.147 Hz × 12.05 m = 1.77 m/s.
Therefore, the velocity of the mechanical wave is 1.77 m/s.
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This timeline woulchre useful to someone who was writing a report titled
Question 1 of 10
What variable represents thermal energy in the equation Q=MAT?
O A. The variable e
O B. The variable Q
O c. The variable
O D. The variablem
Predict the products and balance the equation
classify the reaction
Answer:
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
Explanation:
Hello there!
In this case, when coming across combustion reactions whereby hydrocarbons as fuels are burnt in the presence of oxygen, the main products are said to be carbon dioxide and water in agreement to the breaking and rearrangement of bonds due to the collisions among molecules. Thus, for the reaction between propane and oxygen we have the following balanced reaction:
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
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Calculate the wave number and
Frequency of violet radiation having
wavelength of 3500 Å
Answer: frequency is 8.57 ·10^14 Hz
Explanation: lambda = 3500 A = 0,000 000 350 m
Wave number is 1/ lambda = 2857142.857 1/m
Wave equation c = frequency · lambda and f = c / lambda
Frequency = 300 000 000 m/s / 0,000 000350 m
The wavelength number is [tex]2.85\times 10^{6}\ m^{-1}[/tex] and the frequency is [tex]8.57\times 10^{14}\ Hz[/tex].
Explanation:
Given that,
The wavelength of violet radiation,
[tex]\lambda=3500\ A\\\\=3500\times 10^{-10}\ m\\\\=3.5\times 10^{-7}\ m[/tex]
To find,
The wave number and frequency of violet radiation.
Solution,
Wavelength, [tex]\lambda=3.5\times 10^{-7}\ m[/tex]
Wave number is the reciprocal of the wavelength,
[tex]\overline{\lambda}=\dfrac{1}{\lambda}[/tex]
Put all the values,
[tex]\overline{\lambda}=\dfrac{1}{3.5\times 10^{-7}}\\\\\overline{\lambda}=2.85\times 10^{6}\ m^{-1}[/tex]
The relation between the wavelength, frequency and speed of wave is given by :
[tex]f=\dfrac{c}{\lambda}[/tex]
Where
c is the speed of light
Put all the values,
[tex]f=\dfrac{3\times 10^8}{3.5\times 10^{-7}}\\\\f=8.57\times 10^{14}\ Hz[/tex]
So, the wavelength number is [tex]2.85\times 10^{6}\ m^{-1}[/tex] and the frequency is [tex]8.57\times 10^{14}\ Hz[/tex].
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Unit 4.2 quiz chemistry
Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equation)
Answer:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Explanation:
Solid Iron = FeCopper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)Metal Copper = CuWriting the equation using symbols leaves us with:
Fe + CuNO₃ → Fe(NO₃)₃ + CuIt is not balanced yet. Now we balance the NO₃ species on the left side:
Fe + 3CuNO₃ → Fe(NO₃)₃ + CuFinally we balance the Cu species on the right side:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3CuWhen air hockey is played, a small plastic puck slides across a table that has holes through which air is forced. What effect does the air have on the game?
Answer:
it reduces the atmospheric pressure
When optically active (S)-2-methylcyclopentanone is treated with an acid (H3O ), the compound loses its optical activity. Explain this observation and draw a mechanism that shows how racemization occurs. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.
Answer:
See explanation
Explanation:
When (S)-2-methylcyclopentanone is treated with an acid, the carbonyl oxygen atom is protonated.
This leads to the emergence of a positive charge on the cabonyl oxygen. Then the C=O bond is now transformed into H-C-OH where C is a carbocation which leads to a racemic mixture. Loss of a proton from the adjacent carbon atom completes the mechanism.
In this process, the optically active (S)-2-methylcyclopentanone is converted to a pair of diastereomers thereby loosing its optical activity.
Select the correct term(s) to complete each sentence. a) The ____ is assigned a relative intensity of 100. base peak molecular ion peak b) The ____ is the most intense peak in the mass spectrum. molecular ion peak base peak c) The ____ represents the original molecule that has only lost an electron. molecular ion peak base peak d) ____ could be/represent a smaller, charged fragment of the original molecule. The base peak The molecular ion A radical cation e) ____ is/represents a positively charged species. The base peak The parent ion The molecular ion A radical cation
Answer:
a) Base Peak
b) Base Peak
c) Molecular Ion
d) Base Peak and Radical Cation
e) The Parent Ion, Molecular Ion, the Radical Cation and the Base Peak
Explanation:
a) The Base Peak is assigned a relative intensity of 100.
b) The Base Peak is the most intense peak in the mass spectrum.
c) The Molecular Ion Peak represents the original molecule that has only lost an electron.
d) Base Peak and Radical Cation could be/represent a smaller, charged fragment of the original molecule.
e) The Parent Ion, the Molecular Ion, the Radical Cation/ the Base Peak is/represents a positively charged species.
If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?
Answer:
2.64 M
Explanation:
Use the dilution equation M1V1 = M2V2, where:
M1 = 12.0 M HCl
V1 = 220 mL HCl
M2 = ?
V2 = 1000 mL HCl
(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)
M2 = 2.64 M HCl
When sodium hydroxide NaOH dissociates in water, the oxygen atoms on the hydroxide anions will interact with:
Answer:
Hydroxide ions ( OH−) are negatively charged, and the formal negative charge is on the oxygen atom. Since opposite charges attract, the oxygen atoms will interact with the positive end of water's dipole.
Explanation:
Write the parts of the ear in their correct order of transfer of vibrations. to the brain.
Answer:
The sound waves travel from the outer ear and in through the auditory canal, causing the eardrum, or tympanic membrane, to vibrate. This, in turn, causes the three small bones, known as the ossicles, or the hammer, the anvil and the stirrup, in the middle ear to move.
Radiation from which type of decay has the most energy?
A. Alpha decay
B. Electromagnetic decay
C. Beta decay
D. Gamma decay
Pls answer quick
Answer: D
Explanation:
Radiation from gamma decay has the most energy and the correct option is option D.
What is Radioactive Decay?To become more stable, the nuclei undergo radioactive decay. In this process, the nuclei give off energy and may also emit charged particles of matter.
Types of radioactive decay include alpha, beta, and gamma decay. In alpha and beta decay, both particles and energy are emitted. In gamma decay, only energy, in the form of gamma rays, is emitted.
In the gamma decay, a nucleus changes from a higher energy state to a lower energy state through the emission of electromagnetic radiation.
Therefore, Radiation from gamma decay has the most energy and the correct option is option D.
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what is another name for horse
Answer:
Mount, Charger, Colt, Pony, and Folt
Explanation:
Answer:
A stallion or a mare
Explanation:
8. Zeolite is used to remove moisture from methane. A vertical column is filled with 1000.0 kg of dry zeolite. The zeolite has the capacity to hold 0.100 kg water/kg dry zeolite. Once the zeolite becomes saturated with moisture, it must be regenerated by heating. The inlet moisture content of the methane is 7.00% (by mass) and the outlet moisture content is 0.05% (by mass). How much methane (kg) will be produced before the zeolite must be regenerated
Answer:
Follows are the solution to this question:
Explanation:
Methane inlet humidity content of [tex]=7.00\%[/tex]
Methane moisture outlet content [tex]=0.05\%[/tex]
Zeolite absorption humidity [tex]= 6.95\%[/tex]
Dry zeolite 1 kg will accommodate water[tex]= 0.1000 \ kg[/tex]
One kilogram of Dry Zeolite will carry water from [tex]=0.1000\ kg[/tex]
The water can contain 1000 kg of zeolite [tex]= 100 \ kg[/tex]
Methane which would be made [tex]=\frac{100}{6.95\%}= 1,439 \ kg[/tex]
That's why it will be producing 1439 kg of methane.
The amount of methane that can be produced before the regeneration of zeolite is 1,439 kg.
What is zeolite?
Zeolite belongs from the family of hydrated aluminosilicate minerals, in which alkali and alkaline earth metals are present.
In the question, it is given that:
Capacity of 1kg of zeolite to hold water = 0.100kg
Capacity of 1000kg of zeolite to hold water = 100kg
Inlet moisture content of the methane = 7.00 % (by mass)
Outlet moisture content of the methane = 0.05% (by mass)
Capacity of zeolite to absorb methane content = 6.95 %
Amount of methane before the regeneration of zeolite = 100kg / 6.95% = 14.39% of kg = 1,439 kg
Hence, 1,439 kg methane will be produced before the zeolite must be regenerated.
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Mass of watch glass + filter paper = 105.98 g
Mass of watch glass + filter paper + crystallized product = 109.03 g
Mass of uncrystallized product (show work) =
Mass of methyl benzoate = 3.08 g
Volume of nitric acid used = 2.0 mL
Theoretical yield based on each of the starting materials
(Please use two Dimensional Analysis (DA) equations, one for the maximum amount of product obtainable from the amount of methyl benzoate you used and the other from the concentrated nitric acid, then use the lesser of the two to determine the Limiting Reagent; you must determine the number of moles in 2.00 mL of concentrated nitric acid [concentration 69.0% (w/w), and density (1.42 g/mL)].
Required:
a. Identity of the Limiting reagent (LR) based on the above two DA equations = __________
b. Max amount of product obtainable from the LR = ___________
c. Mass of the product you obtained: ____________
Answer:
Explanation:
Mass of uncrystallized product = (Mass of watch glass + filter paper + crystallized product) - (Mass of watch glass + filter paper)
Mass of uncreystaliized product = 109.03 gm - 105.98 gm
Mass of uncrystaliized product = 3.05 gm
For methyl benzoate;
mass = 3.08 g
no of moles = 3.08 g/ 136.15 g/mol = 0.0226 mole
It is possible for the formation of 1 mole of nitro methyl benzoate from a mole of methyl benzoate.
moles of nitro methyl benzoate that can be formed from 0.0226 moles of methyl benzoate = 0.0226 moles
∴
mass of nitro methyl benzoate = 0.0226 mol × 181.15 gm /mol
mass of nitro methyl benzoate = 4.098 gm
For HNO_3 solution:
mass = 1.42 gm/ml × 2.0 ml
mass = 2.84 gm
Mass of HNO3 in 2.84 gm solution[tex](69\% w/w)= 2.84 gm * \dfrac{69}{100 }[/tex]
= 1.9596 gm
Moles of HNO3 = [tex]\dfrac{ 1.9596 \ gm }{ 63.01 gm /mol}[/tex]
= 0.0311 mole
1 mol of HNO_3 can be formed from 1 mole of nitro methyl benzoate
Thus; moles of nitro methyl benzoate that can be formed from 0.0311 mole of HNO_3 = 0.02256 mole
The mass for nitro methyl benzoate can now be determined as:
= 0.0311 mole × 181.5 gm/mole
= 5.634 gm
Since the mass formed from methyl benzoate is lesser, then methyl benzoate serves as the limiting reagent.
The mass obtainable from the LR = 4.098 gm
Potassium chlorate, a common oxidizing agent in fireworks and matchheads, undergoes a solid-state disproportionation reaction when heated:
4KClO3 (s) ⟶ Δ3KClO4 (s) + KCl (s).
Use ΔHf ° and S° values to calculate ΔG_sys ° (which is ΔGrxn °) in kJ at 25°C for this reaction.
Answer:
Explanation:
[tex]\text{From the information given:}[/tex]
[tex]\text{The chemical reaction is : } 4 KClO_{3(s)} \to 3 KClO_{4(s)} + KCl_{(s)}[/tex]
[tex]\text{To find} \ \Delta G^0_{rxn}\ \text{using the formula}: \\ \\ \Delta G^0_{rxn} = \sum n_p \times \Delta _f G^0 (Products) - \sum n_R \times \Delta _fG^0 ( Reactants) \\ \\ where; n_p = \text{no of moles of products } \ and; \\ \\ n_R = \text{no of moles of reactants }[/tex]
[tex]\implies G^0_{rxn} = 3 \times \Delta _fG^0 [KClO_4{(s)}] + \Delta_fG^0[KCl_{(s)}] - 4 \times \Delta _f G^0 [ KClO_3 (s) ][/tex]
[tex]\Delta _fG^0 \ values \ at \ 25^0 \ C (298 \ K) are\ given \ as:\\\\ \Delta _fG^0 [KClO_4(s)] = -303.09 \ kJ \\ \\ \Delta _fG^0 [KCl(s) ] = - 409.14 \ kJ \\ \\ \Delta_f G^0 [KClO_3_{(s)}] = -296.25 \ kJ \\ \\ replacing \ the \ above \ values \ into \ equation (1) ; then:\\ \\ \\\Delta G^0_{rxn} = 3 *(-303.09) + (-409.14) - 4*(-296.25) \ kJ \\ \\ = (-909.27 - 409.14 + 1185) \ kJ \\ \\ = -133.41 \ kJ \\ \\ \mathbf{\Delta G^0_{rxn} = -133.4 \ kJ }[/tex]
The standard free energy change of the reaction is -133 kJ.
From the reaction equation, we have; 4KClO3 ⇄ 3KClO4 (s) + KCl (s). The standard free energy of formation of each specie is given below;
ΔG°f KClO3 = -296.35 kJ
ΔG°f KClO4 = -303.09 kJ
ΔG°f KCl = -409.14 kJ
Hence;
ΔG°rxn = [3(-303.09)] + ( -409.14)] - [(4( -296.35))]
ΔG°rxn = (-909.27) + (-409.14) - (-1185.4)
ΔG°rxn = -133 kJ
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A scientist places a pH meter in a sample of concentrated potassium hydroxide (KOH). The scientist slowly adds nitric acid (HNO3) to the KOH and monitors the pH. Describe how the pH and hydronium ion concentration will change in the solution as the acid is added.
Answer:
pH of the solution will decrease & hydronium ion concentration will increase in the solution as the acid is added.
Explanation:
10) 81 grams of Au is how many mL ?
Answer: Thus 81 grams of Au is 9210 ml
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]\text{moles of Au}=\frac{81g}{196.96g/mol}=0.411moles[/tex]
1 mole of Au occupies = 22.4 L
Thus 0.411 moles of Au occupy = [tex]\frac{22.4}{1}\times 0.411=9.21L=9210ml[/tex]
81 grams of Au is 9210 ml