Determine which quadrilaterals match the figure: parallelogram, rhombus, rectangle, or square? Select all
that apply.
w
IZ
Given: m 2WXY = 130°, m XWZ = 50°,mZWZY = 130°
B
rectangle
parallelogram
D
rhombus
square

Answer:

f(-4) = 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

f(x) = -3x - 8

f(-4) is x = -4

Step 2: Evaluate

Answer:

the correct answer is:

-3 × -4 -8 = 12 - 8 = 4

Answer: I would think that the midpoint is (2,3)

Step-by-step explanation: Because I have eyes

Answer:

Step-by-step explanation:

Given point

Dilation by a scale factor of 74:

Rotation by 180°:

Answer: n=8

Step-by-step explanation:

1. Subtract 4.4n on both sides:

2n-10=6

2. Add 10 on both sides:

2n=16

3. Divide both sides by 2:

n=8

Have a nice day :D

9514 1404 393

Answer:

  y = 2^x

Step-by-step explanation:

The x-values are sequential integers, which helps the discovery of the function. The y-values have a common ratio of 2 = 2/1 = 4/2 = 8/4. This is the base for the exponential function.

The initial value of y=1 at x=0 tells you the multiplier of the exponential factor is 1, and the exponent is x (with no additions or subtractions). Your function is ...

  y = 2^x

Answer:

The corresponding side length is 8 inches

Step-by-step explanation:

Similar Shapes

Two shapes are similar if all of their side lengths are in the same proportion. For example, triangle 1 has sides of 3-4-5 and another similar triangle has sides of 15-20-25. Note all their lengths are proportional with a scale factor of 5.

We are given the perimeter of figure A Pa=24 inches and the perimeter of figure B Pb=36 inches. The scale factor can be obtained as 36/24=3/2.

If one of the lengths of figure B is 12 inches, then the corresponding length for figure A is 12/(3/2) = 8 in.

The corresponding side length is 8 inches

Answer:

Step-by-step explanation:

10 students participated in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz

Solution: Number of girls = x

Number of boys = y

x + y = 10 -------------------(I)

Number of girls is 4 more than the number of boys

x - y = 4 ----------------------(I)

  x =  4 + y

Substitute x = 4 +y in equation (I)

4+ y + y = 10

4  + 2y = 10

       2y = 10-4

       2y= 6

          y = 6/2

y = 3

Plug in y = 3 in eqution (I)

x + 3 = 10

        x = 10 - 3

x = 7

Number of girls = 7

Number of boys = 3

Answer:

3036

multiples of 12 are 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144 and so on,

multiples of 32 are 264, 396, 528, 660, 792, 924, 1056 and so on,

multiples of 253 are 253, 506, 759, 1012, and so on,

Its quite a time consuming process.

when all the numbers eventually meet together that is the answer.

Answer: c

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given: i. AB||DE

          ii. AC≅DC

Prove: ΔABC≅ΔDEC

From the two triangles, it can be observed that;

m<BAC≅m<EDC (alternate angles)

m<ABC≅m<DEC (alternate angles)

m<BCA≅m<ECD (vertically opposite angles)

m<BAC + m<ABC + m<BCA = m<EDC + m<DEC + m<ECD = [tex]180^{o}[/tex] (sum of angles in a triangle)

Since the three angles of the triangles are congruent respectively, then;

ΔABC≅ΔDEC (AAA congruence property)

Answer:

Step-by-step explanation:

The "holes" are the x-es where function doesn't exist.

One must not divide by 0, so given function doesn't exis if the denominator is equal 0

x + 2 = 0  

x = - 2  

Answer:

b = [tex]\sqrt{45}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle on the left.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

b² + 6² = 9²

b² + 36 = 81 ( subtract 36 from both sides )

b² = 45 ( take the square root of both sides )

b = [tex]\sqrt{45}[/tex]

Answer:

y=[tex]\frac{400}{x}[/tex]

Step-by-step explanation:

Answer: 400/x (over x} = Y {amount on each cookie}

Step-by-step explanation:

If Summer (starting from rest) runs from the 20 m mark to the 35 m mark with an acceleration of 5 m/s². then 12.25 m/s is the final velocity.

Velocity is the distance covered by an object in unit time.

Given that,

Summer (starting from rest) runs from the 20 m mark to the 35 m mark with an acceleration of 5 m/s²

a=0.5 m/s²

s is distance=35-20=15

We have a formula with velocity, acceleration and distance

Now v²=2as

Here v is velocity=2

a is acceleration=5

s is the distance.=15

v²=2×5×15

The multiplication value of 2×5×15 is 150.

v²=150

Take square root on both sides

v=√150

v=12.25 m/s

Therefore final velocity is 12.25m/s.

To learn more on velocity click:

https://brainly.com/question/18084516

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Answer:

Radius????????????????

Answer:

33/3  

55/5

77/7

When these are simplified, they are equal to 11/1

Answer:

2sqrt5

Step-by-step explanation:

We know that the shortest distance would be with drawing a perpendicular line through BC and A.

BC is y = -2x+1

Therefore a perpendicular line should have slope 1/2

y = 1/2x + b

-3 = 1/2*-3 + b

b = -3/2

y = -2x+1

y = 1/2x - 3/2

-2x+1 = 1/2x - 3/2

-4x+2 = x - 3

5 = 5x

x = 1

y = 1

now of course the graph shows that already, but we're just proving that again

The x-difference is 4, the y difference is 2, so 16+4 = 18, sqrt20 = 2sqrt5

Answer:

Solution given:

AB=

[tex]AB = \sqrt{( - 3 +1 {)}^{2} + ( - 3 - 3 {)}^{2} } = 6.32units[/tex]

[tex]AC= \sqrt{( - 3 - 1) ^{2} + ( - 3 + 1) {}^{2} } = 4.5[/tex]units

[tex]AD= \sqrt{( - 3 - 0) {}^{2} + ( - 3 - 1) {}^{2} } = 5units[/tex]

so shortest distance=AC=4.5units

A and C is the answer

hope you'll learn from your teacher how?

Answer:

[tex]3x ^{3} - {4}^{2} - 23x + 10[/tex]

Answer:

2<a<5

Step-by-step explanation:

Answer: y = -1/2x - 1

Answer:

[tex]b)\ Obtuse[/tex]

Step-by-step explanation:

[tex]We\ are\ given\ that:\\There\ are\ three\ rays.\\Lets\ mark\ them\ Ray\ OP, OQ,\ and\ OR\ with\ their\ common\ Vertex\ O.\\\\Now,\\We\ know\ that\ the\ sum\ of\ all\ angles\ around\ a\ point[or\ here\ Vertex\ O]\\ should\ be\ equal\ to\ 360.\\Here,\\\\Lets\ consider\ each\ case\ sepearately.\\If\ all\ the\ angles\ formed: \angle POR, \angle ROQ, \angle POQ,\ are\ acute\ then:\\\angle POR, \angle ROQ, \angle POQ<90\\If\ we\ add\ them\ together,[/tex]

[tex]\angle POR+ \angle ROQ+ \angle POQ<90+90+90<270[/tex]

[tex]But\ here\ the\ sum\ of\ the\ angles\ are\ less\ than\ 270,\ but\ the\ sum\ should\\ instead\ be\ 360.\\Hence,\ the\ angles\ formed\ by\ the\ rays\ are\ NOT\ acute.[/tex]

[tex]Similarly,\\If\ all\ the\ angles\ formed: \angle POR, \angle ROQ, \angle POQ,\ are\ right\ then:\\\angle POR, \angle ROQ, \angle POQ =90\\When\ we\ add\ them\ again:\\\angle POR+ \angle ROQ+ \angle POQ=90+90+90=270\\But\ again\ the\ sum\ here\ is\ equal\ to\ 270,\ but\ instead\ the\ sum\ had\ to\\ be\ equal\ to\ 360.\\Hence,\\The\ angles\ formed\ are\ NOT\ right.[/tex]

[tex]Lets\ consider\ the\ Last\ Case,\\If\ the\ angles\ formed: \angle POR, \angle ROQ, \angle POQ\ are\ obtuse,\\\angle POR, \angle ROQ, \angle POQ>90\\When\ we\ add\ them:\\\angle POR+ \angle ROQ+ \angle POQ>(90+90+90)>270\\Here,\\The\ angles\ formed\ are\ greater\ than\ 270.\ As\ 360>270,\ the\ angles\ ARE\\ obtuse.[/tex]