Can somebody please help me!!!

Answer and Explanation:

The answer is Motion.

We can see that part of the image is blurry, which shows that the fish are moving fast. Moving = motion, so that means the fish has motion.

#teamtrees #PAW (Plant And Water)

Answer:

motion

Explanation:

Answer:

186 mL HCl

Explanation:

M1V1 = M2V2

M1 = 0.215 M HCl

V1 = ?

M2 = 0.800 M NaOH

V2 = 50.0 mL

Solve for V1 --> V1 = M2V2/M1

V1 = (0.800 M)(50.0 mL) / (0.215 M) = 186 mL HCl

Answer:

The entropy increases!!!

Explanation:

a pex

The entropy increases in the reaction.

The entropy increases in the reaction if the total number of product molecules are greater than the total number of reactant molecules.

2C3H6(g) + 9O2(g) → 6C02(g) + 6H2O (g)

In the above reaction, the product molecules are greater than the reactant molecules. Hence, entropy increases.

Hence, we can conclude that option A is the answer.

To learn more about entropy here

https://brainly.com/question/22861773

#SPJ2

Answer:

where:

• A is the wavelength in m.

• h = 6.626 x 10-34Js is Planck's

constant.

• m is the mass of the particle, such as the electron, in kg. The particle must have a mass for this relation to work.

• v is the forward velocity of the particle, in m/s.

Hence, the wavelength is:

6.626 x 10-34J.s

(9.1094 × 10 −³¹kg) (5 × 10³m/s)

We know that 1 J 1 kg. m²/s². So:

6.626 × 10-³4 g · m² / ø

9.1094 x 10 - 31) (5 x 105 m/s)

= 1.455 x 10-9 m

=

= 1.455 nm

Answer:

see calculations below

Explanation:

Given:     HOAc     ⇄    [H⁺]     +    [OAc⁻]            

C(i)          0.12M             0M           0.15M

mix  => 5.55ml(0.092M NaOH) / (50ml + 5.55ml)

            = 0.00555(0.092)mole NaOH / 0.0555 L Soln

            = 0.0092M in NaOH is added into the initial buffer solution

            = 0.0092M in OH⁻ (NaOH is a strong base => 100% ionized)

Rxn => Addition of 0.0092M OH⁻ will react with 0.0092M H⁺ shifting buffer            .           equilibrium to the right decreasing [HOAc] and increasing [OAc⁻] by    .           0.0092M each.

Therfore ...

Given:           HOAc      ⇄    [H⁺]     +       [OAc⁻]            

C(i)                0.12M             0M               0.15M

ΔC           - 0.0092M           +x            +0.0092M

C(f)             0.1108M             x                0.1592M  =>  New Concentrations            .                                                                                     after adding 0.0092M             .                                                                                     NaOH

Substituting new acid and ion concentrations into Ka expression ...

Ka = [H⁺][OAc⁻]/[HOAc] = (x)(0.1592M)/(0.1108M) = 1.75 x 10⁻⁵M

=> x = [H⁺](new) = (1.75 x 10⁻⁵M*)(0.1108M)/(0.1592M) = 1.22 x 10⁻⁵M in H⁺ ions

*units of Ka are Molar

FYI => Adding a strong base to a buffer solution will shift pH to more basic.

          Adding a strong acid   to a buffer solution will shift pH to more acidic.

=> (such is a good way to check that your buffer calculations are correct.)

NOTE => Question asks for moles of HOAc, Na⁺OAc⁻ & NaOH after adding base. Giving answers in terms of Molarity (moles/Liter) is same as moles. Therefore ...

[HOAc] = 0.1108M

[NaOAc] = 0.1592M

[NaOH] = ∅M (from rxn of H⁺ + OH⁻ => H₂O, all NaOH was consumed in acid/base reaction.  Remaining are only Na⁺ as a spectator ion and OH⁻ as a function of the new concentration of H⁺ => [OH⁻] = Kw/[H⁺] = 1 x 10⁻¹⁴/1.22 x 10⁻⁵ = 8.2 x 10⁻¹⁰M.

Hope this helps. :-)

Answer:

water is an example of mixture

Answer:

2c11h21

Explanation:

Answer:

the electrode at the center of a plasma ball emits a high-frequency,high-voltage alternating electric current. This current flows through the plasma filaments to create colorful tendrils of light.

Explanation:

what colors depend upon the gases used inside the plasma ball? common gases include neon, argon, xenon, and krypton.

Answer:

acceleration

pls dont report me

Answer:

javier applied force how this helps

Answer:

The answer could be "Autotrophs that photosynthesis".

Explanation:

At point X, the common characteristic can be written. The common character between protists and plants is autotrophs that photosynthesize which is the characteristic of plant-like protists. Plant-like protists are autotrophs, use carbon dioxide and water to produce glucose by the process of photosynthesis.

Answer:

A nail can rust when exposed to oxygen. the molecules of iron on the surface of the nail exchange atoms with the oxygen in the air and produce a new substance, the reddish brown ferrous oxide i.e rust.

Answer:

63.25 grams of CO₂

Explanation:

To convert from liters to grams, we first need to convert from liters to moles. To do this, we divide the liters by 22.4, the amount of liters of a gas per mole.

32.2 / 22.4

= 1.4375 moles of CO₂

Now we want to convert from moles to grams. To do this, we multiply the moles by the molar mass of CO₂. The total molar mass can be found on the periodic table by adding up the molar mass of carbon (12) and two oxygen (32).

12 + 32 = 44

Now we want to multiply the moles by the molar mass.

1.4375 • 44

= 63.25 grams of CO₂

This is your answer.

Hope this helps!

Answer:

water pollution is a process in which water gets polluted due to discharge of city sewage and industrial waste. I was suffering through the water born disease when I drank the contaminated water. The sources of water becomes dirty. It makes environment unbalanced. People suffer from different water born disease when they drink polluted water.

Answer:

True

Explanation:

tighter the molecules the slower it moves and the harder it gets

solid has very tight particles packed together

gas has its particles spread out

Answer:

20. Mg(NO3)2

21. KClO3

22. CaSO4

23. (NH4)2SO4

24. HC2H3O

25.  CO is carbon dioxide, which is neutral and would not combine with a hydrogen ion. Did you mean H and CO3(2-)? That would be H2CO3 (carbonic acid)

Explanation:

You have to match the charges of the Cations and Anions.

Answer:

1. Strong electrolytes = Nitric acid HNO3,Potassium hydroxide KOH, Sodium bromide NaBr

Weak electrolytes = Formic acid HCOOH Ethyl amine CH3CH2NH2, Butanol C4H9OH

Non-electrolyte = Sucrose C12H22O11

2. The reaction between aqueous HBr and aqueous LiOH is shown innthe equation below:

HBr + LiOH ----> NaBr + H₂O

Explanation:

Electrolytes are substances that when in molten state or in aqueous solution dissociate into ions both positively-charged and negatively-charged ions known as actions and anions, which are then able conduct electricity.

Strong electrolytes are aqueous or molten solutions of compounds which ionize completely to produce anions and actions. Ionic compounds such as organic salts, acids and bases are strong electrolytes.

Weak electrolytes only ionize partially, that is, they produce few ions. Some organic salts, acids and bases are weak elctrolytes

From the compounds given above;

Strong electrolytes = Nitric acid HNO3,Potassium hydroxide KOH, Sodium bromide NaBr

Weak electrolytes = Formic acid HCOOH Ethyl amine CH3CH2NH2, Butanol C4H9OH

Non-electrolyte = Sucrose C12H22O11

2. The reaction between aqueous HBr and aqueous LiOH is shown innthe equation below:

HBr + LiOH ----> NaBr + H₂O

Yes it is an cleaning product

Answer:

yes

Explanation:

it cleans in the house

Answer:

1 - D) friction

2- B) rough

3- B) gravity

4- A)smooth

5- C)gravity pulls you down

Answer:

The reaction given is  

Chemistry homework question answer, step 1, image 1

Since in equilibrium constant expression, the concentration of liquid components is not written.

Hence the equilibrium constant expression for the above reaction can be written as  

Chemistry homework question answer, step 1, image 2

where [NO] = equilibrium concentration of NO

[NO2 ] = equilibrium concentration of NO2

[HNO3 ] = equilibrium concentration of HNO3

Step 2

Given : mass of NO at equilibrium = 18.6 g

mass of NO2 at equilibrium = 15.1 g

and mass of HNO3 at equilibrium = 13.1 g

Since molar mass of HNO3 = 63 g/mol, molar mass of NO = 30 g/mol and molar mass of NO2 = 46 g/mol

Hence the moles of gases at equilibrium are

Chemistry homework question answer, step 2, image 1

Step 3

Since mass of solution = mass of HNO3 + mass of water = 13.1 + 234.8 = 247.9 g

Assuming density of solution = density of water = 1.00 g/mL

=> mass of solution = volume of solution X density of solution  

=> 247.9 = 1.00 X volume of solution  

=> volume of solution = 247.9 mL = 0.2479 L      

Explanation:

Answer:

breathed in air contains oxygen while breathed out air contains higher percentage of CO2

Answer:

A. 30cm³

Explanation:

Based on the chemical reaction:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

1 mol of calcium carbonate reacts with 2 moles of HCl to produce 1 mol of CO₂

To solve this question we must convert the mass of each reactant to moles. With the moles we can find limiting reactant and the moles of CO₂ produced. Using PV = nRT we can find the volume of the gas:

Moles CaCO₃ -Molar mass: 100.09g/mol-

1.00g * (1mol / 100.09g) = 9.991x10⁻³ moles

Moles HCl:

50cm³ = 0.0500dm³ * (0.05 mol / dm³) = 2.5x10⁻³ moles

For a complete reaction of 2.5x10⁻³ moles HCl there are necessaries:

2.5x10⁻³ moles HCl * (1mol CaCO₃ / 2mol HCl) = 1.25x10⁻³ moles CaCO₃. As there are 9.991x10⁻³ moles, HCl is limiting reactant.

The moles produced of CO₂ are:

2.5x10⁻³ moles HCl * (1mol CO₂ / 2mol HCl) = 1.25x10⁻³ moles CO₂

Using PV = nRT

Where P is pressure = 1atm assuming STP

V volume in L

n moles = 1.25x10⁻³ moles CO₂

R gas constant = 0.082atmL/molK

T = 273.15K at STP

V = nRT / P

1.25x10⁻³ moles * 0.082atmL/molK*273.15K / 1atm = V

0.028L = V

28cm³ = V

As 28cm³ ≈ 30cm³

Right option is:

Answer:

0.0922 M

Explanation:

The problem first states that the titration is made using NaOH, and later asks about the addition of KOH. I'm going to assume NaOH was used throughout the whole problem. The result does not change if it was KOH instead.

The reaction that takes place is:

First we calculate how many HClO₄ moles are there in the sample, using the given molarity and volume:

Then we calculate how many NaOH moles were added:

Now we calculate how many HClO₄ remained after the reaction:

As HClO₄ is a strong acid, 4.24 mmol HClO₄ = 4.24 mmol H⁺

Finally we calculate the molarity of H⁺, using the calculated number of moles and final volume:

Answer:

k

Explanation:

Answer:

75.6

Explanation: