Water cannot dissolve all substances that are made from ionic bonds. This is probably because

A.
Water needs to be stirred to dissolve all ionic substances

B.
Some ionic bonds are too strong for the attractions of water molecules to pull them apart

C.
Some water molecules are not as strong as others

Answers

Answer 1
B, some ionic bonds are too strong for the attractions of water molecules to pull them apart
Answer 2

Water cannot dissolve all substances that are made from ionic bonds probably because some ionic bonds are too strong for the attractions of water molecules to pull them apart.

WATER AS A UNIVERSAL SOLVENT:Water is a unique molecule often referred to as a universal solvent because it can dissolve almost all solutes.

Water is capable of dissolving polar substances i.e. substances that have an unequal distribution of positive and negative ions.

However, some ionic bonds formed from ions of elements are unable to be dissolved by water and this is probably attributed to the fact that those bonds are too strong to be pulled apart by water molecules.

Learn more about at ionic compounds at: https://brainly.com/question/9167977


Related Questions

2NaCl ---> 2Na + Cl2
What are the atoms of the products ​

Answers

Answer: ...

Explanation:

Sodium, chlorine

Answer:

2Na = 2 Sodium [has 2 atoms]

Cl2 = Dichlorine (Chlorine) [has 2 atoms]

Is this what you wanted?? I'm not entirely sure if this is the answer you were looking for.

9) What is the density of the gold rock with a mass of 386 grams and has a volume of 20 cubic centimeters?
O 0.193 g/cc
O 193 g/cc
O 1.93 g/cc
19.3 g/cc

Answers

Answer:

density= mass/volume

hence density of gold rock

= 386/20

=19.3 g/cc

Where do we get our energy from ?

Answers

Answer:

energy

Explanation:

from food which we eat

On a hot day, a student places a glass of cold lemonade on a table outdoors. After a few minutes, water droplets have formed on the outside of the glass.

Is energy absorbed or released by the cold lemonade? Explain your answer.
Compare average kinetic energy for the air molecules and lemonade molecules when the student first places the lemonade outdoors. Explain your answer.
Explain how and why the water droplets form on the outside of the glass.

Answers

Answer:

ye but sdfajkd tryng to play me

Explanation:

Answer:

Vapor is released out of the lemonade because when you place it in a hot it will increase.

Explanation:

A student transfers a gas at STP from a 11.0 L tank to a 25.0 L tank. If the pressure
remains constant, what is the new temperature?

Answers

. Consider a sample of oxygen gas at 27° C with a volume of 9.55L at a pressure

Answer:620 k

Explanation:

A compound is composed of 53.33%carbon, 11.11%hydrogen and 35.56%oxygen. If the molecular mass of the compound is 90, what is the molecular formula of this compound?

Answers

The final molecular formula will be C4H10O2
Hope this helps :)

The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in vinegar is around 0.85 M. Based on this information, determine the value of the acid ionization constant, Ka, for acetic acid.

Answers

Answer: The value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]

Explanation:

[tex]CH_3COOH\rightarrow H^+CH_3COO^-[/tex]

 cM              0             0

[tex]c-c\alpha[/tex]        [tex]c\alpha[/tex]          [tex]c\alpha[/tex]  

So dissociation constant will be:

[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]

Give c= 0.85 M and [tex]pH[/tex] = 2.4

[tex]pH=-log[H^+][/tex]

[tex][H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}[/tex]

[tex]K_a=?[/tex]

Putting in the values we get:

[tex]K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}[/tex]

Thus the value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]


8. Of what importance is a smoker to a person keeping bees?​

Answers

Answer:

they help to calm the bees when the person keeping the bees inspects there hives.

If you use 65.34 g of Al2S3, how many grams of AICl3 can be produced?​

Answers

Answer:

sorry po

indi ko po maintindihan

How can I express the composition of a solution?

Answers

Answer:

It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...

Explanation:

It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...

what happen when a piece of silver metal is added to the copper sulphate solution​

Answers

Answer:

Explanation:When silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

Answer:

There will be no reaction

Explanation:

Therefore, when silver Ag metal is added to copper sulphate CuSO4 solution, no reaction takes place as silver is less reactive than that of copper and cannot displace copper from its solution. Hence, when a piece of silver metal is added to copper sulphate solution there will be no reaction.

Pls help really need it pls

Answers

the correct answer is the first one i think

4.What type of energy is used to fuel the process of photosynthesis and what type is produced in
respiration?
A Light energy is used in photosynthesis and created by respiration.
B ATP is used in photosynthesis, which allows the plant to undergo respiration.
C Light energy is used in photosynthesis, whereas respiration creates the energetic product, ATP.
D Food energy is used in photosynthesis and ATP is produced in respiration.

Answers

Answer:

A. light energy is used in photosynthesis and created by respiration

how many grams of AgNO3 (MM=169.87) are needed to prepare 0.125 M solution in 250 mL of water?
a. 0.5 g
b. .03 g
c. 5.3 g
d. 84.9g​

Answers

Answer:

Correct answer-C 5.3g

Explanation:

Molarity = no. of moles of solute/ volume of of solution in litre

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,so the mass of 0.03125 moles of AgNO3 = 0.03125×169.87= 5.3084g

The grams of AgNO₃ are needed to prepare 0.125 M solution in 250 mL of water is 5.3 grams.

How do we calculate mass from moles?

Moles is a unit which is used to define any amount and it is calculated as:

n = W/M, where

W = required mass

M = molar mass

Given molarity of AgNO₃ = 0.125 M

Volume of water = 250mL = 0.25L

moles (n) from the molarity (M) will be calculated as:

n = M × V

n = (0.125)(0.25) = 0.0312 moles

Now we calculate the mass of AgNO₃ by using the above formula as:

W = (0.0312mol)(169.87g/mol)

W = 5.30 g

Hence option (c) is correct.

To know more about moles, visit the below link:

https://brainly.com/question/15374113

In a solution, litmus is blue. The pH of the solution could be
1. 10
2. 2
3. 3
4. 4

Answers

Answer:

1. 10

Explanation

when litmus paper is blue that means the solution is basic and 10 on the pH scale is the most basic out of all your options

If I add 25mL of water to 125 mL of 0.25 M NaOH solution, what will the molarity of the diluted solution be?

Answers

Answer:

0.208333 M

Explanation:

M2=M1V1/V2=(0.25 M)(125mL)/(125mL+25 mL)= 0.208333 M

Why is it important for the daughter cells to divide a second time in meiosis?
The second division switches parts of matching chromatids to increase genetic variation.
The second division forms four identical cells to ensure that all offspring have the same
The second division sorts chromosomes into cells that are the same as the parent cells.
The second division forms haploid cells that can combine with other haploid cells during fertilization.

Answers

Answer:

The second division switches parts of matching chromatids to increase genetic variation.

Explanation:

Meiosis and fertilization create genetic variation by making new combinations of gene variants (alleles).

One major problem with wind and solar energy is that they are conditional. Explain how hydroelectric pumped storage could be used to eliminate this
obstacle? *​
Link to the article https://thinkprogress.org/the-inside story-of-the-worlds-biggest-battery-and-the-future-of-renewable-energy-8984c81283c/

Answers

Answer:

Hydroelectric pumped storage can be used to eliminate the conditional nature of wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.

Explanation:

Pumped-storage hydroelectricity is a type of hydroelectric energy storage used by electric power systems to store excess electrical power during periods of low demand for later release at periods when demand for energy rises again. It stores energy in the form of gravitational potential energy of water, pumped from a lower level reservoir to a higher level reservoir.

At times of low electrical demand, excess generated energy is used to pump water into the upper reservoir. When there is higher demand, water is released back into the lower reservoir through a turbine, generating electricity.

This form of energy storage is useful in circumventing the conditional nature of renewable energy sources such as wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.

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