Answer:
F = 45 KN = 45000 N
Explanation:
Considering the downward direction as the positive direction:
[tex]P = P_1 - P_2[/tex]
where,
P = Resultant Pressure = ?
P₁ = Atmospheric Pressure = 100 KPa
P₂ = Pressure inside the can = 70000 Pa = 70 KPa
Therefore,
[tex]P = 100\ KPa - 70\ KPa\\P = 30\ KPa[/tex]
Now the resultant force will be given as:
[tex]F = PA[/tex]
where,
F = resultant force = ?
A = Area of side of can = 1.5 m²
Therefore,
[tex]F = (30\ KPa)(1.5\ m^2)\\[/tex]
F = 45 KN
Thomas helps his older brothers, who own a junk yard, on the weekends to earn extra money. He likes to help them push broken-down cars to the back of the junk yard because it makes him feel strong. Last Saturday, they pushed three cars with different weights, and he noticed he used different amounts of force for each one. The cars were the following weights:white car: 2,700 poundsred car: 1,500 poundsblue car: 2,100 poundsThink about how much force is needed to move each car. Which correctly organizes the cars in order from the most to least amount of force needed to move them
Answer:
white, blue and red
Explanation:
Force is given by
[tex]F=ma[/tex]
where
m = Mass of object
a = Acceleration of the object
If the acceleration is same for all the cars the force needed to be applied will depend on the mass of the car. The heaviest car requiring the most force and the lightest car requiring the least amount of force.
Here, the weight of the cars in descending order is white, blue and red.
So, the cars in order from the most to least amount of force needed to move them is white, blue and red.
A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position for a -6.0 nC charge.
Answer: [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Explanation:
Given
The magnitude of the first charge is [tex]Q_1=3.5\ nC[/tex]
The magnitude of the second charge is [tex]Q_2=5\ nC[/tex]
[tex]-6\ nC[/tex] charge must be placed in between the two charges to establish equilibrium
The electrostatic force is given by
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Equilibrium will be established when force by both the charges balance out each other. Suppose [tex]-6\ nC[/tex] is placed at a distance of [tex]x[/tex] cm from [tex]3.5\ nC[/tex] . So, we can write
[tex]\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}[/tex]
Canceling similar terms
[tex]\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm[/tex]
Thus, the equilibrium position is [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Answer:
What school do you go to?
Explanation:
Which one of these Target games uses the underhand throw?
A: Golf
B: KanJam
C: Corn-Hole
D: None Of The Above
HELP!!
Answer:
Cornhole
Explanation:
A firework is launched with a force of 700 N and a momentum of 200 kg-m/s. How much time before is explodes?
Answer:
t = 0.28 seconds
Explanation:
Given that,
Force acting on a firework, F = 700 N
The momentum of the firework, p =200 kg-m/s
We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,
[tex]F=\dfrac{P}{t}\\\\t=\dfrac{P}{F}\\\\t=\dfrac{200}{700}\\t=0.28\ s[/tex]
So, the required time is equal to 0.28 seconds.
A physics student of mass 43.0 kg is standing at the edge of the flat roof of a building, 12.0 m above the sidewalk. An unfriendly dog is running across the roof toward her. Next to her is a large wheel mounted on a horizontal axle at its center. The wheel, used to lift objects from the ground to the roof, has a light crank attached to it and a light rope wrapped around it; the free end of the rope hangs over the edge of the roof. The student radius 0.300 m and a moment of inertia of 9.60 kg m^2 for rotation about the axle, how long does it take her to reach the side walk, and how fast will she be moving just beofre she lands?
Answer:
The speed of the student just before she lands, v₂ is approximately 8.225 m/s
Explanation:
The given parameters are;
The mass of the physic student, m = 43.0 kg
The height at which the student is standing, h = 12.0 m
The radius of the wheel, r = 0.300 m
The moment of inertia of the wheel, I = 9.60 kg·m²
The initial potential energy of the female student, P.E.₁ = m·g·h₁
Where;
m = 43.0 kg
g = The acceleration due to gravity ≈ 9.81 m/s²
h = 12.0 h
∴ P.E.₁ = 43 kg × 9.81 m/s² × 12.0 m = 5061.96 J
The kinetic rotational energy of the wheel and kinetic energy of the student supporting herself from the rope she grabs and steps off the roof, K₁, is given as follows;
[tex]K_1 = \dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2[/tex]
The initial kinetic energy, 1/2·m·v₁² and the initial kinetic rotational energy, 1/2·m·ω₁² are 0
∴ K₁ = 0 + 0 = 0
The final potential energy of the student when lands. P.E.₂ = m·g·h₂ = 0
Where;
h₂ = 0 m
The final kinetic energy, K₂, of the wheel and student is give as follows;
[tex]K_2 = \dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2[/tex]
Where;
v₂ = The speed of the student just before she lands
ω₂ = The angular velocity of the wheel just before she lands
By the conservation of energy, we have;
P.E.₁ + K₁ = P.E.₂ + K₂
∴ m·g·h₁ + [tex]\dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2[/tex] = m·g·h₂ + [tex]\dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2[/tex]
Where;
ω₂ = v₂/r
∴ 5061.96 J + 0 = 0 + [tex]\dfrac{1}{2} \times 43.0 \, kg \times v_{2}^2+\dfrac{1}{2} \times 9.60 \, kg\cdot m^2 \cdot \left (\dfrac{v_2}{0.300 \, m} }\right ) ^2[/tex]
5,061.96 J = 21.5 kg × v₂² + 53.[tex]\overline 3[/tex] kg × v₂² = 21.5 kg × v₂² + 160/3 kg × v₂²
v₂² = 5,061.96 J/(21.5 kg + 160/3 kg) ≈ 67.643118 m²/s²
v₂ ≈ √(67.643118 m²/s²) ≈ 8.22454363 m/s
The speed of the student just before she lands, v₂ ≈ 8.225 m/s.
HELP pleaseee which nucleus completes the following equation?
Answer:
its D
Explanation:
i just got it correct on a. p. e. x. :)
A toy gun uses a spring to shoot plastic balls (m = 50 g). The spring is compressed by 3.0 cm. Let k=2.22 × 105 N/m. (a) Of course, you have to do some work on the gun to arm it. How much work do you have to do? (b) Suppose you fire the gun horizontally. How fast does the ball leave the gun? (c) Now suppose you fire the gun straight upwards. How high does the ball go?
Answer:
Explanation:
Given that:
mass of the plastic ball = 50 g = 50 × 10⁻³ kg
spring constant (k) = 2.22 × 10⁵ N/m
compression of spring (x) = 3.0 cm = 3 × 10⁻² m
a) Work done:
[tex]= \dfrac{1}{2}kx^2 \\ \\ = \dfrac{1}{2}\times 2.22 \times 10^{5}\times (3 \times 10^{-2})^2 \\ \\ = 99.9 \ J[/tex]
b) When the gun is fired horizontally;
In the spring, the potential energy is changed to kinetic energy.
i.e.
[tex]\implies \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2 \\ \\ 2.22 \times 10^5 \times (3\times 10^{-2}) ^2 =50 \times 10^{-3} \times v^2\\ \\ \mathbf{v= 63.2 m/s}[/tex]
c) The max height the bullet will reach if the gun is being shot upward is:
[tex]H_{max}= \dfrac{v^2}{2g} \\ \\ H_{max}= \dfrac{63.2^2}{2\times 9.8}[/tex]
[tex]\mathbf{H_{max}= 203.9 \ m}[/tex]
Which of the following ways of writing 1000w is incorrect?
1) 1 kW
2) 1 x 10³ W
3) 10 x 10³ W
4) 1.0 x 10³ W
Answer:
the third one is incorrect
Explanation:
10 x 10³= 10^1 x 10^3 = 10^4
Find the tension in the two groups that are holding the 2.9 kg object in Pl., One makes an angle of 35.6° with respect to the vertical group 2 is pulling horizontally
Answer:
≈ 20.35 N [newton's of tension]
Explanation:
( (2.9 × 9.8) ÷ cos(35.6°) ) × sin (35.6°) =
( (28.42) ÷ (≈0.813) ) × (≈0.582) =
(≈34.96) × (≈0.582) = 20.3449446.... ≈ 20.35
PLS HELP ME
Secondary waves CANNOT travel through
a.
rock.
b.
liquids.
c.
Earth’s mantle.
d.
Earth’s crust.
Answer:
B. Liquids
Explanation:
Just had this question on my test.
Hope this helps :)
How much must you raise the
temperature of 1.00 m^3 of water
so that its volume expands by
0.00100 m^3?
Water
B = 207-10-6 0-1
(Unit = C)
Answer:
4.83 °C
Explanation:
001 = λ*ΔT
ΔT = 10^-3*10^6/207 = 4.83°C
Answer:
4.83
Explanation:
Why would you have trouble breathing at high altitudes?
A. it is colder at the top of a mountain
B. the oxygen molecules are spread farther apart
C. the oxygen molecules are closer together
Answer:
A. It is colder at the top of a mountain
Explanation:
Two resistors, 2.50 Ω and 4.95 Ω, are wired in series to a 12.00 V battery. What is the equivalent resistance of the circuit?
Answer:
7.45 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 2.50 Ω
Resistor 2 (R₂) = 4.95 Ω
Voltage (V) = 12 V
Equivalent Resistance (Rₑq) =?
Since the resistors are in series arrangement, the equivalent resistance can be obtained as follow:
Rₑq = R₁ + R₂
Rₑq = 2.5 + 4.95
Rₑq = 7.45 Ω
Therefore, the equivalent resistance is 7.45 Ω
Can someone list me 6 disadvantages of renewable energy?
A decibel measures the _____________ of sound.
A.pitch
B,frequency
C.loudness
D.amplitude
The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (or the time for the sledge hammer to stop after contact) is 0.0020s. Find the time average of the impact force
Answer:
The average impact force is 12000 newtons.
Explanation:
By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:
[tex]\bar F \cdot \Delta t = m \cdot (v_{2}-v_{1})[/tex] (1)
Where:
[tex]\bar F[/tex] - Average impact force, in newtons.
[tex]\Delta t[/tex] - Duration of the impact, in seconds.
[tex]m[/tex] - Mass of the sledge hammer, in kilograms.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final velocity, in meters per second.
If we know that [tex]\Delta t = 0.0020\,s[/tex], [tex]m = 4\,kg[/tex], [tex]v_{1} = -6\,\frac{m}{s}[/tex] and [tex]v_{2} = 0\,\frac{m}{s}[/tex], then we estimate the average impact force is:
[tex]\bar F = \frac{m\cdot (v_{2}-v_{1})}{\Delta t}[/tex]
[tex]\bar F = 12000\,N[/tex]
The average impact force is 12000 newtons.
A 25 kg block is sliding down 28o incline at a constant speed.
a Q. No. la sap
What is derived is one second time?
Answer:
The second (abbreviation, s or sec) is the Standard International ( SI ) unit of time. One second is the time that elapses during 9,192,631,770 (9.192631770 x 10 9 ) cycles of the radiation produced by the transition between two levels of the cesium 133 atom. ... One second is equal to 1/86,400 of a mean solar day.
Explanation:
How can we teach our kitty to behave properly
Answer:
I have no idea.
Explanation:
I just wanted to tell you I absolutely read this wrong.
Which statement best summarizes the development of the atomic theory over time?
Answer:
electrons move around nucleus in specific regions
We have that the correct statement that summarizes atoms over time will be
The discovery of new evidence resulted in changes to the atomic theory.
Option B
Generally
The Image shows that in the early 1800 the knowledge of atom was limited and it increased over time and by 1920 it had gone through a 4 stages of modifications to the atomic model
Atoms are solid spheresElectrons are attached to atom surfaceElectrons move around in the nucleus in a specificRapid motion of electrons in the cloudTherefore the correct statement that summarizes atoms over time will be
The discovery of new evidence resulted in changes to the atomic theory
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At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant
Answer:
Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer
answer : mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]
To calculate for weight of Bananas = m * g where g = 9.8
Explanation:
Given an amplitude ( A )= 29.8981
Spring constant = x ( unknown )
maximum speed of Bananas( v ) = wA ( unknown )
question : calculate the weight of the bananas
First step : calculate the period of oscillation
T = [tex]\frac{2\pi }{vA}[/tex] --- ( 1 )
next step : express T in terms of mass ( m ) of the bananas
= [tex]2\pi \sqrt{\frac{m}{k} } = \frac{2\pi }{vA}[/tex]
∴ m/k = A^2 / v^2
hence mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]
To calculate for weight = m * g
how is momentum of an object related to stopping distance
Answer:
To stop a car must lose its momentum and its kinetic energy. ... If the forces on two cars are equal then the greater the kinetic energy the greater the distance before stopping. But there will be a relationship to the momentum because momentum and mass are both related to the kinetic energy.
What specific type of tide has the smallest difference between high and low tide?
Answer: Neap tides
Explanation: Neap tides are tides that have the smallest tidal range, and they occur when the Earth the Moon, and the Sun form a 90o angle. They occur exactly halfway between the spring tides when the Moon is at first or last quarter.
You are sharing a house with a few roommates. One of them plays on the basketball team, and is exactly 200 cm tall. The heights of you and the other roommates are 188 cm, 175 cm, and 160 cm. You want to buy the minimum height mirror that will allow all of you to see your entire selves, when the mirror is mounted in a fixed position on the wall. Assume each person's eyes are at a level 95% of their height. How tall a mirror should you buy
Answer:
119 cm
Explanation:
Given heights : 200cm , 188 cm , 175 cm, 160 cm
since the eyes are at 95% level
95% of 200 cm = 190 cm
95% of 160 cm = 152 cm
hence the allowable height of mirror = 200 - ( 5 + 76 ) = 119 cm
and The mirror should be hung 75cm from the floor
it did work lollllllllllllllll
Answer:
Ok.............
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Two waves, each with an amplitude of 0.5m are superimposed with constructive interference such that they are in phase. Describe the resultant amplitude
The resultant amplitude of the two waves is 1.0m
Interference occurs when two or more waves are superimposed over each other. These waves can either be destructive or constructive in nature. If the waves are superimposed with constructive interference such that they are in phase, the resultant amplitude will be the sum of the amplitude of both waves.Resultant amplitude = 0.5m + 0.5m
Resultant amplutude = 1.0m
Hence the resultant amplitude of the two waves is 1.0m
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7. An object can be accelerating even if its speed is
constant if it
(a) comes to a stop
(b) is not possible
(C) changes direction
(d) moves in a straight line
Answer:
I think that the answer might be d
Answer:
D
Explanation:
If a car is moving very fast in a straight road or a highway in such a way that it has reached its limits as soon as it is going that fast it can break it limit
PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject
Answer:
Third option
Explanation:
To calculate meters per second you divide the distance by the time.
it's 8m/s
What are examples of changes in people, animals, or objects that would help you make a claim about their age? NO LINKS OR YOURE GETTING REPORTED. Thanks
It’s Earth Science
Answer:
An example of changes in people based on their age, are mood changes,playfulness and as of objects you can say old or broken, animals can use the same reference as humans, the more mature you are can suggest your older, such as the more worn down your are based on a object
Which statement is true of an alpha particle?
A. It is electromagnetic radiation, not a true particle.
B. It is an electron.
C. It is the largest decay particle
D. It is a particle that travels at the speed of light.
Answer:
Atoms are made up of various parts; the nucleus contains minute particles ... neutrons, and the atom's outer shell contains other particles called electrons. ... Physical Forms of Radiation; Radioactive Decay; Nuclear Fission; Ionizing Radiation ... of high-energy waves that can travel great distances at the speed of light and ...
Explanation:
The true statement of an alpha particle is it is an electron. The correct option is B.
What is an alpha particle?The alpha particle are composite particles which consists of two protons and two neutrons tightly bonded together. They are ejected from the inside the nucleus of heavy radioactive particles, also called alpha decay.
Atoms are made up electrons orbiting in outer shells, protons and neutrons in the nucleus. The radioactive particle emit highly ionized radioactive rays which ionize electrons emitting alpha particle.
Thus, the correct option is B.
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