A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center of the disk. The platform has a mass of 150 kg, a radius of 2.0 m, and a rotational inertia of 300 kg·m2 about the axis of rotation. A 60 kg student walks slowly from the rim of the platform toward the center. If the angular speed of the system is 1.4 rad/s when the student starts at the rim, what is the angular speed when she is 0.70 m from the center?

Answers

Answer 1

Answer: [tex]2.29\ rad/s[/tex]

Explanation:

Given

Mass of Platform M=150 kg

the radius of Platform R=2 m

Moment of inertia of Platform [tex]I=300\ kg.m^2[/tex]

Mass of student [tex]m=60\ kg[/tex]

The initial angular speed of the student is [tex]\omega _1=1.4\ rad/s[/tex]

Initially, the moment of inertia of platform and student is

[tex]I_1=\dfrac{1}{2}MR^2+mR^2\\\\I_1=300+60\times 4=540\ kg.m^2[/tex]

The final moment of inertia

[tex]I_2=\dfrac{1}{2}MR^2+mr^2\\\\I_2=300+60\times 0.7^2=329.4\ kg.m^2[/tex]

Conserving angular momentum

[tex]I_1\omega_1=I_2\omega _2\\\\540\times 1.4=329.4\times \omega_2\\\\\omega_2=\dfrac{756}{329.4}=2.29\ rad/s[/tex]


Related Questions

WILL MAKE BRAINLIEST! How does Hooke’s law help us understand the force and energy in elastic materials?

Answers

Answer:

How does Hooke’s law help us understand the force and energy in elastic materials?:

When the elastic materials are stretched, the atoms and molecules deform until stress is been applied and when the stress is removed they return to their initial state

Explanation:

An object has an angular velocity of 1.0 rad and an angular acceleration of 0.5 rad/s. Is the speed of its rotation increasing or decreasing?

Answers

Answer:

increasing

Explanation:

Given that,

Initial angular speed =1 rad/s

Angular acceleration = 0.5 rad/s²

We know that the angular acceleration is given by :

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Where

[tex]\omega_f[/tex]city and t is time is the final angualr velo

As the angular acceleration of the object is positive. It means that the final speed of the object is more than that initial. As a result, the speed of its rotation is increasing.

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.48 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1840 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.19 V/m, (b) in the negative z direction and has a magnitude of 5.19 V/m, and (c) in the positive x direction and has a magnitude of 5.19 V/m

Answers

Answer:

a)   F = 15.6 10⁻¹⁹  k^   N,  b)  F = -1  10⁻¹⁹  k^   N,

c)  F = (8.3 i^ + 73 k^) 10⁻¹⁹ N

Explanation:

In this exercise we calculate the magnetic and electric force separately.

Let's start by calculating the magnetic force

       F_m = q v x B

where bold letters indicate vectors, the modulus of this expression is

       F_m = q v B

the direction is given by the right hand rule, where the thumb points in the direction of velocity, the fingers are extended in the direction of the magnetic field and the palm is in the directional ne force if the charge is positive

let's calculate the magnitude

      F_m = 1.6 10⁻¹⁹  1840  2.48 10⁻³

      F_m = 7.3 10⁻¹⁹ N

we calculate the direction, the thumb is in the direction of + y,

fingers extended in the direction of -ax

the palm remains + z

therefore the magnetic force is in the direction of the positive side of the z axis

The electric force is

        F_e = q E

give several possibilities for the electric field

a) electric field E = 5.19 V / m in the direction of + z

we calculate

        F_e = 1.6 10⁻¹⁹ 5.19

        F_e = 8.3 10⁻¹⁹ N

the total force is

       F = F_m + F_e

       F = (8.3 k ^ + 7.3 k ^) 10⁻¹⁹

       F = 15.6 10⁻¹⁹  k^   N

b) in the -z direction

       F_e = -8.3 10⁻¹⁹ k^   N

       F = Fm + Fe

       F = (-8.3 k ^ + 7.3 k ^) 10⁻¹⁹

       F = -1  10⁻¹⁹  k^   N

c) in the + x direction

       F_e = 8.3 10⁻¹⁹  i^   N

the total force is

       F = (8.3 i^ + 73 k^) 10⁻¹⁹ N

A boy walks towards a stationary plane mirror at a speed of 12ms^1 what is the relative speed of approach of the boy and his image? (a)zero (b)1.2ms^-1 (c) 2.4ms^-1 (d)1.44ms^-1​

Answers

Answer:

a

Explanation:

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Compare and contrast hydrogen fuel cell vehicles with vehicles that have intemal combustion engines.​

Answers

In a fuel cell vehicle, the hydrogen fuel is combined with oxygen. While the combustion in a hydrogen- or gasoline-powered engine is converted into mechanical energy, in a fuel cell vehicle, the chemical energy from the hydrogen and oxygen is converted into electrical energy.

A hydrogen fuel cell vehicle is different from internal combustion engine as in fuel cell, hydrogen combines with oxygen whereas in internal combustion engines, gasoline is used.

What are hydrogen fuel cell vehicles and internal combustion engines?

In a internal combustion engine or fuel cell vehicle, the hydrogen fuel is combined with oxygen atom. While the combustion in a hydrogen- fuel or in a gasoline-powered engine is converted into mechanical energy, however in the hydrogen fuel cell vehicle, the chemical energy from the hydrogen and oxygen is converted into electrical energy.

Both hydrogen internal combustion engines and the hydrogen fuel cells can power vehicles using hydrogen, a zero-carbon fuel. Hydrogen engines burn hydrogen gas in an internal combustion engine, in the same way as the gasoline is used in a power engine. Examples of hydrogen internal combustion engines include gasoline engines, diesel engines, gas-turbine engines, and rocket-propulsion systems.

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Find the tension in the two groups that are holding the 2.9 kg object in Pl., One makes an angle of 35.6° with respect to the vertical group 2 is pulling horizontally

Answers

Answer:

≈ 20.35 N [newton's of tension]

Explanation:

( (2.9 × 9.8) ÷ cos(35.6°) ) × sin (35.6°) =

( (28.42) ÷ (≈0.813) ) × (≈0.582) =

(≈34.96) × (≈0.582) = 20.3449446.... ≈ 20.35

10. A pitcher in a professional baseball game throws a fastball, giving the baseball
a momentum of 5.83 kg. m/s. Given that the baseball has a mass of 0.145 kg,
what is its speed?

Answers

Answer: 40.2m/sec

Work: v=p/m= 5.83kg/0.145k=40.2cm/sec

Highlight two factors which shows that heat from the sun does reach the earth's surface by convection.

Answers

radiation

when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation

Absence of medium is the factor which shows that heat from the sun does reach the earth's surface by convection.

The heat of the sun reaches the earth only through radiation because radiation does not require any medium for the transfer of energy but convection and conduction required a medium to transfer heat energy.

We know that there is no medium present in vacuum so convection and conduction are impossible in a vacuum that's why the sun's heat does not reach the earth by conduction or convection.

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Please Help Me!!!
Water is a colorless and odorless liquid. It can exist in solid, liquid, and gas states. It boils at 100 degrees C and melts at 0 degrees C.
Which option best describes this information?
A.
These are the physical properties of water.
B.
These are the chemical properties of water.
C.
These are the physical changes water undergoes.
D.
These are the chemical changes water undergoes.
E.
These are the molecular changes water undergoes.

Answers

Answer:

There are the molecular changes water undergoes

Define the types of friction and give FOUR examples of each
Static Friction
Rolling Friction
Sliding Friction
Fluid Friction

Answers

Static Friction is the force that keeps an object at rest
example: pushing against a heavy box but it isnt moving due to the weight of the box and gravity pulling it down

Rolling friction is a resistive force that slows down something thats rolling such as a ball or a wheel
example: a rolling soccer being slowed down from grass

Sliding Friction is the friction created from two object sliding against eachother, just like kinetic friction. It is intended to make the object stop
example: A sled sliding down a hill against snow

Fluid Friction is the force that resist motion in fluid or something moving around a fluid.
example: water pushing against a swimmer when swimming through it

Which nucleus completes the following equation?

Answers

Answer:

B. [tex]\frac{218}{85} At[/tex]

Explanation:

A P E X

The nucleus that completes the following equation is ²²⁶Ac₈₉

²²²Fr₈₇ →⁴He₂ +  ²²⁶Ac₈₉

Therefore the correct answer is option C.

What is radioactive decay?

The phenomenon of Radioactive decay is a type of nuclear reaction in which the unstable nucleus of a radioactive element lose energy in the form of nuclear radiation, some examples of radioactive decay are alpha decay, decay, and beta decay.

The complete equation for the nuclear reaction is

²²²Fr₈₇ →⁴He₂ +  ²²⁶Ac₈₉

For the given problem the nucleus completes the given equation is  ²²⁶Ac₈₉. The correct answer is option C.

learn more about radioactive decay

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At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant

Answers

Answer:

Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer

answer :  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight of Bananas  = m * g      where g = 9.8

Explanation:

Given an amplitude ( A )= 29.8981

Spring constant = x ( unknown )

maximum speed of Bananas( v ) = wA  ( unknown )

question : calculate the weight of the bananas

First  step : calculate the period of oscillation

T = [tex]\frac{2\pi }{vA}[/tex] --- ( 1 )

next step : express T in terms of mass ( m ) of the bananas

= [tex]2\pi \sqrt{\frac{m}{k} } = \frac{2\pi }{vA}[/tex]

∴ m/k = A^2 / v^2

hence  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight = m * g

An object has an acceleration of 18.0 m/s/s. If the net force acting upon this object were doubled, then its new acceleration would be m/s/s.​

Answers

Answer:

36.m/s/s

Explanation:

Is this right? Please help me ITS SOCIOLOGY

Answers

Yes, this is correct Answer.

Which best summarizes a concept related to the work-energy theorem?
- When work is positive, the environment does work on an object.
- When work is negative, the environment does work on an object.
- When work is positive, the kinetic energy in a system remains constant.
- When work is negative, the kinetic energy in a system remains constant.

this is times pls help!

Answers

Answer:

When work is positive, the environment does work on an object.

Explanation:

According to the work-energy theorem, the net work done by the forces on a body or an object is equal to the change produced in the kinetic energy of the body or an object.

The concept that summarizes a concept related to the work-energy theorem is that ''When work is positive, the environment does work on an object.''

Answer:

Your answer is A!

Have a good day!

A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position for a -6.0 nC charge.

Answers

Answer: [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.

Explanation:

Given

The magnitude of the first charge is  [tex]Q_1=3.5\ nC[/tex]

The magnitude of the second charge is [tex]Q_2=5\ nC[/tex]

[tex]-6\ nC[/tex] charge must be placed in between the two charges to establish equilibrium

The electrostatic force is given by

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Equilibrium will be established when force by both the charges balance out each other. Suppose [tex]-6\ nC[/tex] is placed at a distance of [tex]x[/tex] cm from [tex]3.5\ nC[/tex] . So, we can write

[tex]\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}[/tex]

Canceling similar terms

[tex]\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm[/tex]

Thus, the equilibrium position is [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.

Answer:

What school do you go to?

Explanation:

A decibel measures the _____________ of sound.

A.pitch

B,frequency

C.loudness

D.amplitude

Answers

Decibels measure sound intensity- which would be D. Amplitude.

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration

Answers

Answer:

1 m/s²

Explanation:

From the question,

Using

a = (v-u)/t.................... Equation 1

Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.

Given: v = 15 m/s, u = 5 m/s, t = 10 s

Substitute these values into equation 1

a = (15-5)/10

a = 10/10

a = 1 m/s²

Hence the acceleration of the bicycle is 1 m/s²

A machine raised a load of 360N through a distance of 0.2m. The effort, a force of 50N moved 1.8m during the process. Calculate the efficiency of the machine.
Select one:
a. 40%
b. 100%
c. 80%
d. 60%

Answers

Answer:

c. 80%

Explanation:

Given;

load raised by the machine, L = 360 N

distance through which the load was raised, d = 0.2 m

effort applied, E = 50 N

distance moved by the effort, e = 1.8 m

The efficiency of the machine is calculated as follows;

[tex]Efficiency = \frac{ 0utput \ work }{1nput \ work} \times 100\% \\\\Efficiency = \frac{Load \ \times \ distance \ moved \ by \ load }{Efort \ \times \ distance \ moved \ by \ effort} \times 100\%\\\\Efficiency = \frac{360 \times 0.2}{50 \times 1.8} \times 100\%\\\\Efficiency =80\%[/tex]

Therefore, the efficiency of the machine is 80%


What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2

Answers

Answer:

[tex]\boxed {\boxed {\sf 252.5 \ Newtons }}[/tex]

Explanation:

Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.

[tex]F=m*a[/tex]

The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:

[tex]m= 50.5 \ kg[/tex][tex]a= 5.0 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]F= 50.5 \ kg * 5.0 \ m/s^2[/tex]

Multiply.

[tex]F=252.5 \ kg*m/s^2[/tex]

1 kilogram meter per square second is equal to 1 Newton. Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.

[tex]F= 252.5 \ N[/tex]

The force required is 252.5 Newtons.

How do you find the velocity of a moving car?

Answers

Answer:

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt. Speed (or rate, r) is a scalar quantity that measures the distance traveled (d) over the change in time (Δt), represented by the equation r = d/Δt.

Explanation:

hope this helps a little bit sorry if i got it wrong

Which of the following ways of writing 1000w is incorrect?
1) 1 kW
2) 1 x 10³ W
3) 10 x 10³ W
4) 1.0 x 10³ W

Answers

Answer:

the third one is incorrect

Explanation:

10 x 10³= 10^1 x 10^3 = 10^4

PLEASE HELP ME I AM TIMED!

Answers

Answer:

Well my good friend the other person did not give U a good answer, it is actually the third one

Explanation: well it is the most logical of all the answers if you think about it and a lot of the creatures we have in the water today are thought of to have once lived on land based on the fossils we still find to this very day my friend

A 1.80-kg object is attached to a spring and placed on frictionless, horizontal surface. A horizontal force of 15.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations.
(a) Find the force constant of the spring.
N/m

(b) Find the frequency of the oscillations.
Hz

(c) Find the maximum speed of the object.
m/s

(d) Where does this maximum speed occur?
x = ±
m

(e) Find the maximum acceleration of the object.
m/s2

(f) Where does the maximum acceleration occur?
x = ±
m

(g) Find the total energy of the oscillating system.
J

(h) Find the speed of the object when its position is equal to one-third of the maximum value.
m/s

(i) Find the magnitude of the acceleration of the object when its position is equal to one-third of the maximum value.
m/s2

Answers

Answer:

Explanation:

(a) Force constant = force/displacement = 15/0.2

=75 N/m

(b) For SHM with spring, the angular frequency = sqrt ( force constant / mass )

= sqrt ( 75 / 1.8 )

= 6.455

Frequency = Angular frequency / 2pi

= 1.03Hz

(c) Maximum speed is when object's potential energy is at minimum.

1/2*mass*speed^2 = 1/2*force constant*displacement^2

speed^2 = 75*0.2^2/1.8 = 1.67

speed = sqrt (1.67)

= 1.29 m/s

(d) It occurs at x=0

(e) Maximum acceleration = Force / m = 15/1.8

= 8.33 m/s^2

(f) It occurs at x=0.2m

Answer:

Explanation:

given:

The mass of the object attached to the spring: m = 1.80 kg

The magnitude of the maximum horizontal force exerted: F = 15.0 N

The amplitude of the spring-object oscillation: A = 0.200 m

a. k=15/.2=75N/m

b. (2pi*frequency)^2 = k/m = 75/1.8 = 41.67

frequency = 1.03Hz

c. max speed^2 = amplitude^2*k/m = 0.2^2 * 41.67

max speed = 1.29 m/s

d. x=0m

e. max accel = F/m = 15/1.8 = 8.33 m/s^2

f. x=0.2m

e. energy = 1/2*k*A^2

= 1/2*75*0.2^2

= 1.5J

Thomas helps his older brothers, who own a junk yard, on the weekends to earn extra money. He likes to help them push broken-down cars to the back of the junk yard because it makes him feel strong. Last Saturday, they pushed three cars with different weights, and he noticed he used different amounts of force for each one. The cars were the following weights:white car: 2,700 poundsred car: 1,500 poundsblue car: 2,100 poundsThink about how much force is needed to move each car. Which correctly organizes the cars in order from the most to least amount of force needed to move them

Answers

Answer:

white, blue and red

Explanation:

Force is given by

[tex]F=ma[/tex]

where

m = Mass of object

a = Acceleration of the object

If the acceleration is same for all the cars the force needed to be applied will depend on the mass of the car. The heaviest car requiring the most force and the lightest car requiring the least amount of force.

Here, the weight of the cars in descending order is white, blue and red.

So, the cars in order from the most to least amount of force needed to move them is white, blue and red.

The image shows the magnetic field lines around a magnet.
Which statements are true for this magnet?

- the right pole is the south pole

- the left pole is the south pole

- the left pole is the north pole

- the right pole is the north pole

Choose all that apply

Answers

Answer:

The right pole is the south pole

The left pole is the north pole

Explanation:

Reason : -

Magnetic field lines emerge from North pole to South pole in a bar magnet.

En las olimpiadas del 2012 del colegio villapalos maria gano la carrera de los 100 m en 10,56 s y la de 200 m en 22,34 s ¿en cual fue mas veloz

Answers

Answer:

Fue mas velóz en los 100 m.

[tex]v_{1}=9.47\: m/s[/tex]

Explanation:

Tomando en cuanta que la definición de velocidad es:

[tex]v=\frac{\Delta x}{t}[/tex]

Donde:

Δx es el desplazamientot es el tiempo

La primera velodcidad esta dada por:

[tex]v_{1}=\frac{100}{10.56}[/tex]

[tex]v_{1}=9.47\: m/s[/tex]

La segunda velocidad sera:

[tex]v_{1}=\frac{200}{22.34}[/tex]

[tex]v_{1}=8.95\: m/s[/tex]

Por lo tanto, en el primer tramo fue más rápido.

Espero te haya ayudado!

Which of these statements are true about hydroelectric power? A.It is the most widely used renewable energy source in the world. B.It never disrupts ecosystems. C.It is not always available. D.A hydroelectric dam controls the force of moving water to generate electricity.

Answers

D is the answer most true

Your little cousin loves ice cream bars. You buy him one and he starts to lick it. As you sit down on a park bench, he drops
the bar on the seat of the bench. You pick up the bar to throw it away, but he starts to cry, so you shrug and give it back to
him. Will he definitely get sick?

Answers

Answer:

nop

Explanation:

It is not certain whether the child will get sick from eating the ice cream bar that was dropped on the bench.

What is contamination?

Contamination refers to the presence or introduction of harmful substances or organisms into a material, environment, or food source.

There is a possibility that the ice cream bar could have picked up bacteria or other contaminants from the bench that could make the child sick. However, the risk of illness depends on a number of factors, including the cleanliness of the bench, the length of time the ice cream was in contact with the bench, and the overall health of the child's immune system.

To reduce the risk of illness, it is important to wash hands and surfaces frequently, especially when handling food. If possible, it is best to discard food that has come into contact with potentially contaminated surfaces to prevent the spread of illness. However, if the child has already eaten the ice cream bar and does become sick, it is important to monitor their symptoms and seek medical attention if necessary.

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A baseball sits motionless near first base on a baseball diamond. What statement best explains why the baseball remains motionless?

A. The forces acting on the baseball are all balanced.
B. There are no forces acting on the baseball.
C. The dirt is placing an unbalanced force on the baseball.
D. The force on the baseball is unbalanced due to gravity.

Answers

Answer:

B

Explanation:

There are no forces acting in the baseball

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