Answer:
v=m/s m=v.s -1*3= -3 meter/second
The velocity of the elevator after 3 seconds will be equal to 3 m/s.
What are equations of motion?We have three equations of motion that can be used to calculate components such as displacement(s), initial (u) and final velocity (v), time(t), and acceleration(a). The expressions for the three equations of motion are as follows:
First Equation of Motion :
v = u + at
Second Equation of Motion :
S = ut + (1/2) at²
The third equation of motion is:
v² - u² =2aS
Given, the initial velocity (u) of the elevator is zero as the elevator is at rest initially.
The acceleration of the elevator, a = -1 m/s² moving downward.
The final velocity of the elevator after 3 seconds will be:
v = u + at
v = (0) + (-1 m/s²) (3 s)
v = - 3 m/s
Therefore, the velocity of the elevator after 3 seconds will be equal to 3 m/s in the downward direction.
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, A 50 kg astronaut weighs 490 N. What would she way if she landed on Jupiter‘s moon Callisto what fraction is this of her weight on earth?
Answer:
The fraction of the weight of the astronaut on Callisto to the weight on Earth is 0.126.
Explanation:
From Newton's Law of Motion, the weight ([tex]W[/tex]), measured in newtons, of an object is defined by this expression:
[tex]W = m\cdot g[/tex] (1)
Where:
[tex]m[/tex] - Mass, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
The gravitational acceleration in Callisto is 1.236 meters per square second.
If we know that [tex]m = 50\,kg[/tex] and [tex]g = 1.236\,\frac{m}{s^{2}}[/tex], then the weight of the astronaut in Callisto is:
[tex]W = (50\,kg)\cdot \left(1.236\,\frac{m}{s^{2}} \right)[/tex]
[tex]W = 61.8\,N[/tex]
And the fraction is:
[tex]x = \frac{61.8\,N}{490\,N}[/tex]
[tex]x = 0.126[/tex]
The fraction of the weight of the astronaut on Callisto to the weight on Earth is 0.126.
Move the slider on the battery to give it some voltage. What do the particles moving through the coil of wire represent?
It represents electrons. The moving electrons show current passing through the wire
A police car is moving east at 20m/s towards a driver who is moving west at 25m/s. The police car emits a frequency of 900Hz. What frequency is detected by the driver? The speed of sound at the time of this occurrence was 343m/s.
Answer:
f = 2445 Hz
Explanation:
i did the quiz
The frequency that the driver (observer) detects is equal to 1008 Hz
Given the following data:
Observer velocity = 25.0 m/sFrequency of sound = 900 HzSource velocity = 20.0 m/s Speed of sound = 343 m/sTo calculate the frequency that the driver (observer) detects, we would apply Doppler's effect of sound waves:
Mathematically, Doppler's effect of sound waves is given by the formula:
[tex]F_o = \frac{V \;+ \;V_o}{V\; - \;V_s} F[/tex]
Where:
V is the speed of a sound wave.F is the actual frequency of sound.[tex]V_o[/tex] is the observer velocity.[tex]V_s[/tex] is the source velocity.[tex]F_o[/tex] is the observer frequency.Substituting the given parameters into the formula, we have;
[tex]F_o = \frac{343 \;+ \;20}{343\; - \;20} \times 900\\\\F_o = \frac{363}{323} \times 900\\\\F_o = 1.12 \times 900\\\\F_o =1008 \;Hz[/tex]
Driver (observer) frequency = 1008 Hz
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a rock is an example of a solid because
Answer:
The key is that solids hold their shape and they don't flow like a liquid. A rock will always look like a rock unless something happens to it.
Solids can hold their shape because their molecules are tightly packed together.
Explanation:
Yes; it is a solid
Which correctly describes have any giveaway on the electromagnetic spectrum depends on the wavelength and frequency
Answer:
c = λ f
Explanation:
In the electromagnetic spectrum, the wavelength and frequency of a specific radiation are related to the speed of the wave, which in this case the speed of light
c = λ f
where c is the speed of light, λ the wavelength and f the frequency of radiation
The planet Mercury travels around the Sun with a mean orbital radius of 5.8x100 m. The mass of the Sun is 1.99x1030 kg. Use Newton's version of Kepler's third law to determine how long it takes Mercury to orbit the Sun. Give your answer in seconds.
The time taken for Planet Mercury to orbit around the sun is determined as 1.21 x 10⁶ s.
Period of the planet mercury
The time of motion of the planet around the sun is calculated as follows;
[tex]T = 2\pi \sqrt{\frac{a^3}{Gm} } \\\\[/tex]
where;
a is the mean radius of the planet MercuryG is universal gravitation constantM is mass of the sun[tex]T = 2\pi \sqrt{\frac{(5.8 \times 10^{10})^3}{(6.67 \times 10^{-11})(1.99\times 10^{30})} } \\\\T = 1.21 \times 10^6 \ s[/tex]
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2. A bullet was shot by a gun with an initial speed of 260 m/s and is fired at an angle of 30 to the ground. a. How much is the value Vy at the top of the bullet's trajectory? b. Calculate the time taken by the bullet to reach its maximum altitude. c. Deduce the total time taken by the bullet in the air. d. Calculate the range of the bullet.
Answer:
Explanation:
a )
the value Vy at the top of the bullet's trajectory will be zero . At the top , only the horizontal component Vx will exist .
b )
At the top Vy = 0
initial velocity will have vertical component = 260 sin30 = 130 m /s
acceleration = - g = - 9.8
v = u - gt
o = 130 - 9.8 t
t = 13.26 s .
c )
Total time = Time of ascent + time of descent
= 13.26 + 13.26 = 26.52 s
d )
Range R = u² sin2Ф / g , where u is initial velocity , Ф is angle of throw , g is acceleration due to gravity .
R = 260² sin 2 x 30 / 9.8
= 5973.8 m .
Using a box covered with graph paper allows you to simulate which aspect of a car crash?
Answer:
a computer modeling
Explanation:
A horizontal net force F is exerted on an object at rest. The object starts at x=0 m and has a speed of 4.0 m/s after moving 4.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below
Explanation:
The solution is be found in the attachment.
A horizontal net force F is exerted on an object at rest. The object starts at x = 0 m and has a speed of 4.0 m/s after moving 8.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.
What is the mass of the object?
Answer: 30 kg
Which type of information about rattlesnakes does the bar graph above show?
Answer:
Variation
Explanation:
A total lunar eclipse is:
a. Visible only from the path of totality
b. Visible to all observers on the night time side of the earth
c. Visible only during a new moon
d. an opportunity to study the corona of the sun
Answer:
B) Visible to all observers on the night time side of the earth
Explanation:
I hope this helps.
b) The man has a mass of 85 kg. Gravitational field strength = 9.8 N/kg.
Calculate the weight of the man. Use the equation: weight = mass x
gravitational field strength
Answer:
mass× weight
85×9.5=807.5 kg
PLS ANSWER FAST WILL GIVE BRAINLY!! BUT ONLY IF YOU KNOW!!
Fill in the blanks
Cobalt has 27 protons, 32 neutrons and 27 electrons. What is it's atomic mass?
Answer:
58.933195 u or 59 u
Explanation:
Atomic mass of cobalt is 58.933195 u
5 points
What did Alfred Wegener think happens during Continental Drift?
A. Continents move
B. The mantle warms
C. Convection Stops
D. Continents freeze
Answer:
Continents move
Explanation:
A car of mass 150 kg is riding down at constant velocity What is the friction force?
Answer:
I think it's b
Explanation:
friction is the opposite direction of the object do it's definitely left something
Other than the resultant force acting on an object what else do you need to know to calculate the acceleration??
In addition to the resultant force acting on an object, the mass of the object should be known to find the acceleration. So, the mass is the answer.
Newton's second law of motion states that
a = F / m
Where:
a is the acceleration of the object,
The net force acting on the object is F
m is the mass of the object.
By dividing the net force (F) by the mass (m), you can determine the acceleration (a) of the object.
So, both the net force and the mass are necessary to calculate the acceleration. So, the mass is the answer.
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How can we define force?
Explanation:
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.
Answer:
There are 2 definitions chose the suitable one for ur question
Explanation:
1. strength or energy as an attribute of physical action or movement.
2. coercion or compulsion, especially with the use or threat of violence.
HOPE THIS HELPS
A coin is dropped off of a building landing on its side. It hits with a pressure of 400/2 It hits with a force of 0.1 Calculate the area of the coin?
Complete Question:
A coin is dropped off of a building landing on its side. It hits with a pressure of 400 N/m². It hits with a force of 0.1N. Calculate the area of the coin?
Answer:
Area = 0.00025 m²
Explanation:
Given the following data;
Pressure = 400N/m²
Force = 0.1N
To find the area of the coin;
Pressure = Force/area
Area = Force/pressure
Substituting into the equation, we have;
Area = 0.1/400
Area = 0.00025 m²
Which statement best describes what occurs when a warm front occurs?
A)Snow showers occur, followed by colder weather.
B)The weather doesn't change.
C)Rain and showers occur, followed by warmer weather.
D)Cloudy, cold weather occurs.
PHYSICS physics help me pls!
the question is not clear for me the mass of the word and the pivot the artist as the counterweight of the end we calculate the mass of the counterweight sorry
Answer:
calculate mass of the counterweight?
Explanation:
Which two statements are true about the wave shown?
A. The wave could be transmitting light. B. The wave is a transverse wave.
C. The wave is a mechanical wave.
D. The wave could be transmitting sound.
Answer:
c and d
Explanation:
The wave shown in the figure is Sound waves. The sound wave is a mechanical wave. Hence, options C and D are correct.
What are sound waves?Sound is traveled by means of vibrations of particles in the medium. Sound waves require a medium to propagate. The energy propagation by means of adiabatic loading and unloading is called sound or acoustic waves.
The sound waves produce compression and rarefaction in the air. The sound waves are called Longitudinal waves because the direction of propagation is parallel to the vibration of particles.
Sound waves are considered only as waves because they exhibit a wave nature. Light has both properties of wave and particle. Light is an electromagnetic wave and it is transverse in nature.
The sound waves require a medium like air, water, solids, etc for propagation. Hence it is called Mechanical waves. Light waves do not require a medium to propagate. From the given wave pattern, it exhibits the property of sound waves.
Hence, the correct option is C) the wave is a mechanical wave, and D) the wave could be transmitting sound.
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A plant fertilized by another plant is called __________. *
Answer:
pollination
Explanation:
it involves the transfer of a fertilized plant to another
Answer:
pollination
Explanation:
plants can't really do much without bees keep in mind
If you walk up a set of steps empty handed and walk up the same set of steps holding a flower pot in thesame amount of time. Which requires more work?
a.) empty handed b.) holding flower pot c.) same
Explanation:
I think holding a flower pot. more energy will be needed
how could you use Newton's Second Law to study forces?
Answer:
F = ma or force is equal to mass times acceleration.
Explanation:
A wave has a period of 2 seconds and a wavelength of 4 meters. Calculate its frequency and speed.
Note: Recall that the frequency of a wave equals 1/period & the period of a wave equals 1/frequency.
Answer:
frequency = 0.5 /s
speed = 2m/s
Explanation:
frequency = 1/period = 1/2 = 0.5 /s
speed = frequency × wavelength
= 0.5 × 4 = 2m/s
A solar eclipse may occur when:
A. when the moon is 3rd quarter phase
B. when the moon is full
C. when the moon is at 1st quarter phase
D. when the moon is new
A concave mirror is also known as converging mirror
Answer:
true
Explanation:
they have a reflecting surface that is recessed inward
Find the magnitude of the sum of two vectors; A is 5 km , and B is 7 , when the angle btween them is 120
Answer: 6.24 km
Explanation:
Given
The magnitude of the first vector(say) [tex]\left | a\right |=5\ km[/tex]
the magnitude of the second vector(say) [tex]\left | b\right |=7\ km[/tex]
the angle between them is [tex]120^{\circ}[/tex]
The resultant vector magnitude is given by
[tex]\left | \vec{R}\right |=\sqrt{a^2+b^2+2ab\cos \theta}[/tex]
[tex]\left | \vec{R}\right |=\sqrt{5^2+7^2+2\times 5\times 7\cdot \cos 120^{\circ}}\\\left | \vec{R}\right |=\sqrt{74-35}=\sqrt{39}\\\left | \vec{R}\right |=6.24\ km[/tex]
Was Michael Jean Cazabon a local or regional artist?
Answer:
artist
Explanation:
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
low-friction wheels and as the bullet struck the target, the target with
bullet embedded bullet sped off with a velocity of 6.0 ms.
Calculate the velocity of the bullet just before it hit the stationary
target.
Answer:
306 m/s
Explanation:
Law of conservation of momentum
m1v1 + m2v2 = (m1+m2)vf
m1 is the bullet's mass so it is 0.1 kg
v1 is what we're trying to solve
m2 is the target's mass so it is 5.0 kg
v2 is the targets velocity, and since it was stationary, its velocity is zero
vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s
plugging in, we get
(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)
(0.1)(v1) + 0 = 30.6
(0.1)(v1) = 30.6
v1 = 306 m/s
The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.
What is momentum ?Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.
Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.
then, m1 u1 + m2 u2 = m1 v1 + m2 v2.
Given m1 = 5 kg
m2 = 0.1 kg
The velocity of the combined mass v = 6 m/s.
The momentum of the target is zero since it was stationary.
(0.1 × u1) = (0.1 + 5)6 m/s
(0.1 × u1) = 30.6 m/s
then u1 = 30.6/0.1 = 306 m/s
Therefore, the velocity of the bullet before hitting was 306 m/s.
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