Answer:
The answer is "0.91238 and 744.8"
Explanation:
In this scenario it is easier to take a person to the water-pool than to transport the people in the air, as the person's strength is increased by water upwards:
[tex]f_b \to m \to mg =person \\\\F_B \ in\ air = v\ & air\ g \\\\[/tex]
[tex]=0.076 \times 1.225 \times 9.8 \\\\ =0.91238 \ N\\\\[/tex]
[tex]F_B \ in \ water = v \& water \ g \\\\[/tex]
[tex]=0.076 \times 1000 \times 9.8\\\\= 744.8 \ N\\[/tex]
*PLEASE HELP***
Which of the following technologies uses electromagnetic radiation with the
shortest wavelength?
O A. Wireless communications transmitter
O B. Infrared sensor on a DVD player
C. Microwave industrial drying equipment
O D. Compact fluorescent lightbulb
Answer:
A) wireless communications transmitter
Explanation:
Answer:
Compact fluorescent lightbulb
Explanation:
This is because it has the shortest wavelength
William B. Hartsfield was a man of humble origins who became one of the greatest mayors of Atlanta. He served as mayor for six terms (1937–41, 1942–61), longer than any other person in the city's history. Hartsfield held office during a critical period when the color line separating the races began to change and the city grew . . . to a metropolitan population of one million. He is credited with developing Atlanta into the aviation powerhouse that it is today . . . . . . . On August 30, 1961, the city peacefully integrated its public schools. As a result, Atlanta began to acquire its reputation as "A City Too Busy to Hate."
–New Georgia Encyclopedia
During Hartsfield’s time in office, Atlanta became known as "A City Too Busy to Hate.” What factors supported this nickname? Check all that apply.
The city integrated its schools.
Atlanta became a leader in aviation.
The economy declined.
The population increased to one million.
Many people served as the city mayor.
Answer:
It's A, B, and D
A. The city integrated its school
B. Atlanta became a leader in aviation
D. The population increased to one million
Explanation:
Two rubber bullets (each of the same mass) are fired at the same velocity towards two different blocks of equal mass. One block is made of clay and the bullet gets stuck in it, the clay block bullet begins to move in the direction the bullet was fired. The other block is made of aluminum and the bullet bounces off the block, the aluminum block also begins to move in the direction the bullet was fired. Which block (clay or aluminum) will move with greater velocity after being struck by the bullet
Answer:
Aluminum board will move with a higher velocity
Explanation:
The velocity of the block will be higher when the impulse imparted by the bullet is higher.
In case of bullet bouncing off, the impulse imparted on the aluminum board is high and hence, it will move with a high velocity as compared to that of the clay board.
The scanning process and magnetic lenses used in a scanning electron microscope often results in fair to poor resolution and "fuzzy" images.
(A)True
(B)False
Answer:
(B)False is the answer.
Explanation:
Not only did Skid get shot out of a cannon when he was a clown in the circus, but he was also launched into the air by a vertically compressed spring. Skid of 55 kg is standing on a massless platform attached to a spring of constant 8700 N/m that is compressed 125 cm. Skid is launched from rest. He eventually leaves the platform and reaches a peak high above the platform. (a) What is the velocity of Skid when he leaves the platform
Answer:
v = 16.11 m / s
Explanation:
For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation
starting point. When the spring is compressed
Em₀ = K_e + U = ½ k x² + m g x ’
final point. The point where it leaves the platform
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
½ k x² + m g x ’= ½ m v²
v² = [tex]\frac{k}{m}[/tex] x² + g x
let's calculate
v² = [tex]\frac{8700}{55}[/tex] 1.25² + 9.8 1.25
v² = 247.159 + 12.25 = 259.409
v = 16.11 m / s
45 J of work were done on the object that moved 5 meters. How much force was applied to the object?
[tex]\\ \sf\longmapsto Work\:done=Force(Displacement)[/tex]
[tex]\\ \sf\longmapsto Force=\dfrac{Work\:done}{Displacement}[/tex]
[tex]\\ \sf\longmapsto Force=\dfrac{45}{5}[/tex]
[tex]\\ \sf\longmapsto Force=9N[/tex]
Given values:
Work done,
W = 45 JDisplacement,
d = 5 mWe know that,
→ [tex]Work \ done = Force\times Displacement[/tex]
or,
→ [tex]Force = \frac{Work \ done}{Displacement}[/tex]
By putting the values, we get
[tex]= \frac{45}{5}[/tex]
[tex]= 9 \ N[/tex]
Thus the response above is right.
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Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to
A.
first law
B.
second law
C.
third law
D.
law of gravity
Answer:
B . Second law
Explanation:
According to second law:
Net Force acting on the body produce acceleration. The magnitude acceleration of the body is directly proportional to net force and inversly proportional to the mass.
Mathematically:
a = [tex]\frac{F}{m}[/tex]
and
F = ma
So according to the given condition Waldo should use Second law.
You are designing a solenoid to produce a 2.0-kG magnetic field. You wish to wrap your insulated wire uniformly around a cardboard tube that is 8.0 cm in diameter and 58 cm in length, and you have a power supply that will allow you to pass a current of 2.5 A through the solenoid. Determine the total length of wire you will need in order to build the solenoid you have designed.
Answer:
92.7 km
Explanation:
Since the magnetic field due to a solenoid is given by B = μ₀Ni/L where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid, L = length of cardboard tube = 58 cm = 0.58 m, , i = current in wire = 2.5 A and l = length of wire.
So, N = BL/μ₀i
Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T
So, substituting the variables into the equation, we have
N = BL/μ₀i
N = 0.2 T × 0.58 m/(4π × 10⁻⁷ H/m × 2.5 A)
N = 1.16 Tm/(31.416 × 10⁻⁷ HA/m)
N = 0.0369 × 10⁷ turns
N = 0.0369 × 10⁷ turns
N = 3.69 × 10⁵ turns
length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m
So, l = NC
= NπD
= πND
= π × 3.69 × 10⁵ turns × 0.08 m
= 0.9274 × 10⁵ m = 9.274 × 10⁴ m
= 92.74 × 10³ m
= 92.74 km
≅ 92.7 km
The total legnth of the wire to built a solenoid will be 92.7 km
What is solenoid?A solenoid is a electromagnet in which the wires are wounded on the outer surface of the soft iron and then the current is passed so due to flow of the current the magnetic field generated around the wire.
Since the magnetic field due to a solenoid is given by
B = μ₀Ni/L
where
μ₀ = permeability of free space = 4π × 10⁻⁷ H/m,
N = number of turns of solenoid,
L = length of cardboard tube = 58 cm = 0.58 m, ,
i = current in wire = 2.5 A and
l = length of wire.
Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T
So, substituting the variables into the equation, we have
[tex]N=\dfrac{BL}{\mu_oI}[/tex]
[tex]N=\dfrac{0.2\times 0.58}{4\pi\times 10^{-7} \times 2.5}[/tex]
[tex]N=\dfrac{1.16}{31.416\times 10^{-7}}[/tex]
N = 0.0369 × 10⁷ turns
N = 0.0369 × 10⁷ turns
N = 3.69 × 10⁵ turns
length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m
So, l = NC
= NπD
= πND
= π × 3.69 × 10⁵ turns × 0.08 m
= 0.9274 × 10⁵ m = 9.274 × 10⁴ m
= 92.74 × 10³ m
= 92.74 km
≅ 92.7 km
Hence the total legnth of the wire to built a solenoid will be 92.7 km
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Black holes result from
Answer:
supernova explosion or death of massive star
Explanation:
"Most black holes form from the remnants of a large star that dies in a supernova explosion."
A man stands by a railway track.
A train travelling at 40 m/s takes 2.0 s to pass the man.
What is the length of the train?
40 m
D
80m
A 20m
B 38 m
Answer:
length of train is 80m
Explanation:
40*2
Acceleration is rate of change of
A-Position
B-Time
C-Velocity
D-Speed
What do the different colors of stars tell us?
A. The size of the stars
B. The shape of the stars
C. The temperatures of the stars
Answer:
It would Be C The temperatures of the stars
Explanation:
An astronaut brings a cube from the Earth to the Moon.
What is true about the inertial mass and weight of the cube?
Note that the gravitational acceleration on the Moon is about 1.6m/s^2
A) The inertial mass increases but the weight decreases.
B) Both the inertial mass and weight decrease.
C) The inertial mass decreases but the weight increases.
D) The inertial mass remains constant but the weight decreases.
Answer:
Answer D. Inertial mass constant, weight decreases.
Explanation:
Khan Academy
A heat pump with a COP of 3.0 is used to heat air contained in a 1205.4 m3 of well-insulated, rigid tank. Initially the pressure and the temperature inside the gas tank are 100 kPa and 7 oC, respectively. When running, the heat pump consumes 5 kW of electric power. How long does it take for the heat pump to raise the temperature of air in the tank to 22 oC
Answer:
ffff
Explanation:
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A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.55 m/s to the right relative to the plank.
Required:
What is the velocity of the plank relative to the surface of the ice?
Answer:
The speed of the plank relative to the ice is:
[tex]v_{p}=-0.33\: m/s[/tex]
Explanation:
Here we can use momentum conservation. Do not forget it is relative to the ice.
[tex]m_{g}v_{g}+m_{p}v_{p}=0[/tex] (1)
Where:
m(g) is the mass of the girlm(p) is the mass of the plankv(g) is the speed of the girlv(p) is the speed of the plankNow, as we have relative velocities, we have:
[tex]v_{g/b}=v_{g}-v_{p}=1.55 \: m/s[/tex] (2)
v(g/b) is the speed of the girl relative to the plank
Solving the system of equations (1) and (2)
[tex]45v_{g}+168v_{p}=0[/tex]
[tex]v_{g}-v_{p}=1.55[/tex]
[tex]v_{p}=-0.33\: m/s[/tex]
I hope it helps you!
The brightness of a star depends on what
two things?
A. age and color
B. temperature and age
C. size and age
D. size and temperature
180 N
40 kg
140 N
Net Force =
Also how do you find the net force?
Answer:
720N
Explanation:
180+(40×10)+140=720 remember we can only add with same units ;1kg=10N therefore 40 kg=(40×10)N=400N
The net force would be the summation of all the forces in addition to the weight force of the 40 kg weight, thus the net force of all the forces would come out to be 712.4 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
F = ma
As given in the problem we have to find the net force,
Let us assume the acceleration due to gravity would be 9.81 m/s².
The force generated by the 40-kilogram weight =40 ×9.81 Newtons.
The force generated by the 40-kilogram weight = 392.4 Newtons
Net force = 180 + 140 +392.4
=712.4 Newtons
Thus, the net force of all the forces would come out to be 712.4 Newtons.
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B. Exercises
Exercise 1
Direction: identfy the plumbing symbols in each item Write your answer on the space
provided before each number
Answer:
please I do not understand that question
Which of the following is an example of charging by friction?
Answer: where is the examples?
Explanation:
The half-life of argon-44 is 12 minutes. Suppose you start with 20 atoms of
argon-44 and wait 12 minutes. How many atoms of argon-44 will be left?
A. 20 atoms
B. 40 atoms
C. 10 atoms
D. 5 atoms
SUBMIT
Answer:
C. 10
Explanation:
The half-life of argon-44 is 12 minutes, 10 atoms of argon-44 will be left. The correct option is C.
A radioactive substance's half-life is the amount of time it takes for half of the atoms in a sample to decay.
The half-life of argon-44 in this situation is 12 minutes. Starting with 20 argon-44 atoms, half of them will have disintegrated within 12 minutes, leaving 10 atoms.
This happens because radioactive decay is an exponential process with a constant rate of decay. Every half-life cuts the number of atoms in half.
So, if we waited another 12 minutes, half of the remaining 10 atoms would decay, leaving us with 5 atoms. This process is repeated, with half of the remaining atoms dying with each half-life.
Thus, the correct option is C.
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PLEASE ANYBODY HELP <3
ANSWER IS = B. 60 KG
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Light with a wavelength of 600 nm shines onto a single slit, and the diffraction pattern is observed on a screen 2.5 m away from the slit. The distance, on the screen, between the dark spots to either side of the central maximum in the pattern is 25 mm. (a) What is the distance between the same dark spots when the screen is moved so it is only 1.5 m from the slit
Answer:
"6.67 mm" is the right solution.
Explanation:
The given values are:
L = 2.5 my = .0125λ = 600 nmAs we know, the equation
⇒ [tex]\frac{y}{L} =\frac{x \lambda}{a}[/tex]
On substituting the values, we get
⇒ [tex]\frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}[/tex]
On applying cross multiplication, we get
⇒ [tex].0125a=2.5 (600\times 10^{-9})[/tex]
⇒ [tex]a=\frac{2.5(600\times 10^{-9})}{.0125}[/tex]
⇒ [tex]=1.2\times 10^{-4} \ m[/tex]
For new distance, we have to put this value of "a" in the above equation,
⇒ [tex]\frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex](1.2\times 10^{-4})y=1.5(600\times 10^{-9})[/tex]
⇒ [tex]y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex]=3.22\times 10^{-3} \ m[/tex]
The total distance will be twice the value of "y", we get
= [tex]6.67\times 10^{-3} \ m[/tex]
or,
= [tex]6.67 \ mm[/tex]
A 1,571 kilogram car travelling at 129 kilometers per hour is driving down a highway. The driver suddenly realizes a large animal is standing stationary on the highway in the way of the car. The driver manages to release their foot off the accelerator peddle, but does not have time to hit the brake peddle. The car strikes the animal which gets stuck to the car hood. Immediately after the collision the car slows to 59 kilometers per hour. Given this information, accident investigators are able to determine the mass of the animal as what
Answer:
[tex]1863.9\ \text{kg}[/tex]
Explanation:
[tex]m_1[/tex] = Mass of car = 1571 kg
[tex]u_1[/tex] = Initial velocity of car = 129 km/h
[tex]u_2[/tex] = Initial velocity of the animal = 0
[tex]v[/tex] = Velocity of combined mass = 59 km/h
[tex]m_2[/tex] = Mass of the animal
As the momentum of the system is conserved we have
[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow \dfrac{m_1u_1+m_2u_2}{v}-m_1=m_2\\\Rightarrow m_2=\dfrac{1571\times 129+0}{59}-1571\\\Rightarrow m_2=1863.9\ \text{kg}[/tex]
The mass of the animal is [tex]1863.9\ \text{kg}[/tex].
Astronomy Question
Who thinks Venus is the hottest planet instead of the lava planet?
say aye or nay
Answer:
AYE
Explanation:
A disk of known radius and rotational inertia can rotate without friction in a horizontal plane around its fixed central axis. The disk has a cord of negligible mass wrapped around its edge. The disk is initially at rest, and the cord can be pulled to make the disk rotate. Which of the following procedures would best determine the relationship between applied torque and the resulting change in angular momentum of the disk?
a. Pulling on the cord, exerting a force of 15 N for 2 s and then 25 N for 3 s, and measuring the final angular velocity of the disk
b. For five forces of different time intervals, pulling on the cord for 5 s, exerting a force of 15 N, and then measuring the angle through which the disk rotates in each case
c. For five forces of different time intervals, pulling on the cord for 5 s, exerting a force of 15 N, and then measuring the final angular velocity of the disk
d. For five forces of different magnitude, pulling on the cord for 5 s, and then measuring the final angular velocity of the disk
Pulling on the cord, exerting a force of 15 N for 2 s and then 25 N for 3 s, and measuring the final angular velocity of the disk.
What is torque?Torque is defined as the rate of change of angular momentum.[tex]\tau = \frac{dL}{dt} \\\\[/tex]
[tex]Fr = \frac{\Delta L}{\Delta t} \\\\Fr = \frac{\Delta m\omega ^2r}{\Delta t} \\\\F = \frac{\Delta m\omega ^2}{\Delta t}[/tex]
[tex]F = \frac{m\Delta \omega ^2}{\Delta t} \\\\F = \frac{m(\omega _f^2 - \omega _i^2)}{t_2 - t_1}[/tex]
where;
[tex]\omega _i[/tex] is the initial angular velocity
[tex]\omega _f[/tex] is the final angular velocity
Since the disk is initial at rest, applying a force such as 15 N gives the disk its first angular velocity and applying 25 N force for 3 seconds gives the disk its final angular velocity.
Thus, the best procedure to determine the relationship between applied torque and the resulting change in angular momentum of the disk is
Pulling on the cord, exerting a force of 15 N for 2 s and then 25 N for 3 s, and measuring the final angular velocity of the disk.Learn more about torque on a disk here: https://brainly.com/question/25482609
what is Muscular system
what happens to the work done when a force is doubled and the distance moved remain the same?
Answer:
It is doubled
Explanation:
f2=2f1
x1=x2=x
W1=f1*x1=f1*x
W2=f2*x2=f2*x=2*(fi*x)=2*W1
3. A ball thrown vertically upward returns to its starting point in 4s. Find its initial speed. [4]
Answer:
9.8 ×4 equal 39.2 m/s This is v intial
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How long must a 400 W electrical engine work in order to produce 300 kJ of work?
The watt is a rate, similar to something like speed (miles per hour) and other time-interval related measurements.
Specifically, watt means Joules per Second. We are given that the electrical engine has 400 watts, meaning it can make 400 joules per second. If we need 300 kJ, or 3000 Joules, then we can write an equation to solve the time it would take to reach this amount of joules:
w * t = E
w: Watts
t: Time
E: Energy required
(Watts times time is equal to the energy required)
Input our values:
400 * t = 3000
(We need to write 3000 joules instead of 300 kilojoules, since Watts is in joules per second. It's important to make sure your units are consistent in your equations)
Divide both sides by 400 to isolate t:
[tex]\frac{400t}{400}[/tex] = [tex]\frac{3000}{400}[/tex]
t = 7.5 (s)
It will take 7.5 seconds for the 400 W engine to produce 300 kJ of work.
If you have any questions on how I got to the answer, just ask!
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The 400 W electrical engine must work for 12 minute 30 second in order to produce 300 kJ of work.
What is power?The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power of the electrical engine = 400 Watt.
Work done by the electrical energy = 300 kJ
= 300 × 1000 Joule
= 300000 Joule.
Now from the definition of power:
Power = Work done/time interval
Hence, required time interval = work done/ power
= 300000 Joule/400 watt
= 750 second
= 12 minute 30 second.
Hence, a 400 W electrical engine must work for 12 minute 30 second in order to produce 300 kJ of work.
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A baseball was thrown off of a 35 meter high building. It lands 50 meters from the base of the building.
Wonderful.
Look out below !
Was the FAA notified ?