Write a polynomial equation for a graph that passes through the point (-1, 60) and has three x-intercepts: (-4,0),
(1, 0), and (3, 0)

Given:

A graph of a polynomial passes through the point (-1, 60) and has three x-intercepts: (-4,0), (1, 0), and (3, 0).

To find:

The equation of the polynomial.

Solution:

A polynomial is defined as:

[tex]P(x)=a(x-c_1)(x-c_2)...(x-c_n)[/tex]

Where, a is a constant and [tex]c_1,c_2,...,c_n[/tex] are the zeros of the polynomial.

The given polynomial has three x-intercepts (-4,0), (1, 0), and (3, 0). It means [tex]-4,1,3[/tex] are the zeroes of the given polynomial and [tex](x+4),(x-1),(x-3)[/tex] are the factors of the given polynomial.

So, the equation of the polynomial is:

[tex]P(x)=a(x+4)(x-1)(x-3)[/tex]           ...(i)

It passes through the point [tex](-1,60)[/tex].

[tex]60=a(-1+4)(-1-1)(-1-3)[/tex]

[tex]60=a(3)(-2)(-4)[/tex]

[tex]60=24a[/tex]

Divide both sides by 24.

[tex]\dfrac{60}{24}=a[/tex]

[tex]2.5=a[/tex]

Putting [tex]a=2.5[/tex] in (i), we get

[tex]P(x)=2.5(x+4)(x-1)(x-3)[/tex]  

Therefore, the equation of the given polynomial is [tex]P(x)=2.5(x+4)(x-1)(x-3)[/tex].

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