William B. Hartsfield was a man of humble origins who became one of the greatest mayors of Atlanta. He served as mayor for six terms (1937–41, 1942–61), longer than any other person in the city's history. Hartsfield held office during a critical period when the color line separating the races began to change and the city grew . . . to a metropolitan population of one million. He is credited with developing Atlanta into the aviation powerhouse that it is today . . . . . . . On August 30, 1961, the city peacefully integrated its public schools. As a result, Atlanta began to acquire its reputation as "A City Too Busy to Hate."

–New Georgia Encyclopedia

During Hartsfield’s time in office, Atlanta became known as "A City Too Busy to Hate.” What factors supported this nickname? Check all that apply.

The city integrated its schools.
Atlanta became a leader in aviation.
The economy declined.
The population increased to one million.
Many people served as the city mayor.

Answers

Answer 1
so basically the first answer would be correct, i hope i could help.
Answer 2

Answer:

It's A, B, and D

A. The city integrated its school

B. Atlanta became a leader in aviation

D. The population increased to one million

Explanation:


Related Questions

B. Exercises
Exercise 1
Direction: identfy the plumbing symbols in each item Write your answer on the space
provided before each number​

Answers

Answer:

please I do not understand that question

A player kicks a football from ground level with an initial velocity of 27.0 m/s, 30.0° above the Horizontal. Find the distance the ball travels before it hits the ground.

Answers

Answer:

The horizontal distance traveled by the ball before it hits the ground is 64.42 m.

Explanation:

Given;

initial velocity, u = 27.0 m/s

angle of projection, θ = 30⁰

The horizontal distance traveled by the ball before it hits the ground is known as Range;

[tex]Range = \frac{u^2 sin(2\theta)}{g} \\\\Range = \frac{(27^2)sin(2 \times 30)}{9.8} \\\\Range = 64.42 \ m[/tex]

Therefore, the horizontal distance traveled by the ball before it hits the ground is 64.42 m.

What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)

Answers

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

Light with a wavelength of 600 nm shines onto a single slit, and the diffraction pattern is observed on a screen 2.5 m away from the slit. The distance, on the screen, between the dark spots to either side of the central maximum in the pattern is 25 mm. (a) What is the distance between the same dark spots when the screen is moved so it is only 1.5 m from the slit

Answers

Answer:

"6.67 mm" is the right solution.

Explanation:

The given values are:

L = 2.5 my = .0125λ = 600 nm

As we know, the equation

⇒  [tex]\frac{y}{L} =\frac{x \lambda}{a}[/tex]

On substituting the values, we get

⇒  [tex]\frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}[/tex]

On applying cross multiplication, we get

⇒  [tex].0125a=2.5 (600\times 10^{-9})[/tex]

⇒          [tex]a=\frac{2.5(600\times 10^{-9})}{.0125}[/tex]

⇒             [tex]=1.2\times 10^{-4} \ m[/tex]

For new distance, we have to put this value of "a" in the above equation,

⇒  [tex]\frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]

⇒  [tex](1.2\times 10^{-4})y=1.5(600\times 10^{-9})[/tex]

⇒                     [tex]y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]

⇒                        [tex]=3.22\times 10^{-3} \ m[/tex]

The total distance will be twice the value of "y", we get

=  [tex]6.67\times 10^{-3} \ m[/tex]

or,

=  [tex]6.67 \ mm[/tex]

Calculate the equivalent resistance for each of the following circuits.

Answers

Answer:

5. 60 Ω

6. 60 Ω

7. 10 Ω

8. 0.625 KΩ

Explanation:

5. Determination of the equivalent resistance.

Resistor 1 (R₁) = 10 Ω

Resistor 2 (R₂) = 20 Ω

Resistor 3 (R₃) = 30 Ω

Equivalent Resistance (R) =?

Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:

R = R₁ + R₂ + R₃

R = 10 + 20 + 30

R = 60 Ω

Thus, the equivalent resistance is 60 Ω

6. Determination of the equivalent resistance.

Resistor 1 (R₁) = 10 Ω

Resistor 2 (R₂) = 35 Ω

Resistor 3 (R₃) = 15 Ω

Equivalent Resistance (R) =?

Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:

R = R₁ + R₂ + R₃

R = 10 + 35 + 15

R = 60 Ω

Thus, the equivalent resistance is 60 Ω

7. Determination of the equivalent resistance.

Resistor 1 (R₁) = 6 Ω

Resistor 2 (R₂) = 4 Ω

Equivalent Resistance (R) =?

Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:

R = R₁ + R₂

R = 6 + 4

R = 10 Ω

Thus, the equivalent resistance is 10 Ω

8. Determination of the equivalent resistance.

Resistor 1 (R₁) = 10 KΩ

Resistor 2 (R₂) = 2 KΩ

Resistor 3 (R₃) = 1 KΩ

Equivalent Resistance (R) =?

Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/10 + 1/2 + 1/1

Find the least common multiple (lcm) of 10, 2 and 1. The result is 10. Divide 10 by each of the denominator and multiply the result obtained by the numerator. This is illustrated below:

1/R = (1 + 5 + 10) / 10

1/R = 16/10

Invert

R = 10/16

R = 0.625 KΩ

Thus, the equivalent resistance is 0.625 KΩ.

A man stands by a railway track.
A train travelling at 40 m/s takes 2.0 s to pass the man.
What is the length of the train?
40 m
D
80m
A 20m
B 38 m

Answers

Answer:

length of train is 80m

Explanation:

40*2

Which of the following is an example of charging by friction?

Answers

Answer: where is the examples?

Explanation:

Please upload a photo

Two long current-carrying wires run parallel to each other and are separated by a distance of 5.00 cm. If the current in one wire is 1.65 A and the current in the other wire is 3.25 A running in the opposite direction, determine the magnitude and direction of the force per unit length the wires exert on each other.

Answers

Answer:

The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.

Explanation:

Given;

distance between the parallel wires, r = 5.0 cm = 0.05 m

current in the first wire, I₁ = 1.65 A

current in the second wire, I₂ = 3.25 A

The magnitude of the force per unit length between the two wires is calculated as follows;

[tex]\frac{F}{l} =\frac{\mu_0 I_1 I_2}{2\pi r} \\\\\frac{F}{l} =\frac{4\pi \times 10^{-7} \times 1.65 \times 3.25}{2\pi \times 0.05} \\\\\frac{F}{l} = 2.145 \times 10^{-5} \ N/m[/tex]

Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.

A negatively charged rod briefly touches a neutral metal ball. The metal ball will now be ____________

Answers

Answer:

let say it will be positive



The vector matrix [6 -2] is rotated at different angles. Match the angles of rotation with the vector matrices they produce.

Answers

Answer:

Hello your question is incomplete hence I will give you a general answer as regards rotation of vector matrix assuming angle of rotation  = [tex]\frac{\pi }{4}[/tex]

answer :

angle of rotation = [tex]\frac{\pi }{4}[/tex]

vector matrix produced = attached below

Explanation:

lets assume the vector matrix [ 6, -2 ] is rotated clockwise by an angle of [tex]\frac{\pi }{4}[/tex]

The resultant matrix = attached below

Result of the rotation =  attached below

attached below is the detailed solution

Answer: I got it right on Edmentum

Explanation: Answers attached below

The half-life of argon-44 is 12 minutes. Suppose you start with 20 atoms of
argon-44 and wait 12 minutes. How many atoms of argon-44 will be left?
A. 20 atoms
B. 40 atoms
C. 10 atoms
D. 5 atoms
SUBMIT

Answers

Answer:

C.  10

Explanation:

The half-life of argon-44 is 12 minutes, 10 atoms of argon-44 will be left. The correct option is C.

A radioactive substance's half-life is the amount of time it takes for half of the atoms in a sample to decay.

The half-life of argon-44 in this situation is 12 minutes. Starting with 20 argon-44 atoms, half of them will have disintegrated within 12 minutes, leaving 10 atoms.

This happens because radioactive decay is an exponential process with a constant rate of decay. Every half-life cuts the number of atoms in half.

So, if we waited another 12 minutes, half of the remaining 10 atoms would decay, leaving us with 5 atoms. This process is repeated, with half of the remaining atoms dying with each half-life.

Thus, the correct option is C.

For more details regarding half-life, visit:

https://brainly.com/question/31666695

#SPJ2

A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.55 m/s to the right relative to the plank.

Required:
What is the velocity of the plank relative to the surface of the ice?

Answers

Answer:

The speed of the plank relative to the ice is:

[tex]v_{p}=-0.33\: m/s[/tex]

Explanation:

Here we can use momentum conservation. Do not forget it is relative to the ice.

[tex]m_{g}v_{g}+m_{p}v_{p}=0[/tex] (1)

Where:

m(g) is the mass of the girlm(p) is the mass of the plankv(g) is the speed of the girlv(p) is the speed of the plank

Now, as we have relative velocities, we have:

[tex]v_{g/b}=v_{g}-v_{p}=1.55 \: m/s[/tex] (2)

v(g/b) is the speed of the girl relative to the plank

Solving the system of equations (1) and (2)

[tex]45v_{g}+168v_{p}=0[/tex]

[tex]v_{g}-v_{p}=1.55[/tex]

[tex]v_{p}=-0.33\: m/s[/tex]

I hope it helps you!      

What do the different colors of stars tell us?
A. The size of the stars
B. The shape of the stars
C. The temperatures of the stars

Answers

Answer:

It would Be C The temperatures of the stars

Explanation:

A piece of irregularly shaped metal weighs 300N in air. When the metal is completely submerged in water, it weighs 232.5N. Find the volume and specific gravity of the metal.

Answers

Answer:

Volume of metal piece = 0.0069 m³ (Approx.)

Explanation:

Given:

Weight of metal in air = 300 N  

Weight of metal in water = 232.5 N

Find:

Volume of metal piece

Specific gravity of metal

Computation:

We know that;

Density of water = 1,000 kg/m³

Buoyant force applied on metal piece = Weight of metal in air - Weight of metal in water

Buoyant force applied on metal piece = 300 N - 232.5 N

Buoyant force applied on metal piece = 67.5 N

Buoyant force = Volume of metal x Density of water x Gravitational force

67.5 = Volume of metal x 1,000 x 9.8

Volume of metal piece = 0.0069 m³ (Approx.)

A star that is one of the coolest,
about 3,200°C, is going to be which
of the following colors?
Resourcos
A. greenish
Help
B. bluish
C. yellowish
D. reddish

Answers

I believe it would be red

Since water is much denser than air, deep-sea divers experience a much higher ambient pressure underwater. Each 10 meters of depth underwater adds another 1 atm to the ambient pressure experienced by the diver. (Note: this is in addition to the 1 atm ambient pressure at the surface of the water!) What pressure, in psi, is experienced by a diver 50.0 meters below the surface of the water

Answers

Answer:

If you are at sea level, each square inch of your surface is subjected to a force of 14.6 pounds. The pressure increases about one atmosphere for every 10 meters of water depth. At a depth of 5,000 meters the pressure will be approximately 500 atmospheres or 500 times greater than the pressure at sea level.

Explanation:

At sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.

What is pressure?

Pressure is defined as the force applied perpendicularly to an object's surface divided by the surface area over which it is applied.

Pressure is the physical amount of force exerted on a particular area.

Pressure can be expressed as

Pressure = Force / area

There are three types  of pressure.

Absolute pressureGauge pressureDifferential pressure

Thus, at sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.

To learn more about pressure, refer to the link below:

https://brainly.com/question/15170210

#SPJ2

How do home computer scanners generally use electromagnetic waves?

O A. They change information received from sound waves into electromagnetic waves.
OB. They gather information from reflected and absorbed waves.
O C. They receive microwaves that are emitted by natural objects.
O D. They use X-rays that penetrate most objects. SUBMIT​

Answers

Answer:

they gather information from reflected and absorbed waves.

Explanation:

Black holes result from

Answers

Answer:

supernova explosion or death of massive star

Explanation:

"Most black holes form from the remnants of a large star that dies in a supernova explosion."

IM BEGGING ILL GIVE BRAINLEST PLEASEEEEEEE HELP ME Distance and amount of charge are factors that determine which of the
following quantities?
A. Electrostatic force
B. Electric potential
C. Electric potential energy
D. All of the above

Answers

Explanation:

Distance and amount of charge are factors that determine which of the

following quantities?

D. All of the above

I've got this question, which option is correct?

Answers

Answer:

option c is the correct one

528 nm light passes through a single slit. the second (m=2) diffraction minimum occurs at an angle of 3.48 degrees. what is the width of the slit

Answers

Answer:

1.74

Explanation:

right on acellus

Answer:

1.74

Explanation:

acellus

In Milgram's experiment:

A. Yale University would not allow the experiment to be done.

B. participants overwhelmingly did not go all the way to 450 volts.

C. the "learner" was working with Milgram.

D. the "teacher" was working with Milgram.

Answers

Answer:

B. The "Learner" was working with Milgram.

Explanation:

just took the test

give brainliest, please. :)

A heat pump with a COP of 3.0 is used to heat air contained in a 1205.4 m3 of well-insulated, rigid tank. Initially the pressure and the temperature inside the gas tank are 100 kPa and 7 oC, respectively. When running, the heat pump consumes 5 kW of electric power. How long does it take for the heat pump to raise the temperature of air in the tank to 22 oC

Answers

Answer:

ffff

Explanation:

ffffff

The brightness of a star depends on what
two things?
A. age and color
B. temperature and age
C. size and age
D. size and temperature

Answers

It’s D size and temperature

Help answer question in licture

Answers

Answer:

D

Explanation:

D is high pitch c is low pitch

Answer:

D creo que esa es la nota mas alta, la segumda

A baseball was thrown off of a 35 meter high building. It lands 50 meters from the base of the building.

Answers

Wonderful.

Look out below !

Was the FAA notified ?

what happens to the work done when a force is doubled and the distance moved remain the same?​

Answers

Answer:

It is doubled

Explanation:

f2=2f1

x1=x2=x

W1=f1*x1=f1*x

W2=f2*x2=f2*x=2*(fi*x)=2*W1

An auto, moving too fast on a horizontal stretch of mountain road, slides off the road,
falling into deep snow 43.9 m below the road and 87.7 m beyond the edge of the road. What was the acceleration 10m below the edge of the road?

Answers

Answer:

acceleration = - 9.8 m/s²

Explanation:

From the question, we can deduce that the only force that will be acting on the car is gravity and as such the acceleration during free fall will be equal to the acceleration due to gravity but will be negative since it is towards the ground.

Thus, acceleration = - 9.8 m/s²


3. A ball thrown vertically upward returns to its starting point in 4s. Find its initial speed. [4]

Answers

Answer:

9.8 ×4 equal 39.2 m/s This is v intial

Finding Dimensional Formula For x=vt+1/2at is​

Answers

Answer:

In the picture above.

Explanation:

I hope that it's a correct answer for dimensional analysis.

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