Which of these show a set of equivalent expressions ? select all that apply

Answer:

375in^2

Step-by-step explanation:

area of a trapezoid is base + base divded by 2 then times that by the height

20 + 30 = 50

50/2 + 25

25 x 15 = 375

Answer:

I believe one flash drive would cost $16.50.

Step-by-step explanation:

55=2x+22

-22       -22

33=2x

/2    /2

16.50=x

Hope this helps! Have an Amazing day!!

Step-by-step explanation:

i think it means that when negative tow crosses the equal sign, as in a calculation,it becomes positive

eg. -2 +z=0

z =2

Answer:

Negative two is equal to negative two

Step-by-step explanation:

Kinda confused as to why you do not understand that expression...

Answer:

It’s the third option

Step-by-step explanation:

Cuz 4^2 - 2^2 equals the third option

Answer:

3

Step-by-step explanation:

Answer:

60 dollars a week.

Step-by-step explanation:

Just take 15 percent of 400, then you get your answer

Answer:

D: all real numbers,  R: y ≤ -4

Step-by-step explanation:

R: y ≤ -4

Because the line doesn't go beyond -4.  

Answer:

21.c

22.b

23.c

Step-by-step explanation:

Answer:

The angle between the two vectors

∝ = 64°

Step-by-step explanation:

Step(i):-

Given that the vectors

                           [tex]a^{-} = i^{-} - 2j^{-} +5k^{-}[/tex]

          and

                         [tex]b^{-} = 3i^{-} +j^{-} -2k^{-}[/tex]

[tex](a^{-} . b^{-} ) = (i^{-} - 2j^{-} +5k^{-} ) . (3 i^{-} + j^{-} - 2k^{-} )[/tex]

           =  3 (i⁻ . i⁻) - 2(j⁻.j⁻) -10(k⁻.k⁻)

          = 3 - 2 -10

          = -9

Step(ii):-

Let '∝' be the angle between the two vectors

                    [tex]cos\alpha = \frac{a^{-}.b^{-} }{|a||b|}[/tex]

                  [tex]cos\alpha = \frac{|-9| }{\sqrt{1+4+25}\sqrt{9+1+4} }[/tex]

                 [tex]cos\alpha = \frac{|-9| }{\sqrt{30}\sqrt{14} }[/tex]

               [tex]\alpha =cos^{-1} ( \frac{|-9| }{\sqrt{30}\sqrt{14} })[/tex]

              ∝ = cos⁻¹(0.4392) = 63.947

Final answer:-

The angle between the two vectors

               ∝ = cos⁻¹(0.4392) = 63.947

                ∝ = 64°

There is an association because the value 0.15 is not similar to the value 0.55

For the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.

The conditions that satisfy whether there exists an association between conditional relative frequencies are:

1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.

2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.

For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45

We can conclude that there is an association because the value 0.15 is not similar to the value 0.55

Answer:

B

Step-by-step explanation:

9514 1404 393

Answer:

  68°

Step-by-step explanation:

Chords of the same length subtend arcs of the same measure.

  Chord EF = Chord FG . . . . given

  Arc EF = Arc FG = 68°

Answer:

false

Step-by-step explanation:

I say false because the multiplicative inverse of 0 is undefined and the multiplicative inverse tells us that when you multiply a number by its inverse the product will be1 think the multiplicative inverse of 0 is undefined.

Answer:

The maximum height of the ball is 380.25 feet in the air.

Step-by-step explanation:

The quadratic function:

[tex]h(t)=-16t^2+132t+108[/tex]

Models the ball's height h(t), in feet, above the ground t seconds after it was thrown.

We want to determine the maximum height of the ball.

Note that this is a quadratic function. Therefore, the maximum or minimum value will always occur at its vertex point.

Since our leading coefficient is leading, we have a maximum point. So to find the maximum height, we will find the vertex. The vertex of a quadratic equation is given by:

[tex]\displaystyle \left(-\frac{b}{2a},f\left(\frac{b}{2a}\right)\right)[/tex]

In this case, a = -16, b = 132, and c = 108. Find the t-coordinate of the vertex:

[tex]\displaystyle t=-\frac{132}{2(-16)}=-\frac{132}{-32}=\frac{33}{8}=4.125[/tex]

So, the maximum height occurs after 4.125 seconds of the ball being thrown.

To find the maximum height, substitute this value back into the equation. Thus:

[tex]h(4.125)=-16(4.125)^2+132(4.125)+108=380.25\text{ feet}[/tex]

The maximum height of the ball is 380.25 feet in the air.

Answer:

the greatest common factor is 3

Answer:

C :D

Step-by-step explanation:

Answer:

3 3/4 cubic inches

Step-by-step explanation:

2 1/2 × 1 1/2 × 1= 3 3/4

[tex]l*w*h=v[/tex]

Answer:

1. x+y=20,000

2. 105x+75y=$1,740,000

Step-by-step explanation:

let x be the stage level seats and y be the higher level seats.

Answer:

They donated 6%.

Step-by-step explanation:

The total sales were $9800.

The amount donated is $588.

We want to know what percent of 9800 is 588.

Let's make an equation.

what percent of 9800 is 588

x/100 • 9800 = 588

Divide by 9800.

x/100 = 0.06

Multiply by 100.

x = 6

They donated 6%.

Hope this helps!

The interest added at the end of the year is $10, The total goal of O’Neill Raiders fundraiser is $2500 and Sameer scored better than 507 students.

Percentage is the parts of a number per fraction of 100. We can divide a number with it's whole and then multiply with 100 to calculate the percentage of any number.

Initial amount, P = $250

Rate of interest, r = 4% = 0.04

Interest amount = P × r × t, where t is the number of years = 1 here.

                          = 250 × 0.04 × 1

                          = $10

28% of the total fundraising goal = $700

Let x be the total fundraising goal.

28% × x = 700

0.28x = 700

x = 700 / 0.28 = $2500

Total number of students = 650

Sameer scored better than 78% of all students.

Number of students that Sameer scored better = 78% × 650

                                                                               = 0.78 × 650

                                                                               = 507

Hence all the answers are found.

Learn more about Percentage here :

https://brainly.com/question/626448

#SPJ2

Answer:

Step-by-step explanation:

Fraction:

0.8 = 8/10 = 4/5

Percent:

0.8*100 = 80%

Answer:

0.8 can be written as

8/10 and

Percentage = 8/10 × 100

Percentage = 8 × 10

Percentage = 80%

Or,

Simply

Percentage = 0.8 × 100

Percentage = 80%

[tex] \\ [/tex]

Answer:

a = 1.4 and d = 6.9

Step-by-step explanation:

To get the value of d and a, we will use the SOH CAH TOA identity

For the first tringle;

Opposite = d ((opposite angle 60 degrees)

Adjacent = 4

Tan theta = opp/adj

Tan 60 = d/4

d  = 4tan60

d = 4(1.732)

d = 6.9

For the second triangle;

Opposite = a

Hypotenuse = 2

Since sin theta = opp/hyp

Sin45 = a/2

a = 2sin45

a = 2(0.7071)

a = 1.4

Hence a = 1.4 and d = 6.9

A. Angle E = 113°

B. x = 16°

Number A

92 + 70 + 85 + ? = 360

162 + 85 + ? = 360

247 + ? = 360

? = 360 - 247

? = 113°

Number B

108 + 84 + ( x + 30 ) + ( 2x + 18 ) = 360

(180 + 84 + 30 + 18) + (x + 2x) = 360

312 + 3x = 360

3x = 360 - 312

3x = 48

x = 48/3

x = 16°

#LearnWithBrainly

[tex] \boxed{(6, -3)} [/tex]

Step-by-step explanation:

Given the ratio 5:3

and Points A and B where A is located at (-6, 3), and B is located at (26, -13).

Let point A be [tex] (x_{1}, y_{1}) [/tex], and let point B be [tex] (x_{2}, y_{2}) [/tex].

(-6, 3) → [tex] (x_{1}, y_{1}) [/tex].

(26, -13) → [tex] (x_{2}, y_{2}) [/tex].

Let 5 be n, and 3 be m.

5:3 → n:m

[tex] (\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) [/tex].

To solve, just substitute these variables into the expressions of these coordinates to get the answer.

[tex] (\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) [/tex] →

[tex] (\frac{(5)x_{1} + (3)x_{2}}{(5)+(3)}, \frac{(5)y_{1} + (3)y_{2}}{(5) + (3)}) [/tex] →

[tex] (\frac{(5)(-6)+ (3)(26)}{(5)+(3)}, \frac{(5)(3)+ (3)(-13)}{(5) + (3)}) [/tex] →

[tex] (\frac{-30 + 78}{8}, \frac{15+ -39}{8}) [/tex] →

[tex] (\frac{78 – 30}{8}, \frac{15 – 39}{8}) [/tex] →

[tex] (\frac{48}{8}, \frac{-24}{8}) [/tex]

→

[tex] (\frac{6}{1}, \frac{-3}{1}) [/tex]

→

[tex] (6, -3) [/tex].

Thus the coordinates of B are:

[tex] \boxed{(6, -3)} [/tex]

Answer:

Step-by-step explanation:

AB:BC::5:3

let the coordinates be (x,y)

[tex]x=\frac{nx1+mx2}{m+n} \\=\frac{3(-6)+5(26)}{5+3} \\=\frac{-18+130}{8} \\=\frac{112}{8} \\=14\\y=\frac{ny1+my2}{m+n} \\=\frac{3(3)+5(3)}{5+3} \\=\frac{9+15}{8} \\=\frac{24}{8} \\=3\\[/tex]

coordinates of B are (14,3)

Answer:

C:  (0, 5)

Step-by-step explanation:

The x-coordinates are all the same:  0.  In y = 2x + 5, the 2x term would be zero in all those cases, leaving only the y-intercept (5).  

We conclude that the line would pass through (0, 5), which is the y-intercept.

Answer:

The missing number of chicken nuggets is 5.

Step-by-step explanation:

To find the mean of this data set, we must add every number together, then divide the sum by how many numbers are present.

Like this,

1 + 3 + 0 + 6 = 10

10 / 4 = 2.5

There are 4 present numbers in this data set, and one is missing.

Since the only number divided by 5 that would give you a quotient of 3 is 15, the missing number is 5.

Because,

1 + 3 + 0 + 6 + 5 = 15

15 / 5 = 3

Therefore, 5 is the missing number of the data set.

Answer:

JSJXJX

Step-by-step explanation:

CF<DC<DE<DF<FE

Answer:

 =  1 0

Step-by-step explanation:

Solve

1. Combine like terms

2  +  2 0  + 2  =  6 0

4  +  2 0  =  6 0

2. Subtract  20  from both sides of the equation

4  +  2 0  =  6 0

4  +  2 0  −  2 0  =  6 0  −  2 0

3. Simplify

4  +  2 0  −  2 0 =  6 0  −  2 0

4  =  6 0  −  2 0

4 =  6 0  −  2 0

4  =  4 0

4. Divide both sides of the equation by the same term

4x = 40

4x/4 = 40/4

5. Simplify

4x/4 = 40/4

x = 40/4

x = 40/4

x = 10

Answer:

-4a

Step-by-step explanation:

Answer:

that is$ 160 ok alright jf