Answer:
[tex]\dfrac{dE}{dt} \approx 2.261 \overline {36} \times 10^{12} \ V/ms[/tex]
Explanation:
The parameters given in the question are;
The magnitude of the displacement current density between the plates of a parallel-plate capacitor, J = 19.9 A/m²
We have;
[tex]i_d = \epsilon _0 \times \dfrac{d \Phi_E}{dt} =\epsilon _0 \times A \times \dfrac{d E}{dt}[/tex]
Therefore;
[tex]\therefore \dfrac{dE}{dt} =\dfrac{i_d}{\epsilon _0 \cdot A} =\dfrac{J}{\epsilon_0} = \dfrac{19.9}{8.8 \times 10^{-12}} \approx 2.261 \overline {36} \times 10^{12}[/tex]
Therefore;
[tex]\therefore \dfrac{dE}{dt} \approx 2.261 \overline {36} \times 10^{12} \ V/ms[/tex]
can u get this right?
Water in a tank which is positioned 5 feet above the ground is _____ potential energy? (answers would be like thermal, electric, mechanical)
Answer:
Mechanical
Explanation:
The tank is at rest. And energy of any substance at rest is known as potential energy.
Now, in forms of energy, potential energy is a type of mechanical energy.
Thus, the correct option is mechanical Energy.
in each of the following divide the second number by the first number and find the quotient:3/4,-3/8
Answer:
[tex]\dfrac{-1}{2}[/tex]
Explanation:
We need to divide the second number by the first number and the numbers are 3/4,-3/8.
First number = 3/4
Second number = -3/8
Dividing the second number by the first number.
So,
[tex]\dfrac{\dfrac{-3}{8}}{\dfrac{3}{4}}[/tex]
We know that,
[tex]\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}[/tex]
So,
[tex]\dfrac{\dfrac{-3}{8}}{\dfrac{3}{4}}=\dfrac{-3}{8}\times \dfrac{4}{3}\\\\=\dfrac{-1}{2}[/tex]
So, the answer is (-1/2)
A car is traveling at 120 kilometers per hour with 35,000 joules of kinetic energy on the freeway when it suddenly applies its brakes and comes to a screeching stop. How much of the original 35,000 joules of energy is left?
Answer:
0 J is left (No amount of the original 35000 J energy is left)
Explanation:
From the question
Kinetic Energy (K.E) = 1/2mv²................... Equation 1
Where m = mass of the car, v = velocity of the car.
make m the subject of the equation.
m = 2K.E/v²..................... Equation 2
Given: K.E = 35000 Joules, v = 120 km/h = (120×3600/1000) = 432 m/s
Substitute these values into equation 2
m = (2×35000)/432²
m = 0.375 kg.
If a brake is suddenly apply,
Then, the velocity of the car = 0 m/s.
Therefore,
K.E = 1/2(0.375×0²)
K.E = 0 J.
From the baove analysis, No amount of the original 35000 J energy is left.
the distance and direction between starting and ending positions
Answer:
The length traveled by an object moving in any direction or even changing direction is called distance. The location of an object in a frame of reference is called position. For straight line motion, positions can be shown using a number line. The separation between original and final position is called displacement
Explanation:
good luck
Water raises a boat once every 3.0 seconds. What is the frequency (f) of the waves passing the boat?
3.0 Hz
0.33 Hz
0.1 Hz
334 Hz
Answer:
I think its A
Explanation:
if its every 3 seconds wouldnt it be 3.0 Hz
Step 3: Create your graphs. a) Decide how many graphs you will need to show the energy transformation. b) You should have at least 3 graphs, so that the steps of the transformation will be clear. c) Each graph should be clearly labeled. d) Careful use of color on your graphs will make them easy to read and understand. It's for Edge. Project: Energy Transformation Poster. Thank you!
PLS HELP, WILL GIVE BRAINLIEST
what is the right part of a chemical equation called?
2H2 + O2 ---> 2H2O(what is this part called)
a. chemical equation
b. products
c. reactants
d. yields
Answer:
I'm pretty sure its product.
Explanation:
Hope this helps and have a wonderful day!!!!