Answer:
Hyoid
Explanation:
The hyoid is located in the neck area, not the limbs.
A shot-putter exerts an unbalanced force of 128 N on a shot giving it an acceleration of 19
m/s2. What is the mass of the shot?
Answer:
128 is the ans cuz N is also lnown as mass
Explanation:
128
When light waves hit ice, most of them bounce off and radiate back into space. Because of this, ice is best described as which kind of surface?
Answer:
Reflective surface
Explanation:
Ice is a reflective surface because most the of the light waves that hits on it bounces off.
When a surface is smooth and polish, it acts a reflector. When a surface is jagged and not smooth light does not readily reflect. Reflection is through the incident angle of the light waves.Therefore, snow is a reflective surface.
A 1288.1 kg car is traveling at 24.1 m/s when the driver takes his foot off the gas pedal. It takes 4.4 s for the car to slow down to 20 m/s. How large is the net force slowing the car? Answer in units of N.
Answer:
A 1288.1 kg car is traveling at 24.1 m/s when the driver takes his foot off the gas pedal. It takes 4.4 s for the car to slow down to 20 m/s. How large is the net force slowing the car? Answer in units of N.
Explanation:
The vehicle land-speed record has long been held by rocket cars. These vehicles resemble the high-speed rocket planes that were used in the early days of the space program, but they have heavy metal wheels. On September 5, 1997, the world land-speed record was set by the British-built Thrust SSC rocket car, which had a top recorded speed of 341 m/s. The kinetic energy of the car at this speed is 5.289 × 108 J. What is the car’s mass?
Answer:
9096.93 Kg
Explanation:
The following data were obtained from the question:
Velocity (v) = 341 m/s
Kinetic energy (KE) = 5.289×10⁸J.
Mass (m) =.?
The mass of the car can be obtained as follow:
KE = ½mv²
5.289×10⁸ = ½ × m × 341²
5.289×10⁸ = ½ × m × 116281
5.289×10⁸ = m × 58140.5
Divide both side by 58140.5
m = 5.289×10⁸ / 58140.5
m = 9096.93 Kg
Therefore, the mass of the car is 9096.93 Kg
A car accelerates from rest to a certain velocity in a certain time. Assume that there is no friction, and that the engine power is constant. Consider the following scenarios independently. How long would it take to reach double the velocity (also from rest)
Answer:
it will take half of the initial time to reach double the velocity
Explanation:
Given that a car accelerates from rest to a certain velocity in a certain time.
Since the car accelerate from rest, the initial velocity U = 0
Using the first equation of motion,
V = U + at
V = at
Assume that there is no friction, and that the engine power is constant. Consider the following scenarios independently. How long would it take to reach double the velocity (also from rest)
That is V = 2V
Using the same formula ,
2( at ) = at
2T = t
T = t/2
Therefore, it will take half of the initial time to reach double the velocity
A mass of M-kg rests on a frictionless ramp inclined at 30°. A string with a linear mass density of μ=0.025" kg/m" is attached to the M-kg mass. The string passes over a frictionless pulley of negligible mass and is attached to a hanging mass (m). The system is in static equilibrium. A wave is induced on the string and travels up the ramp.
(a) Show that the mass of M is equal to twice the mass of the hanging mass: M = 2m.
(b) and at what wave speed does the wave travel up the string, if m = 5 kg?
Answer:
44.3 m/s
Explanation:
a) Draw a free body diagram of the mass M. There are three forces:
Weight force mg pulling down,
Normal force N pushing perpendicular to the ramp,
and tension force T pulling parallel up the ramp.
Sum of forces in the parallel direction:
∑F = ma
T − Mg sin 30° = 0
T = Mg sin 30°
T = Mg / 2
Draw a free body diagram of the hanging mass m. There are two forces:
Weight force mg pulling down,
and tension force T pulling up.
Sum of forces in the vertical direction:
∑F = ma
T − mg = 0
T = mg
Substitute:
mg = Mg / 2
m = M / 2
M = 2m
b) Velocity of a standing wave in a string is:
v = √(T / μ)
T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N. Therefore:
v = √(49 N / 0.025 kg/m)
v = 44.3 m/s
all the elements are found on earth, where were they formed?
1. in the sun
2. in ancient stars
3. in earths core
4. in the gas cloud that formed earth
Answer:
in the Earths core
Explanation:
Are Stereotyping and prejudice are the same thing true or false
Answer:
Yes it's false for this finish touch
Glucose is a carbohydrate.
True
0r False
Answer: True
Explanation: Glucose is a carbohydrate.
a leaky faucet is dripping at a rate of 1 pint per hour how many hours to fill 10 gallons
Answer:
80 hours :)))))))))))))
In which scenario will the two objects have the greatest gravitational force
between them?
A. Mass of object 1 = 22 kg
Mass of object 2 = 14 kg
Distance between objects = 28 m
B. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 48 m
C. Mass of object 1 = 22 kg
Mass of object 2 = 14 kg
Distance between objects = 48 m
D. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 28 m
Answer: The answer is D
Explanation:
The greater the mass and the less the distance
The two objects that will have the greatest gravitational force between them is:
D. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 28 m
What is Gravitational force?It is an appealing power that exists between all items with mass; an article with mass draws in one more particle with mass; the size of the power is straightforwardly corresponding to the majority of the two articles and contrarily relative to the square of the distance between the two particles.
It is given by:
[tex]F=G*\frac{m_1*m_2}{r^2}[/tex]
So, for the highest value of gravitational force there must be greater mass and lesser distance. So the option that holds good is option D.
Find more information about Gravitational force here:
brainly.com/question/19050897
Using complete sentences and correct punctuation and grammar answer the following question. Must be at least 3 sentences.
Explain why Eclipses do not occur every month.
Answer: A solar eclipse occurs when the moon passes in between the Earth and sun, casting a shadow down on the surface of our planet. If you're in the path of the shadow, the moon destroys the sun. No, wait, I mean the moon blocks the sun briefly.A lunar eclipse happens when the moon passes through the Earth's shadow. We see one limb of the moon darken until the entire thing is in shadow.An eclipse does not occur every month, because one month after an eclipse the relative geometry of the Sun, Moon, and Earth has changed. As seen from the Earth, the time it takes for the Moon to return to a node, the draconic month, is less than the time it takes for the Moon to return to the same ecliptic longitude as the Sun.
Explanation:
Answer:
Because the moon's orbit wobbles up and down with respect to the Earth, the satellite's shadow can be too high or too low to cause a solar eclipse. If the moon partially covers the sun for a given location, that area experiences a partial solar eclipse. But if the moon fully covers the sun, it will cause either a total solar eclipse or an annular solar eclipse; that's when a bright ring of light is still visible in the sky around the dark silhouette of the moon.
A person has a mass of 1000 g and an acceleration of 20 M/S/S what is the force on the person
Answer:
The answer is 20 NExplanation:
The force acting on an object can be found by using the formula
force = mass × accelerationFrom the question
mass = 1000 g = 1 kg
acceleration = 20 m/s²
We have
force = 20 × 1
We have the final answer as
20 NHope this helps you
2. An athlete runs up the stairs of a tall building in 10 s. If she has a mass of 55 KG and the total vertical distance she covers is 8.2 m, what is the average power (in W)developed by her legs?
Answer:
P = 37.0 W (watts)
Explanation:
Using the formula for power :
P = ( kg × m^2/s^2 ) W
given the mass 55kg, the time 10s, and the displacement 8.2m.
55 kg × 8.2^2 / 10^2
55kg × 67.24 / 100
3698.2/100
P = 36.982 ≈ 37.0 W (nearest tenth)
According to the kinetic theory, what happens when the temperature of water
increases?
The water molecules increase their speed.
The water molecules do not change speed.
The water molecules decrease their speed
PLEASE HELP
I need helpppppppppppppppppppppppppppppppppppppppppppppp
Answer:u
Laa c
Explanation:
A force vector has a magnitude of 42 N and is applied at an angle of 108°
above the eastern horizontal.. Determine they component of this force
vector
0 -15 N
O -13 N
39.9 N
35 N
Atoms tend to be stable and nonreactive if they have six valence electrons.
Select one:
O True
O False
Answer:
True
Explanation:
2.9030 has 4 significant digits.
TRUE OR FALSE
Help me out here please!!!
Answer:
I beleive the answer is d
Explanation:
This is beause theball starts going back down because the velocity slows down.
Answer:
d
Explanation:
the velocity changes as it goes down
List 20 examples vector quantities
Answer:
That's all I got.
Explanation:
acceleration
velocity
momentum
force
increase
and decrease in temperature
weight
It takes 25.7 N to push a crate
at a constant speed across flat
ground where uk
= 0.238.
What is the normal force acting
on the crate?
(Unit = N)
Answer:
108 N
Explanation:
Divide the force by uk to get the normal force
(25.7)/(0.238) = 107.98 N = 108 N
Answer:
107
Explanation:
The jogger ran 3km east.
4. Look at the bottom figure. Suppose that a car is 20 km due north of New York City. The car
travels north toward Albany until it is 100 km due north of New York City.
Answer: d
Explanation:
A microwave oven operates at 2.00 GHz . What is the wavelength of the radiation produced by this appliance?
Answer:
Wavelength = 0.15 m
Explanation:
The frequency of a microwave oven is 2.00 GHz or [tex]2\times 10^9\ Hz[/tex].
We need to find the wavelength of the radiation produced by this appliance. We know that the relationship between the frequency and wavelength is given by :
[tex]c=f\lambda[/tex]
Where,
[tex]\lambda[/tex] is the wavelength
So,
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2\times 10^9}\\\\=0.15\ m[/tex]
So, the wavelength of the radiation produced by this appliance is 0.15 m.
My question is on the picture
Answer:
Measure change in temperature after long call
Explanation:
What is the takeoff distance for an airplane on a runway at
300km/hr with acceleration of 1 m/s 2
Answer:
x = 3472 [m]
Explanation:
To solve this problem we must use the following expression of kinematics:
[tex]v_{f}^{2}= v_{i}^{2}+(2*a*x)\\[/tex]
where:
Vi = initial velocity = 0
Vf = final velocity = 300 [km/h]
a = acceleration = 1 [m/s^2]
x = takeoff distance [m]
Note: The initial velocity is equal to zero as avion starts its movement from rest.
Now we have to convert units of kilometers per hour to meters per second, the final velocity.
[tex]300 [\frac{km}{h}]*[\frac{1h}{3600s} ]*\frac{1000m}{1km} \\= 83.33 [\frac{m}{s} ][/tex]
(83.33)^2 = 0 + (2*1*x)
2*x = 6943.88
x = 3472 [m]
Waves do NOT carry.
A)Weight
B)Matter
C)Energy
D)Color
(Choose one)
Explain which planets have seasons and why some planets have none at all.
Discuss which planet has seasons most similar to earth and why.
Discuss additional factors that some planets have that affect their seasons.
What fact about other planet’s seasons most surprised you and what did you find the most interesting? Why?
Answer:
Some planets have seasons some don't bc of the distance from the sun some of them are too cold or too hot to have seasons
What is the formula for speed?
गतत का सूत्र क्या है?
A : Distance covered/Time | तय की गई
दरूी/समय
B : Change in velocity/Time | वेग में
पररवतषन/समय
C : Distance in definite direction /Time |
तनजचचत टदशा में दरूी/समय
D : Change in momentum/Time | संवेग में
पररवतषन/समय
Ans:
A : Distance covered/Time | तय की गई
दरूी/समय
Explanation:
Formula for speed = Distance covered/Time
Therefore,
Option A is correct.
Answer:
a.distance÷timetaken
Explanation:
The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).
A car traveling east in a straight line on a highway decreases its speed from 30. meters per second to 23. meters per second in 2.0 seconds. What is the magnitude of the car's average acceleration to the nearest tenths place, during this time interval?
Answer:
Acceleration = -3.5 m/s²
Explanation:
Given:
Initial velocity u = 30 m/s
final velocity velocity v = 23 m/s
Time t = 2 second
Find:
Acceleration
Computation:
v = u + at
23 = 30 + (a)(2)
-7 = 2 a
a = -7 / 2
a = -3.5 m/s²
Acceleration = -3.5 m/s²