Which is the metric standard for measuring energy?

Answer:

1 MgF2 + 1 Li2CO3 --> 1 MgCO3 + 2 LiF

Explanation:

Answer:  (1.5 M) V1 = (3.40 M) (500mL)

            (multiply 3.40M x 500mL)    V1 = 1700 mL

1700 mL of the 1.5 M NaCl + 1200mL of water.

Explanation:

Answer:

2059.645g Cl

Explanation:

A mole of any element contains 6.022e23 molecules, so we will divide the given amount of molecules by 6.022e23.

3.5e25 / 6.022e23 = 5.81e1

5.81e1 = 58.1 mol Cl

Now that we have found the amount of moles of Chlorine, we will multiply the number of moles by the molar mass of Chlorine, which is 35.45g/mol.

35.45(58.1) = 2059.645g Cl

The answer is 0.015295197308045

We assume you are converting between moles Zinc and gram. You can view more details on each measurement unit: molecular weight of Zinc or grams The molecular formula for Zinc is Zn

Answer:

for the first one we need the previous question to be able to answer it. for the second one density and temperature

Explanation:

Answer:

False

Explanation:

Scientifically, energy can never be created or destroyed. However it can be transfered. This law is called The Law of Conservation of Energy.

Answer:

no it's is false because an electron have negative charges and it is not inside the atom and it is found out side the nucleus

Answer:

13.89% p/p

Explanation:

El porcentaje peso a peso de una solución (%p/p) es definido como cien veces la relación entre la masa del soluto (En este caso, cloruro de calcio) y la masa de la solución. La ecuación es:

%p/p = Masa cloruro de calcio (250g)/ Masa solución * 100

Para hallar la masa de la solución debemos usar el volumen y la densidad de este:

1500mL * (1,2g / mL) = 1800g

Así, el %p/p será:

250g / 1800g * 100

Complete Question:

1. A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calculate the specific heat of aluminum.

a. Compute the percentage of error to the nearest tenth in the student's calculation if the actual specific heat value for aluminum is 0.9 J/g°C

Answer:

Percent error = 55.56 %

Explanation:

Given the following data;

Mass = 140 grams

Initial temperature = 62.2°C

Final temperature = 98.4°C

Quantity of heat = 4817 Joules.

To find the specific heat capacity;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

dt = T2- T1

dt = 98.4 - 62.2

dt = 36.2°C

Making c the subject of formula, we have;

[tex] c = \frac {Q}{mdt} [/tex]

Substituting into the equation, we have;

[tex] c = \frac {4817}{140*36.2} [/tex]

[tex] c = \frac {4817}{5068} [/tex]

Specific heat capacity, = 0.95 J/g°C

b. To find the percentage error;

Given the following data;

Actual specific heat capacity = 0.9 J/g°C

Experimental specific heat capacity = 0.95 J/g°C

Percent error can be defined as a measure of the extent to which an experimental value differs from the theoretical value.

Mathematically, it is given by this expression;

[tex] Percent \; error = \frac {experimental \;value - actual \; value}{ actual \;value} *100[/tex]

Substituting into the formula, we have;

[tex] Percent \; error = \frac {0.95 - 0.9 }{ 0.9} *100[/tex]

[tex] Percent \; error = \frac {0.5}{0.9} *100[/tex]

[tex] Percent \; error = 0.5556 *100[/tex]

Percent error = 55.56 %

Answer:

Kim:

Wendell:

Gonzalo:

Explanation:

did it on Edge.

Answer:

Li⁺(aq) + 2Br⁻(aq) + Pb²⁺(aq) + NO₃⁻(aq) → PbBr₂(s) + NO₃⁻(aq) + Li⁺(aq)

A precipitate forms

Explanation:

To solve this question we must know the general solubility rules:

All group 1A (Li, Na, K...) and NH₄⁺ ions are always soluble.

The nitrates (NO₃⁻) and acetates are always solubles.

Cl⁻, Br⁻ and I⁻ are soluble except in the presence of Ag⁺, Pb²⁺, Cu⁺ and Hg₂²⁺

That means in the mixture of ions that we have, the Br⁻ will react with Pb²⁺ to produce PbBr₂(s):

Answer:

Explanation:

the first and last one

Answer: 1 and 4

A clean renewable source is sustainable

Answer:

7. Ionization energy

8. Lattice energy

9. Free energy

10. Activation energy

Explanation:

I. Ionization energy: The energy required to convert a ground-state atom in the gas phase to a gaseous positive ion. Thus, it is the minimum energy required to remove or detach an electron from a neutral atom in a gaseous state. Generally, atoms with relatively large atomic radii tend to have a low ionization energy.

II. Lattice energy: The energy change that occurs in the conversion of an ionic solid to widely separated gaseous ions. This ultimately implies that, it is the energy generated during the conversion of an ionic solid into gaseous ions and as such is a measure of the cohesive force binding the ions of an ionic compound using the Born-Haber cycle.

III. Free energy: the energy in a chemical or physical change that is available to do useful work. Thus, it is a thermodynamic quantity that measures the maximum capacity of a system to do work at constant temperature and pressure.

IV. Activation energy: The energy required to form the transition state in a chemical reaction. When the activation energy of a reaction is low, the rate of the reaction would be faster. Therefore, an enzyme speeds or catalyzes the rate of a reaction by lowering its activation energy.

I'm hoping the same for my new coaching classes

This is my first time going out to study ngl-

Answer:

A and C

Explanation:

DNA is what makes up you and me and DNA is composed of four bases adenine, guanine, thymine, and cytosine. The others are not true.

Answer:

+1

Explanation:

The oxidation number of Hydrogen atom is +1. As Nitrogen is more electronegative than Carbon, the oxidation number of Nitrogen is - 3. The Net charge on the compound is zero.

(hope that helps)

Answer:

Question 4 is- Solubility

Question 5 is- Suspension

Hopes this helps >:D

Answer:

Input Mask

Explanation:

In this scenario, the best tool for Raul to use would be an Input Mask. When dealing with Microsoft Access or any other database tool, Input Masks are a great way of validating data inputs so that they always match the desired format. In this case, Raul would need to use input mask and apply the desired format while comparing it to the order date, therefore, making sure that it is always a minimum of 2 days after before it is accepted as a valid entry in the database.

Answer: D: sun

Explanation:

Answer:

uhm i believe its D hope i helped

Explanation:

Answer:

D. decomposers

Answer:

The cool people like me XD

Explanation:

Answer:

Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. Their vibration is related to their kinetic energy. In the solid the particles vibrate in place. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart.

Explanation:

Hope this helped Mark BRAINLIEST!!!

Answer:

For A: The molarity is the solution 9.706 M

For B: The molarity of the solution is 10.91 M.

For C: The molarity of the solution is 1.78 M.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.

The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}}{\text{Volume of solution (L)}}[/tex]                 ......(1)

For A:

Number of moles = 3.30 moles

Volume of solution = 0.340 L

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{3.30 mol}{0.340 L}=9.706 mol/L[/tex]

For B:

Number of moles = 6.00 moles

Volume of solution = 550 mL = 0.550 L        (Conversion factor: 1 L = 1000 mL)

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{6.00 mol}{0.550 L}=10.91 mol/L[/tex]

For C:

Number of moles = 0.0160 moles

Volume of solution = 9.00 mL = 0.009 L

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{0.0160 mol}{0.009 L}=1.78 mol/L[/tex]

Answer:

[tex]Q=20.6\frac{J}{g}[/tex]

Explanation:

Hello there!

In this case, according to the equation for the calculation of the heat during a heating process:

[tex]Q=mC(T_f-T_i)[/tex]

It is possible to compute it per gram of ice by just removing m from the equation by dividing at both sides. Next we plug in the given specific heat and the final and initial temperatures to obtain:

[tex]Q=2.06\frac{J}{g\°C}[-15\°C-(-25\°C)] \\\\Q=20.6\frac{J}{g}[/tex]

Best regards!