Answer:
x = 1 and x = 7
Step-by-step explanation:
The given equation is [tex]x^2 - 8x + 7 = 0[/tex].
We need to solve the equation.
It is a quadratic equation whose solution is given by :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
Here, a = 1, b = -8 and c = 7
Put values,
[tex]x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(1)(7)} }{2(1)}\\\\=\dfrac{8\pm \sqrt{64-28}}{2}\\\\=\dfrac{8\pm 6}{2}\\\\=\dfrac{8+6}{2},\dfrac{8-6}{2}\\\\=7,1[/tex]
So, the values of x are x = 1 and x = 7.
Cellular phone service is available for $37 per month for 1847 minutes. What is the monthly cost per minute? Round your answer to the nearest tenth of a cent.
The cost for the phone service is cents per minute.
The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the garden
Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
Hope it helps :)
Answer:
Step-by-step explanation:
Width = w
Length = 2w + 8
Area of rectangular garden = 280 square meter
length * width = 280
(2w + 8 ) *w = 280
2w * w + 8*w = 280
2w² + 8w = 280
2w² + 8w - 280 = 0
Divide the whole equation by 2
w² + 4w - 140 = 0
w² + 14w - 10w - 14 *10 = 0
w(w + 14) - 10(w + 14) = 0
(w + 14)(w - 10)= 0
w - 10 = 0 {Ignore w + 14, as measurements will not be -ve}
w = 10 m
l = 2*10 +8
= 20 +8
l = 28 m
1. Kathy is building a bed for her dollhouse. She used her real bed as a guide for how to
create the dollhouse bed. Her bed is 36 inches wide and 60 inches long. If she wants
to scale this down by 1/10, what would be the dimensions of the dollhouse bed?
Explain how you got your answer.
*Use the term SCALE FACTOR in your explanation.
PLS ANSWER QUICKLY !!!
Find the limit when X approaches zero
2xsinx/1-cosx
Answer:
4
Step-by-step explanation:
[tex] Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}\times \frac{1+\cos x}{1+\cos x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1^2 -\cos^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1 -\cos^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{sin^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2x(1+\cos x) }{sin x} [/tex]
[tex] =Lim_{x \to 0} 2(1+\cos x) \times \frac{1}{Lim_{x \to 0}\frac{sin x}{x}} [/tex]
[tex] =2(1+\cos 0) \times 1 [/tex]
[tex] = 2(1+1) [/tex]
[tex] = 2(2) [/tex]
[tex] \therefore Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}= 4 [/tex]
Determine the equation of a circle with center at (8, 10) and radius is 6
if we use the quadratic expression below to complete a diamond, what value will go at every bottom of the diamond
a. -4
b. 4
c. 1
d. 5
Answer:
if we use the quadratic expression below to complete a diamond, what value will go at every bottom of the diamond
is -4
Answer:
if we use the quadratic expression below to complete a diamond, what value will go at every bottom of the diamond
its 1 because