THIS IS NOT NEEDED FOR ANSWERING JUST TO GET THREE NEEDED QUESTIONS I NEED ANSWERED TODAY OUT INTO BRAINLY... AND ID EXPECT NO LINKS IN THIS OR IN THESE QUESTIONS... BUT I WILL PUT THE THREE QUESTIONS AS PHOTOS IN HERE IF YOU WANT TO ANSWER THEM HERE INSTEAD AS PHOTOS... IF YOU CANT SEE THEM HERE THEN GO INTO THE BRAINLY QUESTION LINKS
other Brainly questions i have today that also need answering:
brainly.com/question/22829066

brainly.com/question/22828757

brainly.com/question/22829297

Ω Entity001 And Project Omega Ω

EXAMPLE OF WHAT NOT TO TRUST BELOW:
Kyuubivi
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Answer: 9.13333333333

3 1/3+ 5 4/5=

Answer#2  1.86666666667

Answer:

a = 9

Step-by-step explanation:

For solve the problem we can use the Pythagorean theorem in this way

a^2 + (3√3)^2 = (6√3)^2

If we solve the equation we have

a^2 + 27 = 108

a^2 = 81

a = +/-9

we take only the the positive value because a length can’t be negative

a = 9

Answer:

X = 3.01

Step-by-step explanation:

To solve for x, you first need to get x by itself. So you would minus 19.95 from both sides. Which would then be

5x = 15.05

Again x is not by itself so you would divide both sides by 5, the eqation would then be

x = 3.01

Which is the answer. If you want you can double check your work by putting the answer back in the eqaution.

5(3.01) + 19.95 = 35

If the statement is true that means you have the right answer

15.05 + 19.95 = 35

35 = 35

We are correct! Hope this helps with your question and how to do others like it.

Answer:

The maximum height of the ball is 380.25 feet in the air.

Step-by-step explanation:

The quadratic function:

[tex]h(t)=-16t^2+132t+108[/tex]

Models the ball's height h(t), in feet, above the ground t seconds after it was thrown.

We want to determine the maximum height of the ball.

Note that this is a quadratic function. Therefore, the maximum or minimum value will always occur at its vertex point.

Since our leading coefficient is leading, we have a maximum point. So to find the maximum height, we will find the vertex. The vertex of a quadratic equation is given by:

[tex]\displaystyle \left(-\frac{b}{2a},f\left(\frac{b}{2a}\right)\right)[/tex]

In this case, a = -16, b = 132, and c = 108. Find the t-coordinate of the vertex:

[tex]\displaystyle t=-\frac{132}{2(-16)}=-\frac{132}{-32}=\frac{33}{8}=4.125[/tex]

So, the maximum height occurs after 4.125 seconds of the ball being thrown.

To find the maximum height, substitute this value back into the equation. Thus:

[tex]h(4.125)=-16(4.125)^2+132(4.125)+108=380.25\text{ feet}[/tex]

The maximum height of the ball is 380.25 feet in the air.

Answer:

ok ok, i think it's the last one

Step-by-step explanation:

Answer:

[tex]2x+3y\geq 60\\x>10[/tex]

Step-by-step explanation:

We know that she will be selling bracelets for $2 each and earrings for $3 each. That means we will have 2x+3y, where x is the number of bracelets she sells and y is the number of earrings she sells. Then we will have [tex]\geq 60[/tex] because she wants to sell at least $60 worth of earrings and bracelets. That means the amount she makes from bracelets and earrings combined has to equal 60 or more, thus we use the greater than or equal to sign.

Now we have [tex]x>10[/tex], where x is still the number of bracelets sold. She said she will sell more than 10, which means we will just have [tex]>10[/tex]. If she said she wanted to sell at least 10, then it would be [tex]\geq10[/tex].

Therefore the system of inequalities is:

[tex]2x+3y\geq60\\x>10[/tex]

Hope this helps!