The unit called horsepower is defined based on the amount of work a horse can do in 1 minute.
What is horsepower?James Watt used the horsepower unit for the first time in 1782. According to the account, James Watt used a pony to charge coal from the mines. According to the narrative, he needed a unit to measure the force of one of these animals.
He discovers that they can move 22.000 lbs per minute and decides to (arbitrarily) boost this metric by 50%. Having been the unit 33.000 lb/ft per minute, horsepower is an engine's output horsepower rating, whereas brake horsepower is an engine's input brake horsepower.
Brake horsepower measures an engine's power without accounting for power losses, whereas HP accounts for power losses. Horsepower of the brakes
Therefore, the horsepower unit is defined by the amount of work a horse can do in one minute.
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A forward horizontal force of 12 N is used to pull a 240-N crate at constant velocity across a
horizontal floor. The coefficient of friction is:
Explanation:
[tex]let \: coefficient \: of \: friction \: be \: \gamma \\ from \: third \: law \: of \: solid \: friction \\friction \: force = \gamma \times normal \: reaction \\ F = \gamma R \\ but \: R = mg = 240N \\ \gamma = \frac{ F}{R} \\ \gamma = \frac{12}{240} \\ \gamma = \frac{1}{20} [/tex]
what is liang most likely trying to do
Answer:
Who is liang
Explanation:
i need more info if i'm going to help you out
He is most likely trying to figure out how to upload the picture to Brainly.
He knows that his question cannot be answered as long as nobody can see the picture.
PLEASE HELP
A problem says a plane is accelerating
3.42 m/s2 northeast. Which one of these
tables includes that information correctly?
Answer:
The answer is C, I just guessed and got it right lol
Explanation:
What are the benefits when you engage in physical fitness?
Answer:
manage your weight better, have stronger bones, have lower blood pressure, less risk of a heart attack, etc.
Answer:
You become healthier, your body starts regulating better, you get stronger bones and muscles, and you lower the risk of diabetes,heart problems and other diseases.
PLEASE HELPPPPPP <333
Answer:
B. As gravity increases weight increases and as gravity decreases weight decreases
Explanation:
Option B is the correct answer.
From the information given, we can deduce that as the gravity increases, the weight also increases and as the gravity decreases, the weight decreases as well.
This is true from the given table. On earth, the gravity of the man was 9.8m/s² and his weight 588N. But get to space, moon precisely, the gravity reduced to 1.62m/s². Then we discover that such decrease in his gravity also led to the sharp decrease in the weight. The weight decreased from 588N on earth to 96N on the moon.
This actually reveals that weight and gravity are related in a way. Weight of an object is known to be the force of gravity on the object. The weight actually vary as a result of varying gravity.
Answer: b
since the pull of gravity on the moon is less we weigh less.
An electromagnetic wave of frequency 7.55 x 10^14 Hz propagates in carbon tetrachloride with a speed of 2.05 x 10^8 m/s. What is the wavelength of the wave in carbon tetrachloride?
A. 3.38 x 10^-7 m
B. 3.61 x 10^-7 m
C. 3.97 x 10^-7 m
D. 3.01 x 10^-7 m
E. 2.72 x 10^-7 m
Answer:
2.72*10^-7m
Explanation:
Using the formula
v = fλ
v is the speed
f is the frequency
λ is the wavelength
Substitute for λ
λ = v/f
λ = 2.05 x 10^8/7.55 x 10^14
λ = 2.05/7.55 * 10^{8-14}
λ = 0.272 * 10^-6
λ = 2.72*10^-7m
Hence the wavelength of the wave in carbon tetrachloride is 2.72*10^-7m
Two balloons become equally charged once they are rubbed against each other. If the force between the balloons is 6.2 * 10^23 N, what would happen to the force if the charge were to triple on one of the balloons?
A) the force would triple
B) the force would become one-nineth
1. The block shown below is being putled to the right on a horizontal table,
Which labeled vectors represent all the forces acting on the block?
Answer:
E
Explanation:
PLEASE HELP, PLEASE A CORRECT ANSWER!
Answer: I like your profile picture
Explanation:
which letter represents the way the wave is moving?
Wouldn't it be B because it's a majority pointing to it?
Sorry if i'm wrong.
The solar glare of sunlight bouncing off water or snow can be a real problem for drivers. The reflecting sunlight is horizontally polarized, meaning that the light waves oscillate at an angle of 90 degrees with respect to a vertical line. At what angle relative to this vertical line should transmission axis of polarized sunglasses be oriented, if they are to be effective against solar glare
Answer:
Explanation:
The light waves in the reflected sunlight are horizontally polarized, which illustrates that they oscillate at a [tex]90^o[/tex] angle related to a vertical line.
Depending on the condition of the height of the light, the glare can be almost entirely horizontally polarized. Furthermore, all reflections from over-water surfaces are partially polarized. The water becomes more translucent when using polarized sunglasses.
If polarized sunglasses are to be efficient against solar glare, the transmission axis should be positioned at an angle of [tex]\theta = 45^{o}[/tex]
A 3.00 x 10^2-W electric immersion heater is
used to heat a cup of water. The cup is made
of glass and its mass is 3.00 10^2 g. It con-
tains 250 g of water at 15° C. How much time
is needed for the heater to bring the water to
the boiling point? Assume the temperature of
the cup to be the same as the temperature of
the water at all times and no heat is lost to
the air.
Answer
t = 367.77 s = 6.13 min
Explanation:
According to the law of conservation of energy:
[tex]Heat\ Supplied\ By \ Heater = Heat\ Absorbed\ by\ Glass + Heat\ Absorbed\ by\ Water\\Pt = m_gC_g\Delta T_g + m_wC_w\Delta T_w\\[/tex]
where,
P = Electric Power of Heater = 300 W
t = time required = ?
m_g = mass of glass = 300 g = 0.3 kg
m_w = mass of water = 250 g = 0.25 kg
C_g = speicific heat of glass = 840 J/kg.°C
C_w = specific heatof water = 4184 J/kg.°C
ΔT_g = ΔT_w = Change in Temperature of Glass and water = 100°C - 15°C
ΔT_g = ΔT_w = 85°C
Therefore,
[tex](300\ W)(t) = (0.3\ kg)(840\ J/kg.^oC)(85^oC)+(0.25\ kg)(4184\ J/kg.^oC)(85^oC)\\[/tex]
t = 367.77 s = 6.13 min
Just as optical astronomers observe the visible light emitted by objects such as stars and galaxies, radio astronomers can also observe the radio waves emitted by these objects, as well as the radio waves emitted by gas and dust. However, radio telescopes are different from optical telescopes in important ways. In general, compared to optical telescopes, radio telescopes are larger. more curved. more expensive. smaller. This is because
Answer:
Radio telescopes are LARGER than optical telescopes and this is because radio wavelengths are much longer than optical wavelengths
Explanation:
In general radio telescopes are LARGER than optical telescopes and this is because radio wavelengths are much longer than optical wavelengths.
The main difference between radio telescopes and other telescopes especially optical telescopes is based on size and wavelength of both telescopes
A pendulum is constructed from a heavy metal rod and a metal disk, both of uniform mass density. The center of the disk is bolted to one end of the rod, and the pendulum hangs from the other end of the rod. The rod has a mass of =1.0 kg and a length of =49.8 cm. The disk has a mass of =4.0 kg and a radius of =24.9 cm. The acceleration due to gravity is =9.8 m/s2.
The pendulum is held with the rod horizontal and then released. What is the magnitude of its angular acceleration at the moment of release?
The magnitude of the angular acceleration of the pendulum at the moment of release is; α = 18.45 rad/s²
We are given;
Mass of rod; m = 1 kg
Length of rod; L = 49.8 cm = 0.498 m
Mass of Disk; M = 4 kg
Radius of disk; r = 24.9 cm = 0.249 m
Let us first calculate the torque acting from the formula;
τ = mg(L/2) + MgL
Thus;
τ = (1 × 9.8 × (0.498/2)) + (4 × 9.8 × 0.498)
τ = 21.96 N.m
Using parallel axis theorem, we can find the moment of inertia about the given axis as;
I = (mL²/3) + ½MR² + ML²
Plugging in the relevant values gives;
I = (1 * 0.498²/3) + ½(4 * 0.249²) + (4 * 0.498²)
I = 1.19 kg.m²
The angular acceleration is given by the formula;
α = I/τ
α = 21.96/1.19
α = 18.45 rad/s²
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What is the average speed of the bicyclist's ride?
A.45m/s
B.7.5m/s
C45mi/hr
D.7.5mi/hr
Electron spin: Radio astronomers can detect clouds of hydrogen too cool to radiate optical wavelengths of light by means of the 21 cm spectral line corresponding with the flipping of the electron in a hydrogen atom from having its spin parallel to the proton spin to having it antiparallel. From this wavelength, and thus E between states, find the magnetic field experienced by the electron in a hydrogen atom
Answer:
the magnetic field experienced by the electron is 0.0511 T
Explanation:
Given the data in the question;
Wavelength λ = 21 cm = 0.21 m
we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T
Plank's constant h is 6.626 × 10⁻³⁴ J.s
speed of light c = 3 × 10⁸ m/s
protein spin causes magnetic field in hydrogen atom.
so
Initial potential energy = -μ[tex]_B[/tex]B × cos0°
= -μ[tex]_B[/tex]B × 1
= -μ[tex]_B[/tex]B
Final potential energy = -μ[tex]_B[/tex]B × cos180°
= -μ[tex]_B[/tex]B × -1
= μ[tex]_B[/tex]B
so change in energy will be;
ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )
ΔE = 2μ[tex]_B[/tex]B
now, difference in energy levels will be;
ΔE = hc/λ
2μ[tex]_B[/tex]B = hc/λ
2μ[tex]_B[/tex]Bλ = hc
B = hc / 2μ[tex]_B[/tex]λ
so we substitute
B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)] / [2(9.27 × 10⁻²⁴) × 0.21 ]
B = [ 1.9878 × 10⁻²⁵ ] / [ 3.8934 × 10⁻²⁴ ]
B = 510556326.09
B = 0.0511 T
Therefore, the magnetic field experienced by the electron is 0.0511 T
why do dzongs have broader base?
Answer:
The base of taller buildings are made broader because it reduces the pressure exerted on the ground so that they do not sink in due to the extremely high pressure of the building.
Explanation:
hope thiss helpss~!
A broad base is used to engage or recruit a diverse range of individuals to broad-based environmentalism.
Broader base:The broader base is a base of taller structures was built wider to reduce the pressure placed on the floor.It preventing the ground from sinking due to the house's extremely high tension.This structures have a wider base because the pressure is inversely proportional to area.That's why the increasing the area reduces the pressure or we can that the structure would not fall apart.Find out more about the broader base here:
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if the dissipated power between a and b equal 210 watt then VB equal
Answer:
correct answer is A
Explanation:
The diagram shows a series circuit with three resistors and two power sources.
In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.
When the power sources are placed in opposite position the voltage between them is subtracted.
V_b - 30 = I (10 + 4 + 6)
V_b = I (20) - 30
V_b = 30 - 2 20
V_b = 10 V
the correct answer is A
An Atwood's machine consists of blocks of masses
m1 = 11.0 kg
and
m2 = 19.0 kg
attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass
M = 7.90 kg
and radius
r = 0.200 m.
The block of mass m2 is allowed to drop, and the cord turns the pulley without slipping.
Answer:
Explanation:
Given that:
[tex]mass \ m_ 1 = 11.0 \ kg[/tex]
[tex]mass \ m_2 = 19.0 \ kg[/tex]
[tex]mass \ of \ the \ pulley\ M = 7.90 \ kg[/tex]
[tex]Radius \ of \ the \ pulley = 0.200\ m[/tex]
1) Provided that the mass in [tex]m_2[/tex] is greater than the mass we have in [tex]m_1[/tex], then likewise the tension we have in [tex]T_2[/tex] will be greater than the tension in [tex]T_1[/tex]
Using Newton's second law to mass [tex]m_1[/tex], we have:
[tex]m_2g - T_2 = m_2 a \\ \\ T_1 = m_1 g +m_1 a \\ \\ T_1= m_1 (g+a) --- (1)[/tex]
By using the second law, we have:
[tex]m_2g - T_2 = m_2a \\ \\ T_2 = m_2 (g-a)---(2)[/tex]
For the pulley, let's use the torque equation, so we have:
[tex]T_2 r -T_1 r = I \alpha \\ \\ T_2r -T_1r = \Big ( \dfrac{Mr^2}{2}\Big) \dfrac{a}{r} \\ \\ T_2 -T_1 = \dfrac{Ma}{2} ---- (3)[/tex]
Altogether, from equation (1)(2) and (3), we have:
[tex]m_2(g-a) -m_1 (g+a) = \dfrac{Ma}{2} \\ \\ m_2g -m_2a -m_1g-m_1a = \dfrac{Ma}{2} \\ \\ a = \dfrac{(m_2 -m_1) g}{(m_1 + m_2 + \dfrac{M}{2})} \\ \\ a = \dfrac{(19.0 \ kg - 11.0 \ kg ) ( 9.8 \ m/s^2)}{(19.0 \ kg + 11.0 \ kg + \dfrac{7.90 \ kg }{2} )}[/tex]
[tex]a = 2.31 \ m/s^2[/tex]
Also; from equation (1), the tension in the string is:
[tex]T_1[/tex] = (11.0 kg ) ( 9.8 + 2.31) m/s²
[tex]T_1[/tex] = 133.21 N
[tex]T_1[/tex] ≅ 133 N
From equation (2):
[tex]T_1[/tex] = m_2(g-a)
[tex]T_1[/tex] = (19.0 kg) ( 9.8 - 2.31) m/s²
[tex]T_1[/tex] = 142.31 N
[tex]T_1[/tex] = 142 N
If the length of the standing wave below is 2 meters, what is the wavelength of the standing
wave? *
Answer:
fffffgggggggggggggghhh
A 1.0μF capacitor with an initial stored energy of 0.50 J is discharged through a 1.0MΩ resistor. (a) What is the initial charge on the capacitor? (b) What is the current through the resistor when the discharge starts? Find an expression that gives, as a function of time t, (c) the potential difference V C across the capacitor, (d) the potential difference V R across the resistor, and (e) the rate at which thermal energy is produced in the resistor.
Answer:
A) q_o = 0.001 C
B) I = 0.001•e^(-t)
C) V_c = 1000e^(-t)
D) V_r = 1000e^(-t)
E) P = e^(-2t) watts
Explanation:
A) We are given;
Initial stored energy; U_o = 0.5 J
Capacitance; C = 1.0μF = 1 × 10^(-6) F
To find the charge, we will use the formula for energy in capacitors which is given by;
U = q²/2C
Thus, since we are dealing with initial energy, U is U_o and q is q_o
Making q the subject, we have;
q_o = √2CU_o
q_o = √(2 × 1 × 10^(-6) × 0.5)
q_o = 0.001 C
B) The charge as a function of time is expressed as;
q = q_o•e^(-t/RC)
Now the current is gotten by differentiating the charge function. Thus;
I = (q_o/RC)•e^(-t/RC)
Where;
R is Resistance = 1.0MΩ = 1 × 10^(6) Ω
C is capacitance = 1 × 10^(-6) F
(q_o/RC) is the initial current = 0.001/(1 × 10^(6) × 1 × 10^(-6))
(q_o/RC) = 0.001 A
Thus;
I = 0.001•e^(-t/(1 × 10^(6) × 1 × 10^(-6)))
I = 0.001•e^(-t)
C) Formula for potential difference across the capacitor is;
V_c = IR
I = 0.001•e^(-t)
R = 1 × 10^(6) Ω
Thus;
V_c = 1 × 10^(6) × 0.001•e^(-t)
V_c = 1000e^(-t)
D) Potential difference across the resistor will be the same as that across the capacitor because the resistor is connected in parallel to the capacitor.
Thus;
V_r = V_c = 1000e^(-t)
E) rate at which thermal energy is produced is basically the power.
Thus;
P = (V_r)²/R
P = (1000²e^(-2t))/1 × 10^(6)
P = e^(-2t) watts
A 10Ω and a 15Ω resistor are connected in series across a 110V potential difference. (Can you find them) please help
A) what is the total resistance of the circuit?
B) what is the current through each resistor?
C) what is the voltage drop across each resistor
Answer:
(A) The total resistance of the circuit is 25 Ω
(B) The current through each resistor is 4.4 A
(C) For 10Ω: Potential drop = 44 V
For 15Ω: Potential drop = 66 V
Explanation:
Given;
potential difference, V = 110V
resistors in series, = 10Ω and a 15Ω
(A) The total resistance of the circuit is calculated as follows;
Rt = 10Ω + 15Ω = 25Ω
(B) The current through each resistor;
Same current will flow through the two resistors since they are in series.
I = V/Rt
I = 110 / 25
I = 4.4 A
(C) The voltage drop across each resistor;
For 10Ω: Potential drop = IR₁ = 4.4 x 10 = 44 V
For 15Ω: Potential drop = IR₂ = 4.4 x 15 = 66 V
: Suppose somebody, using the same apparatus which you used, measured I = 45.5 ma, and V = 8.2 volts on some resistor. Using your recorded uncertainties for the 50 ma and 10-volt scales, what would be the maximum % uncertainty in R if it were calculated from the Ohm’s Law Equation (1)? Use calculus methods to answer this question if you can.
Answer:
R = (18 ± 2) 10¹ Ω
ΔR = 2 10¹ Ω
Explanation:
Ohm's law relates voltage to current and resistance
V = i R
R = [tex]\frac{V}{i}[/tex]V / i
the absolute error of the resistance is
ΔR = | [tex]| \frac{dR}{DV} | \ \Delta V + | \frac{dR}{di} | \ \Delta i[/tex]
the absolute value guarantees the worst case, maximum error
ΔR = [tex]\frac{1}{i} \Delta V+ \frac{V}{i^2} \Delta i[/tex]
The error in the voltage let be approximate, if we use a scale of 10 V, in general the scales are divided into 20 divisions, the error is the reading of 1 division, let's use a rule of direct proportion
ΔV = 1 division = 10 V / 20 divisions
ΔV = 0.5 V
The current error must also be approximate, if we have the same number of divisions
Δi = 50 mA / 20 divisions
Δi = 2.5 mA
let's calculate
ΔR = [tex]\frac{1}{45.5 \ 10^{-3}} \ 0.5 + \frac{8.2}{(45.5 \ 10^{-3})^2 } \ 2.5 \ 10^{-3}[/tex]
ΔR = 10.99 + 9.9
ΔR = 20.9 Ω
The absolute error must be given with a significant figure
ΔR = 2 10¹ Ω
the resistance value is
R = 8.2 / 45.5 10-3
R = 180 Ω
the result should be
R = (18 ± 2) 10¹ Ω
supergiant stars
a.) form from red giants
b.) fuse hydrogen into carbon
c.) form planetary nebulae
d.) form supernovas
Answer:
d.) form supernovas
Explanation:
Learned this in physical school last year
The volumes of two bodies are measured to be
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³. Calculate sum and difference in
volumes with error limits.
Answer:
sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
Explanation:
Here,
V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.
Now,
∆V = ± (∆V₁ + ∆V₂)
= ± (0.02 + 0.01) cm³
= ± 0.03 cm³
V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and
V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³
Thus, sum of volumes = (16.6 ± 0.03) cm³
and difference of volumes = (3.8 ± 0.03) cm³
-TheUnknownScientist
Answer:
I hope it's helpful .............
A –5 μC charge is placed 2 mm from a +3 μC charge. Find the force between the two charges?
Answer:
-33750 N
Explanation:
Use coulomb's law: [tex]\frac{k(q1)(q2)}{r^{2} } = \frac{(9x10^{9})(-5x10^{-6})(3x10^{-6})}{0.002^{2} } = -33750 N[/tex]
As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g. Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward). If the bottom of your window is a height hb above the ground, what is the velocity vground of the pot as it hits the ground? You may introduce the new variable vb, the speed at the bottom of the window, defined by
vb = Lwt + gt2.
Answer:
[tex]\mathbf{v_{ground} = \sqrt{{v^2+2ghb}}}[/tex]
Explanation:
From the information given:
The avg. velocity post the window is;
[tex]v_{avg} = \dfrac{L_w}{t}[/tex]
[tex]v_b[/tex] = velocity located at the top of the window
[tex]v_b[/tex] = velocity situated at the bottom of the window
Using the equation of kinematics:
[tex]v_b = v_t + gt[/tex]
Hence,
[tex]v_t = v_b - gt[/tex]
To determine the average velocity as follows:
[tex]v_{avg} = \dfrac{1}{2} (v_t + v_b)\dfrac{L_w}{t}= \dfrac{1}{2}(v_b - gt +v_b) \\ \\\dfrac{L_w}{t} = v_b - \dfrac{1}{2}gt \\ \\ v_b = \dfrac{L_w}{t }+ \dfrac{1}{2} gt\\ \\ = \dfrac{1}{t} \Bigg(L_w + \dfrac{1}{2}gt^2 \Bigg) \\ \\[/tex]
where;
[tex]v_b[/tex] = velocity gained when fallen through the height h.
Similarly, using the equation of kinematics, we have;
[tex]v_b^2 = 2gh \\ \\h = \dfrac{v_b^2}{2g}[/tex]
[tex]\implies \dfrac{(L_w + \dfrac{1}{2} gt^2_^2}{2gt^2}[/tex]
Thus, the velocity at the ground is;
[tex]v^2_{grround} = v_b^2 + 2ghb[/tex]
[tex]\mathbf{v_{ground} = \sqrt{{v^2+2ghb}}}[/tex]
When the electrons reach the collector, they flow towards the positivly charged grid. The resulting current is measured. Note that as the electrons accelerate from the cathode toward the grid, they collide with the mercury atoms. Assume that these collisions are completely elastic. How does the collected current vary if the ΔVgridΔVgrid is slowly increased? View Available Hint(s)
Answer:
We can conclude by saying that in the beginning current will increase but after sometime, it becomes saturated.
Explanation:
Note: No information on change in number of electron generated.
Since there is a collision, the electrons emitted will not reach the collector at same time. As the voltage is increased, the the speed with which the electrons will reach the collector starts to increase. Due to this, electric current will first increases till all the emitted electrons reach the collector. Since we are not provided with the information that number of electrons generated are changing, after increasing voltage current will increase for some time and then reaches a saturated state.
We can conclude by saying that in the beginning current will increase but after sometime it becomes saturated.
molecules , like hormones , are made up of which of the following
A. cells
B. Atoms
C. Tissues
D. Organs
Answer:
atoms
Explanation:
Hormones are derived from amino acids or lipids. Amine hormones originate from the amino acids tryptophan or tyrosine. Larger amino acid hormones include peptides and protein hormones. Steroid hormones are derived from cholesterol.
LESSION 7:LIGHT UNIT TEST
PHYSICAL SCIENCE B: UNIT 4: LIGHT
17/17 answers u cheaters here you go
Answer:
I cheated on
Spanish
ELA
history
Explanation:
Answer:
thx
Explanation: