Happy Holidays!
We can use the following equation to solve for the gravitational force:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]
Fg = force due to gravity (N)
G = Gravitational constant
m1,m2 = masses of the objects (kg)
r = distance between the objects (m)
Plug in the given values into the equation:
[tex]F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}[/tex]
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. (3 points)
0.60 N, along the line tangent to the circle
0.015 N, along the line tangent to the circle
0.60 N, toward the center of the circle
0.015 N, toward the center of the circle
Answer:
0.60N along the line tangent to the circle
Answer:
A is the answer
Explanation:
Just got finished with the quiz! Hope this helps <3
the normal formula to find force is F = m*a. What kind of math do you need to do
to find the mass of an object?
- Divide: F / a
- Divide: a / F
- Multiply: F* a
- Subtract: F - a
[tex]\\ \sf\Rrightarrow F=ma[/tex]
Take a to leftAs it's multiplied on right side it will be divided on right side.[tex]\\ \sf\Rrightarrow \dfrac{F}{a}=m[/tex]
Or
[tex]\\ \sf\Rrightarrow m=\dfrac{F}{a}[/tex]
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
The final speed of the combined masses is 0.21 m/s
Applying the law of conservation of momentum:
Total momentum before collision = Total momentum after collision.
⇒ Formula:
MU+mu = V(M+m).................. Equation 1
⇒ Where:
M = mass of the first bodym = mass of the second bodyU = Initial speed of the first bodyu = Initial speed of the second bodyV = common final speed.From the question,
⇒ Given:
M = 0.24 kgU = 0.60 m/sm = 0.26 kgu = -0.20 m/s (traveling in opposite direction)⇒ Substitute these values into equation 1
0.24(0.6)+0.26(-0.20) = V(0.24+0.2)⇒ Solve for V
0.144-0.052 = 0.44V0.44V = 0.092V = 0.092/0.44V = 0.209V ≈ 0.21 m/sHence the final speed of the combined masses is 0.21 m/s
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Here's a question from ~ [ AIEEE 2002 ]
The minimum velocity ( in m/s ) with which a car driver must traverse a flat curve of radius 150 m and Coefficient of friction 0.6 to avoid skidding is ~
[ I'm looking for Proper Information, and please don't get it from any Website ]
Thanks for Answering !
As car is avoid skidding
[tex]\\ \sf\hookrightarrow \dfrac{mv^2}{r}=\mu mg[/tex]
Cancel m[tex]\\ \sf\hookrightarrow \dfrac{v^2}{r}=\mu g[/tex]
[tex]\\ \sf\hookrightarrow v^2=\mu rg[/tex]
[tex]\\ \sf\hookrightarrow v^2=0.6(10)(150)[/tex]
[tex]\\ \sf\hookrightarrow v^2=60(150)[/tex]
[tex]\\ \sf\hookrightarrow v^2=900[/tex]
[tex]\\ \sf\hookrightarrow v=30ms^{-1}[/tex]
Done
The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.
The given parameters:
Radius of the curve, r = 150 mCoefficient of friction, μ = 0.6The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is calculated as follows;
[tex]\frac{mv^2}{r} = \mu mg\\\\v^2 = \frac{\mu mgr}{m} \\\\v^2 = \mu gr\\\\v = \sqrt{\mu gr} \\\\v = \sqrt{0.6 \times 9.8 \times 150} \\\\v = 29.7 \ m/s[/tex]
Thus, the minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.
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how to read a micrometer on a clark cm-100 vickers hardness tester
Answer:
Explanation:
Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material
and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is
covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any
equipment, new or used, purchased from anyone other than the LECO Corporation. All replacement parts shall
be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER
REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO
THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR
OTHERWISE.
Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by
this warranty.
LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our
satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This
obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,
neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods
exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR
CONSEQUENTIAL DAMAGES WHATSOEVER.
All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the
facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other
parts. This warranty is voided by failure to comply with these notice requirements.
NOTICE
The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.
Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the
specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO
consumables are employed in conjunction with LECO instruments. If purchaser defaults in making payment for
any parts or equipment, this warranty shall be void and shall not apply to such parts and equipment. No late
payment or cure of default in payment shall extend the warranty period provided herein.
LECO Corporation is not responsible for damage to any associated instruments, equipment or apparatus nor wil
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The instrument should be operated only by technically qualified individuals who have fully read and understand
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The operator should follow all ,of the warnings and cautions set forth in the manual and the operator should follow
and employ all applicable standard laboratory safety procedures.
LECO'" is a registered trademark of the LECO Corporatio
Kepler’s laws of planetary motion describe each of the three laws
Kepler's laws laid the foundation for the early study of astronomy.
Kepler was one of the earliest astronomers that contributed immensely to the study of the planets. The Kepler's laws of planetary motion are as follows;
The planets each travel along an ellipse with the sun at one focus.The line joining the sun and the planets sweeps out equal areas in equal time intervals.The square of the period of the revolution of the planets equals the cube of the planet's mean distance from the sun.Learn more about Kepler's laws; https://brainly.com/question/1017661
a 3 kg rock is falling from a rock ledge in the absence of air resistance how much force will the rock strikes the ground with
Answer:
papi sus
Explanation:
can someone explain it with steps?
A car was moving on a road at a constant speed of 15 m/s when suddenly the car driver saw some animal on the road at a distance of 21 m from the car, so he applied the brakes after a response time of 0.4 s and stopped before hitting the animal by 1 m. What was the deceleration of the car?
a-7.5 m/s^2
b-5.2 m/s^2
c-8.0 m/s^2
d-5.6 m/s^2
Answer:
Option C is the correct answer
Explanation:
Distance travelled by car during reaction time
[tex]=15\times0.4\\\\=6m[/tex]
The car stopped before hitting the animal by [tex]1 m[/tex]
Distance travelled during deceleration is [tex]21-6-1=14m[/tex]
Hence by [tex]v^2=u^2+2as[/tex]
We have
[tex]0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2[/tex]
Option C is the correct answer
Distance traveled during reaction time
15(0.4)=6mTotal distance
21-6-1=14m[tex]\\ \sf\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \sf\longmapsto -(15)^2=2(14)a[/tex]
[tex]\\ \sf\longmapsto -225=28a[/tex]
[tex]\\ \sf\longmapsto a=-8.0m/s^2[/tex]
Which type of border shows the division between Sonora and Chihuahua?
National border
State border
Physical boundary
Natural boundary
define one kilogram mass
Answer:
kg - one thousand grams; the basic unit of mass adopted under the Systeme International d'Unites; "a kilogram is approximately 2.2 pounds"
Explanation:
Two gravitational forces act on a
given object. How do you determine the total gravita-
tional force acting on the object?
Answer:
Explanation:
Depends on the location of the two forces. If they are aligned on the same side of the object, you would simply add.
X -----------F1 -------F2
X is the object. F1 and F2 are both masses which create a gravitational force. They both are the form of Fx = G * m1 * m2 / r^2. The total force is F1 + F2
If they are are on either side of the object, you subtract.
F1 ---------X ---------F2
Fx = F1 - F2
Any other location of F1 and F2 is much more complicated by the use of trigonometry.
A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back on it with a 68 N horizontal force.
Part A
How much work does Paige do on the crate as it slides 3.0 m down the ramp?
Answer:
the answer is 69.7687j
Explanation:
W =F sin Φ
A heating curve is a graph that shows the temperature change of a substance as
thermal energy is introduced.
True
False
Answer:
This statement is true, a heating curve is a graph that shows the temperature change of a substance as thermal energy is introduced.
A heating curve is a graph that represents the temperature change of a substance as thermal energy is introduced.
What is the heating curve?The heating curve can be described as the relationship between the heating supply temperature and the outside air temperature of the system. The heating curve gives what temperature the boiler is to heat the water at an outdoor temperature.
Heating curves indicate how the temperature changes as a substance are heated up. Cooling curves are generally the opposite of the heating curve. They indicate how the temperature changes as a substance are cooled down. Similar to heating curves, cooling curves have horizontal parts where the state transforms from gas to liquid/ from liquid to solid.
The heating curve represents the material in phases of solid, liquid, and gas. As this graph is a plot of T v/s q, the slope is 1/mC. As the heating continues, the solid substance melts. During this time the temperature remains constant. The length of the line can be described as the amount of heat required to melt the solid.
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You're driving your pickup truck around a curve with a radius of 22 m. A box in the back of the truck is pressed up against the wall of the truck. How fast must you drive so that the force of the wall on the box equals the weight of the box?
Answer:
Explanation:
Centrifugal force Fc = m x v2 / r
Weight = mg
As required by the question
Fc = W
v2 /r = g
given radius r = 22 m
v2 /22 = 9.8
Solve for v
required speed v = √(22 * 9.8)
= 14.35 m/s
v=15 m/s
this may help you
The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.
What is centrifugal force?The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.
The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:
[tex]{\displaystyle F=m\omega ^{2}r}[/tex]
Given, the radius of the curve, r = 22m
The acceleration, a = v²/r
The weight of the box, W = mg
We know that, F = ma
mg = m(v²/r)
v = √gr
[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]
v = 14.68 m/s
Therefore, you should drive at a speed of 14.68 m/s
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what are two variables that are always in every experiment?
the independent variable and the dependent variable.
NEED HELP ASAP PLEASE
The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop time compare to the average of your measured drop times? Find the percent error using the following equation measured drop time - calculated drop time % 100 calculated drop time What factors might cause the differences?
did you end up getting the answer- im struggling
Answer:
I would think human error could cause differences like not pressing the stop watch on time.
Explanation:
Which image shows an example of the electromagnetic force in action?
Answer:
Where are the images?
Explanation:
I can't help if there is no image(s) to this question.
What does the diagram show about X and Y?
A They have the same mass and the same volume but different weights.
B They have the same mass and the same weight but different volumes.
C They have the same mass, the same volume and the same weight.
D They have the same weight and the same volume but different masses.
Answer: answer is c rest of explanation is in the comments
If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?
Answer:
96.5 mL
Explanation:
15. Find the density of a certain object that has the dimensions 2cm x 6cm x 7cm and a
mass of 42g.
16. What is the volume of a container of liquid that has a density of 120g/ml and a mass
of 17g.
17. If the mass of an object has a mass of 23g and a volume 123ml, what is its density.
“Express your answer in Kg/ml!"
18. What is the volume of a cubed object with a measure of 12cm on one of its sides, if
the mass of that same object is 45g and its density is 240g/cm3?
19. An object with a density of 3g/ml is placed into a body of water. Since the density of
water is 1g/ml, will this object sink or float.
This question is asking for five different questions about density, mass and volume which can be all summarized with the following definition of density as the degree of compactness of the objects taken into consideration:
[tex]\rho =\frac{m}{V}[/tex]
In such a way, we can proceed as follows:
15. the mass is given as 42 g and the volume can be found by multiplying the given dimensions:
[tex]V=2cm*6cm*7cm=84 cm^3[/tex]
And the density turns out to be:
[tex]\rho =\frac{42g}{84cm^3}=0.5 g/cm^3[/tex]
16. both mass and density are given as 17 g and 120 g/mL respectively, so that we have to solve for the volume as shown below:
[tex]V=\frac{m}{\rho} =\frac{17g}{120g/mL} =0.14 mL[/tex]
17. the mass is given as 23 g and the volume as 123 mL, so that the density is calculated as shown below:
[tex]\rho=\frac{23g}{123 mL} =0.19 g/mL[/tex]
Which can be converted to kg/mL as follows:
[tex]0.19\frac{g}{mL} *\frac{1kg}{1000g}=0.00019 kg/mL[/tex]
18. the mass is given as 45 g and the density as 240 g/cm³, so we can solve for the volume as follows:
[tex]V=\frac{m}{\rho} =\frac{45g}{240g/cm^3}=0.19 cm^3[/tex]
19. In this case, since the water has lower density than the object, we can infer that the latter is heavier than the former, this means that the object will sink according to the Archimedes principle.
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as the mass of an object increases, the force of attraction...
Answer:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
Answer:
thanks
Explanation:
for answer byebye
What is velocity? Explain.
Answer:
The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).What will happen if the two plungers are pressed together firmly? Explain your answer.
Answer:
This air being forced out causing the air pressure inside to be much lower than that on the outside. As higher air pressure always pushes, it keeps the two plungers together.
Hope that helps. x
How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?
Answer:
180 [J].
Explanation:
1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;
2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;
3) then the required work [W]:
W=mg*(h₂-h₁)=30*6=180 [J].
how many asteroids do scientists believe exist in the solar system?
Answer:
Astronomers think there are between 1.1 and 1.9 million asteroids in the solar system.
Explanation:
Explain Body Mechanics.
PLUS BRAINLY! and 50 Points
Answer Body mechanics is a term used to describe the ways we move as we go about our daily lives. It includes how we hold our bodies when we sit, stand, lift, carry, bend, and sleep. ... Good body mechanics means using the body's strength to the best mechanical advantage to do a task efficiently and without injury.
Explanation:
A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
momentum of the pieces after the explosion compare to the total momentum of the
cannonball just before the explosion?
I. They are the same
II. The momentum of the fragments is less than the momentum of the cannonball
III. The momentum of the fragments is more than the momentum of the cannonball
Hi there!
I. They are the same.
Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.
given the formula p=mv what are the units of p
Answer:
They are kg * m/s.
The unit of the momentum p would be kg × m/s..
What is momentum?Momentum is defined as the ability or tendency of an object to continue moving.
Also momentum is the product of mass and velocity. It can be shown as follows;
p = m × v
where,
p = momentum
m = mass
v = velocity
Thus, we can conclude that the formula p = mv show the relationship between momentum, mass, and velocity.
Now the unit of the momentum p would be;
p = m × v
p = kg × m/s
Hence, the unit of the momentum p would be kg × m/s.
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What is the velocity of a dropped object after it has fallen for 3.0 s?
Answer:
30 m/s.
Explanation:
A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = â€""16t2 48t 190. Approximately when will the projectile hit the ground? 1. 5 seconds 3. 2 seconds 5. 3 seconds 6. 2 seconds.
The time for the projectile to hit the ground from the given position is 1.5 s.
The given parameters:
Initial velocity of the projectile, u = 48 ft/sHeight, h = 190 ftModel of the projectile path, h(t) = –16t² + 48t + 190.The time for the projectile to hit the ground is calculated as follows:
when the projectile hits the ground, the final velocity = 0
[tex]v_f = 0\\\\\frac{dh(t)}{dt} = v_f\\\\\frac{dh(t)}{dt} = -32t + 48\\\\-32t+48 = 0\\\\32t = 48\\\\t = \frac{48}{32} \\\\t = 1.5 \ s[/tex]
Thus, the time for the projectile to hit the ground from the given position is 1.5 s.
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