Answers
Answer:
10kg
Explanation:
Weight is "how much does gravity drag this down".
Mass is "how much matter is there here".
The relation is:
[tex]F_g = mg[/tex]
where [tex]F_g[/tex] is the weight, [tex]m[/tex] is the mass and [tex]g[/tex] is the gravitational acceleration (roughly equal to 10N/kg on Earth).
From the task we know that:
[tex]F_g = 100N\\g = 10\frac{N}{kg}[/tex]
So let's input it into the relation:
[tex]100N = m\cdot 10\frac{N}{kg}\\10N = m \cdot 1\frac{N}{kg}\\10N \cdot \frac{kg}{N} = m\\~\\m = 10kg[/tex]
Related Questions
B. Exercises
Exercise 1
Direction: identfy the plumbing symbols in each item Write your answer on the space
provided before each number
Answers
Answer:
please I do not understand that question
A star that is one of the coolest,
about 3,200°C, is going to be which
of the following colors?
Resourcos
A. greenish
Help
B. bluish
C. yellowish
D. reddish
Answers
a 0.1 kg object oscillates as a simple harmonic motion along x axis with a frequency f=3.185 hz. At a position x1 , the object has a kinetic energy of o.7 j and a potential energy 0.3 J.The amplitude of oscillation A is:
Answers
Answer:
The total energy must be .7 J + .3 J = 1 J for a particle at the endpoint or midpoint of motion.
Also, omega = (k / m)^1/2
f = omega / (2 * pi)
omega^2 = 4 pi^2 * f^2 = k / m
k = 4 * pi^2 * f^2 * m = 40.05
Max KE or PE = 1/2 k A^2
A^2 = 2 * E / k = 2 * 1 / k = .0499
A = .223 meters
A baseball was thrown off of a 35 meter high building. It lands 50 meters from the base of the building.
Answers
Wonderful.
Look out below !
Was the FAA notified ?
What do the different colors of stars tell us?
A. The size of the stars
B. The shape of the stars
C. The temperatures of the stars
Answers
Answer:
It would Be C The temperatures of the stars
Explanation:
A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.55 m/s to the right relative to the plank.
Required:
What is the velocity of the plank relative to the surface of the ice?
Answers
Answer:
The speed of the plank relative to the ice is:
[tex]v_{p}=-0.33\: m/s[/tex]
Explanation:
Here we can use momentum conservation. Do not forget it is relative to the ice.
[tex]m_{g}v_{g}+m_{p}v_{p}=0[/tex] (1)
Where:
m(g) is the mass of the girlm(p) is the mass of the plankv(g) is the speed of the girlv(p) is the speed of the plankNow, as we have relative velocities, we have:
[tex]v_{g/b}=v_{g}-v_{p}=1.55 \: m/s[/tex] (2)
v(g/b) is the speed of the girl relative to the plank
Solving the system of equations (1) and (2)
[tex]45v_{g}+168v_{p}=0[/tex]
[tex]v_{g}-v_{p}=1.55[/tex]
[tex]v_{p}=-0.33\: m/s[/tex]
I hope it helps you!
How does a battery generate electrical energy?
Answers
A heat pump with a COP of 3.0 is used to heat air contained in a 1205.4 m3 of well-insulated, rigid tank. Initially the pressure and the temperature inside the gas tank are 100 kPa and 7 oC, respectively. When running, the heat pump consumes 5 kW of electric power. How long does it take for the heat pump to raise the temperature of air in the tank to 22 oC
Answers
Answer:
ffff
Explanation:
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Help answer question in licture
Answers
Answer:
D
Explanation:
D is high pitch c is low pitch
Answer:
D creo que esa es la nota mas alta, la segumda
How do home computer scanners generally use electromagnetic waves?
O A. They change information received from sound waves into electromagnetic waves.
OB. They gather information from reflected and absorbed waves.
O C. They receive microwaves that are emitted by natural objects.
O D. They use X-rays that penetrate most objects. SUBMIT
Answers
Answer:
they gather information from reflected and absorbed waves.
Explanation:
1.00 x 100 kg of clear liquid (specific heat
capacity = 5.11 x 102 J/kg•°C) at a temperature
of 15.0°C gains 3.33 x 10 J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)
Answers
Answer:
No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a ... to change 1 kg of liquid water at the normal boiling point (100ºC at atmospheric pressure) to steam (water vapor).
The melting point of lead is 327.3o C. Assume the final temperature of the system is T. Then the amount of energy released by the lead as it solidifies is. ΔQ = mleadLlead = 0.09 kg*(2.45*104 J/kg) = 2205 J
A player kicks a football from ground level with an initial velocity of 27.0 m/s, 30.0° above the Horizontal. Find the distance the ball travels before it hits the ground.
Answers
Answer:
The horizontal distance traveled by the ball before it hits the ground is 64.42 m.
Explanation:
Given;
initial velocity, u = 27.0 m/s
angle of projection, θ = 30⁰
The horizontal distance traveled by the ball before it hits the ground is known as Range;
[tex]Range = \frac{u^2 sin(2\theta)}{g} \\\\Range = \frac{(27^2)sin(2 \times 30)}{9.8} \\\\Range = 64.42 \ m[/tex]
Therefore, the horizontal distance traveled by the ball before it hits the ground is 64.42 m.
what happens to the work done when a force is doubled and the distance moved remain the same?
Answers
Answer:
It is doubled
Explanation:
f2=2f1
x1=x2=x
W1=f1*x1=f1*x
W2=f2*x2=f2*x=2*(fi*x)=2*W1
Black holes result from
Answers
Answer:
supernova explosion or death of massive star
Explanation:
"Most black holes form from the remnants of a large star that dies in a supernova explosion."
A wheelbarrow full of bricks is lifted to the top of a wall. If the mass of the loaded wheelbarrow is 3000.0 g and the height of the wall is 0.45 meters, what is its GPE?
Answers
Answer:
the Gravitational potential energy is 13.23 J
Explanation:
The computation of the GPE is shown below:
GPE stands for Gravitational potential energy
The following formula should be used for the same
= mass × gravity × height
= 3000 g × 9.8m/sec^2 × 0.45 m
= 13.23 J
Hence, the Gravitational potential energy is 13.23 J
We simply applied the above formula so that we can easily determine the GPE
Since water is much denser than air, deep-sea divers experience a much higher ambient pressure underwater. Each 10 meters of depth underwater adds another 1 atm to the ambient pressure experienced by the diver. (Note: this is in addition to the 1 atm ambient pressure at the surface of the water!) What pressure, in psi, is experienced by a diver 50.0 meters below the surface of the water
Answers
Answer:
If you are at sea level, each square inch of your surface is subjected to a force of 14.6 pounds. The pressure increases about one atmosphere for every 10 meters of water depth. At a depth of 5,000 meters the pressure will be approximately 500 atmospheres or 500 times greater than the pressure at sea level.
Explanation:
At sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.
What is pressure?Pressure is defined as the force applied perpendicularly to an object's surface divided by the surface area over which it is applied.
Pressure is the physical amount of force exerted on a particular area.
Pressure can be expressed as
Pressure = Force / area
There are three types of pressure.
Absolute pressureGauge pressureDifferential pressureThus, at sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.
To learn more about pressure, refer to the link below:
https://brainly.com/question/15170210
#SPJ2
sorry i was gone hope you dident mess me hers a question
Identify the organ that brings oxygen into the body.
brain
chest
heart
lungs
Answers
Answer:
lungs
Explanation:
lungs bring oxygen
Answer:
lungs
Explanation:
i took the quiz
Calculate the equivalent resistance for each of the following circuits.
Answers
Answer:
5. 60 Ω
6. 60 Ω
7. 10 Ω
8. 0.625 KΩ
Explanation:
5. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 20 Ω
Resistor 3 (R₃) = 30 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 20 + 30
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
6. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 35 Ω
Resistor 3 (R₃) = 15 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 35 + 15
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
7. Determination of the equivalent resistance.
Resistor 1 (R₁) = 6 Ω
Resistor 2 (R₂) = 4 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂
R = 6 + 4
R = 10 Ω
Thus, the equivalent resistance is 10 Ω
8. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 KΩ
Resistor 2 (R₂) = 2 KΩ
Resistor 3 (R₃) = 1 KΩ
Equivalent Resistance (R) =?
Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/10 + 1/2 + 1/1
Find the least common multiple (lcm) of 10, 2 and 1. The result is 10. Divide 10 by each of the denominator and multiply the result obtained by the numerator. This is illustrated below:
1/R = (1 + 5 + 10) / 10
1/R = 16/10
Invert
R = 10/16
R = 0.625 KΩ
Thus, the equivalent resistance is 0.625 KΩ.
A piece of irregularly shaped metal weighs 300N in air. When the metal is completely submerged in water, it weighs 232.5N. Find the volume and specific gravity of the metal.
Answers
Answer:
Volume of metal piece = 0.0069 m³ (Approx.)
Explanation:
Given:
Weight of metal in air = 300 N
Weight of metal in water = 232.5 N
Find:
Volume of metal piece
Specific gravity of metal
Computation:
We know that;
Density of water = 1,000 kg/m³
Buoyant force applied on metal piece = Weight of metal in air - Weight of metal in water
Buoyant force applied on metal piece = 300 N - 232.5 N
Buoyant force applied on metal piece = 67.5 N
Buoyant force = Volume of metal x Density of water x Gravitational force
67.5 = Volume of metal x 1,000 x 9.8
Volume of metal piece = 0.0069 m³ (Approx.)
A negatively charged rod briefly touches a neutral metal ball. The metal ball will now be ____________
Answers
Answer:
let say it will be positive
Finding Dimensional Formula For x=vt+1/2at is
Answers
Answer:
In the picture above.
Explanation:
I hope that it's a correct answer for dimensional analysis.
Which of the following is NOT a geological event caused by the movement of tectonic plates?
A) Sand Dunes
B) Mountain forming
C) Earthquakes
D) Volcanoes
Answers
Which of the following is an example of charging by friction?
Answers
Answer: where is the examples?
Explanation:
What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)
Answers
Answer:
When we have a current I, we will have a magnetic field perpendicular to this current.
Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".
Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.
Of course, the intensity of the magnetic field is proportional to the current, given by:
B = (μ*I)/(2*π*r)
Where:
μ is a constant, I is the current and r is the distance between to the current.
Now remember that for a resistor:
R = ρ*L/A
R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.
If we increase the area of the wire (if we use a thicker wire).
And the relation between resistance and current is:
I = V/R
Where V is the voltaje.
Now, if we use a thicker wire, then the cross-section area of the wire increases.
Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.
And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.
If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.
In Milgram's experiment:
A. Yale University would not allow the experiment to be done.
B. participants overwhelmingly did not go all the way to 450 volts.
C. the "learner" was working with Milgram.
D. the "teacher" was working with Milgram.
Answers
Answer:
B. The "Learner" was working with Milgram.
Explanation:
just took the test
give brainliest, please. :)
The vector matrix [6 -2] is rotated at different angles. Match the angles of rotation with the vector matrices they produce.
Answers
Answer:
Hello your question is incomplete hence I will give you a general answer as regards rotation of vector matrix assuming angle of rotation = [tex]\frac{\pi }{4}[/tex]
answer :
angle of rotation = [tex]\frac{\pi }{4}[/tex]
vector matrix produced = attached below
Explanation:
lets assume the vector matrix [ 6, -2 ] is rotated clockwise by an angle of [tex]\frac{\pi }{4}[/tex]
The resultant matrix = attached below
Result of the rotation = attached below
attached below is the detailed solution
Answer: I got it right on Edmentum
Explanation: Answers attached below
3. A ball thrown vertically upward returns to its starting point in 4s. Find its initial speed. [4]
Answers
Answer:
9.8 ×4 equal 39.2 m/s This is v intial
The brightness of a star depends on what
two things?
A. age and color
B. temperature and age
C. size and age
D. size and temperature
Answers
Two long current-carrying wires run parallel to each other and are separated by a distance of 5.00 cm. If the current in one wire is 1.65 A and the current in the other wire is 3.25 A running in the opposite direction, determine the magnitude and direction of the force per unit length the wires exert on each other.
Answers
Answer:
The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Explanation:
Given;
distance between the parallel wires, r = 5.0 cm = 0.05 m
current in the first wire, I₁ = 1.65 A
current in the second wire, I₂ = 3.25 A
The magnitude of the force per unit length between the two wires is calculated as follows;
[tex]\frac{F}{l} =\frac{\mu_0 I_1 I_2}{2\pi r} \\\\\frac{F}{l} =\frac{4\pi \times 10^{-7} \times 1.65 \times 3.25}{2\pi \times 0.05} \\\\\frac{F}{l} = 2.145 \times 10^{-5} \ N/m[/tex]
Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
528 nm light passes through a single slit. the second (m=2) diffraction minimum occurs at an angle of 3.48 degrees. what is the width of the slit
Answers
Answer:
1.74
Explanation:
right on acellus
Answer:
1.74
Explanation:
acellus