PLEASE EXPLAIN IN TWO PARAGRAPHS (A PARAGRAPH IS 4-5 SENTENCES) SOME HEALTHFUL TIPS THAT CAN HELP PREVENT YOU FROM GETTING PHYSICAL FITNESS INJURIES.

Answers

Answer 1

Answer:

A workout injury can happen to anyone, no matter your experience or fitness level. People hurt themselves in all kinds of ways when they work out. Even walking can cause an injury. But you can significantly cut your risk of getting hurt by following certain workout precautions. There are simple steps that can help keep you injury-free during your workout.

Every workout should begin with a warm-up and end with a cool-down period. A warm-up helps your body get ready for exercise. It gradually increases your heart rate and loosens your muscles and joints. Cool-down after you work out so, it brings your heart rate back to normal. Walking for 5 to 10 minutes after you work out is one way to cool down. Do dynamic stretching before and after you work out. This will help increase flexibility. Don't push yourself too hard. As your fitness abilities increase and you will be able to challenge yourself more.

Hope this helps

Answer 2

Maintaining physical fitness is very important in today's world. Each and everyone should be involved in physical fitness.nowaday people are so busy with their work that they have forgotten health is wealth.

Even if we get engaged in physical fitness activity we can some time get insuries . some of tips that can help prevent from getting physical fitness injury, warm up exercises should be done before exercise to avoid muscle strength.safety precautions should be taken if you are dealing with heavy objects .

hence we should maintain physical fitness with getting rid of injury that may occur

mark me


Related Questions

Compare and contrast hydrogen fuel cell vehicles with vehicles that have intemal combustion engines.​

Answers

In a fuel cell vehicle, the hydrogen fuel is combined with oxygen. While the combustion in a hydrogen- or gasoline-powered engine is converted into mechanical energy, in a fuel cell vehicle, the chemical energy from the hydrogen and oxygen is converted into electrical energy.

A hydrogen fuel cell vehicle is different from internal combustion engine as in fuel cell, hydrogen combines with oxygen whereas in internal combustion engines, gasoline is used.

What are hydrogen fuel cell vehicles and internal combustion engines?

In a internal combustion engine or fuel cell vehicle, the hydrogen fuel is combined with oxygen atom. While the combustion in a hydrogen- fuel or in a gasoline-powered engine is converted into mechanical energy, however in the hydrogen fuel cell vehicle, the chemical energy from the hydrogen and oxygen is converted into electrical energy.

Both hydrogen internal combustion engines and the hydrogen fuel cells can power vehicles using hydrogen, a zero-carbon fuel. Hydrogen engines burn hydrogen gas in an internal combustion engine, in the same way as the gasoline is used in a power engine. Examples of hydrogen internal combustion engines include gasoline engines, diesel engines, gas-turbine engines, and rocket-propulsion systems.

Learn more about Internal combustion engines here:

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A plane is flying with an airspeed of 190 miles per hour and heading 150°. The wind currents are running at 30 miles per hour at 170° clockwise from due north. Use vectors to find the true course and ground speed of the plane. (Round your answers to the nearest ten for the speed and to the nearest whole number for the angle.)

Answers

Answer:

[tex]Vg=200mile/hr[/tex]

[tex]\theta=153 \textdegree[/tex]

Explanation:

From the question we are told that:

Plane airspeed [tex]v_p=190mil/h[/tex]

Plane direction [tex]\angle=150 \textdegree[/tex]

Wind current speed [tex]V_w=30mil/h[/tex]

Wind direction [tex]\angle=150 \textdegree[/tex]

Generally the vector form of the forces is mathematically given by

For plane

[tex]\angle Q_p=90-150 \textdegree[/tex]

[tex]V_p=170(cos60 \textdegree ,sin60 \textdegree)[/tex]

[tex]V_p=(85,-147.224)[/tex]

For wind

[tex]\angle Q_w=90-170 \textdegree[/tex]

[tex]V_w=30(cos-80 \textdegree ,sin-80 \textdegree)[/tex]

[tex]V_w=(5.2,-29.54)[/tex]

Generally the equation for resultant force is mathematically given by

[tex]v_r=V_a+V_w[/tex]

[tex]v_r=(85,-147.224)+(5.2,-29.54)[/tex]

[tex]v_r=(90.21,-176.76)[/tex]

[tex]v_r=198.45\angle -63[/tex]

Therefore ground speed

[tex]V_g=198.5miles/hr[/tex]

[tex]Vg=200mile/hr[/tex]

Direction

[tex]\theta=(90+63)=153 \textdegree[/tex]

[tex]\theta=153 \textdegree[/tex]

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.48 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1840 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.19 V/m, (b) in the negative z direction and has a magnitude of 5.19 V/m, and (c) in the positive x direction and has a magnitude of 5.19 V/m

Answers

Answer:

a)   F = 15.6 10⁻¹⁹  k^   N,  b)  F = -1  10⁻¹⁹  k^   N,

c)  F = (8.3 i^ + 73 k^) 10⁻¹⁹ N

Explanation:

In this exercise we calculate the magnetic and electric force separately.

Let's start by calculating the magnetic force

       F_m = q v x B

where bold letters indicate vectors, the modulus of this expression is

       F_m = q v B

the direction is given by the right hand rule, where the thumb points in the direction of velocity, the fingers are extended in the direction of the magnetic field and the palm is in the directional ne force if the charge is positive

let's calculate the magnitude

      F_m = 1.6 10⁻¹⁹  1840  2.48 10⁻³

      F_m = 7.3 10⁻¹⁹ N

we calculate the direction, the thumb is in the direction of + y,

fingers extended in the direction of -ax

the palm remains + z

therefore the magnetic force is in the direction of the positive side of the z axis

The electric force is

        F_e = q E

give several possibilities for the electric field

a) electric field E = 5.19 V / m in the direction of + z

we calculate

        F_e = 1.6 10⁻¹⁹ 5.19

        F_e = 8.3 10⁻¹⁹ N

the total force is

       F = F_m + F_e

       F = (8.3 k ^ + 7.3 k ^) 10⁻¹⁹

       F = 15.6 10⁻¹⁹  k^   N

b) in the -z direction

       F_e = -8.3 10⁻¹⁹ k^   N

       F = Fm + Fe

       F = (-8.3 k ^ + 7.3 k ^) 10⁻¹⁹

       F = -1  10⁻¹⁹  k^   N

c) in the + x direction

       F_e = 8.3 10⁻¹⁹  i^   N

the total force is

       F = (8.3 i^ + 73 k^) 10⁻¹⁹ N

PLEASE HELP!!!!!!!!!!!!!!!!Match the label with the reason it might be important to the consumers.
1. country of origin
Kelli only buys vegetables grown
without pesticides.
Angie only buys foods made with
2. Organic Certification
sea salt to cut sodium intake.
3. dietary guideline
Nikki prefers to buy local products
to lessen her carbon footprint.

Answers

Answer:

1 is Nikki

2 is Kelli

3 is Angie

Explanation:

Hope this helps!

According to the graph, at which time during a sunny summer day are the
particles in a swimming pool likely to be moving the most quickly?
A. 6:00 p.m.
B. 11:00 p.m.
C. 5:00 a.m.
D. 8:00 a.m.

Answers

6:00 pm your welcome

Answer: A 6:00 pm

Explanation: took the exam

A 1,680 kg satellite is in a circular orbit around Earth with a tangential speed of 6,578 m/s. What is the height of the satellite above the surface of the Earth?

Answers

Answer:

Recall that Earth’s radius is 6.38 × 106 m and Earth’s mass is 5.97 × 1024 kg.

Explanation:

Answer:

A- 2.7 on USA Test prep

Explanation:

Juan is studying a group of cells under a microscope. His teacher tells him that the cells either came from the leaf of a tomato plant or the scale of a lizard. Juan could conclude that the cells came from the tomato plant if they contained?

Answers

Answer:

chloroplasts

Explanation:

How do you find the velocity of a moving car?

Answers

Answer:

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt. Speed (or rate, r) is a scalar quantity that measures the distance traveled (d) over the change in time (Δt), represented by the equation r = d/Δt.

Explanation:

hope this helps a little bit sorry if i got it wrong

Which best summarizes a concept related to the work-energy theorem?
- When work is positive, the environment does work on an object.
- When work is negative, the environment does work on an object.
- When work is positive, the kinetic energy in a system remains constant.
- When work is negative, the kinetic energy in a system remains constant.

this is times pls help!

Answers

Answer:

When work is positive, the environment does work on an object.

Explanation:

According to the work-energy theorem, the net work done by the forces on a body or an object is equal to the change produced in the kinetic energy of the body or an object.

The concept that summarizes a concept related to the work-energy theorem is that ''When work is positive, the environment does work on an object.''

Answer:

Your answer is A!

Have a good day!

10. A pitcher in a professional baseball game throws a fastball, giving the baseball
a momentum of 5.83 kg. m/s. Given that the baseball has a mass of 0.145 kg,
what is its speed?

Answers

Answer: 40.2m/sec

Work: v=p/m= 5.83kg/0.145k=40.2cm/sec

A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position for a -6.0 nC charge.

Answers

Answer: [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.

Explanation:

Given

The magnitude of the first charge is  [tex]Q_1=3.5\ nC[/tex]

The magnitude of the second charge is [tex]Q_2=5\ nC[/tex]

[tex]-6\ nC[/tex] charge must be placed in between the two charges to establish equilibrium

The electrostatic force is given by

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Equilibrium will be established when force by both the charges balance out each other. Suppose [tex]-6\ nC[/tex] is placed at a distance of [tex]x[/tex] cm from [tex]3.5\ nC[/tex] . So, we can write

[tex]\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}[/tex]

Canceling similar terms

[tex]\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm[/tex]

Thus, the equilibrium position is [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.

Answer:

What school do you go to?

Explanation:

Highlight two factors which shows that heat from the sun does reach the earth's surface by convection.

Answers

radiation

when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation

Absence of medium is the factor which shows that heat from the sun does reach the earth's surface by convection.

The heat of the sun reaches the earth only through radiation because radiation does not require any medium for the transfer of energy but convection and conduction required a medium to transfer heat energy.

We know that there is no medium present in vacuum so convection and conduction are impossible in a vacuum that's why the sun's heat does not reach the earth by conduction or convection.

Learn more about convection here: https://brainly.com/question/9382711

Learn more: https://brainly.com/question/22811911

At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant

Answers

Answer:

Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer

answer :  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight of Bananas  = m * g      where g = 9.8

Explanation:

Given an amplitude ( A )= 29.8981

Spring constant = x ( unknown )

maximum speed of Bananas( v ) = wA  ( unknown )

question : calculate the weight of the bananas

First  step : calculate the period of oscillation

T = [tex]\frac{2\pi }{vA}[/tex] --- ( 1 )

next step : express T in terms of mass ( m ) of the bananas

= [tex]2\pi \sqrt{\frac{m}{k} } = \frac{2\pi }{vA}[/tex]

∴ m/k = A^2 / v^2

hence  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight = m * g

Define the types of friction and give FOUR examples of each
Static Friction
Rolling Friction
Sliding Friction
Fluid Friction

Answers

Static Friction is the force that keeps an object at rest
example: pushing against a heavy box but it isnt moving due to the weight of the box and gravity pulling it down

Rolling friction is a resistive force that slows down something thats rolling such as a ball or a wheel
example: a rolling soccer being slowed down from grass

Sliding Friction is the friction created from two object sliding against eachother, just like kinetic friction. It is intended to make the object stop
example: A sled sliding down a hill against snow

Fluid Friction is the force that resist motion in fluid or something moving around a fluid.
example: water pushing against a swimmer when swimming through it

An object has an angular velocity of 1.0 rad and an angular acceleration of 0.5 rad/s. Is the speed of its rotation increasing or decreasing?

Answers

Answer:

increasing

Explanation:

Given that,

Initial angular speed =1 rad/s

Angular acceleration = 0.5 rad/s²

We know that the angular acceleration is given by :

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Where

[tex]\omega_f[/tex]city and t is time is the final angualr velo

As the angular acceleration of the object is positive. It means that the final speed of the object is more than that initial. As a result, the speed of its rotation is increasing.

Please Help Me!!!
Water is a colorless and odorless liquid. It can exist in solid, liquid, and gas states. It boils at 100 degrees C and melts at 0 degrees C.
Which option best describes this information?
A.
These are the physical properties of water.
B.
These are the chemical properties of water.
C.
These are the physical changes water undergoes.
D.
These are the chemical changes water undergoes.
E.
These are the molecular changes water undergoes.

Answers

Answer:

There are the molecular changes water undergoes

A longitudinal wave is a type of wave that transfers energy

Answers

Answer:

It transfers energy parallel to the direction of wave motion. A transverse wave..

Explanation:

Answer:

The answer is a Wave Motion

Explanation:

A longitudinal wave is a type of wave that transfers energy is called," Wave Motion".

Hope you have a great day :)

Which of the following ways of writing 1000w is incorrect?
1) 1 kW
2) 1 x 10³ W
3) 10 x 10³ W
4) 1.0 x 10³ W

Answers

Answer:

the third one is incorrect

Explanation:

10 x 10³= 10^1 x 10^3 = 10^4

A truck with a mass of 15,000 kg moving at 25 m/s crashes into the back of a small 1,100 kg car moving at 15 m/s. They
stick together after the collision. Calculate the momentum of the system before the collision and after the collision.

Answers

Explanation:

Given that,

Mass of a truck = 15,000 kg

Speed of the truck = 25 m/s

Mass of car = 1,100 kg

Speed of the car = 15 m/s

As they stick together after the collision. Let V be the speed after the collision.

Initial momentum of the system,

[tex]P_i=15000\times25+1100\times15\\\\=391500\ kg-m/s[/tex]

Final momentum of the system,

[tex]P_f=(15000+1100)V\\\\=16100V[/tex]

Hence, this is the required solution.

Is telekinesis real??? I really wanna start learning it!

Answers

Answer:

Highly doubt something that requires great focus and mental strength exists

9.) This 200 kg
stag that weighs
1,960 N on earth
would only weigh
324 N on the
moon. Calculate the moon's
acceleration due to gravity.

Answers

Answer:

Mass on moon = 33.06 kg

Explanation:

Given the following data;

Mass on earth = 200 kg

Weight on earth = 1960 N

Weight on moon = 324 N

To find the mass on moon;

First of all, we would determine the acceleration due to gravity.

Weight = mass * acceleration due to gravity

1960 = 200 * g

g = 1960/200

g = 9.8 m/s²

Next, we find the mass on moon;

Mass on moon = weight on moon/acceleration due to gravity

Mass on moon = 324/9.8

Mass on moon = 33.06 kg

A spring of force constant 1500 Nm-l is acted
upon by a constant force of 75 N. Calculate
the potential energy stored in the spring.​

Answers

Answer:

1.876 J

Explanation:

First, let’s calculate the compression of the spring from the Hooke’s law:

F=kx,

here, F=75 N is the force acted on the spring, k=1500 N⁄m is the force constant of the spring, x is the compression of the spring.

Then, we get:

x=F/k=(75 N)/(1500 N/m)=0.05 m.

Finally, we can find the potential energy stored in the spring:

PE=1/2 kx^2=1/2∙1500 N/m∙(0.05 m)^2=1.875 J.

correct my answer if it's wrong ^^

An object has an acceleration of 18.0 m/s/s. If the net force acting upon this object were doubled, then its new acceleration would be m/s/s.​

Answers

Answer:

36.m/s/s

Explanation:

A 1.80-kg object is attached to a spring and placed on frictionless, horizontal surface. A horizontal force of 15.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations.
(a) Find the force constant of the spring.
N/m

(b) Find the frequency of the oscillations.
Hz

(c) Find the maximum speed of the object.
m/s

(d) Where does this maximum speed occur?
x = ±
m

(e) Find the maximum acceleration of the object.
m/s2

(f) Where does the maximum acceleration occur?
x = ±
m

(g) Find the total energy of the oscillating system.
J

(h) Find the speed of the object when its position is equal to one-third of the maximum value.
m/s

(i) Find the magnitude of the acceleration of the object when its position is equal to one-third of the maximum value.
m/s2

Answers

Answer:

Explanation:

(a) Force constant = force/displacement = 15/0.2

=75 N/m

(b) For SHM with spring, the angular frequency = sqrt ( force constant / mass )

= sqrt ( 75 / 1.8 )

= 6.455

Frequency = Angular frequency / 2pi

= 1.03Hz

(c) Maximum speed is when object's potential energy is at minimum.

1/2*mass*speed^2 = 1/2*force constant*displacement^2

speed^2 = 75*0.2^2/1.8 = 1.67

speed = sqrt (1.67)

= 1.29 m/s

(d) It occurs at x=0

(e) Maximum acceleration = Force / m = 15/1.8

= 8.33 m/s^2

(f) It occurs at x=0.2m

Answer:

Explanation:

given:

The mass of the object attached to the spring: m = 1.80 kg

The magnitude of the maximum horizontal force exerted: F = 15.0 N

The amplitude of the spring-object oscillation: A = 0.200 m

a. k=15/.2=75N/m

b. (2pi*frequency)^2 = k/m = 75/1.8 = 41.67

frequency = 1.03Hz

c. max speed^2 = amplitude^2*k/m = 0.2^2 * 41.67

max speed = 1.29 m/s

d. x=0m

e. max accel = F/m = 15/1.8 = 8.33 m/s^2

f. x=0.2m

e. energy = 1/2*k*A^2

= 1/2*75*0.2^2

= 1.5J

Tyson has been assigned to the offensive line as a left guard on his football team which requires him to make explosive movements and push other players body weight in a specific direction. Which sport skill does he demonstrate as his dominant skill based on this position assignment?

Answers

Answer:

The answer is power.

Explanation:

because in the reading it says it's his dominant skill.

and beacuse i got it right on the test.

Answer:

The answer is power.

Explanation:

1. The movement of water between the oceans, atmosphere, land, and living things is the ______________________.
2. The changing of water from liquid to vapor is called ______________________.
3. During ______________________, water vapor cools and returns to a liquid state.
4. Water that falls from the atmosphere to the land and oceans is called ______________________.
5. Precipitation that falls on land and then flows into streams, rivers, and lakes is called ______________________.
6. Precipitation that seeps into the ground and is stored among rocks is called ______________________.
7. Water vapor is released by plants and returned to the environment in a process called ______________________.
8. Name three reasons water is needed for life on Earth.

Answers

3 reasons water needed for earth: keep oceans going, liquid, and help earth with poloution

Is this right? Please help me ITS SOCIOLOGY

Answers

Yes, this is correct Answer.

A machine raised a load of 360N through a distance of 0.2m. The effort, a force of 50N moved 1.8m during the process. Calculate the efficiency of the machine.
Select one:
a. 40%
b. 100%
c. 80%
d. 60%

Answers

Answer:

c. 80%

Explanation:

Given;

load raised by the machine, L = 360 N

distance through which the load was raised, d = 0.2 m

effort applied, E = 50 N

distance moved by the effort, e = 1.8 m

The efficiency of the machine is calculated as follows;

[tex]Efficiency = \frac{ 0utput \ work }{1nput \ work} \times 100\% \\\\Efficiency = \frac{Load \ \times \ distance \ moved \ by \ load }{Efort \ \times \ distance \ moved \ by \ effort} \times 100\%\\\\Efficiency = \frac{360 \times 0.2}{50 \times 1.8} \times 100\%\\\\Efficiency =80\%[/tex]

Therefore, the efficiency of the machine is 80%

Which of these statements are true about hydroelectric power? A.It is the most widely used renewable energy source in the world. B.It never disrupts ecosystems. C.It is not always available. D.A hydroelectric dam controls the force of moving water to generate electricity.

Answers

D is the answer most true

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration

Answers

Answer:

1 m/s²

Explanation:

From the question,

Using

a = (v-u)/t.................... Equation 1

Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.

Given: v = 15 m/s, u = 5 m/s, t = 10 s

Substitute these values into equation 1

a = (15-5)/10

a = 10/10

a = 1 m/s²

Hence the acceleration of the bicycle is 1 m/s²

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