Paano mo mapapanatili na gumagana ang iyong negosyo sa gitna ng pandemic na ito?​

Answer:

[tex]\boxed {\boxed {\sf 1.6 \times 10^{24} \ atoms \ Si}}[/tex]

Explanation:

We are asked to find how many atoms are in a sample of 75 grams of silicon.

First, we must convert grams to moles using the molar mass. This is the mass of 1 mole of a substance. The molar mass is found on the Periodic Table because it is equal to the atomic mass, but the units are grams per mole instead of atomic mass units.

Look up the molar mass of silicon.

We convert using dimensional analysis, so we must set up a conversion factor.

[tex]\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

We are converting 75 grams of silicon to moles, so we multiply by this value.

[tex]75 \ g \ Si*\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

Flip the conversion factor so the units of grams of silicon cancel.

[tex]75 \ g \ Si*\frac {1 \ mol \ Si}{28.085 \ g \ Si}[/tex]

[tex]75 *\frac {1 \ mol \ Si}{28.085 }[/tex]

[tex]\frac {75}{28.085} \ mol \ Si[/tex]

[tex]2.670464661 \ mol \ Si[/tex]

Next, we convert moles to atoms using Avogadro's Number, or 6.022 ×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this problem, the particles are atoms of silicon.

Set up another conversion factor, this time with Avogadro's Number.

[tex]\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}[/tex]

Multiply by the number of moles we found.

[tex]2.670464661 \ mol \ Si*\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}[/tex]

The units of moles of silicon cancel.

[tex]2.670464661 *\frac {6.022 \times 10^{23} \ atoms \ Si}{1 }[/tex]

[tex]2.670464661 * {6.022 \times 10^{23} \ atoms \ Si}[/tex]

[tex]1.60815382 \times 10^{24} \ atoms \ Si[/tex]

The original value of grams (75) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredths place tells us to leave the 6 in the tenths place.

[tex]1.6 \times 10^{24} \ atoms \ Si[/tex]

Answer:

cpd 2

Explanation:

aldehyde is such a cpd which contains an alkyle gp with the formula R-CH=O

Functional group can be interconverted into each other by the means of suitable reagent. Functional group are responsible for the chemical and physical properties of a compound. Therefore the correct option is option 2 that is having group  R-CHO.

A group of atoms forming a component of a molecule that accounts for a particular function or chemical behavior is called a functional group. There are so many functional group in organic chemistry.

The list of functional groups with their corresponding formulas can be given as

Carboxylic group COOH

Alcoholic group OH

Ammine group NH₂

Ketonic group R-CO_R

Aldehydic group R-CHO

Thiol group R-S-H

Cyanide group -CN

Therefore the correct option is option 2 that is having group  R-CHO.

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[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The atomic number of the shown element Al (Alluminium) is ~

Explanation:

atomic number = no. of protons = 13

therefore atomic number of aluminium is 13 as given

so option D 13 is correct option .

hope this answer helps you dear! take care

Answer:

B. Activated Carbon

Explanation:

Answer:

D

Explanation:

Answer:

for plato users, the answer is: give the plant structure and support

Answer:

880.5

Explanation:

Express the result of adding 856.6g and 23.86g to the correct number of significant figures.

856.6 +23.86  = 856.6 + 23.9 = 880.5

The result of adding 856.6 g and 23.86 g after rounding off to correct significant figures is 856.6 + 23.9=880.5.

Significant figures are used for establishment  of a number which is presented in the form of digits. These digits give a meaningful representation  to the numbers.

The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:

1)All non-zero digits are significant .

2)All zeroes which occur between non-zero digits are significant.

3)All zeroes to the left and right of  a non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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[tex]\boxed{\sf °F=\dfrac{9}{5}°C+32}[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{9}{5}(197)+32[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{1773}{5}+32[/tex]

[tex]\\ \sf\longmapsto °F=354.6+32[/tex]

[tex]\\ \sf\longmapsto °F=386.6°F[/tex]

[tex]\rule{200pt}{5pt}[/tex]

[tex]\boxed{\sf K=°C+273}[/tex]

[tex]\\ \sf\longmapsto K=197+273[/tex]

[tex]\\ \sf\longmapsto K=470K[/tex]

The pressure of hydrogen gas produced is 0.997 atm

Using the standard table of temperature and water vapour pressure;

Recall that:

[tex]\mathbf{P_{moist \ gas} = P_{dry \ gas} + P_{water vapor}}[/tex]

where;

[tex]\mathbf{ P_{dry \ gas} = P_{moist \ gas} - P_{water vapor}}[/tex]

[tex]\mathbf{ P_{dry \ gas} = (786- 28.3) mmHg}}[/tex]

[tex]\mathbf{ P_{dry \ gas} = (757.7) mmHg}}[/tex]

We know that 1 atmospheric pressure = 760 mmHg

∴

757.7 mmHg will be:

[tex]\mathbf{=\dfrac{757.7 \ mmHg \times 1 \ atm}{760 \ mmHg}}[/tex]

= 0.997 atm

Therefore, we can conclude that the pressure of hydrogen gas produced is 0.997 atm

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The answer to the question is 14 no cap

Answer:

one Sodium (Na) atom, two oxygen (O) atoms, two carbon (C) atoms, and three hydrogens (H) atoms

Explanation:

Answer:

Refer to the attachments!!

Explanation:

Answer:

Before we can sketch the Lewis structures of molecules, we must first understand the octet rule. The octet rule asserts that when atoms combine to create compounds, electrons are gained, lost, or shared among them, resulting in a stable electron configuration defined by eight valence electrons as a result. These rules are used in conjunction with the main-group components of the second period.

Explanation:

Hope it helps:)

Answer:

First option

Explanation:

The option that says CH3CH2CH2CH3 is the correct option (I hope that I am right because the order of the answers is not very clear :/)

Answer:

using Charles law

v1/t1= v2/ t2

Explanation:

875/t1=955/56+273

t1= 329* 875/955

t1= 302.82k

The initial temperature of the hot air balloon can be calculated from Charles's law. The initial temperature of the balloon was, 51.3 °C.

According Charles's law, at constant pressure, the temperature and volume of a gas is in direct proportionality. Thus volume increases with an increase in temperature. Therefore V/T = a constant.

Let V₁ and T₁ be the initial volume and initial temperature and V₂ and T₂ be the final volume and temperature respectively. Thus we can write the relation as:

V₁ /T₁  = V₂/T₂ .

Given that the initial and final volume are 875 L and 955 L respectively. The final temperature is 56 °C. Thus the initial temperature is calculated as :

T₁ = V₁T₂/V₂

   = (875 L × 56 °C )/955 L

   = 51.3 °C.

Hence, the initial temperature of the hot air balloon was 51.3 °C.

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The best way to balancing a combustion equation of an organic compound, like the one in the question, is to start balancing the carbon, then the hydrogen and finish with the oxygen. For that you have to split the hydrocarbon into individual elements. And once you have finished you shall always try to reduce the coefficient if possible. Therefore, the answers are A. and C.

This problem is asking for the consumption of silver ions when silver nitrate is reacted with copper. In such a case, since no masses are given, we can use the following from similar problems:

Mass of empty beaker: 110.000 g

Mass of beaker with silver nitrate (after all additions) and copper: 331.634 g.

Mass of beaker with silver: 113.395 g.

This means we can write the following chemical equation:

[tex]Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag[/tex]

And thus calculate the mass of silver nitrate that will produce the following mass of silver:

[tex]m_{Ag}^{produced}=113.395g-110.000g=3.395g[/tex]

Next, we use the 2:2 mole ratio of silver to silver nitrate (silver ions source):

[tex]3.395gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg} *\frac{169.87gAgNO_3}{1molAgNO_3} = 5.35gAgNO_3[/tex]

The step will be defined for the given mass of available silver nitrate which will be compared to 5.35 g (consumed mass) to see if they are the same (all consumed) or different (partial consumption).

Learn more:

Answer:

chemical reaction

Explanation:

The chemical reaction produces chemical changes to provide energy. Chemical reactions often involve changes in energy due to the breaking and formation of bonds.

Answer:

The answer is A and B

Explanation:

Answer:

barium chloride (BaCl2) is added to sodium carbonate (Na2CO3). The result is a white precipitate.

Explanation:

Answer:approximately 5.627 × 1019 milliliters

Explanation:

Answer:

337.5 g NaCl

Explanation:

.90% saline solution = 90g saline (NaCl)/100mL water (H2O)

1. Use 375 mL to find mass

375 mL × (90 g NaCl/100 mL) = 337.5 g NaCl in 375 mL .9% saline solution

The amount of sodium chloride dissolved in 375 ml of a 0.90% saline solution is 337.5 g.

The concentration can be calculated when we have the molecular formula and its molecular weight. The concentration of the solution is calculated as the weight of a solute divided by the volume of the solution.

The weight/volume percentage of the solution is determined in the following way.

W/v (%) = weight of the solute/Volume of the Solution ( in mL)

Given, the concentration of the saline solution = 0.90 %

0.90 % saline solution means 90 g of NaCl is dissolved in 100 ml of water.

Given, the volume of solution = 375 ml

100 ml of saline solution containing NaCl = 90 g

Then 375 ml of saline solution containing NaCl = 90 ×375/100 = 337.5 g

Therefore, the amount of NaCl is equal to 337.5 g.

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Answer:

it doesn't house the sweat and oil glands

Explanation:

the epidermis doesn't house the oil and sweat glands but the dermis does

Explanation:

no sé de qué me estás hablando

This is a precipitation reaction and 1.38 g of the precipitate will be formed is the statement is correct. Hence, option C is correct.

A precipitation reaction is when two or more dissolved chemicals combine to form one solid products. The exchange of ions between ionic compounds in aqueous solutions is a common component of these reactions, which are also occasionally referred to as double displacement, double replacement, or metathesis reactions.

in response to precipitation a process that converts soluble salts into solids that are insoluble in water. a neutralizing response an interaction between an acid and a base that results in the production of salt, water, and an ionic molecule.

Precipitate refers to a solid that forms from a solution. The blending of two transparent solutions is a common example: NaCl in combination with silver nitrate The answer is. The soli cannot be dissolved in water.

Thus, option C is correct.

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Answer:

385 cm^3

Explanation:

375cm3 of a gas has a pressure of 770 mm Hg, find it Volume if the pressure is reduced to 750 mm Hg

​if we reduce the pressure, the volume increase since since PV is constant

so the new volume = 0.375 cm^3 X 770/750 = 385 cm^3

63

Answer:

Beryllium, carbon, and oxygen do not create stars like the sun. The sun is a massive cluster of hydrogen atoms being fused into helium atoms and heavier metals like Beryllium, carbon, and oxygen through the process of nuclear fusion. The more mass a star has in its core the more fusions that can occur and the heavier the metals inside can be fused into.

Explanation:

hope this helps. . . <3

good luck!     uωu

Answer:

The bowling ball has kinetic energy as it moves toward the pins.

Explanation:

Answer:

Most of it is transferred to the pins, but some of it is changed into heat and sound energy.

Explanation:

study island

Answer:

see explanation

Explanation:

An AX₂E₂ geometry is derived from an AX₄ parent geometry and is based upon 4 regions of electron density about the central element and defines a tetrahedral geometry and the geometry is bent angular.

An example is the water molecule (H₂O) with two covalent O - H bonds and two free pair electrons on the central oxygen element.