(Not a question) Doesn't matter what people say about you you shouldn't care about what other people say or talk about if it's natively! PRAY THE HARDEST WHEN ITS THE HARDEST to PRAY!!!!

Answer:

The main demographic factors that predict an increase in the fiscal deficit in the future are, on the one hand, the progressive aging of baby boomers, who reach retirement age and withdraw from the labor market, thereby beginning to withdraw their funds. pension; and on the other hand, the low birth rate that began to be experienced in the 1990s, with which the population proportion of working people is increasingly lower, with which the government collects less taxes and has the need to maintain to more people.

For a particle with some position function y(t), we're given its velocity function v(t) = 1 - tan⁻¹(eᵗ ) and we're told that it starts with a position of y = -1 at the start.

(a) Acceleration is the rate of change of velocity, so to get the acceleration function a(t), you have to differentiate v(t) :

a(t) = d/dt v(t)

a(t) = d/dt [1 - tan⁻¹(eᵗ )]

a(t) = - d/dt [tan⁻¹(eᵗ )]

Apply the chain rule: take f(u) = tan⁻¹(u) and u(t) = eᵗ, so that

df/dt = df/du × du/dt

→   a(t) = - 1/(1 + u ²) × eᵗ = - eᵗ / (1 + e²ᵗ )

Then when t = 2, the acceleration is

a (2) = - e² / (1 + e⁴) ≈ -0.1329

(b) The acceleration of the particle at t = 2 is negative, so the particle's speed at this moment is decreasing. (Recall the first derivative test.)

(c) Note that at t = 0, the particle's velocity is v (0) = 1 - tan⁻¹(e⁰) = 1 - π/4 ≈ 0.2416 > 0. This means that the particle is moving upward at the start.

From part (a), we see that the acceleration is always negative, so the particle would be slowing down until it reaches zero velocity, after which point its velocity will become negative (meaning its speed would increase again as it starts to accelerate in the negative direction).

This means the particle's highest position on the y-axis occurs at the same time v(t) becomes 0, so you solve:

1 - tan⁻¹(eᵗ ) = 0

1 = tan⁻¹(eᵗ )

tan(1) = tan(tan⁻¹(eᵗ ))

tan(1) = eᵗ

ln(tan(1)) = ln(eᵗ )

ln(tan(1)) = t ≈ 0.443

(d) Use the fundamental theorem of calculus to find an expression for y(t) :

y(t) = y (0) + ∫₀ᵗ v(s) ds

(where s is just a dummy variable)

Then the particle's position at t = 2 is

y (2) = y (0) + ∫₀² v(s) ds

v(t) unfortunately does not have a nice antiderivative, so you'll have to use a calculator. (I hope this question is given in the calculator portion!) You would find

∫₀² v(s) ds ≈ -0.3607

so that

y (2) ≈ -1 + (-0.3607) ≈ -1.3607

The sign of the particle's velocity at this time tells you in which way the particle is moving. We have

v (2) = 1 - tan⁻¹(e²) ≈ -0.4363

which is negative, so the particle is moving away from the origin. This is consistent with the answer found in part (c):

• before t ≈ 0.443, the particle is moving upward toward the origin;

• at t ≈ 0.443, the particle reaches its highest point at y (2) ≈ -1.3607, then turns around and accelerates back downward and away from the origin

Answer:

True

Explanation:

Some  clinicians are able to develop a clearer understanding of a future patient if the patient already has a prior diagnosis is a true statement.

The term clinician is known to be any individual who has been qualified in the area or job of clinical practice such as medicine, psychiatry, etc.

Note that clinicians are people who are able to develop a clearer understanding of a future patient if the patient already has a previous diagnosis.

Learn more about clinicians from

https://brainly.com/question/2926684

The confidence interval that is contained in the question shows that at 99% confidence, the interval falls between 0.43354,  0.5093

The sample size of the population is given as 1152

x = 543 that support the buy pas

We have to find the proportion

p = 543/1152

= 0.4714

α = 1 - 99%

= 0.01

α/2 = 0.01/2

= 0.005

Zα/2 = 2.5758

In order to calculate this you have to use the critical value calculator on excel

[tex]0.4714+-\frac{\sqrt{0.4714(1-0.4714)} }{1152}[/tex]

0.4714 ± √0.0002163

0.4714 ± 0.0147x2.5758

0.4714 ± 0.03786

0.43354,  0.5093

Read more on confidence interval here: https://brainly.com/question/16974109