Answer:
H0 : μd = 0
H1 : μd ≠ 0
Test statistic = 0.6687 ;
Pvalue = 0.7482 ;
Fail to reject H0.
Step-by-step explanation:
H0 : μd = 0
H1 : μd ≠ 0
Given the data:
Before: 15 26 66 115 62 64
After: 16 24 42 80 78 73
Difference = -1 2 24 35 -18 -9
Mean difference, d ; Σd / n
d = Σx / n = ((-1) + 2 + 24 + 35 + (-18) + (-9))
d = Σx / n = 33 / 6 = 5.5
Test statistic = (d / std / sqrt(n))
std = sample standard deviation = 20.146
Test statistic = 5.5 ÷ (20.146/sqrt(6))
Test statistic = 0.6687
The Pvalue :
P(Z < 0.6687) = 0.7482
At α = 0.05
Pvalue > α ; Hence we fail to reject H0
The data does not suggest a significant mean difference in the average number of accidents after information was added to road signs.
1. Kathy is building a bed for her dollhouse. She used her real bed as a guide for how to
create the dollhouse bed. Her bed is 36 inches wide and 60 inches long. If she wants
to scale this down by 1/10, what would be the dimensions of the dollhouse bed?
Explain how you got your answer.
*Use the term SCALE FACTOR in your explanation.
PLS ANSWER QUICKLY !!!
solve 7!!!!!!!!!!!!!!!!!!!!!!!
Answer:
?
Step-by-step explanation:
Drag each tile to the table to multiply
(6x – y)(2x – y + 2).
fill the table
2x -y 2
6x 12^2 -6xy 12x
-y -2xy y^2 -2y
The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the garden
Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
Hope it helps :)
Answer:
Step-by-step explanation:
Width = w
Length = 2w + 8
Area of rectangular garden = 280 square meter
length * width = 280
(2w + 8 ) *w = 280
2w * w + 8*w = 280
2w² + 8w = 280
2w² + 8w - 280 = 0
Divide the whole equation by 2
w² + 4w - 140 = 0
w² + 14w - 10w - 14 *10 = 0
w(w + 14) - 10(w + 14) = 0
(w + 14)(w - 10)= 0
w - 10 = 0 {Ignore w + 14, as measurements will not be -ve}
w = 10 m
l = 2*10 +8
= 20 +8
l = 28 m
Solve for x.
3x - 4 = 2x - 10
O x = 6
OX= -6
OX= 14
O x=-14
Please help
Will give you brainly
Answer:
x = -6
Step-by-step explanation:
We have the equation 3x - 4 = 2x - 10 and are asked to find "x".
To solve , we need to get "x" alone entirely.
3x - 4 = 2x - 10
Subtract 2x from both sides :
x - 4 = -10
Add 4 to both sides to get our answer :
x = -6
Answer:
the answer is equal to-6
17% adults favor the use of unmanned drones by police agencies. Twelve U.S. adults are randomly selected. Find the probability that the number of U.S. adults who
favor the use of unmanned drones by police agencies is (a) exactly three, (b) at least four, (c) less than eight
(a) P(3)=(Round to three decimal places as needed)
(b) P(x24) =(Round to three decimal places as needed.)
(c) P(x<8)=(Round to three decimal places as needed.)
Answer:
Following are the solution to these question:
Step-by-step explanation:
Following are the binomial distribution with parameters:
[tex]n = 12\\\\p = 0.24[/tex]
For point a:
[tex]\to P(X = 3) = binom.dist(3, 12, 0.24, False) = 0.2573[/tex]
For point b:
[tex]\to P(X > 4) = 1 - P(X < 3) = 1 - binom.dist(3, 12, 0.24, True) = 0.3205[/tex]
For point c:
[tex]\to P(<8) = binom.dist(7, 12, 0.24, True) = 0.9979[/tex]
if we use the quadratic expression below to complete a diamond, what value will go at every bottom of the diamond
a. -4
b. 4
c. 1
d. 5
Answer:
if we use the quadratic expression below to complete a diamond, what value will go at every bottom of the diamond
is -4
Answer:
if we use the quadratic expression below to complete a diamond, what value will go at every bottom of the diamond
its 1 because
Find the limit when X approaches zero
2xsinx/1-cosx
Answer:
4
Step-by-step explanation:
[tex] Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}\times \frac{1+\cos x}{1+\cos x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1^2 -\cos^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1 -\cos^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{sin^2 x} [/tex]
[tex] =Lim_{x \to 0}\frac{2x(1+\cos x) }{sin x} [/tex]
[tex] =Lim_{x \to 0} 2(1+\cos x) \times \frac{1}{Lim_{x \to 0}\frac{sin x}{x}} [/tex]
[tex] =2(1+\cos 0) \times 1 [/tex]
[tex] = 2(1+1) [/tex]
[tex] = 2(2) [/tex]
[tex] \therefore Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}= 4 [/tex]
Determine the equation of a circle with center at (8, 10) and radius is 6
Need help with this if possible
Answer:
hope it helps...
Step-by-step explanation: