17% adults favor the use of unmanned drones by police agencies. Twelve U.S. adults are randomly selected. Find the probability that the number of U.S. adults who

favor the use of unmanned drones by police agencies is (a) exactly three, (b) at least four, (c) less than eight

(a) P(3)=(Round to three decimal places as needed)

(b) P(x24) =(Round to three decimal places as needed.)

(c) P(x<8)=(Round to three decimal places as needed.)

Answers

Answer 1

Answer:

Following are the solution to these question:

Step-by-step explanation:

Following are the binomial distribution with parameters:

[tex]n = 12\\\\p = 0.24[/tex]

For point a:

[tex]\to P(X = 3) = binom.dist(3, 12, 0.24, False) = 0.2573[/tex]

For point b:

[tex]\to P(X > 4) = 1 - P(X < 3) = 1 - binom.dist(3, 12, 0.24, True) = 0.3205[/tex]

For point c:

[tex]\to P(<8) = binom.dist(7, 12, 0.24, True) = 0.9979[/tex]


Related Questions

1. Kathy is building a bed for her dollhouse. She used her real bed as a guide for how to
create the dollhouse bed. Her bed is 36 inches wide and 60 inches long. If she wants
to scale this down by 1/10, what would be the dimensions of the dollhouse bed?
Explain how you got your answer.
*Use the term SCALE FACTOR in your explanation.


PLS ANSWER QUICKLY !!!

Answers

The answer to the question is Ashby

Determine the equation of a circle with center at (8, 10) and radius is 6​

Answers

Use the equation ( x - h ) ^ 2 + ( y - k ) ^2 = r ^2
Where (h,k) is the center and the r is the radius . So the equation is as follows
( x- 8 ) ^2 + ( y -10 ) ^ 2 = 6^2

Hope this helped

The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the garden

Answers

Step-by-step explanation:

Given :-

The length of the garden 8m greater than 2 times the width.

Area of the garden is 280 m²

Let us consider the length as x and width as y.

Sp, we can day length as :-

x = 8 + 2y ---(1)

Now, we know that:-

Area of Rectangle = Length × Breadth

280 = x * y

We can replace the value of x now,

280 = y × ( 8 + 2y)

280 = 8y + 2y²

2y² + 8y - 280 = 0

y² + 4y - 140 = 0

Factorise it.

(y -10)(y + 14)

Cancelling -ve value, we get the width as 10 metres.

Hope it helps :)

Answer:

Step-by-step explanation:

Width = w

Length = 2w + 8

Area of rectangular garden = 280 square meter

length * width = 280

(2w + 8 ) *w = 280

2w * w + 8*w = 280

2w² + 8w = 280

2w² + 8w - 280 = 0

Divide the whole equation by 2

w² + 4w - 140 = 0      

w² + 14w - 10w - 14 *10 = 0

w(w + 14) - 10(w + 14) = 0

(w + 14)(w - 10)= 0

w - 10 = 0       {Ignore w + 14, as measurements will not be -ve}

w = 10 m

l = 2*10 +8

= 20 +8

l  = 28 m

Need help with this if possible ​

Answers

Answer:

hope it helps...

Step-by-step explanation:

Solve for x.
3x - 4 = 2x - 10
O x = 6
OX= -6
OX= 14
O x=-14
Please help
Will give you brainly

Answers

Answer:

x = -6

Step-by-step explanation:

We have the equation 3x - 4 = 2x - 10 and are asked to find "x".

To solve , we need to get "x" alone entirely.

3x - 4 = 2x - 10

Subtract 2x from both sides :

x - 4 = -10

Add 4 to both sides to get our answer :

x = -6

Answer:

the answer is equal to-6

solve 7!!!!!!!!!!!!!!!!!!!!!!!

Answers

ummmmm what? Is this a troll or something

Answer:

?

Step-by-step explanation:

Drag each tile to the table to multiply
(6x – y)(2x – y + 2).

Answers

fill the table

2x -y 2

6x 12^2 -6xy 12x

-y -2xy y^2 -2y

Find the limit when X approaches zero
2xsinx/1-cosx

Answers

Answer:

4

Step-by-step explanation:

[tex] Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x} [/tex]

[tex] =Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}\times \frac{1+\cos x}{1+\cos x} [/tex]

[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1^2 -\cos^2 x} [/tex]

[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{1 -\cos^2 x} [/tex]

[tex] =Lim_{x \to 0}\frac{2 x\sin x(1+\cos x) }{sin^2 x} [/tex]

[tex] =Lim_{x \to 0}\frac{2x(1+\cos x) }{sin x} [/tex]

[tex] =Lim_{x \to 0} 2(1+\cos x) \times \frac{1}{Lim_{x \to 0}\frac{sin x}{x}} [/tex]

[tex] =2(1+\cos 0) \times 1 [/tex]

[tex] = 2(1+1) [/tex]

[tex] = 2(2) [/tex]

[tex] \therefore Lim_{x \to 0}\frac{2 x\sin x}{1-\cos x}= 4 [/tex]

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