Engineering College

Knowing that the central portion of the link BD has a uniform cross-sectional area of 800 2, determine the magnitude of the load P for which the normal stress in that portion of BD is 50 .

Answers

Answer 1

Answer: 50

Explanation:

Related Questions

In warm climates, a vapor barrier is placed on the exterior side of the insulation, and in cold climates it is installed on the interior side of the
insulation. Which of the following explains this placement of the barrier?
The barrier should always be placed on the side opposite from where the water condenses.
The barrier should always be placed on the side opposite where rain or snow hit.
The barrier should always be placed on the side where rain or snow hit.
The barrier should always be placed on the side where the water condenses

Answers

Answer: its c

Explanation:

Which statements describe the motion of car A and car B? Check all that apply. Car A and car B are both moving toward the origin. Car A and car B are moving in opposite directions. Car A is moving faster than car B. Car A and car B started at the same location. Car A and car B are moving toward each other until they cross over.

Answers

Answer:

car a is moving faster than the car b

Answer:

B: Car A and car B are moving in opposite directions.

C: Car A is moving faster than car B.

E: Car A and car B are moving toward each other until they cross over.

Explanation:

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Fig_Q5
6. A steel rod is stressed by a tension force of 250 N. It is found that the rod has length of 45
m and diameter of 1.5 mm. If the modulus of elasticity of the steel rod is assumed as 2 x 105
MPa, determine the strain of the steel rod due to the applied force.

Answers

Answer:

The strain of the steel rod due to the applied force is 41.93

Explanation:

Modulus of elasticity is equal to stress divided by strain.

And stress is equal to force divided by area

Surface area of cylindrical rod

[tex]2\pi r (r+h)[/tex]

Substituting the given values we get -

[tex]2 *3.14 * \frac{1.5}{1000} * 45 (45 + \frac{1.5}{1000}) = 19.07[/tex]

[tex]2 * 10 ^5 = \frac{250}{19.07 * S=(\frac{\Delta L}{L} )}[/tex]

Hence, strain is equal to

Strain = 41.93

Combinations of velocity and acceleration

Answers

Answer:

acceleration=change in velocity/ time

Explanation:

The velocity of an object is its speed in a particular direction. Velocity is a vector quantity because it has both a magnitude and an associated direction. To calculate velocity, displacement is used in calculations, rather than distance.

2. (Problem 4.60 on main book, diameters different) Water flows steadily through a fire hose and nozzle. The hose is 35 mm diameter and the nozzle tip is 25 mm diameter; water gage pressure in the hose is 510 kPa, and the stream leaving the nozzle is uniform. The exit speed and pressure are 32 m/s and atmospheric, respectively. Find the force transmitted by the coupling between the nozzle and hose. Indicate whether the coupling is in tension or compression.

Answers

Answer:

coupling is in tension

Force = -244.81 N

Explanation:

Diameter of Hose ( D1 ) = 35 mm

Diameter of nozzle ( D2 ) = 25 mm

water gage pressure in hose = 510 kPa

stream leaving the nozzle is uniform

exit speed and pressure = 32 m/s and atmospheric

Determine the force transmitted by the coupling between the nozzle and hose

attached below is the remaining part of the  detailed solution

Inlet velocity ( V1 ) = V2 ( D2/D1 )^2  

= 32 ( 25 / 35 )^2

= 16.33 m/s

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