Jeff Brown has collected sales data for his cupcake stand. Calculate the exponential smoothing forecast for period 13 with α = 0.4. And F2 = A1. Round your answers to 2 decimals. Time 1 2 3 4 5 6 7 8 9 10 11 12 Sales 48 41 37 32 36 31 43 52 60 48 41.9 29.7

Answer:

The exponential smoothing forecast for period 13 = 39.68

Step-by-step explanation:

As given,

[tex]\alpha[/tex] = 0.4

Time                 Sales                              forcast

1                            48                                  

2                           41                                 48

3                           37                                 48 + [tex]\alpha {(41 - 48)}[/tex] = 45.2

4                           32                                 45.2 + [tex]\alpha {(37 - 45.2)}[/tex] = 41.92

5                           36                                 41.92 + [tex]\alpha {(32 - 41.92)}[/tex] = 37.95

6                           31                                 37.95 + [tex]\alpha {(36 - 37.95)}[/tex] = 37.17

7                            43                                 37.17 + [tex]\alpha {(31 - 37.17)}[/tex] =  34.70

8                           52                                 34.70 + [tex]\alpha {(43 - 34.70)}[/tex] = 38.02

9                           60                                 38.02 + [tex]\alpha {(52 - 38.02)}[/tex] = 43.61

10                          48                                 43.61 + [tex]\alpha {(60 - 43.61)}[/tex] = 50.17

11                           41.9                                 50.17 + [tex]\alpha {(48 - 50.17)}[/tex] = 49.30

12                           29.7                                 49.30 + [tex]\alpha {(41.9 - 49.30)}[/tex] = 46.34

13                                                                    46.34 + [tex]\alpha {(29.7 - 46.34)}[/tex] = 39.68

∴ we get

The exponential smoothing forecast for period 13 = 39.68

answer asap please!!

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