in which diagram 1 or 2 would the person be experiencing winter? explain​

Answer:

Acceleration = 0.5 m/s²

Explanation:

Given the following data;

Initial velocity, u = 1m/s

Final velocity, v = 3m/s

Time, t = 4 seconds

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

[tex]a = \frac{v - u}{t}[/tex]

Substituting into the equation, we have;

Acceleration = (3 - 1)/4

Acceleration = 2/4

Acceleration = 0.5 m/s²

Answer:

the amount of mass needed is:  4.5 10^9 kg

Explanation:

Use the given equation:

E = m * c^2

with E = 1.35 * 10^(18)  J

and c = 3 * 10^8 m/s

and solve for the mass as shown below:

m = 1.35 * 10^(18) / 3 * 10^8 ≈ 4.5 10^9 kg

Answer:

30m³

Explanation:

Calculation for the volume the balloon would have

First step is to calculate the Constant

Constant=30pka*5m³

Constant=150m³

Now let calculate the Volume using this formula

Balloon Volume=Constant/ Pressure

Let plug in the formula

Balloon Volume=150m³/5kpa

Balloon Volume=30m³

Therefore the volume that the balloon would have when the pressure inside the ballon has fallen to 5kpa is 30m³

Answer:

i would say the neuron

Answer:

180.7km/hr²

Explanation:

Given parameters:

Initial velocity  = 10miles/hr

Final velocity  = 25miles/hr

Time taken = 5minutes

     To hr

               60min  = 1hr

               5min gives 0.083hr

Unknown:

Acceleration  = ?

Solution:

To solve this problem,

   Acceleration  = [tex]\frac{v - u}{t}[/tex]  

v is the final velocity

u is the initial velocity

  Acceleration  = [tex]\frac{25 - 10}{0.083}[/tex]   = 180.7km/hr²

Answer:

The weight is 7.5 N

Explanation:

Since the rod is uniform, its weight applies downwards at its middle (i.e 50 cm mark). The diagram attached to this answer shows the appropriate sketch.

Applying the principle of moment to the question, let the weight by represented by W.

Total clockwise moment = Total counterclockwise moment

[tex]F_{1}[/tex] x [tex]d_{1}[/tex] = [tex]F_{2}[/tex] x [tex]d_{2}[/tex]

5 x 0.3 = W x 0.2

1.5 = 0.2 W

W = [tex]\frac{1.5}{0.2}[/tex]

   = 7.5 N

The value of the weight is 7.5 N.

Answer:

17.56 N

Explanation:

Given that,

Mass of a crate, m = 5 kg

It is on a 21.0° hill

We need to find the y component of the weight.

y component = mgsinθ

Put all the values,

y-component = 5×9.8×sin(21)

= 49×sin(21)

= 17.56 N

So, the y-component of the weight is 17.56 N.

Answer:

-45.745

Explanation:

it is negative because it is downwards.

Answer:

12 km/hr

Explanation:

Speed= Distance/Time

Answer:

12km/h

Explanation:

average speed= Distance covered /time taken

average speed=2km/20minutes

=but 1 minutes is 60 seconds

=2km/60minutes

=12km/h

Answer:

I dont know to be honest

Explanation:

i dont know to be honest

Complete question :

A flight attendant pulls her 70 N flight bag a distance of 318 m along a level airport floor at a constant velocity. The force she exerts is 41 N at an angle of 57° above the horizontal.

(a) Find the work she does on the flight bag.

(b) Find the work done by the force of friction on the flight bag.

(c) Find the coefficient of kinetic friction between the flight bag and the floor.

Answer:

7107 J ; - 7107 J ; 0.55

Explanation:

Given that :

Distance, d = 318m

Applied force = 41 N

θ = 57°

A.) Workdone = Force exerted along direction of motion

Workdone = applied Force * distance * cosθ

Workdone = 41 * 318 * cos57 = 7101.0037

Workdone = 7,101 J

B.) Workdone by force of friction on flight bag:

- 7,101 J (since the body moves at constant velocity)

C.)

Coefficient of kinetic friction (μ) = Frictional force / normal reaction)

μ = F / N

Frictional force, F = Workdone by friction / distance

F = 6200 / 318

F = 19.47N ;

Ff = weight of Flight bag = 70 N

N = Ff - Fsinθ

N = 70 - applied Force sinθ

N = 70 - 41sin57

N = 70 - 34.385493

N = 35.614506

μ = 19.47 / 35.614506

μ = 0.5466873

Answer:

Ernest Rutherford, 1st Baron Rutherford of Nelson

Answer:

A. Serbia and service

Explanation:

A guide word is a word written on top of a page to indicate the first or last word entry on that page. For example in a dictionary, they indicate the alphabetical first and last words on the page.

In this example; the word ' serpent ' note the first three letters to guide you in the words that are on that page;

In this case : Serbia  and Service.

Answer:

I believe you are correct but we just started this unit

Explanation:

Answer:

(a) The length of the stretched string is approximately 42.53846 cm

(b) The elastic potential energy stored in the string is approximately 0.073877 Joules

Explanation:

(a) The given parameter are;

The force constant of the vertical spring, k = 26 N/m

The relaxed length of the spring, L = 35 cm = 0.35 m

The mass attached to the end of the spring, m = 200 g = 0.2 kg

By Hooke's law, we have;

F = k·x

Where;

F = The applied force on the sting = The weight of the attached mass, W

∴ F = W

The weight of the attached mass, W = m × g

Where;

g = The acceleration due to gravity ≈ 9.8 m/s²

Therefore, F = W = 0.2 kg × 9.8 m/s² = 1.96 N

From Hooke's law, we have;

x = F/k = 1.96 N/(26 N/m) ≈ 0.0753846 m

The extension of the stretched spring, x ≈ 0.0753846 m

The length of the stretched string, L[tex]_{stretched}[/tex] = L + x

∴ L[tex]_{stretched}[/tex] ≈ 0.35 m + 0.0753846 m ≈ 0.4253846 m

0.4253846 m = 42.53846 cm

The length of the stretched string ≈ 42.53846 cm

(b) The elastic potential energy stored in the string, U = 1/2·k·x²

By substituting the known values, we get;

U = 1/2 × 26 N/m × (0.0753849 m)² ≈ 0.073877 Joules

Answer: A) All matter and energy were contained inside the small point.

Explanation: The theory that all matter and energy in the universe expanded from one condensed point (this is called the big bang theory) is the generally accepted explanation of the origins of our universe. Thought increasing amounts of doubt have been cast upon this theory in the last decade.

Answer:

A 20 Hz sound wave is 75 m long in the water (1500/20 = 75) whereas a 20 Hz sound wave in air is only 17 m long (340/20 = 17) in air. As we descend below the surface of the sea, the speed of sound decreases with decreasing temperature.

Answer:

W= F × d

W= 2kn × 3.6

W= 7.2 J

Work is measured in Joules!

Answer:

The magnitude of the final velocity is approximately 0.526 m/s in approximately the direction of 8.746° East of South

Explanation:

The given collision parameters are;

The kind of collision experienced by the four velcro-lined air-hockey disk = Inelastic collision

The mass of the first disk, m₁ = 50.0 g

The velocity of the first disk, v₁ = 0.80 m/s West = -0.8·i

The mass of the second disk, m₂ = 60.0 g

The velocity of the second disk, v₂ = 2.50 m/s North = 2.5·j

The mass of the third disk, m₃ = 100.0 g

The velocity of the third disk, v₃ = 0.20 m/s East = 0.20·i

The mass of the fourth disk, m₄ = 40.0 g

The velocity of the fourth disk, v₄ = 0.50 m/s South = -0.50·j

Therefore, the total initial momentum of the four velcro-lined air-hockey disk, [tex]\Sigma P_{initial}[/tex] is given as follows;

[tex]\Sigma P_{initial}[/tex] = m₁·v₁ + m₂·v₂ + m₃·v₃ + m₄·v₄ = 50.0×(-0.80·i) + 60.0×(2.50·j) + 100 × (0.20·i) + 40.0 × (-0.50·j)

∴ [tex]\Sigma P_{initial}[/tex] = -40·i + 150·j + 20·i - 20·j = -20·i + 130·j

∴ [tex]\Sigma P_{initial}[/tex] = -20·i + 130·j

By the law of conservation of linear momentum, we have;

[tex]\Sigma P_{initial} = \Sigma P _{final}[/tex] = -20·i + 130·j

Therefore, given that the collision is perfectly inelastic, the disks move as one after the collision and the four masses are added to form one mass, "m", m = m₁ + m₂ + m₃ + m₄ = 50.0 + 60.0 + 100.0 + 40.0 = 250.0

∴ m = 250.0 g

Let, "v" represent the final velocity of the four disks moving as one after the collision

We have;

[tex]\Sigma P _{final}[/tex] = m × v = 250.0 × v = -20·i + 130·j

∴ v = -20·i/250 + 130·j/250 = -0.08·i + 0.52·j

The final velocity of the four disks after collision, v = -0.08·i + 0.52·j

The magnitude of the final velocity, [tex]\left | v \right |[/tex] = √((-0.08)² + (0.52)²) ≈ 0.526

[tex]\left | v \right |[/tex] ≈ 0.526 m/s

The direction of the final velocity, θ = arctan(0.52/(-0.08)) ≈ -81.254°

The direction of the final velocity, θ ≈ -81.254° which is 8.746° East of South

Answer:

(1) The relationship between the altitude height, 'h', and the orbital speed, [tex]v_{orbit}[/tex], of the satellite is an inverse relationship

[tex]v_{orbit}[/tex] = 1/(h + R)

(2) The height of the satellite, is approximately 24,442 meters

(3) Please find attached the drawing showing the two lines that indicate the direction of the gravitational force on the satellites created with Microsoft Visio

Explanation:

(1) From the given data table, as the altitude increases, the orbital velocity decreases, therefore, the relationship between altitude, 'h', and orbital velocity, '[tex]v_{orbit}[/tex]', is an inverse relationship which can be expressed as follows;

[tex]v_{orbit} = \sqrt{\dfrac{G \cdot M}{r} }[/tex]

Where;

G = The universal gravitational constant

M = The mass of the Earth, or planet about which the satellite orbits

r = The distance between the center of the planet and the satellite = h + R

R = The radius of the planet

When [tex]v_{orbit}[/tex] = 27,500, h = r - R = 1000

We have;

[tex]v_{orbit}[/tex]² ∝ 1/r

[tex]v_{orbit}[/tex]² = k/r = k/(R+ h)

When, [tex]v_{orbit}[/tex]² = 27,500² = 756,250,000

r = h + R = 1000 + R

∴ 756,250,000 = k/(1000 + R)

(1,000 + R) × 756,250,000  = k

When, [tex]v_{orbit}[/tex]² = 18,000² = 324,000,000

r = h + R = 10,000 + R

∴ 324,000,000 = k/(10,000 + R)

324,000,000 = ((1,000 + R) × 756,250,000)/(10,000 + R)

∴ 324,000,000×(10,000 + R) = (1,000 + R) × 756,250,000

R × (756,250,000 - 324,000,000) = 324,000,000×10,000 - 1,000 × 756,250,000

R = (324,000,000×10,000 - 1,000 × 756,250,000)/(756,250,000 - 324,000,000) = 5746.09600925

R = 5,746.09600925

k = (1,000 + R) × 756,250,000  = (1,000 + 5,746.09600925) × 756,250,000 = 5.1017351 × 10¹²

k = 5.1017351 × 10¹²

(2) When, [tex]v_{orbit}[/tex] = 13,000 m/s, we have;

13,000² = 5.1017351 × 10¹²/(5,746.09600925 + h)

∴ 5,746.09600925 + h = 5.1017351 × 10^(12)/(13,000²) = 30187.7816568

h = 30187.7816568 - 5,746.09600925 = 24,441.6856476

The height of the satellite, h ≈ 24,442 meters

(3) Please find attached the drawing showing the two lines indicating the direction of the force of gravity exerts on the satellites created with Microsoft Visio.

Answer:

The true statements are;

The median of A is the same as the median of B

The interquartile range of B is greater than the interquartile range of A

Explanation:

The given parameters are;

The set of the number of runs, A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

The number of runs the pitcher allows in the tenth game = 9 runs

The set of the number of runs allowed in 10 games B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging the data, we get  

A = 1, 1, 1, 1, 2, 2, 2, 3, 4

B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

For the set A, we have;

Q₁ = 1, Q₂ = 2, Q₃ = 2

Therefore, the interquartile range of A = Q₃ - Q₁ = 2.5 - 1 = 1.5

For the set B, we have;

Q₁ = 1, Q₂ = 2, Q₃ = 2

Therefore, the interquartile range of A = Q₃ - Q₁ = 3.25 - 1 = 2.25

Therefore, the correct answers with regards to the two data are;

The median of A is the same as the median of B

The interquartile range of B is greater than the interquartile range of A

Answer:

Gamma rays

Explanation:

Answer:

52.802

Explanation:

"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.

The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.

Explanation:

five significant of 52.8015=52.801 ..

Solar energy source contributes least to global warming. Hence option C is correct.

Renewable energy is a energy from a source that is not exhausted or depleted when used. Solar energy or wind energy are examples of the renewable energy source. as wind and solar power is abundantly present everywhere in the environment, it can not be exhausted after its over use.

Non-renewable energy comes from sources that will be exhausted or will not be replenished after its use. Fossil fuels: coal, petroleum, and natural gas are the examples of the non renewable energy sources . Coal is the main element in fossil fuels.

Solar energy is abundantly available in the entire solar system. It is renewable energy source, it has no bad effect on the environment and global warming.

Hence option C is correct.

To know more about solar energy :

https://brainly.com/question/9704099

#SPJ7.

Answer:

moment's equilibrium required

moment = force x perpendicular distance from force's line of action (from pivot)

counter clockwise = clockwise moments

=> 15g(1.5) = F(0.3)

=> F = 15*9.81*5 = 735.75 ~= 736 N

Explanation:

When light is transmitted through an object things can happen. The light could be reflected by the thing. Or it could be absorbed by the object. Saying this based on what I know.