In one football game, a team scored 24 points with a combination of six-point touchdowns, three-point field goals, and one-point "extra points." They made 2 more touchdowns than field goals, and 3 times as many "extra points" as field goals. Let x be the number of touchdowns, y be the number of field goals, and z be the number of "extra points." Write a system of equations that can be solved to find how many touchdowns, field goals, and "extra points" the team made. Do not solve your system.

Answers

Answer 1

Given:

Total score = 24 points

They made 2 more touchdowns than field goals, and 3 times as many "extra points" as field goals.

To find:

The system of equations for the given problem.

Solution:

Let x be the number of touchdowns.

y be the number of field goals.

z be the number of "extra points."

Total score is 24 points. So,

[tex]x+y+z=24[/tex]

They made 2 more touchdowns than field goals.

[tex]x=y+2[/tex]

They made 3 times as many "extra points" as field goals.

[tex]z=3y[/tex]

Therefore, the required system of equation is

[tex]x+y+z=24[/tex]

[tex]x=y+2[/tex]

[tex]z=3y[/tex]


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Answers

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Step-by-step explanation:

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