Hydrocarbons are by-products of which of the following:
a. Fossil oils, mines and fossil fuels
b. Burning fires, water treatment plants and fossil oils
C. Combustion in fossil, lighting and exhaust fumes
d. Petrol, sea waves and combustion in vehicles
e. Burning fires and combustion in factories and vehicles​

Answers

Answer 1

Answer:

A

Explanation:

Answer 2
Key word part: hydro - water
I believe the answer is A
Please give me Brainliest

Related Questions

Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate View Available Hint(s) Suppose we replace both hover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment the same. Compared to the pucks in the video, this pair of pucks will rotate four times as fast. at the same rate. one-fourth as fast. twice as fast. one-half as fast.

Answers

Answer:

w = w₀ / 2    the angular velocity is half the initial value.

Explanation:

We can analyze this exercise as if we added another disk to obtain a disk with twice the mass, for which if the system is two disks, the angular tidal wave is conserved

initial instant.

          L₀ = I₀ w₀

final moment

          L_f = I w

the moment is preserved

          L₀ = L_f

          I₀ w₀ = I w

the moment of inertia of a disk is

         I = ½ m R²

we substitute

          ½ m R² w₀ = ½ (2m) R² w

          w = w₀ / 2

for the case of a disk with twice the mass, the angular velocity is half the initial value.

does altitude has an effect on weight, yes or no​

Answers

Answer: yes

Explanation:

Weight is the gravitational force experienced on a body. If you move up to higher altitudes, the distance between you and earth increases. ... Yes, weight drops as you go up in altitude (because of diminishing gravity), though your mass remains the same. However, the effect is not huge.

Assignment: Calculating Speed Investigation

Data Analysis:
Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.





2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.







3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.








4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.








5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.






Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.
Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.












Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?




2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your own

Answers

Answer:

Assignment: Calculating Speed Investigation

Data Analysis:

Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.

2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.

3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.

4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.

5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.

Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.

Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.

Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?

2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your own

Explanation:

Assignment: Calculating Speed Investigation

Data Analysis:

Note: Please submit your data table with this assignment.

1. Write your original hypothesis here.

2. Calculate the average time for vehicle 1 from the information in your data table. Show all work.

3. Calculate the average time for vehicle 2 from the information in your data table. Show all work.

4. Calculate the average speed for vehicle 1 from the information in your data table. Show all work, including the formula used.

5. Calculate the average speed for vehicle 2 from the information in your data table. Show all work, including the formula used.

Conclusion:

Think about this information and then write a conclusion based on the data of this experiment. Don’t forget to connect the conclusion to the original hypothesis.

Were you able to support your hypothesis or not? Be sure to base your answer on the data you collected. Consider whether your conclusion is the only explanation for the data you collected or if there could be alternate explanations. Don’t forget to mention any scientific laws or theories you have studied that would apply to this experiment.

Follow-up Questions:

1. If your experiment did not seem to match the expected results, what did you learn from the experience?

2. Instantaneous speed is the rate of motion of an object at a particular moment in time. What change(s) to the experimental procedure would be necessary if you wanted to gather data on instantaneous speed?

and as for the data can you please make your ownWhich sentence uses a superlative adjective correctly?

Anthony is running more quickly than anyone else on the field.

Shalon is a very talented pianist.

That is the best chocolate cake I have ever tasted.

Ani is the better gymnast of the two.

Which statement best compares and contrasts the purpose of "PROSERPINE" to that of "How Old Man Winter Was Driven Back"?

The Greek myth explains the creation of the earth, while the Iroquois myth also explains why there is evil in the world.

The Greek myth explains the creation of the earth, while the Iroquois myth also explains the creation of the moon.

The Greek myth explains the changing of the seasons as well as the existence of the underworld, while the Iroquois myth also explains the changing of the seasons.

The Greek myth explains the creation of the moon, while the Iroquois myth explains the creation of the sun.

Read the passages:

from "How Old Man Winter Was Driven Back"

"I, too, am powerful, and I am young! I do not fear you. When I touch the earth, it grows soft and warm. Every living thing stirs in its sleep,—birds and bees, flowers and trees, animals and men. When I speak, the sleeping sun awakes. See! Already he begins to send down his arrows. Hasten! that they may not find you, on the trail to the North Sky."

from "How the World Was Made"

Even some of the trees went to sleep. Only the cedar, the pine, the spruce, the holly, and the laurel were awake all seven nights. Therefore they are always green. They are also sacred trees. But to the other trees it was said, “Because you did not stay awake, therefore you shall lose your hair every winter.”

Which best uses textual evidence to compare and contrast these two myths?

Both myths show the change in seasons as a violent battle.

In "How Old Man Winter Was Driven Back," the change in

Coherent light with wavelength of 580 nm passes through two very narrow slits, and the interference pattern is observed on a screen a distance of 3.00 m from the slits. The first-order bright fringe is at 4.81 mm from the center of the central bright fringe. For what wavelength of light will the first-order dark fringe be observed at this same point on the screen?

Answers

Answer:

the required wavelength is 1.15815 μm

Explanation:

Given the data in the question;

The position of bright fringes [tex]y_m[/tex] on screen in double slit experiment is expressed as follows;

[tex]y_m[/tex] = mλD / d

solving for d, we substitute 1 for m

y₁ = (1)λD / d

d = λD / y₁

given that λ = 580 nm = 5.8 × 10⁻⁷ m,  D = 3.00 m and y₁= y₀ = 4.81 mm = 0.00481 m

so we substitute

d = λD / y₁

d = ( 5.8 × 10⁻⁷ m × 3.00 m ) / 0.00481 m

d = 0.00000174 m² / 0.00481 m

d = 3.6117 × 10⁻⁴ m

Now, position of dark fringe  [tex]y_m[/tex] on screen in double slit experiment is expressed as;

[tex]y_m[/tex] = ( m + 1/2 )λD / d

we substitute 0 for m

y₀ = ( 0 + 1/2 )λD / d

y₀ = λD / 2d

2y₀d = λD

λ =  2y₀d  / D

we substitute

λ =  ( 2(0.00481 m) ( 3.6117 × 10⁻⁴ m) )  / 3.0 m

λ = 1.15815 × 10⁻⁶ m

λ = 1.15815 μm

Therefore, the required wavelength is 1.15815 μm

Help please is for today

Answers

Answer:

All of the above.

Explanation:

A person is said to be at rest when he or she is not performing any action. The heartbeat stays normal in this condition.

A person is said to perform a moderate activity when his heart beats faster than the normal rest condition. It requires extra effort within the limit. For example, walking and dancing are examples of moderate activity.

A person is said to perform a vigorous activity when his heart beats much than in moderate activity. It requires a lot of effort over the limit. Running is an example of vigorous activity.

In view of the above information, all the options given in the question are true. Hence, the correct answer will be:

All of the above.

Question Set: Waves and Wave Properties

Answers

Answer:

The basic properties (parts) of a wave include: frequency, amplitude, wavelength and speed. Frequency is a measure of how many waves pass a point in a certain amount of time.

Which of the following best describes
pollutants?
A. harmful substances in the air, water, or soil
B. radioactive particles that pass through the atmosphere
C. oxygen molecules that are released by plants
D. beneficial substances that increase overall health

Answers

Answer:

A. harmful substances in the air, water, or soil

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The answer is A as it is more dangerous to the planet.

In many places on Earth, humans are responsible for the removal of grasses, shrubs, trees, and other plants with roots that hold soil in place. This activity is best described by which of the following? *
A) deforestation
B) urbanization
C) air pollution
D) rise in sea level

Answers

D is the correct answer

3.
Two Cars, A and B, (starting, at the same time, from the same point) are moving
with average speeds of 40 km/h and 50 km/h, respectively, in the same direction.
Find how far will Car B be from Car A after 3 hours.

Answers

Answer:

car B will be 30 Km ahead of car A.

Explanation:

We'll begin by calculating the distance travelled by each car. This is illustrated below:

For car A:

Speed = 40 km/h

Time = 3 hours

Distance =?

Speed = distance / time

40 = distance / 3

Cross multiply

Distance = 40 × 3

Distance = 120 Km

For car B:

Speed = 50 km/h

Time = 3 hours

Distance =?

Speed = distance / time

50 = distance / 3

Cross multiply

Distance = 50 × 3

Distance = 150 Km

Finally, we shall determine the distance between car B an car A. This can be obtained as follow:

Distance travelled by car B (D₆) = 150 Km

Distance travelled by car A (Dₐ) = 120 Km

Distance apart =?

Distance apart = D₆ – Dₐ

Distance apart = 150 – 120

Distance apart = 30 Km

Therefore, car B will be 30 Km ahead of car A.

does altitude has an effect on weight? HELP​

Answers

Answer:  lose weight at high altitudes.

Explanation:

Answer:

Just a week at high altitudes can cause sustained weight loss, suggesting that a mountain retreat could be a viable strategy for slimming down. Overweight, sedentary people who spent a week at an elevation of 8,700 feet lost weight while eating as much as they wanted and doing no exercise

g A velocity selector consists of crossed electric and magnetic fields. The electric field has a magnitude of 480 N/C and is in the negative z direction. What should the magnetic field (magnitude and direction) be to select a proton moving in the negative x direction with a velocity of 3.50 cross times 10 to the power of 5 m/s to go un-deflected

Answers

Answer:

B = 1.37 mT

Explanation:

Given that,

The magnitude of the electric field, E = 480 N/C

The speed of the proton, [tex]v=3.50 \times 10^5\ m/s[/tex]

We need to find the magnitude of the magnetic field. In a velocity selector, the electric field is balanced by the magnetic field. So,

[tex]qE=qvB[/tex]

Where

B is the magnetic field

[tex]B=\dfrac{E}{v}\\\\B=\dfrac{480}{3.5\times 10^5}\\\\B=1.37\times 10^{-3}\ T\\\\or\\\\B =1.37\ mT[/tex]

So, the magnetic field is equal to 1.37 mT.

Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) respectively. Determine the position of the center of mass of this system?​

Answers

Answer:

(1.9756, -2.1951)

Explanation:

The center of mass equation is: [tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex], where m represents the masses and x represents the position.

In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.

x-values:

[tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41}[/tex] = [tex]\frac{81}{41}[/tex] = 1.9756

y-values:

[tex]y_{cm}[/tex] = [tex]\frac{m_{1}y_{1} + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41}[/tex] = [tex]\frac{-90}{41}[/tex] = -2.1951

center of mass:

(1.9756, -2.1951)

Calculate the velocity of a wave that has a frequency of 60 Hz and wavelength of 2.0 m/s

Answers

Answer:We have , a relation in frequency f and wavelength  λ of a wave having the velocity v as ,

           v=fλ ,

given f=60Hz , λ=20m ,

therefore velocity of wave , v=60×20=1200m/s

Consider a pulley of mass mp and radius R that has a moment of inertia 1/2mpR2. The pulley is free to rotate about a frictionless pivot at its center. A massless string is wound around the pulley and the other end of the rope is attached to a block of mass m that is initially held at rest on frictionless inclined plane that is inclined at an angle β with respect to the horizontal. The downward acceleration of gravity is g. The block is released from rest .
How long does it take the block to move a distance d down the inclined plane?
Write your answer using some or all of the following: R, m, g, d, mp,

Answers

Answer:

  a = [tex]\frac{m}{m+ \frac{1}{2} m_p} \ g \ sin \beta[/tex]  ,       t = [tex]\sqrt{ \frac{2d}{a} }[/tex]

Explanation:

To solve this exercise we must use Newton's second law

For the block

let's set a reference system with the x axis parallel to the plane

X axis

         Wₓ - T = m a

Y axis  

         N- W_y = 0

         N = W_y

for pulley

          ∑τ = I α

           T R = (½ m_p R²) α

         

let's use trigonometry for the weight components

         sin β = Wₓ / W

         cos β = W_y / W

         Wx = W sin β

angular and linear variables are related

          a = α R

          α = a / R

we substitute and group our equations

         W sin β - T = m a

         T R = ½ m_p R² (a / R)

         

         W sin β - T = m a

                        T = ½ m_p a

we solve the system of equations

         W sin β = (m + ½ m_p) a

          a = [tex]\frac{m}{m+ \frac{1}{2} m_p} \ g \ sin \beta[/tex]

let's find the time to travel the distance (d) through the block

          x = v₀ t + ½ a t²

          d = 0 + ½ a t²

          t = [tex]\sqrt{ \frac{2d}{a} }[/tex]

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