How many moles are in 30.1 grams of O ? Watch your significant figures.
et
1.88 moles O
1.9 moles O
1.88 g O
2.00 g O

How Many Moles Are In 30.1 Grams Of O ? Watch Your Significant Figures.et1.88 Moles O1.9 Moles O1.88

Answers

Answer 1

Answer:

1 mole of O contains 16g

x mole of O will contains 30.1 g

= 16x = 30.1

16x/16= 30.1/16

= 1.88 mole of O

the answer is 1.88 mole of O


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Lab: Limiting Reactant and Percent Yield
Student Guide
Pre-Lab Information
Purpose Explore the yield of a chemical reaction by identifying the limiting reactant, comparing the
theoretical and actual yields, and explaining the sources of error.
Time Approximately 45 minutes
Question While observing a chemical reaction, how can you tell which reactant is limiting?
Reaction The reaction of copper(II) chloride and aluminum is shown in this balanced equation:
3CuCl2 + 2Al  2AlCl3 + 3Cu
Hypothesis If a substance is the limiting reactant, then it will be fully consumed by the time the
reaction completes because it is the reactant that reacts completely and the reaction
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Summary You will react copper(II) chloride with different quantities of aluminum in two trials. You
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Limiting Reactant and Percent Yield Lab Report attached

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Answer:

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Answer:

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Explanation:

How many grams is 2.393 x 10^24 atoms of CI
70.45 g CI
140.9 ga
140.9 mole CI
70.45 mole CI
How many grams is 2.393 x 10^24 atoms of O
70.45 g O
140.9 g O
63.58 mole O
63.58 g O

Answers

Answer: 1. 140.9 g Cl

2. 63.58 g O

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given atoms}}{\text {avogadro's number}}[/tex]

1. [tex]\text{Number of moles of Cl}==\frac{2.393\times 10^{24}}{6.023\times 10^{23}}=3.973moles[/tex]

1 mol of Cl weighs = 35.5 g

Thus 3.973 mol of Cl weighs = [tex]\frac{35.5}{1}\times 3.973=140.9g[/tex]

2. [tex]\text{Number of moles of O}==\frac{2.393\times 10^{24}}{6.023\times 10^{23}}=3.973moles[/tex]

1 mol of O weighs = 16 g

Thus 3.973 mol of O weighs = [tex]\frac{16}{1}\times 3.973=63.58g[/tex]

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METHOD 1:
Explanation:
METHOD 2:
Explanation:

Answers

Answer:

METHOD 1: (surface area of a solid reactant)  METHOD 2: (concentration or pressure of a reactant)

Explanation:

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Answers

Answer:

A

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Answers

Answer:

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Answers

Answer:

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Answers

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Answers

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Hope this helps

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Answers

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Answers

Answer:

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