Help ASSp please work out the value of A

Answer:

d = 5√2 units

Step-by-step explanation:

Let's use the distance formula: d = √[(x₂ - x₁)² + (y₂ - y₁)²]

Plug in the values with your endpoints.

d = √[(-6 - (-7))² + (4 - 11)²]

Solve within the parentheses.

d = √[(1)² + (-7)²]

Solve the exponents.

d = √[1 + 49]

Solve within the brackets.

d = √50

Simplify the square root.

25 • 2 = 50

√25 • √2 = √50

5 • √2 = √50

d = 5√2 units

Hope this helps!

Answer:

5 for $4.45

Step-by-step explanation:

Answer:

3x-2

Step-by-step explanation:

3 times a number is 3x, if we use x as the number

Two less than (3x) is 3x - 2

Answer:

40

Step-by-step explanation:

10x10=100

100-60=40

Hope this helps! :)

Answer: 4x-6= 18

4x=24

x= 24 & 4

x=6

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

I'm not exactly sure of what you mean by property but I think it might be associative property of multiplication?  

But to solve for x you would subtract 6 from 18 which gives your 12. Then you divide by 4 to get the x alone and 12/4 is 3.

Answer:

m=-25

Step-by-step explanation:

m=Δh/Δt

(Im choosing for the difference in height and time (Δh and Δt) to be the difference between the data in the first two rows)

m=(4500-5000)/(20-0)

m=-500/20

m=-25

Answer:

[tex]\frac{x - 20}{ x^2 + x - 20} = \frac{5}{9(x-4)}+\frac{4}{(x+5)}[/tex]

Step-by-step explanation:

Given

[tex]\frac{x - 20}{ x^2 + x - 20}[/tex]

Required

Decompose into partial fraction

Start by factorizing the denominator:

[tex]x^2 + x - 20 =x^2 + 5x -4x- 20[/tex]

[tex]x^2 + x - 20 =x(x + 5)-4(x+5)[/tex]

[tex]x^2 + x - 20 =(x-4)(x+5)[/tex]

So, we have:

[tex]\frac{x - 20}{ x^2 + x - 20} = \frac{A}{x-4}+\frac{B}{x+5}[/tex]

Take LCM

[tex]\frac{x - 20}{ x^2 + x - 20} = \frac{A(x+5)+B(x-4)}{(x-4)(x+5)}[/tex]

Cancel out the denominator

[tex]x - 20 = A(x+5)+B(x-4)}[/tex]

Open brackets

[tex]x - 20 = Ax+5A+Bx-4B[/tex]

Collect Like Terms

[tex]x - 20 = Ax+Bx+5A-4B[/tex]

[tex]x - 20 = (A+B)x+5A-4B[/tex]

By comparison;

[tex](A +B)x = x[/tex] ==>[tex]A + B = 1[/tex]

[tex]5A - 4B = 1[/tex]

Make A the subject in [tex]A + B = 1[/tex]

[tex]A = 1 - B[/tex]

Substitute 1 - B for A in [tex]5A - 4B = 1[/tex]

[tex]5(1-B) -4B = 1[/tex]

[tex]5-5B -4B = 1[/tex]

[tex]5-9B = 1[/tex]

Collect Like Terms

[tex]-9B = 1 - 5[/tex]

[tex]-9B = - 4[/tex]

[tex]B = \frac{4}{9}[/tex]

[tex]A = 1 - B[/tex]

[tex]A = 1 - \frac{4}{9}[/tex]

[tex]A = \frac{9-4}{9}[/tex]

[tex]A = \frac{5}{9}[/tex]

So:

[tex]\frac{x - 20}{ x^2 + x - 20} = \frac{A}{x-4}+\frac{B}{x+5}[/tex]

[tex]\frac{x - 20}{ x^2 + x - 20} = \frac{5}{9(x-4)}+\frac{4}{(x+5)}[/tex]

Answer:

15 units

Step-by-step explanation:

[tex]distance formula =\sqrt{(x_{2} -x_{1} )^{2} + (y_2 -y1)^{2} } } \\[/tex]

[tex]x_{1} = -2\\x_{2} = -14\\y_{1} = -5\\y_{2} = 4[/tex]

[tex]distance\\= \sqrt{(-14 - -2)^{2} + (4 - -5)^2 } \\= \sqrt{(-12)^2 + (9)^2} \\= \sqrt{144 + 81} \\= \sqrt{225} \\= 15\\Thus distance between the two points (-2,-5) and (-14,4) = 15 units[/tex]

Hope it helps....

Answer:

20 boys in the class

Step-by-step explanation:

40% of 50 is 20

Answer:

SANAOL COMPUTER

Step-by-step explanation:

SORRY DI KO PO ALAM EHH

Answer: The greatest common factor, or GCF, is the greatest factor that divides two numbers. To find the GCF of two numbers: List the prime factors of each number. Multiply those factors both numbers have in common.

Step-by-step explanation:

Answer:

-180000

Step-by-step explanation:

Answer:

1.0.003

2.40 minutes

3.a,e

4.a,c,d

5.1/24

Step-by-step explanation:

Answer:

3^6z

Step-by-step explanation:

you multiply 6 and z since they are exponets and one is in a (

Answer:

3 to the power of 6z of 3^6z

Step-by-step explanation:

Answer:

should be segment BT, that's what i put and it was right. hope this helps

Step-by-step explanation:

The altitude to the line segment AC is line segment BL.

A triangle is a three-sided closed-plane figure formed by joining three noncolinear points. Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.

Given, L, M, N are midpoints.

We know the altitude of a triangle is a line segment that originates from one vertex of a triangle and bisects the opposite side of the triangle.

By observing the given figure we conclude that the altitude to the line segment AC is the line segment BL.

learn more about the altitude of a triangle here :

https://brainly.com/question/17020135

#SPJ5

Answer:

160 cans for 5 pounds of aluminum

Step-by-step explanation:

9514 1404 393

Answer:

  $6475.56

Step-by-step explanation:

The maturity value is ...

  A = P(1 +rt)

where P is the principal amount, r is the annual rate, and t is the number of years. For ordinary interest, a year is 360 days, so the number of years is 160/360 = 4/9.

The loan value is ...

  A = $6200(1 + 0.10×4/9) ≈ $6475.56

Stephen's loan has a maturity value of $6,475.56.

Step-by-step explanation:

Given

Area of a circle (A) = 641 ft²

Circumference (C) = ?

We know

πr² = 641

r² = 641 / 3.142

r² = 204

r = 14.28 ft

Now

Circumference

= 2πr

= 2 * 3.14 * 14.28

= 89.68 ft

Hope it will help :)

Answer:

The circumference is 89.68 ft.

Answer:

The coefficient is 3.

Step-by-step explanation:

The coefficient is the number that is grouped with an unknown number represented by a letter.

Answer:

Step-by-step explanation:

For this question, it's C

Answer:

Height, h = 21 millimeters.

Step-by-step explanation:

Given the following data;

Volume = 8792mm³

Radius = 20 mm

To find the height;

We know that the shape of an anthill is conical in nature.

Mathematically, the volume of a cone is given by the formula;

[tex] V = \frac{1}{3} \pi r^{2}h[/tex]

Where;

Substituting into the equation, we have;

[tex] 8792 = \frac{1}{3} * 3.142*20^{2}*h [/tex]

[tex] 8792 = \frac{1}{3} * 3.142*400*h [/tex]

[tex] 8792 = \frac{1}{3} * 1256.8*h [/tex]

[tex] 8792 = 418.93*h [/tex]

[tex] Height, h = \frac {8792}{418.93}[/tex]

Height, h = 20.99 ≈ 21 mm.

Therefore, the height of the cone is 21 millimeters.

Answer:

It has side lengths of 3 and 13

Step-by-step explanation:

If it has an area of 39, then let the sides be x and y: thus we get the two relationships:

xy=39

2(x+y)=32

From the second equation, you get x+y=16. Now, rearrange to get y=16-x. You can now plug this into the first equation:

x(16-x)=39 -> 16x-x^2=39 -> x^2-16x+39=0 -> (x-3)(x-13)=0

This implies that x=3, or x=13, which further implies that the side lengths must be 3 and 13.

Answer:

La longitud del alambre que sostiene el poste es 8.94 metros.

Step-by-step explanation:

La longitud del alambre se puede calcular usando Pitágoras:

[tex] L^{2} = P^{2} + B^{2} [/tex]                      

En donde:

L: es la longitud del alambre =?

P: es la altura del poste = 8 m

B: es la distancia del alambre al poste = 4 m

Entonces, la longitud del alambre es:

[tex] L = \sqrt{P^{2} + B^{2}} = \sqrt{(8 m)^{2} + (4 m)^{2}} = 8.94 m [/tex]  

Por lo tanto, la longitud del alambre que sostiene el poste es 8.94 metros.

Espero que te sea de utilidad!

Answer:

c

Step-by-step explanation:

Answer:

The answer is 1

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

x - 5 = y

6 - 5 = 1

Hope that helps!

Answer:

25

Step-by-step explanation: