can someone help w/ chem plzz

Can Someone Help W/ Chem Plzz

Answers

Answer 1

Answer:

my answer I think is tetrahedral


Related Questions

4 points
What is the volume of an object with a density of 5.20 g/cm3 and a mass
of 6.00 x 10^2? g?

Answers

divide mass by density to determine volume. 115.384 cm^3 (unsure if you need to round.)

how many atoms of alumminum are in 3.9 mol of aluminum​

Answers

Answer:

2.35 x 10²⁴ atoms Al

Explanation:

Given 3.9 moles of aluminum (Al), determine number of aluminum atoms in that quantity of substance.

By definition a mole is the mass of substance containing one Avogadro's Number (N₀) of particles. That is, 1 mole = 1 N₀ = 6.023 x 10²³ particles*.

So, if 1 mole aluminum contains 6.023 x 10²³ atoms of aluminum then

3.9 moles Al = 3.9 moles Al  x  6.023 x 10²³ atoms Al/mole Al = 2.35 x 10²⁴ atoms Al.

________________

*The complete equivalent relationship is ...

1 mole (atoms or compounds) = 6.023 x 10²³ atoms or molecules = 1 formula weight of the substance = 22.4 Liters (if in gas phase at STP conditions (0°C and 1atm pressure).

________________

Sure hope this is understandable ... if not, kick back a note. Doc

Is hydrogen bond an attraction between polar molecules

Answers

Answer:

No because if there was an attraction hydrogen would not do it's function

What is the mass of a liquid that has a density of 124 g/mL and takes up a volume of 18 mL. What mass should the liquid have? (round you answer to the nearest hundredth)

Answers

the mass of the liquid should have 69

What is the boiling point of water?
A. 0°C
B. 50°C
C. 70°C
D. 100°C

Answers

Answer:

D) 100*C

Explanation:

Answer:

A. 0°C

Explanation:

El agua se evapora a los 0 grados

The bouncing of a wave off an object is called a what


Answers

Answer:

Reflection-energy waves bouncing off the surface of an object

Explanation:

Practice Problem #2: How many atoms
of Ba are in 7.8 moles of Ba?

Answers

[tex]7.8 \: mol = \frac{6.02 \times {10}^{23} atoms}{1 \: mol} = 4.6956 \times {10}^{24} \: atoms[/tex]

round as you wish.

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