Calculate the pH when [H]= 7.5 x 10^-12M

Answer:

True

Explanation:

All metals do rust but at different rates. Gold, platinum, and silver can rust if but at different rates. It can take time for it to rust, if you clean your metals, it won't rust, it'll take awhile before it rusts if you keep cleaning them.

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Answer:

C. gravity causing a curved path as an object tries to go straight.

Answer:

False, Solubility increases with temperature for most solids.

Explanation:

Answer:

A and C

Explanation:

The other answers didn't seem reasonable,

I took the quiz and got it right.

If I am wrong, please correct me

The biome can be given as the collection of flora and fauna in the region. The latitude affects the biome, with the short summers in the north and hot weather at the equator.

The latitude can be given as the horizontal lines imaginary drawn on the earth. The equator is the center of latitude passing from the middle of the earth.

The sun's rays fall directly towards the equator, while the poles in the north and the south experiences the transverse rays of the sun.

The direct rays falling at the equator termed the area closer to the equator warmer, while the falling rays to the north resulted in the short summers and cold for trees. Thus, options A and C are correct.

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Answer:

Al,Ga,B

Explanation:

Now since i helped you can you help me with this plz

Matteo took 5 math quizzes. The mean of the 5 quizzes was 8.2. Here are four of his quiz scores 7, 7, 8, 10. What is the 5th quiz score? Show work.

Boron ( B )

Aluminium ( Al )

Gallium ( Ga )

Answer:

here you are

Explanation:

atomic energy

Answer:

True

Explanation:

Hydrogen bonding is a bond that exists between hydrogen and a highly electronegative element such as oxygen, nitrogen, fluorine etc.

The greater solubility of the triphenylphosphine oxide owes to the hydrogen bonded interaction between it and the 1-propanol.

The alkene lacks such hydrogen bonded interaction because it does not have a highly electronegative atom in its structure.

Hence, triphenylphosphine oxide is removed based on its polarity and hydrogen bonding ability.

If anyone still needed help on this, someone wrote out the student table on brainly.com, look up Lab: Calorimetry and Specific Heat.

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Answer:

If anyone still needed help on this, someone wrote out the student table on brainly.com, look up Lab: Calorimetry and Specific Heat.

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Explanation:

Explanation:

Na3PO4+ FeCl3 = 3NaCl + FePO4

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The net ionic equation is found to be balanced by both mass and charge. There are equal masses of each element on the product and reactant sides in a balanced net ionic equation.

A chemical equation which shows only those elements, compounds, and ions which are directly involved in the chemical reaction is defined as the net ionic equation. The net ionic equation give us information about the ions that exists in aqueous medium.

A net ionic equation does not consider the spectator ions. The ions which do not participate in chemical reactions and are seen on both sides of the reactions are called spectator ions.

The complete ionic equation for the given reaction is:

3Na⁺ (aq) + PO₄³⁻ (aq) + Fe³⁺ (aq) + 3Cl⁻ (aq) → 3Na⁺ (aq) + 3Cl⁻ (aq) + FePO₄ (s)

The net ionic equation is:

PO₄³⁻ (aq) + Fe³⁺ (aq) → FePO₄ (s)

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Answer:

We can simply refer to the cation in the ionic compound as magnesium. Phosphorus, Pstart text, P, end text, is a group 15 element and therefore forms 3- anions.

Explanation:

Because it is an anion, we add the suffix -ide to its name to get phosphide as the name of the ion.

Answer:

Objects appear different colours because they absorb some colours (wavelengths) and reflected or transmit other colours. ... For example, a red shirt looks red because the dye molecules in the fabric have absorbed the wavelengths of light from the violet/blue end of the spectrum

A red object appear red because it absorbs light of wavelengths other than red. Therefore, option C is correct.

The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal propagated in space or along a wire is defined as the wavelength. This length is typically specified in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

A transverse wave's wavelength is defined as the distance between two adjacent crests. A longitudinal wave's wavelength can be calculated as the distance between two adjacent compressions.

The wavelengths that are reflected or transmitted are what we see as colors. A red shirt, for example, appears red because the dye molecules in the fabric have absorbed light wavelengths from the violet/blue end of the spectrum. The only light reflected from the shirt is red light.

Thus, option C is correct.

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Answer:

c

Explanation:

Answer:

Vapor pressure does not changes , Boiling point of liquid increases.

Explanation:

The external pressure creates the water molecules to move rapidly. The boiling point of liquid will increase as a result of external pressure induced on the surface of the liquid. The temperature must be kept constant to bring the liquid to boil.

Answer:

Topographic maps are used by hikers and backpackers to plan routes, estimate travel times, find water, good campsites, and track their progress on hikes. They're designed to depict the three dimensional shape of the world (mountains, valleys, plains, etc.)

Explanation:

Answer:

The correct approach is "1 M".

Explanation:

The given values are:

Volume of HCL,

V₁ = 45 ml

In prepared solution,

V₂ = 15 ml

Concentration,

C₁ = ?

C₂ = 3.0 M

As we know,

⇒  [tex]V_1C_1=V_2C_2[/tex]

or,

⇒      [tex]C_1=\frac{V_2C_2}{V_1}[/tex]

On substituting the values, we get

⇒           [tex]=\frac{15\times 3}{45}[/tex]

⇒           [tex]=\frac{45}{45}[/tex]

⇒           [tex]=1 \ M[/tex]

Answer:

C

Explanation:

Answer:

1Zn+ 2HCI → 1ZnCl2 + 1H2

Answer:

Blood capillaries

Explanation:

The walls of capillaries are just one cell thick. Capillaries therefore allow the exchange of molecules between the blood and the body's cells - molecules can diffuse across their walls. This exchange of molecules is not possible across the walls of other types of blood vessel.

Answer:Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.

Explanation:

Answer: The answer is a. limiting, excess. I took the test.

Explanation:

Answer:

[tex]Q=54.8kJ[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:

[tex]\Delta H=\frac{46.2kJ}{mol} *\frac{1mol}{3molH_2}\\\\ \Delta H=15.4\frac{kJ}{molH_2}[/tex]

Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:

[tex]Q=7.19gH_2*\frac{1molH_2}{2.02gmolH_2}*15.4\frac{kJ}{molH_2} \\\\Q=54.8kJ[/tex]

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Answer:

0.4 L

Explanation:

Calculate by using Boyle's Law P₁V₁=P₂V₂

(0.14atm)(2.4L) = (0.84atm)(V₂)

0.336 atmL = (0.84atm)(V₂)

V₂ = 0.336 atmL/0.84atm

V₂ = 0.4 L

Answer:

The weak acid is - E. [tex]NH_3[/tex]

Explanation:

Ammonia is a strong base, which in turn make it to be a weak acid.

As, the rest of the options are acid and therefore furnish hydrogen ions when dissolved in water, making them strong acid.

And ammonia dissolves in water to form its conjugate ammonium ion and hydroxide ion, therefore making the solution basic.

Hence, from the given options, the correct option is E. [tex]NH_3[/tex]

The compound which when dissolved in water, forms a weak acid is; Choice E: NH3

According to the question;

Unlike other compounds (HNO3, HClO, HBr, HClO) which dissolve in water to yield H+ ion, Ammonia dissolves in water to form ammonium ion and hydroxide ion, OH-.

In essence, NH3 is a strong base when dissolved in water and consequently, is a weak acid when dissolved in water.

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The data set is missing in the question. The data set is given in the attachment.

Solution :

a). In the table, there are four positive examples and give number of negative examples.

Therefore,

[tex]$P(+) = \frac{4}{9}$[/tex]   and

[tex]$P(-) = \frac{5}{9}$[/tex]

The entropy of the training examples is given by :

[tex]$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$[/tex]

= 0.9911

b). For the attribute all the associating increments and the probability are :

  [tex]$a_1$[/tex]   +   -

  T   3    1

  F    1    4

Th entropy for   [tex]$a_1$[/tex]  is given by :

[tex]$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$[/tex]

= 0.7616

Therefore, the information gain for [tex]$a_1$[/tex]  is

  0.9911 - 0.7616 = 0.2294

Similarly for the attribute [tex]$a_2$[/tex]  the associating counts and the probabilities are :

  [tex]$a_2$[/tex]  +   -

  T   2    3

  F   2    2

Th entropy for   [tex]$a_2$[/tex] is given by :

[tex]$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$[/tex]

= 0.9839

Therefore, the information gain for [tex]$a_2$[/tex] is

  0.9911 - 0.9839 = 0.0072

[tex]$a_3$[/tex]     Class label      split point       entropy        Info gain

1.0         +                        2.0            0.8484        0.1427

3.0        -                         3.5            0.9885        0.0026

4.0        +                        4.5            0.9183         0.0728

5.0        -

5.0        -                        5.5            0.9839        0.0072

6.0        +                       6.5             0.9728       0.0183

7.0        +

7.0        -                        7.5             0.8889       0.1022

The best split for [tex]$a_3$[/tex]  observed at split point which is equal to 2.

c). From the table mention in part (b) of the information gain, we can say that [tex]$a_1$[/tex] produces the best split.

Answer: At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]

Explanation:

Moles of  [tex]H_2[/tex] = 0.682 mole

Moles of  [tex]Br_2[/tex] = 0.440 mole

Volume of solution = 2.00 L

Initial concentration of [tex]H_2[/tex] = [tex]\frac{0.682}{2.00}=0.341 M[/tex]

Initial concentration of [tex]Br_2[/tex] =  [tex]\frac{0.440}{2.00}=0.220 M[/tex]

Equilibrium concentration of [tex]H_2[/tex] = [tex]\frac{0.516}{2.00}=0.258 M[/tex]

The given balanced equilibrium reaction is,

             [tex]H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)[/tex]

Initial conc.   0.341 M    0.220 M        0 M    

At eqm. conc.   (0.341-x) M   (0.220-x) M   (2x) M

Given : (0.341-x) M = 0.258 M

x= 0.083 M

Thus equilibrium concentartion of [tex]Br_2[/tex] = (0.220-0.083) M = 0.137 M

Thus moles of [tex]Br_2[/tex] at equilibrium = [tex]0.137M\times 2.00L=0.274mol[/tex]

At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]