The vector matrix [6 -2] is rotated at different angles. Match the angles of rotation with the vector matrices they produce.

Answers

Answer 1

Answer:

Hello your question is incomplete hence I will give you a general answer as regards rotation of vector matrix assuming angle of rotation  = [tex]\frac{\pi }{4}[/tex]

answer :

angle of rotation = [tex]\frac{\pi }{4}[/tex]

vector matrix produced = attached below

Explanation:

lets assume the vector matrix [ 6, -2 ] is rotated clockwise by an angle of [tex]\frac{\pi }{4}[/tex]

The resultant matrix = attached below

Result of the rotation =  attached below

attached below is the detailed solution

The Vector Matrix [6 -2] Is Rotated At Different Angles. Match The Angles Of Rotation With The Vector
Answer 2

Answer: I got it right on Edmentum

Explanation: Answers attached below

The Vector Matrix [6 -2] Is Rotated At Different Angles. Match The Angles Of Rotation With The Vector

Related Questions

An electromagnetic wave of frequency 7.55 x 10^14 Hz propagates in carbon tetrachloride with a speed of 2.05 x 10^8 m/s. What is the wavelength of the wave in carbon tetrachloride?
A. 3.38 x 10^-7 m
B. 3.61 x 10^-7 m
C. 3.97 x 10^-7 m
D. 3.01 x 10^-7 m
E. 2.72 x 10^-7 m

Answers

Answer:

2.72*10^-7m

Explanation:

Using the formula

v = fλ

v is the speed

f is the frequency

λ is the wavelength

Substitute for λ

λ = v/f

λ = 2.05 x 10^8/7.55 x 10^14

λ = 2.05/7.55 * 10^{8-14}

λ = 0.272 * 10^-6

λ = 2.72*10^-7m

Hence the wavelength of the wave in carbon tetrachloride is 2.72*10^-7m

A pendulum is constructed from a heavy metal rod and a metal disk, both of uniform mass density. The center of the disk is bolted to one end of the rod, and the pendulum hangs from the other end of the rod. The rod has a mass of =1.0 kg and a length of =49.8 cm. The disk has a mass of =4.0 kg and a radius of =24.9 cm. The acceleration due to gravity is =9.8 m/s2.
The pendulum is held with the rod horizontal and then released. What is the magnitude of its angular acceleration at the moment of release?

Answers

The magnitude of the angular acceleration of the pendulum at the moment of release is; α = 18.45 rad/s²

We are given;

Mass of rod; m = 1 kg

Length of rod; L = 49.8 cm = 0.498 m

Mass of Disk; M = 4 kg

Radius of disk; r = 24.9 cm = 0.249 m

Let us first calculate the torque acting from the formula;

τ = mg(L/2) + MgL

Thus;

τ = (1 × 9.8 × (0.498/2)) + (4 × 9.8 × 0.498)

τ = 21.96 N.m

Using parallel axis theorem, we can find the moment of inertia about the given axis as;

I = (mL²/3) + ½MR² + ML²

Plugging in the relevant values gives;

I = (1 * 0.498²/3) + ½(4 * 0.249²) + (4 * 0.498²)

I = 1.19 kg.m²

The angular acceleration is given by the formula;

α = I/τ

α = 21.96/1.19

α = 18.45 rad/s²

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PLEASE HELP
A problem says a plane is accelerating
3.42 m/s2 northeast. Which one of these
tables includes that information correctly?

Answers

Answer:

The answer is C, I just guessed and got it right lol

Explanation:

A 1,571 kilogram car travelling at 129 kilometers per hour is driving down a highway. The driver suddenly realizes a large animal is standing stationary on the highway in the way of the car. The driver manages to release their foot off the accelerator peddle, but does not have time to hit the brake peddle. The car strikes the animal which gets stuck to the car hood. Immediately after the collision the car slows to 59 kilometers per hour. Given this information, accident investigators are able to determine the mass of the animal as what

Answers

Answer:

[tex]1863.9\ \text{kg}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of car = 1571 kg

[tex]u_1[/tex] = Initial velocity of car = 129 km/h

[tex]u_2[/tex] = Initial velocity of the animal = 0

[tex]v[/tex] = Velocity of combined mass = 59 km/h

[tex]m_2[/tex] = Mass of the animal

As the momentum of the system is conserved we have

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow \dfrac{m_1u_1+m_2u_2}{v}-m_1=m_2\\\Rightarrow m_2=\dfrac{1571\times 129+0}{59}-1571\\\Rightarrow m_2=1863.9\ \text{kg}[/tex]

The mass of the animal is [tex]1863.9\ \text{kg}[/tex].

help plz fast :(((( need helpl

Answers

Answer:

True

Explanation:

I’m not 100% sure

How do home computer scanners generally use electromagnetic waves?

O A. They change information received from sound waves into electromagnetic waves.
OB. They gather information from reflected and absorbed waves.
O C. They receive microwaves that are emitted by natural objects.
O D. They use X-rays that penetrate most objects. SUBMIT​

Answers

Answer:

they gather information from reflected and absorbed waves.

Explanation:

Which of the following is NOT a geological event caused by the movement of tectonic plates?
A) Sand Dunes
B) Mountain forming
C) Earthquakes
D) Volcanoes

Answers

The answer is A. Mountains form because tectonic plates overlap. Earthquakes form because of the moving of tectonic plates. The moving of tectonic plates causes holes in the crust so magma from the mantle escapes and erupts from volcanoes. I hope I helped!

Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to
A.
first law
B.
second law
C.
third law
D.
law of gravity

Answers

Answer:

B . Second law

Explanation:

According to second law:

Net Force acting on the body produce acceleration. The magnitude acceleration of the body is directly proportional to net force and inversly proportional to the mass.

Mathematically:

                   a = [tex]\frac{F}{m}[/tex]

and

                   F = ma

So according to the given condition Waldo should use Second law.

PLEASE HELP, PLEASE A CORRECT ANSWER!​

Answers

Answer: I like your profile picture

Explanation:

what is energy and types of energy

Answers

Energy- the ability to do work/how things can change and move

Types
Potential Energy
Kinetic Energy
Nuclear Energy
Mechanical Energy
Sound Energy
Heat

A –5 μC charge is placed 2 mm from a +3 μC charge. Find the force between the two charges?

Answers

Answer:

-33750 N

Explanation:

Use coulomb's law: [tex]\frac{k(q1)(q2)}{r^{2} } = \frac{(9x10^{9})(-5x10^{-6})(3x10^{-6})}{0.002^{2} } = -33750 N[/tex]

Which of the following is an example of charging by friction?

Answers

Answer: where is the examples?

Explanation:

Please upload a photo

When carbon bonds with oxygen,
what
gas is formed?
When carbon bonds with oxygen, what gas is formed?

Answers

Answer:

Carbon dioxide

Explination:

I remember it from biology.

I hope this helps ^-^

In a chemical reaction, carbon combines with oxygen to form carbon dioxide gas.

What is a chemical reaction?

A chemical reaction can be defined as a process that causes the chemical transformation of one chemical substance to another. The chemical reactions accompany chemical changes that involve the rearrangement of electrons in the forming and breaking of bonds between atoms, with no change to the nuclei.

The substances which are primarily involved in a reaction are known as reactants or reagents. Chemical reactions are commonly characterized by a chemical change, and yield products, which exhibit properties different from the reactants.

Chemical reactions take place at a characteristic rate of reaction at a given temperature, pressure, and chemical concentration. The rates increase with the increasing temperature of the reaction when more thermal energy is available to achieve the activation energy for breaking bonds between atoms.

The combustion reaction takes place when carbon combines with oxygen to produce carbon dioxide gas.

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A negatively charged rod briefly touches a neutral metal ball. The metal ball will now be ____________

Answers

Answer:

let say it will be positive

what happens to the work done when a force is doubled and the distance moved remain the same?​

Answers

Answer:

It is doubled

Explanation:

f2=2f1

x1=x2=x

W1=f1*x1=f1*x

W2=f2*x2=f2*x=2*(fi*x)=2*W1

528 nm light passes through a single slit. the second (m=2) diffraction minimum occurs at an angle of 3.48 degrees. what is the width of the slit

Answers

Answer:

1.74

Explanation:

right on acellus

Answer:

1.74

Explanation:

acellus

Since water is much denser than air, deep-sea divers experience a much higher ambient pressure underwater. Each 10 meters of depth underwater adds another 1 atm to the ambient pressure experienced by the diver. (Note: this is in addition to the 1 atm ambient pressure at the surface of the water!) What pressure, in psi, is experienced by a diver 50.0 meters below the surface of the water

Answers

Answer:

If you are at sea level, each square inch of your surface is subjected to a force of 14.6 pounds. The pressure increases about one atmosphere for every 10 meters of water depth. At a depth of 5,000 meters the pressure will be approximately 500 atmospheres or 500 times greater than the pressure at sea level.

Explanation:

At sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.

What is pressure?

Pressure is defined as the force applied perpendicularly to an object's surface divided by the surface area over which it is applied.

Pressure is the physical amount of force exerted on a particular area.

Pressure can be expressed as

Pressure = Force / area

There are three types  of pressure.

Absolute pressureGauge pressureDifferential pressure

Thus, at sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.

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Electron spin: Radio astronomers can detect clouds of hydrogen too cool to radiate optical wavelengths of light by means of the 21 cm spectral line corresponding with the flipping of the electron in a hydrogen atom from having its spin parallel to the proton spin to having it antiparallel. From this wavelength, and thus E between states, find the magnetic field experienced by the electron in a hydrogen atom

Answers

Answer:

the magnetic field experienced by the electron is 0.0511 T

Explanation:

Given the data in the question;

Wavelength λ = 21 cm = 0.21 m

we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T

Plank's constant h is 6.626 × 10⁻³⁴ J.s

speed of light c = 3 × 10⁸ m/s

protein spin causes magnetic field in hydrogen atom.

so

Initial potential energy = -μ[tex]_B[/tex]B × cos0°

= -μ[tex]_B[/tex]B × 1

= -μ[tex]_B[/tex]B

Final potential energy = -μ[tex]_B[/tex]B × cos180°

= -μ[tex]_B[/tex]B × -1

= μ[tex]_B[/tex]B

so change in energy will be;

ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )

ΔE = 2μ[tex]_B[/tex]B

now, difference in energy levels will be;

ΔE = hc/λ

2μ[tex]_B[/tex]B = hc/λ

2μ[tex]_B[/tex]Bλ = hc

B = hc /  2μ[tex]_B[/tex]λ

so we substitute

B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)]  /  [2(9.27 × 10⁻²⁴) × 0.21 ]

B = [ 1.9878 × 10⁻²⁵ ]  /  [ 3.8934 × 10⁻²⁴ ]

B = 510556326.09

B = 0.0511 T

Therefore, the magnetic field experienced by the electron is 0.0511 T

The volumes of two bodies are measured to be

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³. Calculate sum and difference in

volumes with error limits.​

Answers

Answer:

sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

Explanation:

Here,

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

Now,

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Thus, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

Answer:

I hope it's helpful .............

Two long current-carrying wires run parallel to each other and are separated by a distance of 5.00 cm. If the current in one wire is 1.65 A and the current in the other wire is 3.25 A running in the opposite direction, determine the magnitude and direction of the force per unit length the wires exert on each other.

Answers

Answer:

The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.

Explanation:

Given;

distance between the parallel wires, r = 5.0 cm = 0.05 m

current in the first wire, I₁ = 1.65 A

current in the second wire, I₂ = 3.25 A

The magnitude of the force per unit length between the two wires is calculated as follows;

[tex]\frac{F}{l} =\frac{\mu_0 I_1 I_2}{2\pi r} \\\\\frac{F}{l} =\frac{4\pi \times 10^{-7} \times 1.65 \times 3.25}{2\pi \times 0.05} \\\\\frac{F}{l} = 2.145 \times 10^{-5} \ N/m[/tex]

Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.

LESSION 7:LIGHT UNIT TEST
PHYSICAL SCIENCE B: UNIT 4: LIGHT

17/17 answers u cheaters here you go

Answers

Answer:

I cheated on

Spanish

ELA

history

Explanation:

Answer:

thx

Explanation:

180 N
40 kg
140 N
Net Force =

Also how do you find the net force?

Answers

Answer:

720N

Explanation:

180+(40×10)+140=720 remember we can only add with same units ;1kg=10N therefore 40 kg=(40×10)N=400N

The net force would be the summation of all the forces in addition to the weight force of the 40 kg weight, thus the net force of all the forces would come out to be 712.4 Newtons.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

F = ma

As given in the problem we have to find the net force,

Let us assume the acceleration due to gravity would be 9.81 m/s².

The force generated by the 40-kilogram weight =40 ×9.81 Newtons.

The force generated by the 40-kilogram weight = 392.4 Newtons

Net force = 180 + 140 +392.4

         

                =712.4 Newtons

Thus, the net force of all the forces would come out to be 712.4 Newtons.

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Acceleration is rate of change of
A-Position
B-Time
C-Velocity
D-Speed​

Answers

C-Velocity would be the answer

You are designing a solenoid to produce a 2.0-kG magnetic field. You wish to wrap your insulated wire uniformly around a cardboard tube that is 8.0 cm in diameter and 58 cm in length, and you have a power supply that will allow you to pass a current of 2.5 A through the solenoid. Determine the total length of wire you will need in order to build the solenoid you have designed.

Answers

Answer:

92.7 km

Explanation:

Since the magnetic field due to a solenoid is given by B = μ₀Ni/L where  μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid, L = length of cardboard tube = 58 cm = 0.58 m, , i = current in wire = 2.5 A and l = length of wire.

So, N = BL/μ₀i

Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T

So, substituting the variables into the equation, we have

N = BL/μ₀i

N = 0.2 T × 0.58 m/(4π × 10⁻⁷ H/m × 2.5 A)

N = 1.16 Tm/(31.416 × 10⁻⁷ HA/m)

N = 0.0369 × 10⁷ turns

N = 0.0369 × 10⁷ turns

N = 3.69 × 10⁵ turns

length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m

So, l = NC

= NπD

= πND

= π × 3.69 × 10⁵ turns × 0.08 m

= 0.9274 × 10⁵ m = 9.274 × 10⁴ m

= 92.74 × 10³ m

= 92.74 km

≅ 92.7 km

The total legnth of the wire to built a solenoid will be  92.7 km

What is solenoid?

A solenoid is a electromagnet in which the wires are wounded on the outer surface of the soft iron and then the current is passed so due to flow of the current the magnetic field generated around the wire.

Since the magnetic field due to a solenoid is given by

B = μ₀Ni/L

where

μ₀ = permeability of free space = 4π × 10⁻⁷ H/m,

N = number of turns of solenoid,

L = length of cardboard tube = 58 cm = 0.58 m, ,

i = current in wire = 2.5 A and

l = length of wire.

Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T

So, substituting the variables into the equation, we have

[tex]N=\dfrac{BL}{\mu_oI}[/tex]

[tex]N=\dfrac{0.2\times 0.58}{4\pi\times 10^{-7} \times 2.5}[/tex]

[tex]N=\dfrac{1.16}{31.416\times 10^{-7}}[/tex]

N = 0.0369 × 10⁷ turns

N = 0.0369 × 10⁷ turns

N = 3.69 × 10⁵ turns

length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m

So, l = NC

= NπD

= πND

= π × 3.69 × 10⁵ turns × 0.08 m

= 0.9274 × 10⁵ m = 9.274 × 10⁴ m

= 92.74 × 10³ m

= 92.74 km

≅ 92.7 km

Hence the total legnth of the wire to built a solenoid will be  92.7 km

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what is 60mph (miles per hour) in meters per second? ( A mile is 5280ft)
please someone help me

Answers

Answer:

60mph=26.8224meters per second

Explanation:

A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.55 m/s to the right relative to the plank.

Required:
What is the velocity of the plank relative to the surface of the ice?

Answers

Answer:

The speed of the plank relative to the ice is:

[tex]v_{p}=-0.33\: m/s[/tex]

Explanation:

Here we can use momentum conservation. Do not forget it is relative to the ice.

[tex]m_{g}v_{g}+m_{p}v_{p}=0[/tex] (1)

Where:

m(g) is the mass of the girlm(p) is the mass of the plankv(g) is the speed of the girlv(p) is the speed of the plank

Now, as we have relative velocities, we have:

[tex]v_{g/b}=v_{g}-v_{p}=1.55 \: m/s[/tex] (2)

v(g/b) is the speed of the girl relative to the plank

Solving the system of equations (1) and (2)

[tex]45v_{g}+168v_{p}=0[/tex]

[tex]v_{g}-v_{p}=1.55[/tex]

[tex]v_{p}=-0.33\: m/s[/tex]

I hope it helps you!      

why do dzongs have broader base?​

Answers

Answer:

The base of taller buildings are made broader because it reduces the pressure exerted on the ground so that they do not sink in due to the extremely high pressure of the building.

Explanation:

hope thiss helpss~!

A broad base is used to engage or recruit a diverse range of individuals to broad-based environmentalism.

Broader base:

The broader base is a base of taller structures was built wider to reduce the pressure placed on the floor.It preventing the ground from sinking due to the house's extremely high tension.This structures have a wider base because the pressure is inversely proportional to area.That's why the increasing the area reduces the pressure or we can that the structure would not fall apart.

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Which structure is represented by letter C?
Choose 1 answers
A. Cell wall
B. Cell membrane
C. Ribosome
D. Cytosol

Answers

Answer: C. Ribosome

Explanation: Ribosome is responsible for protein synthesis. I got it right on khan academy :) hope this helps have a blessed day.

The structure which is represented by the letter C is known as free ribosomes. Thus, the correct option for this question is C.

What are Ribosomes?

Ribosomes may be defined as a type of cell organelle which is spherical and glandular in shape. They occur freely in the matrix or remain bound with ER.

The major components of ribosomes may include RNA and protein. Ribosomes were first discovered by Palade in 1953. There are two types of ribosomes, ie. the 70s and 80s.

Ribosomes play an important function in the process of protein synthesis. The structure which is represented by the letter A is known as the cell membrane. The structure which is represented by the letter B is known as Cytosol.

Therefore, the structure which is represented by the letter C is known as free ribosomes. Thus, the correct option for this question is C.

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As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g. Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward). If the bottom of your window is a height hb above the ground, what is the velocity vground of the pot as it hits the ground? You may introduce the new variable vb, the speed at the bottom of the window, defined by
vb = Lwt + gt2.

Answers

Answer:

[tex]\mathbf{v_{ground} = \sqrt{{v^2+2ghb}}}[/tex]

Explanation:

From the information given:

The avg. velocity post the window is;

[tex]v_{avg} = \dfrac{L_w}{t}[/tex]

[tex]v_b[/tex] = velocity located at the top of the window

[tex]v_b[/tex] = velocity situated at the bottom of the window  

Using the equation of kinematics:

[tex]v_b = v_t + gt[/tex]

Hence,

[tex]v_t = v_b - gt[/tex]

To determine the average velocity as follows:

[tex]v_{avg} = \dfrac{1}{2} (v_t + v_b)\dfrac{L_w}{t}= \dfrac{1}{2}(v_b - gt +v_b) \\ \\\dfrac{L_w}{t} = v_b - \dfrac{1}{2}gt \\ \\ v_b = \dfrac{L_w}{t }+ \dfrac{1}{2} gt\\ \\ = \dfrac{1}{t} \Bigg(L_w + \dfrac{1}{2}gt^2 \Bigg) \\ \\[/tex]

where;

[tex]v_b[/tex] = velocity gained when fallen through the height h.

Similarly, using the equation of kinematics, we have;

[tex]v_b^2 = 2gh \\ \\h = \dfrac{v_b^2}{2g}[/tex]

[tex]\implies \dfrac{(L_w + \dfrac{1}{2} gt^2_^2}{2gt^2}[/tex]

Thus, the velocity at the ground is;

[tex]v^2_{grround} = v_b^2 + 2ghb[/tex]

[tex]\mathbf{v_{ground} = \sqrt{{v^2+2ghb}}}[/tex]

What is the approximate size of the Earth's magnetic field? (dont ask me to specify thats what the question is and im as confused as heck too)

Answers

Answer:

The Earth's magnetic field intensity is roughly between 25,000 - 65,000 nT (.25 -.65 gauss).

Explanation:

To measure the Earth's magnetism in any place, we must measure the direction and intensity of the field. The Earth's magnetic field is described by seven parameters. These are declination (D), inclination (I), horizontal intensity (H), the north (X), and east (Y) components of the horizontal intensity, vertical intensity (Z), and total intensity (F). The parameters describing the direction of the magnetic field are declination (D) and inclination (I). D and I are measured in units of degrees, positive east for D and positive down for me. The intensity of the total field (F) is described by the horizontal component (H), vertical component (Z), and the north (X) and east (Y) components of the horizontal intensity. These components may be measured in units of gauss but are generally reported in nanoTesla (1nT * 100,000 = 1 gauss). The Earth's magnetic field intensity is roughly between 25,000 - 65,000 nT (.25 - .65 gauss). Magnetic declination is the angle between magnetic north and true north. D is considered positive when the angle measured is east of true north and negative when west.  The magnetic inclination is the angle between the horizontal plane and the total field vector, measured positive into Earth. In older literature, the term “magnetic elements” is often referred to as D, I, and H.

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