Answer:
[tex]2H_2 + O_2 -> 2 H_2 O[/tex]
In a separate location, take notes from the sources you’ve identified. The notes will provide details for your paper. While taking notes, you may want to use these reading strategies. Use these sources if you find them helpful: Using your notes, compare the features of analog and digital signals in the table provided. Include one to three points for each feature and type of signal.
Answer:
Here is every answer for analog and digital (in order)
Analog:
Signal Shape: Smooth and continuousNumerical Values for Signal Measurements: Analog signals represent one continuous variable as the result of another continuous time-based variable. They are capable of outputting continuous information with a theoretically infinite number of possible values.Amount of Data that can be transmitted: analog circuits can conduct only fairly low-speed data communications. The maximum data rate over an analog facility is 33.6K bps when there are analog loops at either end. With 56K bps modems, only one end of the loop can be analog. The other end of the connection has to be digital. Energy requirements: light, sound, temperature, position, and pressurePrivacy and security (ability of the signal to be encoded in a secret code): not encryptedClarity of Signal: noise affects clarity and quality, noise is amplified, amplified noise causes more random information in the signal, signal bandwidth is lowDigital (in order):
Signal shape: stepping, square, and discreteNumerical Values for Signal Measurements: digital communication methods transmit a complete measured value, in other words both a numeric value and a unit of measurement Amount of data that can be transmitted: First of all, it is theoretically possible to transmit digital signals directly. Unfortunately when we use capacitors and inductors (energy storage devices) to match the impedance from the transmitter to the air (low impedance transistor say 5 ohms to 388 ohms (air)) these components introduce a bandwidth limiting match. Since all impulse functions have infinite bandwidth (transmitting a 1 and a zero) the bandwidth of the transceiver must be multi octave in order to have any reasonable efficiency. Systems engineers simplify the problem by introducing direct sequence modulation where a carrier is modulated 0/180 degrees dependent on the data rate.Energy requirements: voltage, accoustic pressure, and magnetization of a magnetic storage mediaPrivacy and security: encryptedClarity of signal: noise is lower in amplitude, electronics can ignore the noise, quality of signal is maintained, signal is highExplanation:
I did mine in bullet points, hopefully this helped!
Analog:
Signal Shape: Smooth and continuous
Numerical Values for Signal Estimations: Analog signals speak to one ceaseless variable as the result of another ceaseless time-based variable.
Amount of Information that can be transmitted: analog circuits can conduct as it were reasonably low-speed information communications.
Energy necessities: light, sound, temperature, position, and pressure Privacy and security : not encrypted
Clarity of Signal: clamor influences clarity and quality, commotion is amplified,
Digital:
Signal shape: stepping, square, and discrete
Numerical Values for Signal Measurements: digital communication methods transmit a complete measured value, in other words both a numeric value and a unit of measurement
Amount of data that can be transmitted: First of all, it is theoretically possible to transmit digital signals directly.
Energy requirements: voltage, accoustic pressure.
Privacy and security: encrypted
Clarity of signal: noise is lower in amplitude, electronics can ignore the noise, quality of signal is maintained, signal is high
Analog and digital is :Analog signal could be a continuous signal which speaks to physical estimations.
Digital signals are discrete time signals created by computerized balance.
Example :Human voice in discuss, analog electronic gadgets. Computers, CDs, DVDs, and other advanced electronic gadgets.
A student transfers a gas at STP from a 11.0 L tank to a 25.0 L tank. If the pressure
remains constant, what is the new temperature?
. Consider a sample of oxygen gas at 27° C with a volume of 9.55L at a pressure
Answer:620 k
Explanation:
are you chemistry because you just blew up my heart
Answer:
i needed that lol
thank you
Explanation:
Nitrous acid is classified as an Arrhenius acid because HNO2 contains
1. OH-ions
2. 02-ions
3. NO2-ions
4. H+ ions
4) H+ions is your answer , good morning , have a great day ahead.
How does every single cell in the body get the substances it needs to carry out the chemical reaction that provides it energy?
8. Of what importance is a smoker to a person keeping bees?
Answer:
they help to calm the bees when the person keeping the bees inspects there hives.
9) What is the density of the gold rock with a mass of 386 grams and has a volume of 20 cubic centimeters?
O 0.193 g/cc
O 193 g/cc
O 1.93 g/cc
19.3 g/cc
Answer:
density= mass/volume
hence density of gold rock
= 386/20
=19.3 g/cc
Where do we get our energy from ?
Answer:
energy
Explanation:
4.What type of energy is used to fuel the process of photosynthesis and what type is produced in
respiration?
A Light energy is used in photosynthesis and created by respiration.
B ATP is used in photosynthesis, which allows the plant to undergo respiration.
C Light energy is used in photosynthesis, whereas respiration creates the energetic product, ATP.
D Food energy is used in photosynthesis and ATP is produced in respiration.
Answer:
A. light energy is used in photosynthesis and created by respiration
One major problem with wind and solar energy is that they are conditional. Explain how hydroelectric pumped storage could be used to eliminate this
obstacle? *
Link to the article https://thinkprogress.org/the-inside story-of-the-worlds-biggest-battery-and-the-future-of-renewable-energy-8984c81283c/
Answer:
Hydroelectric pumped storage can be used to eliminate the conditional nature of wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.
Explanation:
Pumped-storage hydroelectricity is a type of hydroelectric energy storage used by electric power systems to store excess electrical power during periods of low demand for later release at periods when demand for energy rises again. It stores energy in the form of gravitational potential energy of water, pumped from a lower level reservoir to a higher level reservoir.
At times of low electrical demand, excess generated energy is used to pump water into the upper reservoir. When there is higher demand, water is released back into the lower reservoir through a turbine, generating electricity.
This form of energy storage is useful in circumventing the conditional nature of renewable energy sources such as wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.
How can I express the composition of a solution?
Answer:
It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...
Explanation:
It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...
In an exothermic the change in enthalpy is usually
Positive, because the potential energy of the reactants is higher than the potential energy of the products
Neutral, because the potential energy of the products and reactants cancel each other out.
Negative, because the potential energy of the reactants is higher than the potential energy of the products
Positive, because the potential energy of the reactants is lower than the potential energy of the products
Answer:
Negative, because the potential energy of the reactants is higher than the potential energy of the products
Explanation:
Exothermic reaction is a reaction in which heat is released to surrounding. This is due to the fact that the heat content of the reactant is higher than the heat content of product thus producing a negative enthalpy change (ΔH) i.e
Enthalpy change = Heat of product – Heat of reactant
ΔH = Hp – Hr = negative
Considering the options given in the question above, the correct answer is:
Negative, because the potential energy of the reactants is higher than the potential energy of the products
DUE TONIGHT!
I need help doing this question and please type an ACTUAL answer. I don’t want none of that “aNsWeR iN FiLe”. Thank you!
Calculate the specific heat (Cp) for indium metal given a 1.0 mole absorbs 53.0 J
while increasing in temperature from 297.5K to 299.5K.
Answer:
27J/Kmol
Explanation:
Heat = number of moles times the Moeller heat capacity chimes the change in temperature.
^ Q = nC△T
^ C = Q/ n△T = +53J / (1mol) (299.5K - 297.5K)
^ = 26.5 (rounded to 27)
If I add 25mL of water to 125 mL of 0.25 M NaOH solution, what will the molarity of the diluted solution be?
Answer:
0.208333 M
Explanation:
M2=M1V1/V2=(0.25 M)(125mL)/(125mL+25 mL)= 0.208333 M
Why is it important for the daughter cells to divide a second time in meiosis?
The second division switches parts of matching chromatids to increase genetic variation.
The second division forms four identical cells to ensure that all offspring have the same
The second division sorts chromosomes into cells that are the same as the parent cells.
The second division forms haploid cells that can combine with other haploid cells during fertilization.
Answer:
The second division switches parts of matching chromatids to increase genetic variation.
Explanation:
Meiosis and fertilization create genetic variation by making new combinations of gene variants (alleles).
In a solution, litmus is blue. The pH of the solution could be
1. 10
2. 2
3. 3
4. 4
Answer:
1. 10
Explanation
when litmus paper is blue that means the solution is basic and 10 on the pH scale is the most basic out of all your options
A compound is composed of 53.33%carbon, 11.11%hydrogen and 35.56%oxygen. If the molecular mass of the compound is 90, what is the molecular formula of this compound?
On a hot day, a student places a glass of cold lemonade on a table outdoors. After a few minutes, water droplets have formed on the outside of the glass.
Is energy absorbed or released by the cold lemonade? Explain your answer.
Compare average kinetic energy for the air molecules and lemonade molecules when the student first places the lemonade outdoors. Explain your answer.
Explain how and why the water droplets form on the outside of the glass.
Answer:
ye but sdfajkd tryng to play me
Explanation:
Answer:
Vapor is released out of the lemonade because when you place it in a hot it will increase.
Explanation:
what is the difference between isotopes and allotrope not more than three line
Answer:
An allotrope is one way that atoms can be arranged in a solid. An isotope is one way that protons and neutrons can form the same atomic element.
Most of the matter making up the earth is composed of
A. gases
B. compounds
C. mixtures
Most of the matter making up earth is composed of compounds. I think
What is the percent by mass concentration of 1000 ml of a solution (d=1.5 g/ml) that contains 50 g of solute in it?
Answer: The percent by mass concentration is 33.3 %
Explanation:
Mass percent is the ratio of mass of solute to the mass of solution in terms of percentage.
mass of solute = 50 g
mass of solution = [tex]{\text {density of solution}}\times {\text {volume of solution}}=1.5g/ml\times 1000ml=1500g[/tex]
Mass percentage = [tex]\frac{50g}{1500g}\times 100\%=33.3\%[/tex]
Thus percent by mass concentration of 1000 ml of a solution (d=1.5 g/ml) that contains 50 g of solute in it is 33.3 %
2NaCl ---> 2Na + Cl2
What are the atoms of the products
Answer: ...
Explanation:
Sodium, chlorine
Answer:
2Na = 2 Sodium [has 2 atoms]
Cl2 = Dichlorine (Chlorine) [has 2 atoms]
Is this what you wanted?? I'm not entirely sure if this is the answer you were looking for.
The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in vinegar is around 0.85 M. Based on this information, determine the value of the acid ionization constant, Ka, for acetic acid.
Answer: The value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]
Explanation:
[tex]CH_3COOH\rightarrow H^+CH_3COO^-[/tex]
cM 0 0
[tex]c-c\alpha[/tex] [tex]c\alpha[/tex] [tex]c\alpha[/tex]
So dissociation constant will be:
[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]
Give c= 0.85 M and [tex]pH[/tex] = 2.4
[tex]pH=-log[H^+][/tex]
[tex][H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}[/tex]
[tex]K_a=?[/tex]
Putting in the values we get:
[tex]K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}[/tex]
Thus the value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]
how many grams of AgNO3 (MM=169.87) are needed to prepare 0.125 M solution in 250 mL of water?
a. 0.5 g
b. .03 g
c. 5.3 g
d. 84.9g
Answer:
Correct answer-C 5.3g
Explanation:
Molarity = no. of moles of solute/ volume of of solution in litre
olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125
olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,
olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,so the mass of 0.03125 moles of AgNO3 = 0.03125×169.87= 5.3084g
The grams of AgNO₃ are needed to prepare 0.125 M solution in 250 mL of water is 5.3 grams.
How do we calculate mass from moles?Moles is a unit which is used to define any amount and it is calculated as:
n = W/M, where
W = required mass
M = molar mass
Given molarity of AgNO₃ = 0.125 M
Volume of water = 250mL = 0.25L
moles (n) from the molarity (M) will be calculated as:
n = M × V
n = (0.125)(0.25) = 0.0312 moles
Now we calculate the mass of AgNO₃ by using the above formula as:
W = (0.0312mol)(169.87g/mol)
W = 5.30 g
Hence option (c) is correct.
To know more about moles, visit the below link:
https://brainly.com/question/15374113