Asanji stands at the edge of the top of a tall building and lobs a watermelon up into the air then proceeds to watch it fall to the street below (luckily it's empty because everybody is at home). The equation below represents the height, off the ground in meters, of the watermelon t seconds after Asanji has thrown it.
h = -4.9t^2 + 9.8t + 28
Approximately, how long does it take the watermelon to hit the ground? Round to the nearest tenth of a second.
Answers
9514 1404 393
Answer:
3.6 s
Step-by-step explanation:
This is nicely solved by a graphing calculator. It takes about 3.6 seconds to hit the ground.
__
We notice that the vertical velocity is a multiple of the leading coefficient, so we can solve this by completing the square.
0 = -4.9(t^2 -2t) +28 . . . . . for h = 0
28 +4.9 = 4.9(t^2 -2t +1) . . . . . rearrange, add 4.9 to both sides
32.9/4.9 = (t -1)^2
1 +(1/7)√329 = t ≈ 3.5912. . . . . square root and add 1
It takes about 3.6 seconds for the watermelon to hit the street.
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9514 1404 393
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Step-by-step explanation:
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Step-by-step explanation:
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Step-by-step explanation:
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9514 1404 393
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Step-by-step explanation:
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Step-by-step explanation:
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the
گج
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Answers
Using angle sum property
[tex]\\ \sf\longmapsto x+43+73+70=180[/tex]
[tex]\\ \sf\longmapsto x+43+143=180[/tex]
[tex]\\ \sf\longmapsto x+186=180[/tex]
[tex]\\ \sf\longmapsto x=180-186[/tex]
[tex]\\ \sf\longmapsto x=-6[/tex]
Option C is correct
Sum of angles of any triangle is 180°
x+43+73+70=180x+186=180x=180-186x=-6Option C