Answer:
B. Four bits are enough to store the eight directions
Explanation:
The summary of the question is to determine whether 4 bits can store 8 directions or not.
To understand this question properly, the 8 bits will be seen as 8 different characters.
In computer memory, a computer of n bits can store 2^n characters.
In this case:
[tex]n = 4[/tex] i.e. 4 bits
So:
[tex]2^n = 2^4[/tex]
[tex]2^n = 16[/tex]
This implies that the memory can store up to 16 characters.
Because 16 > 8, then (b) answers the question.
Plz help, will guve brainliest to best answer (if i can)
Answer:
Online text:1,3,4
not online text:2,5
Write a program that implements a class called Dog that contains instance data that represent the dog's name and age. • define the Dog constructor to accept and initialize instance data. • create a method to compute and return the age of the dog in "person-years" (note: dog age in person-years is seven times a dog's age). • Include a toString method that returns a one-line description of the dog • Write a driver class called Kennel, whose main method instantiated and updates several Dog objects
Answer:
Dog.java:
Dog{
//Declare instance variables
private String name;
private int age;
//Create the constructor with two parameters, and initialize the instance variables
public Dog(String name, int age){
this.name = name;
this.age = age;
}
//get methods
public String getName(){
return name;
}
public int getAge(){
return age;
}
//set methods
public void setName(String name){
this.name = name;
}
public void setAge(int age){
this.age = age;
}
//calculateAgeInPersonYears() method to calculate the age in person years by multiplying the age by 7
public int calculateAgeInPersonYears(){
return 7 * getAge();
}
//toString method to return the description of the dog
public String toString(){
return "Name: " + getName() + ", Age: " + getAge() + ", Age in Person Years: " + calculateAgeInPersonYears();
}
}
Kennel.java:
public class Kennel
{
public static void main(String[] args) {
//Create two dog objects using the constructor
Dog dog1 = new Dog("Dog1", 2);
Dog dog2 = new Dog("Dog2", 5);
//Print their information using the toString method
System.out.println(dog1.toString());
System.out.println(dog2.toString());
//Update the first dog's name using setName method
dog1.setName("Doggy");
System.out.println(dog1.toString());
//Update the second dog's age using setAge method
dog2.setAge(1);
System.out.println(dog2.toString());
}
}
Explanation:
*The code is in Java.
You may see the explanations as comments in the code
differentiate between a university and a TVET college in terms of what each offers and explain the stigma associated with TVET colleges
Answer: See explanation
Explanation:
The main focus of a Technical Vocational Education and Training (TVET) college is to prepare the students and train them so that they'll be functional in a skilled trade. It focuses on vocational training and education. University isn't really concerned about transfer of skills but rather more concerned with the transfer of knowledge to the students
The Technical Vocational Education and Training (TVET) qualification is also faster, cheaper and easier to get than the university certificate which is costlier and takes longer period to get.
The stigma associated with TVET colleges has been created by both the society and the government. Firstly, people believed that only those from poor backgrounds or those that couldn't gain university admisson go to TVET colleges.
Also, the government isn't helping matters as public funding for education are allocated more to universities and not really allocated to TVET colleges. These has brought about the stigma to the TVET.
The difference between a university and a TVET college in terms of what each offers is university impact knowledge while TVET college is more of practical.
University and TVET collegeThe major difference is University provide students with knowledge the need based on the course they are studying while TVET colleges is more of practical as they provide the students with practical skills they need because they render technical and vocational education and training.
The stigma associated with TVET colleges is because people think that University student has higher opportunities when in labor market than TVET colleges student.
Inconclusion the difference between a university and a TVET college in terms of what each offers is university impact knowledge while TVET college is more of practical.
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Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the gas cost for 20 miles, 75 miles, and 500 miles. Output each floating-point value with two digits after the decimal point, which can be achieved by executing cout << fixed << setprecision(2); once before all other cout statements.
Answer:
Explanation:
The following is written in C++ and asks the user for inputs in both miles/gallon and dollars/gallon and then calculates the gas cost for the requested mileages using the input values
#include <iostream>
#include <iomanip>
using namespace std;
int main () {
// distance in miles
float distance1 = 20.0, distance2 = 75.0, distance3 = 500.0;
float miles_gallon, dollars_gallon;
cout << "Enter cars miles/gallon: "; cin >> miles_gallon;
cout << "Enter cars dollars/gallon: "; cin >> dollars_gallon;
cout << "the gas cost for " << distance1 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance1 / miles_gallon << "$\n";
cout << "the gas cost for " << distance2 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance2 / miles_gallon << "$\n";
cout << "the gas cost for " << distance3 << " miles is " << fixed << setprecision(2) << (float) dollars_gallon * distance3 / miles_gallon << "$\n";
return 0;
}
When gathering the information needed to create a database, the attributes the database must contain to store all the information an organization needs for its activities are _______ requirements.
Answer:
Access and security requirements
9. Which of the following is the
leading use of computer?
Complete Question:
What is the leading use of computers?
Group of answer choices.
a. web surfing.
b. email, texting, and social networking.
c. e-shopping.
d. word processing.
e. management of finances.
Answer:
b. email, texting, and social networking.
Explanation:
Communication can be defined as a process which typically involves the transfer of information from one person (sender) to another (recipient), through the use of semiotics, symbols and signs that are mutually understood by both parties. One of the most widely used communication channel or medium is an e-mail (electronic mail).
An e-mail is an acronym for electronic mail and it is a software application or program designed to let users send texts and multimedia messages over the internet.
Also, social media platforms (social network) serves as an effective communication channel for the dissemination of information in real-time from one person to another person within or in a different location. Both email and social networking involves texting and are mainly done on computer.
Hence, the leading use of computer is email, texting, and social networking.
What is a key consideration when evaluating platforms?
Answer:
The continuous performance of reliability data integrity will lead to the benefit and profit of the platform's regular structure changes. Cleanliness in the platform whereas addresses the straightforward structure of task performance and adequate data integrity.
What Is the Purpose of a Web Browser? *
Answer:
This is your answer. If I'm right so,
Please mark me as brainliest. thanks!!!
An administrator wants to restrict access to a particular database based upon a stringent set of requirements. The organization is using a discretionary access control model. The database cannot be written to during a specified period when transactions are being reconciled. What type of restriction might the administrator impose on access to the database
Answer:
Time of the day and object restrictions
Explanation:
From the question, we understand that the database is not allowed to be accessed at a certain period of time.
Because this has to do with time (period), the administrator will need to set a time of the day object restriction on the database in order to prevent the users from accessing the database objects
define a computer, state its 3 main activities with examples of the functions of each of those activities
Answer:
The four main functions of a computer are to:
- take data and instructions from a user
-process the data according to the instructions
- and display or store the processed data.
These functions are also referred as the input function, the procedure function, the output function, and the storage function.
Explanation:
Bugs always seem to creep into programs and code. What strategies have you learned to find bugs more easily and crush them with a fix?
The process involves in finding bugs as well as crushing them in a debugging process is extensive and this can consist of following process;
Examination of the error symptoms
identifying the cause of it
fixing of the error.
This process is usually required a large amount of work, Although no precise procedure that is set in for fixing all error, but some useful strategies that use in reducing the debugging effort.
One of the significant part of this process is localizing of the error, which is figuring out the cause as well as the symptoms. Strategies that I have learnt in finding and fixing the error in the process of debugging includes;Incremental as well as bottom-up program development; development of the program incrementally remains one of the most effective ways that can be used in localizing the error, often testing as the piece of code is added, so with this it will be easier to find the error since any error is from the last piece of code added.And also since the last fragment of the code will be small then searching for bugs won't take much time to find and debug.Bottom-up development helps in maximizing the benefits that comes from incremental development. With bottom-up development, after successful testing of a code, it's behavior will not change once another piece is added to it, since existing code will never replied on new part so it will be easier to trace error in the new code and fix it.Instrument program can be used to log information and there can be insertion of print statements.Instrument program using assertions; Assertions can be used in checking if the program actually maintains the properties or those invariant that the code relies on, Because the program will definitely stops once the assertion fails, and there is actuality that the point where the program reached and stops is closer to the cause, as well as good indicator of how the problem looks like , then the bug can then be fixed.breakpoints can be set in the program as well as stepping and over functions, then watching program expressions, as well as inspection of the memory contents at a particular point during the execution can give the needed run-time information.Backtracking: this option works in a way whereby one will need to start from the point that the problem occurred then go back through the code to to detect the issue, then the bug can then be fixed.Binary search: this is exploration of the code by using divide and conquer approach, so that the the bug be pin down quickly.Therefore, Bugs are treat to programs and they can be dealt with using discussed methods.
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See the lseek_example.c file. Modify the lseek_example.c, such that it reads from an input file (named "start.txt") and will print to an output file (named "end.txt") every (1+3*i)th character, starting from the 1st character in the input file. In other words, it will print the 1st character, then skip 2 characters and print the 4th one, then skip 2 characters and print the 7th one, and so on.
For instance, for input file:
ABCDEFGHIJKLM
It will output:
ADGJM
Iseek_example.c file contant:
// C program to read nth byte of a file and
// copy it to another file using lseek
#include
#include
#include
#include
void func(char arr[], int n)
{
// Open the file for READ only.
int f_read = open("start.txt", O_RDONLY);
// Open the file for WRITE and READ only.
int f_write = open("end.txt", O_WRONLY);
int count = 0;
while (read(f_read, arr, 1))
{
// to write the 1st byte of the input file in
// the output file
if (count < n)
{
// SEEK_CUR specifies that
// the offset provided is relative to the
// current file position
lseek (f_read, n, SEEK_CUR);
write (f_write, arr, 1);
count = n;
}
// After the nth byte (now taking the alternate
// nth byte)
else
{
count = (2*n);
lseek(f_read, count, SEEK_CUR);
write(f_write, arr, 1);
}
}
close(f_write);
close(f_read);
}
// Driver code
int main()
{
char arr[100];
int n;
n = 5;
// Calling for the function
func(arr, n);
return 0;
}
Answer:
See the lseek_example.c file. Modify the lseek_example.c, such that it reads from an input file (named "start.txt") and will print to an output file (named "end.txt") every (1+3*i)th character, starting from the 1st character in the input file. In other words, it will print the 1st character, then skip 2 characters and print the 4th one, then skip 2 characters and print the 7th one, and so on.
For instance, for input file:
ABCDEFGHIJKLM
It will output:
ADGJM
Iseek_example.c file contant:
// C program to read nth byte of a file and
// copy it to another file using lseek
#include
#include
#include
#include
void func(char arr[], int n)
{
// Open the file for READ only.
int f_read = open("start.txt", O_RDONLY);
// Open the file for WRITE and READ only.
int f_write = open("end.txt", O_WRONLY);
int count = 0;
while (read(f_read, arr, 1))
{
// to write the 1st byte of the input file in
// the output file
if (count < n)
{
// SEEK_CUR specifies that
// the offset provided is relative to the
// current file position
lseek (f_read, n, SEEK_CUR);
write (f_write, arr, 1);
count = n;
}
// After the nth byte (now taking the alternate
// nth byte)
else
{
count = (2*n);
lseek(f_read, count, SEEK_CUR);
write(f_write, arr, 1);
}
}
close(f_write);
close(f_read);
}
// Driver code
int main()
{
char arr[100];
int n;
n = 5;
// Calling for the function
func(arr, n);
return 0;
}
Explanation:
NO LINKS OR I WILL DELETE YOUR FORTNITE ACCOUNT
What can you do with the free version of the splice editor
Answer:
can i have ur fortnite account if u hav one and dont use it :) i only say that cuz u mentioned fortnite
Explanation:
with the free version you can add effects (cheap effects) cut the video, crop some parts. and posting leaves a watermark until u buy money
Answer:
It has a 7 day free trial while your using the free version
Explanation:
A colleague has written a section of the main body of the same financial report. He has a long paragraph with lots of numbers. You suggest that he make this section easier to read by adding _____.
graphics
a reference
columns
a table
Answer:
a table
Explanation:
Answer: a table
Explanation:
Which lighting technique can often heighten a dramatic story?
No lighting.
Front lighting.
Natural lighting.
Side or back lighting.
Answer:
side or back lighting
Explanation:
big brain
Creative Commons material often costs money to use.
True
False
Answer:
true
Explanation:
how to check if serial interface is dte ot DCE?
If you can see the DTE/DCE cable, you can tell by looking which router has the DCE interface connected to it - the letters "DTE" or "DCE" will either be molded into the connector itself, or if it's an older cable there should be a little piece of tape on the cable that tells you what the interface type is.
Assume the data link protocol used by NDAS has the following associated characteristics:
An 8-bit ASCII code is used. Each frame has a size (length) of 11936 bits. A half-duplex circuit with a speed of 1 million bits per second is used for transmission. There is a 30-millisecond turnaround time on the half-duplex circuit. Each frame contains 20 overhead (non-user-data) bytes. Assume that the probability of a frame requiring retransmission due to error in transmission is 1 percent. A millisecond is one-thousandth of a second. Also, 8 bits = 1 character = 1byte
Fill in the blanks
K= _________ bits per bytes
M=_________ bytes
C= _________ overhead bytes
Answer:
The transmission speed = 0.278 MB/s
Explanation:
K = 8 bits
M = 11936/8 bits = 1492 bits
transmission rate R = 1000000/ 8 = 125000 bps
overhead bytes C = 20
probability = 0.01
time T = 30 ms = 30 x10^-3 s
The data transmission speed formula = K(M-C)(1-p) / (M/R) + T
= 8( 1492 - 20)(0.99)/ (1492/125000) + 30 x10^-3
= 0.278 MB/s
X274: Recursion Programming Exercise: Cannonballs Spherical objects, such as cannonballs, can be stacked to form a pyramid with one cannonball at the top, sitting on top of a square composed of four cannonballs, sitting on top of a square composed of nine cannonballs, and so forth.
RequireD:
Write a recursive function that takes as its argument the height of a pyramid of cannonballs and returns the number of cannonballs it contains.
Answer:
The function in C is as follows:
#include <stdio.h>
int C_ball(int height){
if(height == 1) {
return 1;}
return (height * height) + C_ball(height - 1);}
int main(){
int n;
printf("Height: ");
scanf("%d",&n);
printf("Balls: %d",C_ball(n));
return 0;
}
Explanation:
The function begins here
#include <stdio.h>
This defines the function
int C_ball(int height){
If height is 1, return 1
if(height == 1) {
return 1;}
This calls the function recursively
return (height * height) + C_ball(height - 1);}
The main begins here
int main(){
This declares the height as integer
int n;
This prompts the user for the height
printf("Height: ");
scanf("%d",&n);
This calls the function
printf("Balls: %d",C_ball(n));
return 0;
}
Use the drop-down menu to complete each statement. First, calculate the time spent doing each activity _____ . Next, multiply each category by ____ . Then, ___ the totals. Last, subtract the total from ____ .
Answer:1. Every day 2. 7 3. add 4. 168
Explanation:
I got it right on Edge
First, calculate the time spent doing each activity every day. Next, multiply each category by 7. Then, add the totals. Last, subtract the total from 365.
What is the significance of the activity?The significance of activity may be determined by the fact that it usually enhances your health and lowers the threat of developing several diseases and other abnormal conditions like type 2 diabetes, cancer, and cardiovascular disease.
According to the context of this question, if you are required to calculate the time spent doing each activity in each day. You are required to make a chart that represents all such activities followed by multiplication. Then, you are considerably required to add the totals followed by subtracting the total from the total number of days in a year.
Therefore, first, calculate the time spent doing each activity every day. Next, multiply each category by 7. Then, add the totals. Last, subtract the total from 365.
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Your co-worker who went to UCLA tells you that DHCP is not enabled at your new job, so you should just use the same IP address that you have at home to connect to the internet. He told you it should work because your computer is communicating with a unique public IP address at home, so no other computer in the world would have it. When you try this, your computer does not have internet access. Give two reasons why?
Answer:
1. internet connection is not enabled on the computer.
2. The DHCP server in the company is not enabled as well.
Explanation:
For a user to access the internet, the computer must have a public IP address that is either assigned to it by a service provider or dynamically from the DHCP server in the computer. In the case of the former, the user just needs to enable the internet connection to obtain the unique IP address.
If the DHCP server or the internet connection is not enabled, the user would not have access to the internet.
Which option in a Task element within Outlook indicates that the task is scheduled and will be completed on a later
date?
O Waiting on someone else
O In Progress
O Not started
O Deferred
Answer: D: Deferred
Explanation:
took test
what is the difference between the flip horizontal and the flip vertical option
Answer:
Flip horizontal: Flip around the vertical axis. Flip vertical: Flip around the horizontal axis.
Explanation:
hope this helps
Consider the regular expressions:
R1 = (01)* (0*1*) (10)
R2 = (101)* (01)*
R3 = (10) (01*)*(01)
R4 = 10(R2*)|R3
Recall that, for a list of regular expressions, the function getToken() returns the next token from the input that matches one of the regular expressions. If there is more than one match, the longest match is returned. If there is more than one longest match, the token with the longest match that appears first in the list is returned. If there is no match, ERROR is returned. If the function getToken() is called once on input 1000101, it will return:
a. R1
b. R2
c. R3
d. R4
e. ERROR
Answer:
c. R3
Explanation:
For R1;
there are 10 matches, after these 10 no matches occur again
for R2;
this also does not match more than 10 as we have in R1
for r3;
R3 has the longest match. Its matching can be done 1000101 times.
for r4;
The whole of r4 can be matched.
Error;
we cannot have an error because matches exist.
so in answer to this question we pick R3 as the solution because there are more than one longest march and the one returned in the list is that which appeared first. R3 came first
In this exercise we have to use computer knowledge to identify which is the correct sequence of code that best corresponds to the given question, in this way we have that the correct alternative is:
[tex]c. R3[/tex]
So analyzing the first alternative, we find;
For R1, there are 10 matches, after these 10 no matches occur again.
So analyzing the second alternative, we find;
For R2, this also does not match more than 10 as we have in R1
So analyzing the third alternative, we find;
R3 has the longest match. Its matching can be done 1000101 times.
So analyzing the fourth alternative, we find;
For R4, the whole of r4 can be matched.
So analyzing the fifth alternative, we find;
Error; we cannot have an error because matches exist.
So in answer to this question we pick R3 as the solution because there are more than one longest march and the one returned in the list is that which appeared first.
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1. Add the following method to the Point class:
public double distance(Point other)
Returns the distance between the current Point object and the given other Point object. The distance between two points is equal to the square root of the sum of the squares of the differences of their x- and y-coordinates. In other words, the distance between two points (x1, y1) and (x2, y2) can be expressed as the square root of (x2 - x1)2 + (y2 - y1)2. Two points with the same (x, y) coordinates should return a distance of 0.0.
public class Point {
int x;
int y;
// your code goes here
}
2. Create a class called Name that represents a person's name. The class should have fields named firstName representing the person's first name, lastName representing their last name, and middleInitial representing their middle initial (a single character). Your class should contain only fields for now.
3. Add two new methods to the Name class:
public String getNormalOrder()
Returns the person's name in normal order, with the first name followed by the middle initial and last name. For example, if the first name is "John", the middle initial is 'Q', and the last name is "Public", this method returns "John Q. Public".
public String getReverseOrder()
Returns the person's name in reverse order, with the last name preceding the first name and middle initial. For example, if the first name is "John", the middle initial is 'Q', and the last name is "Public", this method returns "Public, John Q.".
4. Add the following method to the Point class:
public int quadrant()
Returns which quadrant of the x/y plane this Point object falls in. Quadrant 1 contains all points whose x and y values are both positive. Quadrant 2 contains all points with negative x but positive y. Quadrant 3 contains all points with negative x and y values. Quadrant 4 contains all points with positive x but negative y. If the point lies directly on the x and/or y axis, return 0.
public class Point {
private int x;
private int y;
// your code goes here
}
Answer:
Explanation:
The following code is written in Java and creates all of the methods that were requested in the question. There is no main method in any of these classes so they will have to be called from the main method and call one of the objects created method for the code to be tested. (I have tested it and it is working perfectly.)
class Point {
private int x, y;
public void Point(int x, int y) {
this.x = x;
this.y = y;
}
public double distance (Point other) {
double distance = Math.sqrt(Math.pow((other.x - this.x), 2) + Math.pow((other.y - this.y), 2));
return distance;
}
public int quadrant() {
if (this.x > 0 && this.y > 0) {
return 1;
} else if (this.x < 0 && this.y > 0) {
return 2;
} else if (this.x < 0 && this.y < 0) {
return 3;
} else if (this.x > 0 && this.y < 0) {
return 4;
} else {
return 0;
}
}
}
class Name {
String firstName, lastName;
char middleInitial;
public String getNormalOrder() {
String fullName = firstName + " " + middleInitial + " " + lastName;
return fullName;
}
public String getReverseOrder() {
String fullName = lastName + ", " + firstName + " " + middleInitial;
return fullName;
}
}
What is the New York Times doing to try to keep up with digital technology?
Answer:
Clover Food Labs: Using Technology to Bring The “Real Food” Movement to Cambridge, ... The New York Times is one of the many companies that has had its existence ... That monthly limit has since been reduced to 10 articles in an attempt to ... which has at least kept pace with the limited expectations for the industry
Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, and C) in the instruction set. M1 has a clock rate of 60MHz and M2 has a clock rate of 80MHz. The average number of cycles of each instruction class and their frequencies (for a typical program) are as follows:
Instruction Class M1-cycles M2-cycles/ Frequency
/instruction class instruction class
A 1 2 50%
B 2 3 20%
C 3 4 30%
a. Calculate the average CPI for each machine, M1 and M2.
b. Calculate the CPU execution time of M1 and M2.
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
how can we achieve an effective communication with other people
. Which of these perform real-world activities such as eating, sleeping, walking, and running in virtual worlds?
Answer:
all
Explanation:
Answer:
avatars
Explanation: I just took the test
____ a device receiving a process variable
Answer:
Transmitter
Maybe this is the answer or the question is wrong.
Explanation:
In the world of process control, a Transmitter is a device that converts the signal produced by a sensor into a standard instrumentation signal representing a process variable being measured and controlled.