A ship’s captain sights the top of a 200 foot cliff at a 17° angle of elevation. How far is the ship from the base of the cliff? Round to the nearest foot.

Answer:

654 ft

Step-by-step explanation:

in this case you have a SOH-CAH-TOA problem.

we need Adjacent and opposite so we use tan

tan (17) = O/A

tan (17) = 200ft / x

x = 654.17 ft

to the nearest foot = 654 ft

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Leave a like and mark brainliest if this helped

The distance that represent the ship from the base of the cliff should be considered as the 654 ft.

Since

A ship’s captain sights the top of a 200 foot cliff at a 17° angle of elevation.

So the following formula should be applied

[tex]tan (17) = O/A\\\\tan (17) = 200ft / x[/tex]

x = 654.17 ft

= 654 ft

hence, The distance that represent the ship from the base of the cliff should be considered as the 654 ft.

Learn more about distance here: https://brainly.com/question/24705024

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