A rocket blasts off from the Earth's surface. During the initial phase of flight, the engine of the rocket burns fuel at a rate α, which creates thrust by expelling exhaust gas downward with velocity β relative to the velocity of the rocket. The thrust from the engine provides an additional upward force on the rocket of magnitude αβ. By Newton's 2nd Law, the equation governing the motion of the rocket while the rocket is burning fuel is

Answers

Answer 1

Answer:

αβ = Ma

Explanation:

By Newton's 2nd Law, the equation governing the motion of the rocket while the rocket is burning fuel is

αβ = Ma where  α = rocket's fuel burning rate, β = relative to the velocity of the rocket, M = instantaneous mass of the rocket and a = acceleration of rocket.


Related Questions

A positively charged particle of mass 7.2 x 10-8 kg is traveling due east with a speed of 88 m/s and enters a 0.6-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 2.2 x 10-3 s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. Determine the magnitude of its charge in mC. (1 mC

Answers

Answer:

q = 8.57 10⁻⁵ mC

Explanation:

For this exercise let's use Newton's second law

         F = ma

where force is magnetic force

        F = q v x B

the bold are vectors, if we write the module of this expression we have

         F = qv B sin θ

as the particle moves perpendicular to the field, the angle is θ= 90º

        F = q vB

the acceleration of the particle is centripetal

        a = v² / r

we substitute

        qvB = m v² / r

         qBr = m v

          q =[tex]\frac{m\ v}{B\ r}[/tex]

The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use

          v = d / t

the distance is ¼ of the circle,

          d = [tex]\frac{1}{4} \ 2\pi r[/tex]

           d =[tex]\frac{\pi }{2r}[/tex]

we substitute

           v =  [tex]\frac{\pi r}{2t}[/tex]

           r = [tex]\frac{2 \ t \ v}{\pi }[/tex]

           

let's calculate

           r =[tex]\frac{2 \ 2.2 \ 10^{-3} \ 88}{\pi }[/tex] 2 2.2 10-3 88 /πpi

           r = 123.25 m

         

let's substitute the values

           q = [tex]\frac{ 7.2 \ 10^{-8} \ 88}{ 0.6 \ 123.25}[/tex]7.2 10-8 88 / 0.6 123.25

            q = 8.57 10⁻⁸ C

Let's reduce to mC

           q = 8.57 10⁻⁸ C (10³ mC / 1C)

           q = 8.57 10⁻⁵ mC

6th grade science I mark as brainliest (can someone answer my other question like this?)

Answers

Answer:A: July

B: July and august

C:true

Explanation:

Which sentence is correct?

Answers

Answer:

pretty sure its B if it isnt im so so sorry

Explanation:

A force of 350 N is applied to an object that accelerated at a rate of 5 m/sec2. What is the mass of the object

Answers

Answer:

7/ m5sec per minute ckvhxrsuvj

image.
A concave lens always produces a(n)
A. inverted
o
B. real
C. virtual
D. magnified

Answers

Answer : B - real

Explanation : 1. you can see the image the way it is as in its no in a mirror.
2. The image will not be inverted

But it could be magnified too tbh. But I would go for real

Answer:

Explanation:

Its Virtual, how would you describe the image formed by a convex mirrior? virtual upright, smaller

How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?

Answers

W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J

Two carts collide and have a perfectly inelastic collision. Cart1 has a mass of 500 grams and
Cart2 has a mass of 600 grams. Cart1 has an initial westward velocity of 1.6 m/s and collides
with Cart2 which was initially at rest. What is was the final velocity of the two cart system (SI
units)?

Answers

Answer: look at the file

(PLEASE) You go sledding down a hill and are traveling toward the east. At 0s, your velocity is 0m/s. At 5s, your velocity is 30m/s. Calculate your acceleration.

Answers

Answer:

your acceleration is 6 m/s²

Explanation:

Given;

initial velocity, u = 0

initial time, t₀ = 0

final velocity, v = 30 m/s

final time, t = 5 s

The acceleration of is calculated as follows;

[tex]a = \frac{v-u}{t_1-t_0} \\\\a = \frac{30-0}{5-0} \\\\a =\frac{30}{5} \\\\a = 6 \ m/s^2[/tex]

Therefore, your acceleration is 6 m/s²

A 16 g ball at the end of a 1.4 m string is swung in a horizontal circle. It revolves once every 1.09 s. What is the magnitude of the string's tension?



Answer and I will give you brainiliest

Answers

Answer:

6.56

Explanation:

frequency = 1/1.09 = 0.92 Hz

f = 1/(2L) × √T/m

0.92 = 1/2(1.4) × (√T/√16)

0.92 = 0.36 × (√T)/4

multiply all through by 4

3.68 = 1.44 × √T

√T = 3.68/1.44 = 2.56

T = 2.56² = 6.56

The magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton

Given the data in the question;

Mass of the ball;[tex]m = 16g = 0.016kg[/tex]String is swung in a horizontal circle, Radius; [tex]r = 1.4m[/tex]Period of revolution; [tex]T = 1.09s[/tex]Magnitude of the string's tension; [tex]F_T = ?[/tex]

First, we need to get magnitude of the centripetal acceleration:

[tex]a_c = \frac{4\pi ^2r}{T^2}[/tex]

We substitute in our given values

[tex]a_c = \frac{4\pi ^2\ *\ 1.4m}{(1.09s)^2} \\\\a_c = 46.519 m/s^2[/tex]

Now, from Newton's Second Law of Motion:

[tex]F = m\ * \ a[/tex]

Where F is the force, m is the mass of the object and a is the acceleration

We substitute into the equation to get the magnitude of the string's tension.

[tex]F = 0.016kg \ *\ 46.519m/s^2[/tex]

[tex]F = 0.744 kg.m/s^2\\\\F = 0.744 N[/tex]

Therefore, the magnitude of the string's tension as it is swung in a horizontal circle is 0.744 Newton

Learn more; https://brainly.com/question/14039108

The amount of energy a substance has depends on the state of matter
the substance is in at the time.

True
or False

Answers

False I believe!
Hope it’s right!

A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 458 N and have a center of gravity that is 1.34 m above the floor. His upper legs weigh 120 N and have a center of gravity that is 0.766 m above the floor. Finally, his lower legs and feet together weigh 89.8 N and have a center of gravity that is 0.204 m above the floor. Relative to the floor, find the location of the center of gravity for the entire body.

Answers

Answer:

the location of the center of gravity for the entire body is 1.08 m

Explanation:

Given the data in the question;

w1 = 458 N, y1 = 1.34 m

w2 = 120 N, y2 = 0.766 m

w3 = 89.8 N, y2 = 0.204 m

The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.

so,

[tex]Y_{centre of gravity}[/tex] = (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )

so we substitute in our values

[tex]Y_{centre of gravity}[/tex] = (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )

[tex]Y_{centre of gravity}[/tex] = 723.9592 / 667.8

[tex]Y_{centre of gravity}[/tex] = 1.08 m

Therefore, the location of the center of gravity for the entire body is 1.08 m

Could a sea breeze occur at night? Explain why or why not.

Answers

No sea breeze can not occur at night because while sea breezes occur during the day, land breezes occur at night. Despite the difference in times at which the land breezes and sea breezes occur, the reason for the land breeze's formation is basically the same as the sea breeze, but the role of the ocean and land is reversed.
Hope this helps ✌️

whk is thefounder of pakistan?​

Answers

Answer:

Muhammad Ali Jinnah (Urdu: محمد علی جناح‎; born Mahomedali Jinnahbhai; 25 December 1876 – 11 September 1948) was a barrister, politician and the founder of Pakistan.

Mohammed Ali Jinnah, also called Qaid-i-Azam (Arabic: “Great Leader”), (born December 25, 1876?, Karachi, India [now in Pakistan]—died September 11, 1948, Karachi), Indian Muslim politician, who was the founder and first governor-general (1947–48) of Pakistan

James makes a treasure map to locate a secret item on McEachern Campus. He uses the
following displacement vectors to locate the treasure
A student wants to simplify this information
5 m East
7 m North
5 m South
7 m East
3 m South
2 m West
A. Determine the Displacement Vector Components. (x componenty component)
Show all work. 2 pts
B. Use the Pythagorean Theorem to calculate the resultant vector. Show all work. 2 pts
Answer format:
a. work & answer...
b. work and answer...
(4 Points)

Answers

Answer:

south

Explanation:

A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is the initial height of the bob?

Answers

Answer:

h = 18.4 cm

Explanation:

Given that,

The speed of the bob at the bottom of the swing is 1.9m/s.

We need to find the initial height of the bob. Let it is h.

We can find it using the conservation of energy i.e.

[tex]mgh=\dfrac{1}{2}mv^2[/tex]

Where

v is speed of the bob

So,

[tex]h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m[/tex]

or

h = 18.4 cm

So, the initial height of the bob is 18.4 cm.

The initial height of bob will be "18.4 cm".

Speed and height:

Speed would be the scalar quantity that describes "how quickly an attribute moves." This could sometimes be defined as this same rate whereby an object travels a given distance.

According to the question,

The speed of the bob = 1.9 m/s

Let,

The initial height be "h".

By using the conservation of energy, we get

→ mgh = [tex]\frac{1}{2}[/tex]mv²

or,

→      h = [tex]\frac{v^2}{2g}[/tex]

By substituting the values, we get

          = [tex]\frac{(1.9)^2}{2\times 9.8}[/tex]

          = 0.184 m or,

          = 18.4 cm

Thus the above answer is correct.

Find out more information about speed here:

https://brainly.com/question/13665920

give two differences between sextusl reproduction and asextual reproduction

Answers

Answer:

Sexual reproduction you need two organisms to reproduce.

Asexual is when you can multiply yourself and there is nothing different about the offspring and the parent.

why don't we draw lewis dot diagrams for nobel gases

Answers

In a ground-state atom, the first two valence electrons go into the "s" orbital, so they'll be paired and it's appropriate to put a pair of dots into a Lewis dot diagram. ... Noble gases have a complete set of valence electrons (2 for helium and 8 for the others), so this one can't be a noble gas.

proof that the kinetic energy of a moving body is half mv square​

Answers

Answer:

1

Explanation:

a virtual image is formed by
a) simple microscope b) telescope c) the ordinary camera d) a slide projector in a cinema hall​

Answers

Answer: ordinary camera

Explanation:

Answer:

C.

Explanation:

A person in car slides to the right when going through a very sharp left turn on the highway. Is that law of inertia or law of acceleration?​

Answers

Answer:

Inertia :)

Explanation:

ELE Review questions
POSSIBLE POINTS: 3
Match the energy transformation sequence with the device it describes:
A hair dryer plugged into the wall
a
A hand crank generator emergency radio
A battery operated fan
11 CE to ELE
+ ELE to KE
:: KE to ELE
h
1
2
A Review

Answers

Answer:

1. ELE to KE = Electrical energy conversion to kinetic energy.

2. KE to ELE = kinetic energy conversion to electrical energy.

3. CE to ELE = chemical energy conversion to electrical energy.

Explanation:

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

Some examples of energy are chemical energy, electrical energy, kinetic energy, sound energy, potential energy, light energy, etc.

The transformation of energy from one form to another are described below;

1. A hair dryer plugged into the wall: it involves the conversion of electrical energy to kinetic energy. The energy type present in the wall socket is electrical energy which powers the hair dryer to have kinetic energy i.e the energy possessed due to motion of hair dryer.

2. A hand crank generator emergency radio: it illustrates the conversion of kinetic energy to electrical energy. The hand crank generator possess kinetic energy as it is being wounded before it is then converted into electrical energy which powers the radio.

3. A battery operated fan: it illustrates the conversion of chemical energy to electrical energy. The cells present in battery possess chemical energy that is being converted into electrical energy to power the fan.

if a wave passes every 17.4 seconds, what is the frequency?

Answers

Answer:

to be completely honest I have no idea however I tried calculating it on a calculator and umm...

I think the frequency is...

17,229,452

but ya know I could be totally wrong so if I am sorry

How does the energy in a system of magnets change when two magnets repel and move away from each other

Answers

When the magnetic force between opposite poles pulls them together the potential energy of the system decreases. Because like poles repel each other, to push them together you have to transfer energy to the system.

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular aluminum plates, each 20 cm in diameter, separated by 1.0 cm. How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, the field that causes a spark is at the high end of the range pre- sented in the chapter; assume a value of 3 * 106 N/C.

Answers

Answer:

Q = 0.83 μC

Explanation:

Assuming that plates are much larger than the distance between them, we can think the electric field as constant and perpendicular to the outer surface of the plates.Applying Gauss' law to a rectangular surface half inside one of the plates and half outside it, since E and A are parallel each other, and E is zero on the other three faces, we can find the following expression for the electric field created by the charge on the plate:

      [tex]E = \frac{Q*A}{\epsilon_{0} } (1)[/tex]

Solving for Q, replacing E by the maximum electric field that doesn't cause the dielectric strength to break (3*10⁶ N/C), we get:

      [tex]Q_{max} = E_{max} * \pi *\frac{d^{2}}{4} *\epsilon_{0} = 3e6N/C*\pi *\frac{(0.2m)^{2} }{4} * 8.85e-12C2/Nm2 = 0.83\mu C (2)[/tex]

it is a line that intersects a circle at exactly two points.​

Answers

Secant is the answer. Please mark brainliest.

A line that intersects a circle at exactly two points is called a secant line.

hope this helped!

You are hiking pine mountain and have finally reached the top. You are peering over the edge and accidentally drop your phone while taking pictures. Your phone falls and hit the
ground 13 seconds later. How tall is the mountain?

Answers

Answer:

The cliff is 12.71m tall.

Explanation:

Why?

Before solving the problem, we must remember that the phone was dropped, it means that there is no initial velocity, also, the acceleration acting on the phone is the acceleration due to gravity.

So, to find how tall is the cliff, we can use the following equations:

\begin{gathered}y=y_o+v_o*t-\frac{1}{2}g*t^{2}\\\\v_f=v_o+g*t\end{gathered}y=yo+vo∗t−21g∗t2vf=vo+g∗t

\begin{gathered}t=\frac{v_f}{g} \\\\t=\frac{-15.75\frac{m}{s}}{-9.81\frac{m}{s^{2}}}=1.61s\end{gathered}t=gvft=−9.81s2m−15.75sm=1.61s

Now that we know the time, we can calculate how tall is the cliff:

\begin{gathered}y=y_o+v_o*t+\frac{1}{2}g*t^{2}\\\\y=0+0*1.61s-\frac{1}{2}*(-9.81\frac{m}{s^{2}})*(1.61s)^{2}\\\\y=12.71m\end{gathered}y=yo+vo∗t+21g∗t2y=0+0∗1.61s−21∗(−9.81s2m)∗(1.61s)2y=12.71m

Approximately where is it currently high tide on Earth? Group of answer choices wherever it is currently noon anywhere that ocean water laps upon the shore on the portion of Earth facing directly toward the Moon and on the portion of Earth facing directly away from the Moon only on the portion of the Earth facing directly toward the Moon

Answers

Answer:

Option D, only on the portion of the Earth facing directly toward the Moon

Explanation:

Tides are caused by the gravitational pull of moon. The part of earth that faces the moon experiences the highest gravitational force and hence the high tides will occur in this regions only. The regions that do not faces the moon experiences low tides. It is the gravity of moon that attracts the ocean water towards itself.

Hence, Option D is correct

Which list below contains only ionic compounds?
A. CaCl2, H2O, LIF
B. CO2, K20, P4010
C. LiF, CaCl2, Mgo
D. NO2, Mgo, CuCl2

Answers

Answer:

C. LiF, CaCl2, MgO

Explanation:

Ionic compound: It is that compound which consist of negative and position ions and held together by electrostatic force of attraction.

The ionic compound is neutral.

The ionic compound formed between metal and non-metal.

Covalent compound: It is that compound in which sharing of electrons between two atoms occur.

A.[tex]CaCl_2,H_2O,LiF[/tex]

H2O is not ionic compound. It is polar covalent.

Therefore, it does not contain only ionic compounds.

B.CO2,K2O,P4O10

CO2 and P4O10 are not ionic .It is covalent.

Therefore, it does not contain only ionic compounds.

C. LiF,CaCl2 ,MgO

All compounds are ionic because in given compounds one ion is negative  and one is metal (positive).

Therefore, it contains only ionic compounds.

D.NO2,MgO,CuCl2

NO2 is not ionic.

Therefore, it does not contain only ionic compounds.

Option C is correct.

I need help with this, I can't figure it out.
Here is the link:
https://platform.breakoutedu.com/game/play/fun-in-the-sun-140559-XMWCQF1LPL

Answers

Answer:

Star, Triangle, Circle, Rhombus, Square.Left, Down, Right, Down, Up.2,3,2,4.L,O,O,K,I,N,G,F,L,Y.

Explanation: You're welcome ✓

A rotating paddle wheel is inserted in a closed pot of water. The stirring action of the paddle wheel heats the water. During the process, 30 kJ of heat is transferred to the water and 5 kJ is lost to the surrounding air. The paddle wheel work amounts to 500 J. Determine the final energy of the system if its initial energy is 10 kJ.

Answers

Answer:

the final energy of the system is 35.5 kJ.

Explanation:

Given;

initial energy of the system, E₁ = 10 kJ

heat transferred to the system, q₁  30 kJ

Heat lost to the surrounding, q₂ = 5kJ

heat gained by the system, Q = q₁ - q₂ = 30 kJ - 5kJ = 25 kJ

work done on the system, W = 500 J = 0.5 kJ

Apply first law of thermodynamic,

ΔU = Q + W

where;

ΔU  is change in internal energy

Q is the heat gained by the system

W is work done on the system

ΔU = 25kJ + 0.5 kJ

ΔU = 25.5 kJ

The final energy of the system is calculated as;

E₂ = E₁ + ΔU

E₂ = 10 kJ + 25.5 kJ

E₂ =  35.5 kJ.

Therefore, the final energy of the system is 35.5 kJ.

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