A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
mass.
Question 1: The empirical formula for this compound is :

Question 2: The molar mass for this compound is 82.98 g/mol.
The Molecular formula for this compound is:

Answers

Answer 1

Answer: 1. The empirical formula is [tex]PNF_2[/tex]  

2. The molecular formula is [tex]PNF_2[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P =[tex]\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles[/tex]

Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles[/tex]

Moles of F =[tex]\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = [tex]\frac{1.20}{1.20}=1[/tex]

For N = [tex]\frac{1.20}{1.20}=1[/tex]

For F =[tex]\frac{2.41}{1.20}=2[/tex]

The ratio of P: N: F= 1: 1: 2  

Hence the empirical formula is [tex]PNF_2[/tex]

The empirical weight of [tex]PNF_2[/tex]= 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1[/tex]

The molecular formula will be=[tex]1\times PNF_2=PNF_2[/tex]


Related Questions

Calculate the percent by mass of the solute in an aqueous solution of 27.2 g ethanol in 250 g of total solution.

Answers

Answer:

Explanation:

H

Mass percent can be calculated from the mass of solute in grams divided by the mass of solution multiplied by 100. The percent by mass of the solute in aqueous solution of 27.2 g  ethanol in 250 g of total solution 10.88 %.

What is mass percentage?

Mass percentage is term used to represent the concentration of a solution. Mathematically mass percent of a component in a mixture is  the mass of the component divided by the total mass multiplied by 100.

A solution  is made of a solvent and solute. Thus, the total mass of the solution is the sum of mass of solute and mass of the solvent. Here, the solute is ethanol with a mass of 27.2 g. The total mass of solution is 250g.Hence, the mass percent of ethanol can be calculated as follows:

Mass percent of ethanol = mass of ethanol/total mass ×100

                                         =   (27.2/250)×100

                                         = 10.88 %.

Hence, the percent by mass of solute ethanol in the total solution is 10.88%.

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What are the benefits of Fluoride?

Answers

Answer:

The benefits of Fluoride are rebuild (remineralize) weakened tooth enamel.slow down the loss of minerals from tooth enamel.reverse early signs of tooth decay.prevent the growth of harmful oral bacteria

Answer:

Fluoride is often called nature's cavity fighter and for good reason. Fluoride, a naturally-occurring mineral, helps prevent cavities in children and adults by making the outer surface of your teeth (enamel) more resistant to the acid attacks that cause tooth decay.

How do you balance: Al+Fe3O4=Al2O3+Fe ?

Answers

Answer:

8Al+3Fe3O4=4Al2O3+9Fe

Answer:

8Al + 3Fe3O4 → 4Al2O3 + 9Fe

Explanation:

A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.What is the specific heat of the substance?

Answers

Answer:

0.3832

Explanation:

Givens

m = 437.2 grams

c = ?

delta t = 69.8 - 19.3

H = 8460 J

Formula

H = m*c*Δt

Solution

8460 = 437.2 * c * (69.8 - 19.3)

8460 = 437.2 * c * 50.5

8460 = 22078.6 * c

c = 8460 / 22078,6

c = .3832 J / (oC * gr)

How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)
I really couldn't find the answer since molarity and volume for sodium carbonate are not given.
I will mark the correct answer with steps as best answer.

Answers

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

The amount of HCl required for counterbalancing 1.25 g of Na2CO3(Sodium Carbonate) would be:

- [tex]34 ml[/tex]

Given that,

Mass of Na2CO3 [tex]= 1.25 g[/tex]

To find the Moles of Na2CO3, we will find the molar mass of Na2CO3,

Molar Mass of or Na2CO3 [tex]= 106 g/mol[/tex]

So,

Moles of Na2CO3 [tex]= mass /molar mass[/tex]

[tex]= 1.25/106[/tex]

[tex]= 0.012 mol[/tex]

To determine the quantity of HCl required to display the reaction with 0.012 mol of Na2CO3

[tex]Na_{2} CO_{2} + 2HCl[/tex][tex]H_{2}CO_{3} + 2NaCl[/tex]

While balancing the equation, we know that [tex]0.012[/tex] × [tex]2 = 0.024 mole of HCl[/tex] is necessary to process the reaction.

Now,

As we know,

HCl moles [tex]= 0.024[/tex]

Molarity of HCl [tex]= 0.715 M[/tex]

∵ Quantity of HCl required = Moles/Molarity

[tex]= 0.024 / 0.715[/tex]

[tex]= 0.034 l[/tex] [tex]or 34ml[/tex]

Thus, 34 ml is the correct answer.

Learn more about 'Molarity' here:

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Consider a solution which is 0.10M in NH3 and 0.20M in NH4Cl. Choose ALL of the following that are false. If a small amount of NaOH is added, the pH becomes slightly more basic. If HCl is added, the H ions react with the NH3. If a small amount of HCl is added, the pH becomes slightly more basic. If NaOH is added, the OH- ions react with the NH3. If NH4NO3 is added, the pH becomes more basic.

Answers

Answer:

The incorrect or the false options are -

(B) - If NH4NO3 is added, the pH becomes more basic.

(D) - If a small amount of HCl is added, the pH becomes slightly more basic.

 (E) - If NaOH is added, the OH- ions react with the [tex]NH_3[/tex].

Explanation:

The given solution the buffer basic .

When a small amount of either is added, the hydrogen ion reacts with the ammonium ion, raising the pH slightly.When a small amount of HCl is added, the hydronium ion reacts with the ammonia, raising the pH slightly.

Therefore , the options A ( If a small amount of NaOH is added, the pH becomes slightly more basic.) and C ( If HCl is added, the H+ ions react with the NH3.) All other B , D , E are false .

Cosmic rays are

A. High energy radiation produced in the ozone layer.
B. High energy radiation produced by the earth’s core.
C. None of these.
D. High energy radiation produced by the sun.

Answers

A. High energy radiation produced in the ozone layer. (:

How many milliliters of a 25% (m/v) NaOH solution would contain 75 g of NaOH?
A 19 mL
B) 25 mL
C
33 mL
D
75 mL
E
3.0 x 102 mL

Answers

Answer:

E  3.0 x 10² mL.

Explanation:

Hello there!

In this case, according to the formula for the calculation of the mass-volume percent:

[tex]\% m/V=\frac{m_{solute}}{V_{solution}}*100\%[/tex]

Whereas it is necessary to know the mass of the solute and the volume of the solution. Thus, given the mass of NaOH as the solute, the volume of the solution would be:

[tex]V_{solution}=\frac{m_{solute}}{\% m/V}*100\%[/tex]

Then, by plugging in we obtain:

[tex]V_{solution}=\frac{75g}{25\%}*100\%\\\\V_{solution}=3.0x10^2mL[/tex]

Thus, the answer is E  3.0 x 10² mL.

Best regards!

Which one is it for a brialiest

Answers

I’m confused about the question

Calculate the pH when [H]= 7.5 x 10^-12M

Answers

Answer:

11.1249387366083

Explanation:

you do -log([H+]

which method is adopted in the seperation of lead chloride from water​

Answers

Explanation:

by dissolving the mixture of lead sulphate and lead chloride in water we can separate the two. after dissolving the mixture on water lead sulphate can be obtained as the solid that 's left behind lead chloride can be recovered by evaporating.

Which of these actions precedes a precipitation event
A: clouds form
B: the air gets colder
C: the wind picks up speed
D: Raindrops are supercooled​

Answers

Answer:

C. The wind picks up speed

Explanation:

Im not sure but i hope im correct

Btw goodluck:)

I think it is C but I’m not sure

thesis: physical science improves nursing through technology, energy, and Matter.

write a 4-page essay explaining how science improves Nursing career and how it revolves around

Technology

Energy

Matter

Answers

Answer:

When science educators teach nurses, their primary aim should be to help them to develop understanding of their world of nursing. From a study of registered nurses' conceptions of the physical science underlying their clinical practice, we assert that nurses' understanding of the physical sciences is inadequate in terms of the competencies required of them as nurses.

Explanation: Hopes this helps You A lot :-D

The trait that seems to fade into the background.
Dominant
Recessive

Answers

The correct answer is Recessive
Recessive I guess? I don’t even know what this mean

Which element had the smallest atomic radius

Answers

Answer:

helium is the answer

Explanation:

helium is the smallest element in francium is the largest hope this helps

Marked out of 1.50
A student weights his unknown sample on
uncalibrated balance and obtains a weight of
1.0555 g. If the true weight of the unknown sample
is 1.0755 g, what is the % relative error in his
weight measurements?
+0.94٪
- 1.86%
+1.86%
-0.94​

Answers

Answer:

+.0.94%

Explanation:

Relative and average atomic mass both describe properties of an element related to its different isotopes. Out of these two Relative atomic mas is more accurate. Thus the % relative error in his weight measurements is +.0.94%.

What is mass?

Mass defines the quantity of a substance. It is measured in gram or kilogram. Average mass is the mass of atoms of an element that are isotopes. It can be calculated by multiplying mass of a isotope to natural abundance of that isotope.

The relative mass is the mass that is with respect to mass of a matter that is considered as standard. In chemistry relative mass is equal to the mass of one-twelfth the mass of C-12 isotope .

% relative error=(Difference in weight÷ original weight)×100

Difference in weight= original weight -calculated weight

original weight=1.0755 g

calculated weight=1.0555 g

Difference in weight= 1.0755 g-1.0555 g=0.02g

% relative error=(0.02g÷ 1.0755 g)×100

                         =+.0.94%

Thus the % relative error in his weight measurements is +.0.94%.

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The particle in the atom with a negative charge is the...

Answers

Answer: electrons

Explanation: An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons.

what volume of 1.75 h2so4 would be needed to neutralize 350 ml of 3.33 m sodium hydroxide?​

Answers

Answer:

1.332 L

Explanation:

The reaction that takes place is:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

First we calculate the number of NaOH moles, using the given volume and concentration:

350 mL * 3.33 M = 1165.5 mmol NaOH

Then we convert NaOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

1165.5 mmol NaOH * [tex]\frac{2mmolH_2SO_4}{1mmolNaOH}[/tex] = 2331 mmol H₂SO₄

Finally we calculate the required volume of a 1.75 M solution of H₂SO₄, using the concentration and number of moles:

2331 mmol / 1.75 M = 1332 mL

We can convert mL into L:

1332 mL / 1000 = 1.332 L

Which nitrogenous base is NOT found in DNA? *
A. cytosine
B. guanine
C. uracil
D. adenine

Answers

Answer:

c. uracil

Explanation:

uracil is not found in DNA. the missing base would be thymine

Bacteria can be heterotrophs or autotrophs
true or false?

Answers

Answer:

True

Explanation:

I learned about it a few years ago

If 8.25g N2 gas is inside a 1.50L flask at 325K what is the pressure inside the flask

Answers

Answer:

8.26g

Explanation:

8.25g +1.50÷325k=8.26g

PLEASE ASNWR ASAP
If I have a 50 liter container that holds 45 moles of gas at a pressure of 2.66 x 104 mmHg, what is the
temperature inside the container? ** convert pressure to atm**

Answers

34.95 atm

lol i hope i’m not too late



K(+1)Cl(+5)O3(-2) → K(+1)Cl(-1) + O2(0)

Answers

Answer:

Looooolllllllllllll

Explanation:

What is the question bro

In an experiment, 135.2 grams of a mystery metal is heated to 100.0*C. The metal is then dumped into a calorimeter with 59.0 grams of water at 26.0*C. The temperature of the water in the calorimeter increases to 35.0*C after the metal is dumped into it. What is the specific heat capacity of the metal? Express your answer to 2 past the decimal. Do NOT include units

Answers

The answer wound be 23 units I think

What type of chemical reaction is this?

2Na + 2H20 - 2NaOH + H2

Answers

Single replacement reaction

Question 7 point
What is the name of the covalent compound with the formula P2N3?

Answers

List of covalent compounds
Binary molecular (covalent) compounds
compound systematic name
NO2 nitrogen dioxide
N2O3 dinitrogen trioxide
N2O4 dinitrogen tetroxide
N2O5 dinitrogen pentoxide

How many molecules of O2 will be formed from 0.500 grams of KCIO3

Answers

Answer:

3.7 x 10²¹ O₂ molecules

Explanation:

2KClO₃ => 2KCl + 3O₂

given 0.500g KClO₃ => 0.500g/122.55g/mol = 0.0041 mole KClO₃

0.0041 mole KClO₃ => 3/2(0.0041) mole O₂ = 0.0061 mole O₂

0.0061 mole O₂ = 0.0061 mole O₂ x 6.02 x 10²³ molecules O₂/mole O₂

= 3.7 x 10²¹ molecules O₂

Which statement accurately describes renewable energy sources?

1. They provide the majority of the energy for the United States.

2. They take millions of years to form and should be used responsibly.

3. They are found in nearly limitless supply.

4. They include fossil fuels and hydroelectric power.

Answers

1 I pretty sure not 100% but I think

At some temperature for the equilibrium PX3(g) + X2(g) # PX5(g) the equilibrium constant is 0.74. At the same temperature the equilibrium constant for PX5(9) + PX3(g) X2(g) is​

Answers

Answer: The equilibrium constant for [tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex] is 1.35

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]  

For the given chemical reaction:

[tex]PX_3(g)+X_2(g)\rightarrow PX_5(g)[/tex]

The expression for [tex]K_c[/tex] is written as:

[tex]K_c=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}[/tex]

[tex]0.74=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}[/tex]

For the reverse chemical reaction:

[tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex]

The expression for [tex]K_c'[/tex] is written as:

[tex]K_c'=\frac{[PX_3]^1[X_2]^1}{[PX_5]^1}[/tex]

[tex]K_c'=\frac{1}{K_c}=\frac{1}{0.74}=1.35[/tex]

The equilibrium constant for [tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex] is 1.35

Is chemistry required to get into speech language pathology?​

Answers

Answer:

As of right now (4-7-2021), the physical science requirement for the SLP certificate must be met by completing coursework in the areas of either chemistry or physics.

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