a reflection across y=2
HELP DUE VERY SOON

Answer: 10 miles

Step-by-step explanation:

Given

The length of the road is 1000 miles

Solve

1 : 100 = x : 1000 ⇔ Proportion Set Up

100x = 1000 ⇔ Cross Multiply

100x/100 = 1000/100 ⇔ Divide both sides by 100

x=10 ⇔ Simplify

Hope this helps!! :)

Please let me know if you have any questions

Remove parenthesis, rearrange, and combine like terms.

7+i-6+4i

1i+4i+7-6

5i+1

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hope it helps

Answer:

Domain- (-∞,∞), {x/x ∈ R}

Step-by-step explanation:

Answer: here is your answer

Step-by-step explanation:

A= 16

B= -8

C= 6

D= -16

E= -4

Answer: 166 2/3m

Step-by-step explanation:

Area of a rectangle = length times width

Length: 16 2/3

To find the width, multiply it by 3/5.

w = 16 2/3 ·  3/5

w = 10

Then, multiply the length by the width.

a = l · w

a = 16 2/3 · 10

a = 166 2/3m

Answer:

y-3 = 2x

2x-y+3=0 we have

slope

m =- coefficient of x/coefficient of y=-2/-3=2/3 is a slope..

Answer:

sinx=opp/hyp=6/10=0.6

x=sin-(0.6)=37°

Answer:

216

Step-by-step explanation:

6*6*6= 216

btw i am not using the formula for volume. 6*6 because you need the area of one side. then multiply that by 6 because there are 6 sides of a cube so 6*6*6=216

Answer:

(a) Always true

Step-by-step explanation:

In the case when there is a matrix of coefficient for a homogeneous system for n linear equations so it does not have an opposite and then the system would be have the infinite various solutions

So this is always true as in this it can be unique test or infinite.

So according to the given situation, the option a is correct

Step-by-step explanation:

length = l

width = w

perimeter of garden = 76 ft

perimeter = 2l + 2w

2l + 2w = 76 (eqn 1)

l - w = 12 (eqn 2)

(eqn 1) ÷ 2

l + w = 38 (eqn 3)

(eqn 2) + (eqn 3)

2l = 50

2l/2 = 50/2

l = 25

The length of the garden is 25 ft.

Substitute l = 25 into (eqn 3)

l + w = 38

25 + w = 38

w = 38 - 25

w = 13

The width of the garden is 13 ft.

Answer:

300

Step-by-step explanation:

3x10x10=300

Answer:

300 cm^2

Step-by-step explanation:

A= (3)(10^2)

A= 3(100)

A= 300

Answer:

pirwvjihpwrugh

Step-by-step explanation:

wrhfuwhfuhugfrifhi

Answer:

not possible

Step-by-step explanation:

It can't be possible because the ratio would be 50:1 is possible

Answer:

D

Step-by-step explanation:

Answer:D

Step-by-step explanation:

Answer:

No, Andre is not correct.

Step-by-step explanation:

I believe Andre is not correct because each 1 on the left balances with a 1 on the right. So taking away the two 1s on the left only leaves the hanger balanced if two 1s are removed on the right. This leaves on the left and three 1s on the right, so x=3. This is like x+2=5 if you subtract 2 from the x side then you get x=3. Hope this helps!

Answer:

The awnser is 14

Step-by-step explanation:

If you multiply length x width then divide u get 14

The question is incomplete. The complete question is :

The volume of a sphere is increasing at a rate of 7 cm^3/sec. Find the rate of change of its surface area when its volume is 4 pi / 3 cm^3. (Do not round your answer.)

Solution :

Volume of the sphere, [tex]$V=\frac{4}{3} \pi r^3$[/tex]

Given that [tex]$\frac{dV}{dt}= 7 \ cm^3/s $[/tex]

V = [tex]$\frac{4 \pi}{3} = \frac{4 \pi r^3}{3}$[/tex]

∴ r = 1

[tex]$\frac{dV}{dt} =\frac{4}{3} \pi .3.r^2 \ \frac{dr}{dt}$[/tex]

[tex]$7 = \frac{4}{3} ( \pi )(3) (1)^2 \frac{dr}{dt}$[/tex]

[tex]$\frac{dr}{dt}=\frac{7}{4 \pi}$[/tex]   cm/s

Surface area, [tex]$A = 4 \pi r^2$[/tex]

    [tex]$\frac{dA}{dt} = 8 \pi r \ \frac{dr}{dt}$[/tex]

[tex]$\frac{dA}{dt} = 8 \pi \times \frac{7}{4 \pi} \times 1$[/tex]

    [tex]$=14 \ cm^2/s $[/tex]

Ewan HH

Step-by-step explanation:

Ewanjajsbehudbeiisiejebejehehehheehhehehe

Answer:

???

Step-by-step explanation:

Answer:

3-270x

Step-by-step explanation:

Answer:

0.09

Step-by-step explanation:

Answer:

Between the lower-bound of 117 mg/dl and the upper bound of 137 mg/dl.

Step-by-step explanation:

Empirical Rule

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this question:

Mean of 127, standard deviation of 10.

For the sample mean:

By the Central Limit Theorem, mean is 127, while the standard deviation is [tex]s = \frac{10}{\sqrt{4}} = 5[/tex]

According to the empirical rule, in 95 percent of samples the SAMPLE MEAN blood-glucose level will be between?

By the Empirical Rule, within 2 standard deviations of the mean. So

127 - 2*5 = 117 mg/dl

127 + 2*5 = 137 mg/dl.

Between the lower-bound of 117 mg/dl and the upper bound of 137 mg/dl.

Answer:

60

Step-by-step explanation:

Answer:

The equation is [tex]A(t) = 0.52*(0.9885)^{(t)}[/tex].

0.4713 grams would remain in the tumor after 8.5 days.

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance that decays, after t days, is given by:

[tex]A(t) = A(0)*(1-r)^t[/tex]

In which A(0) is the initial amount and r is the decay rate, as a decimal.

A tumor is injected with 0.52 grams of Iodine-125.

This means that [tex]A(0) = 0.52[/tex]

After 1 day, the amount of Iodine-125 has decreased by 1.15%.

This means that [tex]r = 0.0115[/tex]

So

[tex]A(t) = A(0)*(1-r)^t[/tex]

[tex]A(t) = 0.52*(1-0.0115)^t[/tex]

[tex]A(t) = 0.52*(0.9885)^t[/tex]

Then use the formula for A(t) to find the amount of Iodine-125 that would remain in the tumor after 8.5 days.

This is A(8.5).

[tex]A(t) = 0.52*(0.9885)^t[/tex]

[tex]A(8.5) = 0.52*(0.9885)^{8.5} = 0.4713[/tex]

0.4713 grams would remain in the tumor after 8.5 days.

Answer:

Equation: 2.25x+4.7=58.70

Answer: x = 24x=24

Hope this helps

Answer:

<5,2>

Step-by-step explanation: