A bag of marbles is hanging motionless on a spring scale. What prevents the bag from falling?​

Answers

Answer 1

Answer:

The vector sum of all forces acting on it is zero, its at equilibrium.

Explanation:

The bag of marbles hanging on a spring scale applies its weight downwards, which was counterbalanced by the reaction from the spring scale (obeying the Newton's third law of motion). And since no external forces are applied to the system, thus the equilibrium of the system.

If the weight of the bag is greater than the reaction from the spring scale, the scale breaks and the system would not be balanced.


Related Questions

A plane moves at 15 km/h for a total distance of 300km. How long did it fly for? *
20 hours
0.05 hours
450,000 hours
2 hours

Answers

20 hours you do 300 divided by 15 and get 20 hours

A 35 g block of ice is cooled to −83 ◦C. It is added to 565 g of water in an 87 g copper calorimeter at a temperature of 22◦C. Find the final temperature. The specific heat of copper is 387 J/kg · ◦C and of ice is 2090 J/kg · ◦C . The latent heat of fusion of water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg · ◦C . Answer in units of ◦C.

Answers

Answer:

Explanation:

Heat gained by ice in warming up to 0⁰C = .035 x 2090 x (83-0)= 6071.45 J

heat used up by ice to melt at 0⁰C = .035 x 3.33 x 10⁵ J = 11655 J

Heat used up in warming up water to t⁰C = .035 x 4186 x t = 146.51 t

heat released by warm water to cool from 22⁰C to t = .565 x 4186 x ( 22 - t )

=52032 -2365.1 t

heat released by copper calorimeter  to cool from 22⁰C to t =  .087 x 387 x ( 22 - t ) = 740.72 - 33.7 t

total heat released = 52032 -2365.1 t  + 740.72 - 33.7 t

= 52772.72 - 2398.8 t

Heat lost = heat gained

52772.72 J- 2398.8 t  = 6071.45 J + 11655 J + 146.51 t

2545.31 t = 35046.27

t = 13.8°C.

Based on the graph, describe how momentum changes with time for an object in free fall. If you can help, I would be so grateful.

Answers

With time, momentum increases as it builds speed assuming their is nothing in the way to stop it. Based on the graph, you can see that example being displayed as the line on the graph gets higher

Which of the following statements is true about absolute zero?

It is the point at which electrons separate from the nucleus of atoms.
It is the point at which electrons separate from the nucleus of atoms.

It is theoretically the point at which all particle motion stops.
It is theoretically the point at which all particle motion stops.

It occurs at 273 degrees Kelvin.
It occurs at 273 degrees Kelvin.

It is the point at which protons separate from neutrons in the nucleus

Answers

Answer:

It is the point at which electrons separate from the nucleus of atoms. It is the point at which electrons separate from the nucleus of atoms. It is theoretically the point at which all particle motion stops. ... It occurs at 273 degrees Kelvin. ... It is the point at which protons separate from neutrons in the nucleus.

Explanation:

A squash ball with an initial velocity of 19.21 m/s [W] is hit by a squash racket, changing its velocity to 40.22 m/s [E] in 0.312 s. What is the squash ball’s average acceleration?

Answers

Acceleration = (change in velocity) / (time for the change)

Change in velocity = 59.43 m/s East

Time for the change = 0.312 s

Acceleration = 190.5 m/s^2 East

How far is it between the cafeteria and the swimming pool
A.
length
B.
volume
C.
distance
D.
displacement

Answers

C distance

Explanation:

A wave traveling at 200 m/sec has a wavelength of 2.5 meters. What is the frequency of this wave

Answers

Answer:

600Hz

Explanation:

Three people push a piano on wheels with forces of 130 N to the right, 150 N to the left, and 165 N to the right. What is the strength and direction of the net force on the piano?

Answers

Answer:

45 N to the right possibly?

What are the purposes of these items aboard the Voyager probes? • Low-energy particle detector: • Magnetometer boom: • High-gain antenna: • Photopolarimeter: • Cosmic ray:

Answers

Explanation:

1. Low-energy particle detector: This particle detector measures the charged particles of the solar winds.

2. Magnetometer boom: This device measures magnetic fields produced by astronomical bodies.

3. High-gain antenna: A HGA has a narrow radio beam that is used to enhance the strength of signal. They simply amplify the weak signals.

4. Photopolarimeter: This is an instrument that is used to measure the strength and intensity and polarization of reflected light.

Answer:

what they said

Explanation:

1. What is the magnitude of the force on a charge of +40 μC that is 0.6 m from a charge of - 80 μC?

Answers

Answer:

The magnitude of the force is 79.893 N.

Explanation:

The magnitude of the electrostatic force between the two particles is determined by Coloumb's Law, whose formula is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)

Where:

[tex]\kappa[/tex] - Electrostatic constant, in newtons-square meters per square coulomb.

[tex]q_{A}, q_{B}[/tex] - Electric charges, in coulombs.

[tex]r[/tex] - Distance, in meters.

If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q_{A} = +40\times 10^{-6}\, C[/tex], [tex]q_{B} = - 80\times 10^{-6}\, C[/tex] and [tex]r = 0.6\,m[/tex], then the magnitude of the force is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]

[tex]F = 79.893\,N[/tex]

The magnitude of the force is 79.893 N.

The equation below shows a general equation for a reaction, and the amounts of the substance are written underneath.

AB + CD → AC + BD
(15 g) (?) (?) (10 g)

The total mass of the products is 50g. Which best completes the other two amounts?

The amount of CD is 40 g, and the amount of AC is 35 g.
The amount of CD is 35 g, and the amount of AC is 40 g.
The amount of CD and AC would be the same.
The amount of CD and AC is undetermined.

Answers

Explanation:

The amount of CD is 35 g, and the amount of AC is 40 g.

Explanation:

AB + CD \rightarrow AC + BDAB+CD→AC+BD

The law of conservation of mass states that in any chemical reaction, the total mass of the reactants must be equal to the total mass of the products.

In this reaction, we know the mass of one reactant (AB, 15 g) and the mass of one product (BD, 10 g). In order to have the same total mass on the left side and on the right side of the equation, the mass of AC must be 5 g more than the mass of CD. We see that the only choice that satisfies this condition is:

The amount of CD is 35 g, and the amount of AC is 40 g.

In fact, if we assume these masses are correct, we have:

- on the reactant side: m(AB)+m(CD)= 15g + 35g = 50g

- on the product side: m(AC)+m(BD)= 40g + 10g = 50g

so, we have the same mass on both sides of the equation, and the law of conservation of mass is satisfied.

Answer:

B is  the answer on edge

Explanation:

B: The amount of CD is 35 g, and the amount of AC is 40 g.

Question 6 of 10
If this vector were twice as long, what would be the coordinates of the tip?
O A. (1,-2)
O B. (-2, 1)
O C. (-4,2)
D. (2,-4)
PREVIOUS

Answers

The answer is c or b u choose

Why must the Moon travel more than a full orbit around the Earth for the full moon to be complete?

Answers

Answer:

The difference between the sidereal and synodic months occurs becuase as our moon moves around the earth, the earth also moves around our sun. Our moon must travel a little farther in its path to make up for the added distance and complete the phase cycle.

Explanation:

Hope this helps.

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration

Answers

[tex]\Large {{ \sf {Question :}}} [/tex]

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?

[tex]\Large {{ \sf {Given :}}} [/tex]

Initial Velocity (u) - 5 m/sFinal Velocity (v) - 15 m/sTime (t) - 10 sec

[tex]\Large {{ \sf {Formulae :}}} [/tex]

If the velocity of an object changes from an initial value u to the final value v in time t, the acceleration a is, [tex]a \: = \frac{v - u}{t} [/tex][tex]\Large {{ \sf {Step-by-step explanation :}}} [/tex]

[tex]a \: = \frac{v - u}{t} \\ or \: \: a = \frac{(15 - 5)}{10} m \: s^{ - 2} \\ or \: \: a \: = \frac{10}{10}m \: s^{ - 2} \\ or \: \: a = 1m \: s^{ - 2} [/tex]

[tex]\Large {{ \sf {Answer :}}} [/tex]

His acceleration is [tex]1m \: s^{ - 2} [/tex]

Please help me look at the image below

Answers

I can’t see anything

A tuba creates a 4th harmonic of frequency 116.5 Hz. What is the frequency of the third harmonic? (Speed of sound = 343 m/s) (Unit = Hz )​

Answers

Answer:

3rd Harmonic Frequency created by tuba is equal to [tex]87.375[/tex] hertz

Explanation:

Given -

4th Harmonic frequency created by tuba is equal to [tex]116.5[/tex] hertz

1st Harmonic Frequency created by tuba is equal to [tex]\frac{116.5}{4}[/tex] hertz

3rd Harmonic Frequency created by tuba is equal to [tex]3* \frac{116.5}{4}[/tex] hertz

3rd Harmonic Frequency created by tuba is equal to [tex]87.375[/tex] hertz

Answer:

87.375 Acellus

Explanation:

In the the table there is 20 kj of coal, how much energy in joules is 1g of coal?

Answers

Answer:

what do u meN by this i really don't know

A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center of the disk. The platform has a mass of 150 kg, a radius of 2.0 m, and a rotational inertia of 300 kg·m2 about the axis of rotation. A 60 kg student walks slowly from the rim of the platform toward the center. If the angular speed of the system is 1.4 rad/s when the student starts at the rim, what is the angular speed when she is 0.70 m from the center?

Answers

Answer: [tex]2.29\ rad/s[/tex]

Explanation:

Given

Mass of Platform M=150 kg

the radius of Platform R=2 m

Moment of inertia of Platform [tex]I=300\ kg.m^2[/tex]

Mass of student [tex]m=60\ kg[/tex]

The initial angular speed of the student is [tex]\omega _1=1.4\ rad/s[/tex]

Initially, the moment of inertia of platform and student is

[tex]I_1=\dfrac{1}{2}MR^2+mR^2\\\\I_1=300+60\times 4=540\ kg.m^2[/tex]

The final moment of inertia

[tex]I_2=\dfrac{1}{2}MR^2+mr^2\\\\I_2=300+60\times 0.7^2=329.4\ kg.m^2[/tex]

Conserving angular momentum

[tex]I_1\omega_1=I_2\omega _2\\\\540\times 1.4=329.4\times \omega_2\\\\\omega_2=\dfrac{756}{329.4}=2.29\ rad/s[/tex]

Which type of map best shows the three dimensions of Earth’s surface?

Answers

Answer:

please give me brainlist and follow

Explanation:

topographic map

A topographic map shows a three-dimensional representation of a flat surface. It has contour lines joining points of equal elevation; the closer the lines are the steeper the elevation is.

Waves that move through space are called

Answers

Answer:

Electromagnetic waves are waves that can travel through matter or through empty space

A baseball sits motionless near first base on a baseball diamond. What statement best explains why the baseball remains motionless?

Answers

Answer:

Explanation:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. This postulate is known as the law of inertia.

hope this helps :))

There is no force acting on the baseball the statement best explains why the baseball remains motionless.

What is inertia?

A body wants to remain in its original position until or unless the external force is not applied to it. Such a phenomenon is known as inertia.

Newton's first law asserts that if a body is at rest or traveling at a uniform speed in a straight direction,

It will remain at rest or continue to move in a straight path at a constant speed until acted on by a force. This is referred to as the law of inertia.

There is no force acting on the baseball the statement best explains why the baseball remains motionless.

Hence option B is correct.

To learn more about the inertia refer to the link;

https://brainly.com/question/3268780

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject

Answers

Explanation:

speed : • how fast an object changes position

• miles per hour.

• distance/time.

velocity: • speed in a direction

• miles per hour North

• distance/ time in a direction

Decribe the general shape of the graph.​

Answers

Answer:

the results increase, positive

1 poi
True or False: An object can be in motion and not in motion at the same
time depending on which frame of reference you are comparing the
motion to.
O True
False

Answers

Answer:

true

Explanation:

for example assume you are setting in a moving bus and when someone see you from the ground you are in motion but for some who is with you in the bus you are not in motion.

A 20 g block of ice is cooled to −65 ◦C. It

is added to 570 g of water in an 76 g copper

calorimeter at a temperature of 26◦C.

Find the final temperature. The specific

heat of copper is 387 J/kg ·

◦C and of ice is

2090 J/kg ·

◦C . The latent heat of fusion of

water is 3.33 × 10^5

J/kg and its specific heat

is 4186 J/kg ·

◦C .

Answer in units of ◦C.

Answers

Answer:

The final temperature is approximately 23.55°C

Explanation:

The given parameters are;

The mass of the ice block, m₁ = 20 g

The initial temperature of the block, T₁ = -65°C

The mass of the water to which the block is added, m₂ = 570 g

The mass of the copper container containing the water, m₃ = 76 g

The initial temperature of the water and the copper, T₂ = 26°C

The specific heat capacity of copper, c₃ = 387 J/(kg·°C)

The specific heat capacity of ice, c₄ = 2,090 J/(kg·°C)

The latent heat of fusion of ice, l = 3.33 × 10⁵ J/kg

The specific heat capacity of water, c₁ = 4,186 J/(kg·°C)

We have;

ΔQ = m₁·c₁·ΔT + m₁·l = m₂·c₂·ΔT + m₃·c₃·ΔT

Therefore, we get;

20 × 2,090 × -65 +  20 × 3.33 × 10⁵ + 20 × T × 4,186  = 570 × 4,186 × (26 - T) + 76 × 387 × (26 - T)

Using a graphing calculator, we get;

83720·T + 3943000 = 62801232 - 2415432·T

The final temperature, T ≈ 23.55 °C

How do you rationalize the tension being used in Tennis Racket strings using the concept of impulse and momentum?

Answers

Answer:

The momentum, ΔP, and therefore, kinetic energy given to the ball in a serve is the result of the product of the tension force, 'F', in the string and the time of contact, Δt, between the ball and the string

ΔP = F × Δt

Explanation:

The impulse, ΔP, is the produce of the force, 'F', applied to a body for a given period of time, Δt', that gives motion to the body, and it is equal to the change of momentum of the body

ΔP = F × Δt

The momentum, 'P', of a body is the product of the mass, 'm', of the body and its velocity, 'v'

P = m × v

Tension is the axial pulling force of a string

T = Axial Force, F[tex]_{axial}[/tex]

The tension used in Tennis Racket strings is between 40 to 65 lbs.

When high tension is used in the string, the string is taut, and the contact duration between the Racket string and the ball is minimal, and the player needs to use more force to obtain a high momentum, and therefore, energy in the ball, which reduces control, and increase stress, as force is more emphasized

When low tension is used in the string, the Tennis Racket strings are more elastic. During a serve, the ball pushes the strings further back into the racket, such that the ball spends more time in contact with the string, (Δt is larger), and therefore, the impulse, F·Δt = ΔP, given to the ball is larger, therefore, the ball has a larger change in momentum, and therefore more energy in the intended direction.

However, a very slackened string will increase the increase area and time (large Δt) of contact of the ball and the racket such that the force given to the ball, F = ΔP/(large Δt) is reduced and therefore reduce the likelihood of gaining points from a serve against an opponent with a much forceful return of a serve.

______ charges repel each other.

Answers

Answer:

like I commented it yesterday can i have brainiest

Explanation: oh and HI

Answer:

Like

Explanation:

I put it before but my answer got deleted

John, a fireman, slides down a pole when the fire alarm sounds. He reaches the ground at 5m^-1. Give that his mass is 60kg. Find the friction that acts against his motion as he slides down the pole.

Answers

Friction as it is acting upon an object over a surface

The tendency to pull other objects toward it is called

Answers

Answer:

""gravity. the force that pulls on objects and causes acceleration if the objects are not balanced by an opposing force. speed. distance traveled per unit time. Newton's Second Law of Motion.""

Explanation:

The half-life of technetium-99 is 6 hours.How much of a 100 milligram sample of
technetium-99 will remain after 30 hours? *
O 3.125 mg
O 12.5 mg
O 6.25 mg
O 1.56 mg

Answers

6.25 mg ...............
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