Answers
Answer:
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Step-by-step explanation:
Related Questions
Determine the equation of a circle with center at (8, 10) and radius is 6
Answers
Where (h,k) is the center and the r is the radius . So the equation is as follows
( x- 8 ) ^2 + ( y -10 ) ^ 2 = 6^2
Hope this helped
The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the garden
Answers
Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
Hope it helps :)
Answer:
Step-by-step explanation:
Width = w
Length = 2w + 8
Area of rectangular garden = 280 square meter
length * width = 280
(2w + 8 ) *w = 280
2w * w + 8*w = 280
2w² + 8w = 280
2w² + 8w - 280 = 0
Divide the whole equation by 2
w² + 4w - 140 = 0
w² + 14w - 10w - 14 *10 = 0
w(w + 14) - 10(w + 14) = 0
(w + 14)(w - 10)= 0
w - 10 = 0 {Ignore w + 14, as measurements will not be -ve}
w = 10 m
l = 2*10 +8
= 20 +8
l = 28 m