You are studying the boiling points of liquids with some fellow students. You have two liquids of different molecular weights, and you test each of them twice. You find that the one with a lower molecular weight also has a lower boiling point. You would like to be more confident with the pattern you are noticing. What are two possible next steps? In one to two sentences, give specific, different examples of how the experiment could be extended, assessed, or improved.

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Answer 1

The boiling points of two or three other pairs of liquids in which one liquid has a lower molecular mass than the other can be studied in order to see if the pattern is consistent.

The boiling point of a substance refers to the temperature at which its vapor pressure is equal to the atmospheric pressure. The boiling point of a substance has a lot to do with its molecular mass.

Generally, substances that has a higher molecular mass has a higher boiling point except other factors at at work. In order to confirm whether the pattern that you are noticing about molecular weights and boiling point is consistent, three other liquids with different molecular masses, one being higher than the other can be studied and their boiling points compared.

Learn more about boiling points: https://brainly.com/question/2153588


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[tex] \huge \rm \ \blue \:{ \overbrace{ \underbrace{ \tt{ \color{red}{ \: \: \: \: \: \: answer \: \: \: \: \: \: }}}}}[/tex]

[tex] \huge \color{darkblue}P₂S_{5}[/tex]

hope it helps

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A sample of Ammonia gas at 650mmHg and 15 degree has a mass of 56.8g.calculate the volume occupied by the gas. Take N=14, H=1,R=8.3145jk.

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Answer:

The first thing we have to do is change and state all the units so that we can use our ideal gas law equation ([tex]PV = nRT[/tex]).

650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.

[tex]650 \ mmHg \ * \ \frac{101kPa}{760 mmHg} = 86 \ kPa[/tex]

P = 86kPa

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n (moles) = [tex]\frac{mass}{molar \ mass}[/tex] [tex]= \frac{56.8}{17} =[/tex] 3.34 mol

V = ?

Rearrange the equation to solve for Volume:

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V = [tex]\frac{(3.34)(8.31)(288)}{(86)} = 93 L (rounded)[/tex]

Therefore 93 L of volume is occupied by the ammonia gas.

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