The total time she spends playing soccer in a year is 104 hours, which is calculated using the concept of fraction and arithmetic operations.
What is a fraction?
Any numerical number which does not represent the entire quantity is called a fraction. It depicts a part or portion of something. It is generally written in the form of numerator by denominator.
Calculation of the total time Yolanda spends playing soccer
Given that Yolanda plays soccer for 8 ⅔ hours in a month
Firstly, convert the hours in mixed fraction to improper fraction i.e. 8 ⅔ = (8 × 3 + 2) / 3
= 26 / 3
Now, we need to calculate the no. of hours she played in a year, which is done by multiplying the obtained improper fraction with 12
i.e. (26 / 3) × 12
= 104 hours
Hence, Yolanda spends 104 hours a year playing soccer.
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HELP URGENTLY PLEASE
here's the coordinates
b'= (4,5)
c'= (5,3)
solve the equation 3x = 21
Answer:
x = 7
Step-by-step explanation:
3x = 21 ( isolate x by dividing both sides by 3 )
x = 7
To maintain a healthy weight a dog requires 30 calories of food per pound of body weight. if a certain dog weighs 38.45 ibs how many calories would they require
Step-by-step explanation:
30 cal for 1 lb
x cal for 38.45 lbs
x = 38.45lbs × 30 cals
x = 1153.5 cals
Laura runs during her lunch break.
The average speed S, in kilometers per hour, at which Laura runs depends on the temperature t, in degrees Celsius (°C), at the start of her run and can be modeled by the function S(t) = 6 + 0.2(25 - t).
The distance, D, in kilometers, that she can run in 30 minutes given that her average speed is a kilometers per hour can be modeled by the function D(x) = 0.5x.
Which expression models the distance that Laura runs in 30 minutes given that it is t°C outside at the start of her run?
A. 5.5 - 0.2t
B. 11 - 0.1t
C. 11 - 0.5t
D. 5.5 - 0.1t
Using composite functions, the expression that models the distance that she runs is:
D. 5.5 - 0.1t.
What is the composite function of f(x) and g(x)?The composite function of f(x) and g(x) is given by:
(f ∘ g)(x) = f(g(x)).
In this problem, we have that:
The velocity as a function of the temperature is: S(t) = 6 + 0.2(25 - t) = 11 - 0.2t.The distance as a function of the velocity is: D(x) = 0.5x.Hence the distance as a function of the temperature is given as follows:
(D ∘ S)(t) = D(S(t)) = 0.5(11 - 0.2t) = 5.5 - 0.1t.
Which means that option D is correct.
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HELPPP 25 pointssss MATH
Answer: [tex]\frac{3}{4s}[/tex]
Step-by-step explanation:
3s^2 / 4(s)^3=
3s^2 / 4s^3=
3/4 * s^2/s^3=
3/4 * s^(2-3)=
3/4 * s^(-1)=
3/4 * 1/s=
3*1 / 4s=3/(4s)
to find the ratio of 7
Answer:
Ratios compare two numbers, usually by dividing them If you are comparing one data point (A) to another data point (B), your formula would be A/B. This means you are dividing information A by information B. For example, if A is five and B is 10, your ratio will be 5/10
Step-by-step explanation:
hope this helps u :) have a good day! ^-^
I dont get it pls helpppp ihave ten min left it a test HELP
Answer:
d. p+1
a negative 1 point something decimal plus one negative decimal.
gl sh awty
charlotte denning earns both $13/hour and $26 for every sale she completes. during the most recent week, she worked 47 hours and made a total of 71 sales.
Answer: nice for her
Step-by-step explanation:
identify the meanings of the varibles in the point-slope form of a line
The variables in the point-slope form of a line (x₁,y₁) is a given point on the line, m the slope of the line and (x,y) is any point on the line.
Given that the variables in the point-slope form of a line.
The general form of the equation of a line is y - y₁ = m (x-x₁) where m is the slope of line, y₁ and x₁ is any point on the line
It is an equation of degree one x and y represent the coordinate of the point on the line represented in the coordinate plane
m = slope of the line
The general equation of a line is y = mx + c where
m = slope of line
(x₁ , y₁) = it is the given point on the line as data points are represented as (x₁,y₁) , (x₂,y₂) , (x₃,y₃) and so on
(x ,y) = it is any point line where x is any point on the x-axis and y is any point on y-axis
Hence, the variables in the point-slope form of a line where (x₁,y₁) is a given point on the line, m the slope of the line and (x,y) is any point on the line.
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A line passes through point (6, -6) and has a slope of -4/3
Write an equation in Ax+By=C form for this line.
Use integers for A, B, and C.
-
Answer:
4x + 3y = 6
A = 4
B = 3
C = 6
Step-by-step explanation:
A line have a function:
y = ax + b
Because the line has a slope of - 4/3
=> a = - 4/3
=> y = - 4/3 x + b
Because the line go through point (6; - 6)
=> - 6 = - 4/3 .6 + b
=> b - 8 = - 6
=> b = 2
=> The function of the line
y = - 4/3 x + 6
=> 3y = - 4x + 6
=> 4x + 3y = 6
please help need the answer fast
Answer:
n=7
Step-by-step explanation:
Aileen is a salesperson at Lopez Sporting Goods. She is paid a monthly commission on all Little League uniforms she sells. She receives 10% of her first $2,000 in sales and 12% of the balance of her sales. Last week she earned $231.20. What was the total value of the uniforms she sold?
The total value of the uniform Aileen sold is x= 2260 on monthly Commission sells.
Given,
Let us assume the all little League uniform = x
Aileen first commission 10% of 2000$ in sales.
Aileen Second Commission 12% of (x-2000)$
Total Commission Aileen Earner = 10% ×2000 + 12% × (x-2000)
231.2 = 0.1× 2000 + 0.12× (x-2000)
231.2 = 200 + (0.12x - 240 )
231.2 = 200 + 0.12x - 240
After Transformation, we get
0.12x = 231.2 - 200 +240
0.12x = 271.2
x = 271.2/.12
x = 2260
Aileen Sell the total value of Lopez Sporting Goods Uniform is 2260.
So the final Answer is x = 2260$.
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Simplify
(2m^3n^2)^5
[tex] \large \bf \implies{32 {m}^{15} {n}^{10} }[/tex]
Step-by-step explanation:[tex]\bf \longrightarrow{(2m^{3}n^{2})^{5} } \\ \\ \bf \longrightarrow {2}^{5} \times ( {m}^{3})^{5} \times ( {n}^{2})^{5} \\ \\ \bf \longrightarrow32( {m}^{3})^{5}( {n}^{2})^{5} \\ \\ \bf \longrightarrow32 {m}^{15} {n}^{10} [/tex]
Note : We have used the two exponent rules:
[tex](1) \: \: \large \bf \boxed{ \bf \green{(ab)^{n} = {a}^{n} \times {b}^{n} }}[/tex]
[tex](2) \: \: \large \bf \boxed{ \bf \green{(a^{n})^{m} = {a}^{nm} }}[/tex]
Solve for n.
-3=18m+6n
Answer: n= -1/2 -3m
Step-by-step explanation:
A car salesman earns 1/36 in commission. If he sold a car for $43,000, how much did he earn in commission?
Answer:
1194 ....................... is the answer
if a and b are matrix functions such that the matrices a(0) and b(0) are the same, then a and b are the same matrix function.
It is true that if a and b are matrix functions such that the matrices a(0) and b(0) are the same, then a and b are the same matrix function.
What do you mean by the term matrix?Without further explanation, matrices represent linear maps and enable explicit computations in linear algebra. In mathematics, a matrix (plural matrices) is a rectangular array or table of numbers, symbols, or expressions arranged in rows and columns to represent a mathematical object or a property of such an object. As a result, a significant portion of linear algebra involves the study of matrices, and the majority of the characteristics and operations of abstract linear algebra may be described in terms of matrices. The composition of linear maps, for instance, is represented by matrix multiplication.
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Help anyone with both
The word phrases given can be written in algebraic expressions as:
1. B. 4g
2. B. 6/(x + y).
How to Write an Algebraic Expression?"Product" means multiplication.
"The product of g and 4" can be written as an algebraic expression as: 4 × g = 4g.
"Quotient" means the result you get by dividing a number by another number.
"Sum" means addition, or what you get by adding two quantities together.
Therefore, "the sum of x and y" is written in algebraic expression as: x + y.
Thus, the quotient of 6 and (x + y) would be written in algebraic expression as: 6/(x + y).
Therefore, the word phrases given can be written in algebraic expressions as:
1. B. 4g
2. B. 6/(x + y).
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What is the five number summary for this data set 9,14,15,18,20,22,29,36,36,42,45,51
Answer:
Min = 0
Max = 51
M = 25.5
Q1 = 16.5
Q3 = 39
Hope this helps! <3
which inquality best represents the domain of the function shown on the graph?G, 3
Which flaw most accurately illustrates the graphed function's domain?
The inequality most accurately depicts the part's intended domain, which should be -9<x ≤2.
Domain here refers to the x change. The values of with regard to function should be the domain in this case. Additionally, we need to pay attention to the blank line that starts at -9 to 2 in x values.
Since 9 should not be filled however 2 should be.
Therefore, The inequality most accurately depicts the part's intended domain, which should be -9<x ≤2.
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The cross country team left school and trotted to the duck pond at 3mph then ran back to the school at 7mph if the total trip took ten hours how far was the duck pond
Answer:
hey thank you it's I don't know lol thanks
Find a vector function that represents the curve of intersection of the two surfaces. the cylinder x 2 y 2 = 4 and the surface z = xy. r(t) = 2cos(t) i j k
Let [tex]x=2\cos(t)[/tex] and [tex]y=2\sin(t)[/tex], so that
[tex]x^2 + y^2 = 4\cos^2(t) + 4\sin^2(t) = 4[/tex]
is preserved. Then from the surface equation, we get
[tex]z = xy = 4\cos(t)\sin(t) = 2\sin(2t)[/tex]
The curve of intersection is then given by the vector function
[tex]\vec r(t) = 2\cos(t) \, \vec\imath + 2\sin(t)\,\vec\jmath + 2\sin(2t)\,\vec k[/tex]
Round this number to the
nearest hundredth.
0.7456
Answer:
0.75
Step-by-step explanation:
it goes tenths hundredths thousandths....
Answer:
0.75
Step-by-step explanation:
4 is the hundredth in this number. The number after 4 is 5. The rule is if its 5 and over you round up and if not, you round down. In this case the number is 5 so we round up. So the number becomes 0.75 instead of 0.74
True or False? If a grapefruit cost
$0.32 in 1984 and $0.64 in 2006,
then it must have cost $0.48 in
1995.
Answer:
False
Step-by-step explanation:
Without a graph, figure, or any other context the cost of grapefruit in 1995 in not related to the other years by any other facts or figures.
Can you help me solve for x in these 3
can you solve for x −68<8x−4<−36
Answer:
- 8 < x < - 4
Step-by-step explanation:
- 68 < 8x - 4 < - 36 ( add 4 to each interval )
- 64 < 8x < - 32 ( divide each interval by 8 )
- 8 < x < - 4
HELPPPPPPPPPPPPPPP ILL MARK AS BRAINLIST HELPP
The graphs of the equations can be obtained by finding the intercepts, and drawing a line through the intercepts.
1. Please find attached the graph of 2•x - y - 6 = 0
2. Please find attached the graph of 4•x + 2•y + 8 = 0
How can a graph be drawn using the intercepts?The graph of the linear equations using the x and y intercepts are found as follows;
1. 2•x - y - 6 = 0
Therefore;
2•x - y - 6 = 0
y = 2•x - 6
The y-intercept is given by the point where x = 0
The y-intercept is therefore;
y = 2×0 - 6 = -6
The y-intercept is y = -6The x-intercept is given by the point where y = 0
Therefore;
0 = 2•x - 6
x = 6/2 = 3
The x-intercept is at x = 3Please find attached the graph of 2•x - y - 6 = 0, created using the x and y-intercept.
2. 4•x + 2•y + 8 = 0
Therefore;
4•x + 2•y + 8 = 0
y = -(4•x + 8)/2 = -2•x - 4
y = -2•x - 4
The y-intercept is therefore;
y = -2×0 - 4 = -4
The y-intercept is y = -4
The x-intercept is therefore;
0 = -2•x - 4
x = -4/2 = -2
The x-intercept is at x = -2
Please find attached the graph of 4•x + 2•y + 8 = 0, created using the x and y-intercept.
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a light is suspended at a height h above the floor. the illumination, i, at a point p is inversely proportional to the square of the distance, r, from the point p to the light and directly proportional to the cosine of the angle theta. assume k is the constant of proportionality. which of the following can be used to represent the illumination at point p? i
a light is suspended at a height h above the floor. the illumination, i, at a point p is inversely proportional to the square of the distance, r, from the point p to the light and directly proportional to the cosine of the angle theta , I = k cos x / r² can be used to find the illumination at point p.
Light must be at the height of 7.07 for maximum illumination.
I = k cos x / r²
r² = h² + 10²
cos θ = h / [tex]\sqrt{h^{2} +10^{2} }[/tex]
then
I = [tex]k \frac{h}{(h^{2} + 100)^{2/3}}[/tex]
on differentiating, we get,
[tex]\frac{dI}{dh} = k\frac{h^{2} + 100^{3/2 - 3h^{2}(h^{2} + 100 )^{1/2} } }{(h^{2} +100)^{3} }[/tex]
[tex]= k\frac{100 - 2h^{2} }{(h^{2} + 100)^{5/2} } \\\frac{dI}{dh} = 0\\ It gives that \\h = \sqrt{50} = 7.07\\on differentiating again,\\\frac{d^{2} I}{dh^{2} } = k \frac{(6h^{3} - 900h )}{(h^{2} + 100)^{7/2} }[/tex]
for h = 7.07,
[tex]\frac{dI^{2} }{dh^{2} } = -10267.6[/tex]
So , we can conclude that the light must be at the height of 7.07 for maximum illumination.
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Question 5 pls help Pre algebra explain your answer
Answer: -6.62 x 10^-8
Step-by-step explanation:
Which expression is equivalent to this
expression?
√2³
1
2 12
Answer:
calculators are available
Step-by-step explanation:
You start at (1, 3). You move up 2 units and left 6 units. Where do you end?
Answer:
(-5,5)
Step-by-step explanation: